Giao an Vat Ly 11 Cb Moi.13957

Trng THPT Bnh Sn Ngay soan : 08//08/2011 Ngay day : 08/08/2011

GV : Nguyn Vn ng

PHAN I. IEN HOC. IEN T HOCChng I. IN TCH. IN TRNGTit 1. IN TCH. NH LUT CU-LNGI. MUC TIEU 1. Kin thc - Trnh by c khi nim in tch im, c im tng tc gia cc in tch, ni dung nh lut Cu-lng, ngha ca hng s in mi. - Ly c v d v tng tc gia cc vt c coi l cht im. - Bit v cu to v hot ng ca cn xon. 2. K nng - Xc nh phng chiu ca lc Cu-lng tng tc gia cc in tch gia cc in tch im. - Gii bi ton ng tng tc tnh in. - Lm vt nhim in do c xt. II. CHUAN B 1. Gio vin - Xem SGK Vt l 7 v 9 bit HS hc g THCS. - Chun b cu hi hoc phiu cu hi. 2. Hc sinh: n tp kin thc hc v in tch THCS. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Gii thiu chng trnh, sch gio khoa, sch bi tp, sch tham kho. Hot ng 1 (20 pht) : Tm hiu s nhim in ca cc vt, in tch, in tch im, tng tc gia cc in tch. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. S nhim in ca cc vt. in tch. Tng tc in 1. S nhim in ca cc vt Cho hc sinh lm th nghim Lm th nghim theo s hng Mt vt c th b nhim in do : c v hin tng nhim in do c dn ca thy c. xt ln vt khc, tip xc vi mt vt xt. Ghi nhn cc cch lm vt nhim in khc, a li gn mt vt Gii thiu cc cch lm vt nhim in. nhim in khc. nhim in. Nu cch km tra xem vt c b C th da vo hin tng ht cc Gii thiu cch kim tra vt nhim in hay khng. vt nh kim tra xem vt c b nhim in. nhim in hay khng. 2. in tch. in tch im Vt b nhim in cn gi l vt Gii thiu in tch. Tm v d v in tch. mang in, vt tch in hay l mt Cho hc sinh tm v d. in tch. Gii thiu in tch im. Tm v d v in tch im. in tch im l mt vt tch in -1Gio n Vt L 11CB

Trng THPT Bnh Sn Cho hc sinh tm v d v in tch im.

GV : Nguyn Vn ng

c kch thc rt nh so vi khong cch ti im m ta xt. Ghi nhn s tng tc in. 3. Tng tc in Gii thiu s tng tc in. Thc hin C1. Cc in tch cng du th y nhau. Cho hc sinh thc hin C1. Cc in tch khc du th ht nhau. Hot ng 3 (15 pht) : Nghin cu nh lut Coulomb v hng s in mi. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. nh lut Cu-lng. Hng s in mi Gii thiu v Coulomb v th Ghi nhn nh lut. 1. nh lut Cu-lng nghim ca ng thit lp Lc ht hay y gia hai din tch nh lut. im t trong chn khng c phng trng vi ng thng ni hai in tch im , c ln t l thun vi tch ln ca hai in tch Gii thiu biu thc nh lut Ghi nhn biu thc nh lut v v t l nghch vi bnh phng v cc i lng trong . nm vng cc i lng trong khong cch gia chng. Gii thiu n v in tch. . |q q | F = k 1 2 2 ; k = 9.109 Nm2/C2. Cho hc sinh thc hin C2. Ghi nhn n v in tch. r Thc hin C2. n v in tch l culng (C). 2. Lc tng tc gia cc in tch im t trong in mi ng tnh. Gii thiu khi nim in mi. Hng s in mi Cho hc sinh tm v d. Ghi nhn khi nim. + in mi l mi trng cch in. Tm v d. + Khi t cc in tch trong mt Ghi nhn khi nim. in mi ng tnh th lc tng tc gia chng s yu i ln so vi khi t n trong chn khng. gi l Cho hc sinh nu biu thc hng s in mi ca mi trng ( tnh lc tng tc gia hai in Nu biu thc tnh lc tng tch im t trong chn khng. tc gia hai in tch im t 1). + Lc tng tc gia cc in tch trong chn khng. im t trong in mi : F = k Cho hc sinh thc hin C3. | q1q2 | Thc hin C3. . r 2 + Hng s in mi c cho tnh cht cch in ca cht cch in. Hot ng 4 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh c mc Em c bit ? c mc Sn tnh in. Cho hc sinh thc hin cc cu hi 1, 2, 3, 4 trang Thc hin cc cu hi trong sgk. 9, 10. Ghi cc bi tp v nh. Yu cu hc sinh v nh gi cc bi tp 5, 6, 7, 8 sgk v 1.7, 1.9, 1.10 sch bi tp. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB

Trng THPT Bnh Sn Ngay soan : 08/08/2011 Ngay day : 11/08/2011

GV : Nguyn Vn ng

Tiet 2 . THUYET ELECTRON. NH LUAT BAO TOAN IEN TCHI. MUC TIEU 1. Kin thc - Trnh by c ni dung thuyt lectron, ni dung nh lut bo ton in tch. - Ly c v d v cc cch nhim in. - Bit cch lm nhim in cc vt. 2. K nng - Vn dng thuyt lectron gii thch c cc hin tng nhim in. - Gii bi ton ng tng tc tnh in. II. CHUAN B 1. Gio vin - Xem SGK Vt l 7 bit HS hc g THCS. - Chun b phiu cu hi. 2. Hc sinh n tp kin thc c hc v in tch THCS. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Pht biu, bit biu thc ca nh lut Cu-lng. Hot ng 2 (20 pht) : Tm hiu thut electron. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. Thuyt electron 1. Cu to nguyn t v phng din in. in tch nguyn t a) Cu to nguyn t Yu cu hc sinh nu cu to Nu cu to nguyn t. Gm: ht nhn mang in tch ca nguyn t. dng nm trung tm v cc Nhn xt thc hin ca hc sinh. electron mang in tch m chuyn ng xung quanh. Ht nhn cu to bi hai loi ht l ntron khng mang in v prtn mang in dng. Gii thiu in tch, khi lng Ghi nhn in tch, khi lng Electron c in tch l -1,6.10-19C ca electron, prtn v ntron. ca electron, prtn v ntron. v khi lng l 9,1.10-31kg. Prtn c in tch l +1,6.10-19C v khi lng l 1,67.10-27kg. Khi lng ca ntron xp x bng khi lng ca prtn. Yu cu hc sinh cho bit ti sao Gii thch s trung ho v in S prtn trong ht nhn bng s bnh thng th nguyn t trung ca nguyn t. electron quay quanh ht nhn nn ho v in. bnh thng th nguyn t trung ho v in. b) in tch nguyn t Gii thiu in tch nguyn t. Ghi nhn in tch nguyn t. in tch ca electron v in tch ca prtn l in tch nh nht m ta c th c c. V vy ta gi Gii thiu thuyt electron. Ghi nhn thuyt electron. chng l in tch nguyn t. 2. Thuyt electron -3Gio n Vt L 11CB

Trng THPT Bnh Sn Yu cu hc sinh thc hin C1. Thc hin C1.

GV : Nguyn Vn ng + Bnh thng tng i s tt c cc in tch trong nguyn t bng khng, nguyn t trung ho v in. Nu nguyn t b mt i mt s electron th tng i s cc in tch trong nguyn t l mt s dng, n l mt ion dng. Ngc li nu nguyn t nhn thm mt s electron th n l ion m. + Khi lng electron rt nh nn chng c linh ng rt cao. Do electron d dng bt khi nguyn t, di chuyn trong vt hay di chuyn t vt ny sang vt khc lm cho cc vt b nhim in. Vt nhim in m l vt thiu electron; Vt nhim in dng l vt tha electron.

Yu cu hc sinh cho bit khi Gii thch s hnh thnh ion no th nguyn t khng cn trung dng, ion m. ho v in. Yu cu hc sinh so snh khi So snh khi lng ca lng ca electron vi khi lng electron v khi lng ca ca prtn. prtn.

Yu cu hc sinh cho bit khi no th vt nhim in dng, khi Gii thch s nhim in no th vt nhim in m. dng, in m ca vt.

Hot ng3 (10 pht) : Vn dng thuyt electron. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Gii thiu vt dn in, vt cch Ghi nhn cc khi nim vt dn II. Vn dng in. in, vt cch in. 1. Vt dn in v vt cch in Yu cu hc sinh thc hin C2, Thc hin C2, C3. Vt dn in l vt c cha cc C3. Gii thch. in tch t do. Yu cu hc sinh cho bit ti sao Vt cch in l vt khng cha s phn bit vt dn in v vt Gii thch. cc electron t do. cch in ch l tng i. S phn bit vt dn in v vt Thc hin C4. cch in ch l tng i. Yu cu hc sinh gii thch s 2. S nhim in do tip xc nhim in do tip xc. V hnh 2.3. Nu cho mt vt tip xc vi Yu cu hc sinh thc hin C4 mt vt nhim in th n s Gii thch. nhim in cng du vi vt . Gii tthiu s nhim in do 3. S nhim din do hng ng hng ng (v hnh 2.3). Thc hin C5. a mt qu cu A nhim in Yu cu hc sinh gii thch s dng li gn u M ca mt nhim in do hng ng. thanh kim loi MN trung ho v Yu cu hc sinh thc hin C5. in th u M nhim in m cn u N nhim in dng. Hot ng 4 (5 pht) : Nghin cu nh lut bo ton in tch. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn III. nh lut bo ton in tch Gii thiu nh lut. Ghi nhn nh lut. Trong mt h vt c lp v in, tng Cho hc sinh tm v d. Tm v d minh ho. i s cc in tch l khng i. Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kit thc hc trong bi.Yu cu hc Tm tt li nhng kin thc trong bi. sinh v nh gii cc bi tp 5, 6 sgk v 2.1, 2.2, 2.5, 2.6 sch bi tp. Ghi cc bi tp v nh. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 3. IEN TRNG VA CNG O IEN TRNG. NG SC IENI. MUC TIEU 1. Kin thc - Trnh by c khi nim in trng. - Pht biu c nh ngha ca cng in trng v nu c c im ca vect cng in trng. - Bit cch tng hp cc vect cng in trng thnh phn ti mi im. - Nu c khi nim ng sc in v cc c im ca ng sc in. 2. K nng - Xc nh phng chiu ca vect cng in trng ti mi im do in tch im gy ra. - Vn dng quy tc hnh bnh hnh xc nh hng ca vect cng in trng tng hp. - Gii cc Bi tp v in trng. II. CHUAN B 1. Gio vin - Chun b hnh v 3.6 n 3.9 trang 19 SGK. - Thc k, phn mu. - Chun b phiu cu hi. 2. Hc sinh - Chun b Bi trc nh. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu v gii thch hin tng nhim in do tip xc, do hng ng. Hot ng 2 (10 pht) : Tm hiu khi nim in trng. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. in trng 1. Mi trng truyn tng tc in Gii thiu s tc dng lc gia Tm thm v d v mi trng Mi trng tuyn tng tc gia cc cc vt thng qua mi trng. truyn tng tc gia hai vt. in tch gi l in trng. 2. in trng Gii thiu khi nim in Ghi nhn khi nim. in trng l mt dng vt cht bao trng. quanh cc in tch v gn lin vi in tch. in trng tc dng lc in ln in tch khc t trong n. Hot ng 3 (30 pht) : Tm hiu cng in trng. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Cng d in trng 1. Khi nim cng d in trng Gii thiu khi nim in Ghi nhn khi nim. Cng in trng ti mt im l trng. i lng c trng cho mnh yu ca in trng ti im . 2. nh ngha Nu nh ngha v biu thc Ghi nhn nh ngha, biu Cng in trng ti mt im l nh ngha cng in thc. i lng c trng cho tc dng lc trng. ca in trng ca in trng ti im . N c xc nh bng -5Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

thng s ca ln lc in F tc dng ln in tch th q (dng) t ti im v ln ca q. Yu cu hc sinh nu n v Nu n v cng in F E= cng in trng theo nh trng theo nh ngha. q ngha. n v cng in trng l N/C Gii thiu n v V/m. Ghi nhn n v tthng hoc ngi ta thng dng l V/m. dng. 3. Vc t cng in trng Gii thiu vc t cng in trng. V hnh biu din vc t cng in trng gy bi mt in tch im. Ghi nhn khi nim.; V hnh. F E= q

Vc t cng in trng E gy bi mt in tch im c : - im t ti im ta xt. - Phng trng vi ng thng ni Da vo hnh v nu cc yu in tch im vi im ta xt. t xc nh vc t cng - Chiu hng ra xa in tch nu l in trng gy bi mt in in tch dng, hng v pha in tch nu l in tch m. tch im. |Q| Yu cu hc sinh thc hin C1. - ln : E = k 2 Thc hin C1. r V hnh 3.4. 4. Nguyn l chng cht in trng Nu nguyn l chng cht. V hnh. E = E1 + E 2 + ... + E n Ghi nhn nguyn l.

IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 4. IEN TRNG VA CNG O IEN TRNG. NG SC IENI. MUC TIEU 1. Kin thc - Trnh by c khi nim in trng. - Pht biu c nh ngha ca cng in trng v nu c c im ca vect cng in trng. - Bit cch tng hp cc vect cng in trng thnh phn ti mi im. - Nu c khi nim ng sc in v cc c im ca ng sc in. 2. K nng - Xc nh phng chiu ca vect cng in trng ti mi im do in tch im gy ra. - Vn dng quy tc hnh bnh hnh xc nh hng ca vect cng in trng tng hp. - Gii cc Bi tp v in trng. II. CHUAN B 1. Gio vin - Chun b hnh v 3.6 n 3.9 trang 19 SGK. - Thc k, phn mu. - Chun b phiu cu hi. 2. Hc sinh - Chun b Bi trc nh. III. TIEN TRNH DAY HOC Hot ng 1 (35 pht) : Tm hiu ng sc in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn III. ng sc in 1. Hnh nh cc ng sc in Gii thiu hnh nh cc ng Quan st hnh 3.5. Ghi nhn Cc ht nh cch in t trong in sc in. hnh nh cc ng sc in. trng s b nhim in v nm dc theo nhng ng m tip tuyn ti mi im trng vi phng ca vc t cng in trng ti im . 2. nh ngha Gii thiu ng sc in Ghi nhn khi nim. ng sc in trng l ng m trng. tip tuyn ti mi im ca n l gi ca vc t cng in trng ti V hnh dng ng sc ca V cc hnh 3.6 n 3.8. im . Ni cch khc ng sc in mt s in trng. trng l ng m lc in tc dng dc theo n. Gii thiu cc hnh 3.6 n Xem cc hnh v nhn xt. 3. Hnh dng ng sc ca mt d 3.9. in trng Ghi nhn c im ng Xem cc hnh v sgk. Nu v gii thch cc c sc ca in trng tnh. 4. Cc c im ca ng sc in im cuae ng sc ca in + Qua mi im trong in trng c trng tnh. mt ng sc in v ch mt m thi + ng sc in l nhng ng c hng. Hng ca ng sc in ti mt im l hng ca vc t cng -7Gio n Vt L 11CB

Trng THPT Bnh Sn Thc hin C2. Yu cu hc sinh thc hin C2. Ghi nhn khi nim. V hnh. Gii thiu in trng u. V hnh 3.10.

GV : Nguyn Vn ng in trng ti im . + ng sc in ca in trng tnh l nhng ng khng khp kn. + Qui c v s ng sc i qua mt din tch nht nh t vung gc vi vi ng sc in ti im m ta xt t l vi cng in trng ti im . 4. in trng u in trng u l in trng m vc t cng in trng ti mi im u c cng phng chiu v ln. ng sc in trng u l nhng ng thng song song cch u.

Hot ng 2 (10 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh c phn Em c bit ? c phn Em c bit ? Yu cu hc sinh tm tt nhng kin thc c bn Tm tt kin thc. hc trong bi. Yu cu hc sinh v nh gi cc bi tp 9, 10, 11, Ghi cc cu hi v bi tp v nh. 12, 13 sgk 3.1, 2.2, 3.3, 3.4, 3.6, 3.7, 3.10 sch bi tp. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 5 : BAI TAPI. MUC TIEU 1. Kin thc : - Vc t cng in trng gy b mt in tch im v nhiu in tch im. - Cc tnh cht ca ng sc in. 2. K nng : - Xc nh c cng in trng gy bi cc din tch im. - Gii thch c mt s hin tng lin quan n in trng, ng sc in trng. II. CHUAN B Gio vin - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii. Hot ng 2 (15 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Yu cu hs gii thch ti sao chn Gii thch la chn. Cu 9 trang 20 : B B. Gii thch la chn. Cu 10 trang 21: D Yu cu hs gii thch ti sao chn Gii thch la chn. Cu 3.1 : D D. Gii thch la chn. Cu 3.2 : D Yu cu hs gii thch ti sao chn Gii thch la chn. Cu 3.3 : D D. Gii thch la chn. Cu 3.4 : C Yu cu hs gii thch ti sao chn Gii thch la chn. Cu 3.6 : D D. Yu cu hs gii thch ti sao chn D. Yu cu hs gii thch ti sao chn C. Yu cu hs gii thch ti sao chn D. Hot ng 3 (20 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 12 trang21 Hng dn hc sinh cc bc gii. Gi tn cc vc t cng Gi C l im m ti cng V hnh in trng thnh phn. in trng bng 0. Gi E 1 v E 2 l Xc nh vc t cng trng in trng tng hp ti C. cng in do q1 v q2 gy ra ti C, ta c E = E 1 + E 2 = 0 Hng dn hc sinh tm v tr ca C. => E 1 = - E 2 . Lp lun tm v tr ca Hai vc t ny phi cng phng, C. tc l im C phi nm trn ng thng AB. Hai vc t ny phi ngc chiu, tc l C phi nm ngoi on AB. Hai vc t ny phi c mun -9Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng bng nhau, tc l im C phi gn A hn B vi |q1| < |q2|. Do ta c: | q2 | | q1 | k 2 = k ( AB + AC ) 2 . AC q 4 AB + AC => = 2 = q1 3 AC => AC = 64,6cm. Ngoi ra cn phi k tt c cc im nm rt xa q1 v q2. Ti im C v cc im ny th cng in trng bng khng, tc l khng c in trng. Bi 13 trang 21 Gi Gi E 1 v E 2 l cng in trng do q1 v q2 gy ra ti C. Ta c : | q1 | 5 E1 = k 2 = 9.10 V/m (hng . AC theo phng AC). E2 = k2

Yu cu hc sinh tm biu thc xc nh AC. Yu cu hc sinh suy ra v thay s tnh ton. Hng dn hc sinh tm cc im khc.

Tm biu thc tnh AC. Suy ra v thay s tnh AC. Tm cc im khc c cng in trng bng 0.

Hng dn hc sinh cc bc gii. V hnh

Gi tn cc vc t cng in trng thnh phn. Tnh ln cc vc t cng in trng thnh phn

| q1 | = 9.105V/m (hng .BC 2 theo phng CB). Cng in trng tng hp ti C Xc nh vc t cng E = E1 + E 2 in trng tng hp ti C. E c phng chiu nh hnh v. Hng dn hc sinh lp lun V tam gic ABC l tam gic vung Tnh ln ca E tnh ln ca E . nn hai vc t E 1 v E 2 vung gc vi nhau nn ln ca E l: 2 E = E12 + E 2 = 12,7.105V/m. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 6. CONG CUA LC IENI. MUC TIEU 1. Kin thc - Nu c c im ca lc tc dng ln in tch trong in trng u. - Lp c biu thc tnh cng thc ca lc in trong in trng u. - Pht biu c c im ca cng dch chuyn in tch trong in trng bt k. - Trnh by c khi nim, biu thc, c im ca th nng ca in tch trong in trng, quan h gia cng ca lc in trng v gim th nng ca in tch trong in trng. 2. K nng - Gii Bi ton tnh cng ca lc in trng v th nng in trng. II. CHUAN B 1. Gio vin: V trn giy kh ln hnh 4.2 sgk v hnh nh h tr trng hp di chuyn in tch theo mt ng cong t M n N. 2. Hc sinh: n li cch tnh cng ca trng lc v c im cng trng lc. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu nh ngha v cc tnh cht ca ng sc ca in trng tnh. Hot ng 2 (20 pht) : Tm hiu cng ca lc in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn V hnh 4.1 ln bng. V hnh 4.1. I. Cng ca lc in Xc nh lc in trng tc 1. c im ca lc in tc dng dng ln in tch q > 0 t ln mt in tch t trong in trong in trng u c cng trng u in trng E . F = qE V hnh 4.2 ln bng. V hnh 4.2. Tnh cng khi in tch q di chuyn theo ng thng t M n N. Tnh cng khi in tch di chuyn theo ng gp khc MPN. Nhn xt. Ghi nhn c im cng. Lc F l lc khng i.. 2. Cng ca lc in trong in trng u AMN = qEd Vi d l hnh chiu ng i trn mt ng sc in. Cng ca lc in trng trong s di chuyn ca in tch trong in trng u t M n N l AMN = qEd, khng ph thuc vo hnh dng ca ng i m ch ph thuc vo v tr ca im u M v im cui N ca ng i. 3. Cng ca lc in trong s di chuyn ca in tch trong in trng bt k Cng ca lc in trong s di chuyn ca in tch trong in trng bt k khng ph thuc vo hnh dng ng i m ch ph thuc vo v tr im u v im cui ca ng i. Lc tnh in l lc th, trng tnh in l trng th. Gio n Vt L 11CB

Cho hc sinh nhn xt. a ra kt lun.

Ghi nhn c im cng ca Gii thiu c im cng ca lc din khi in tch di chuyn lc din khi in tch di chuyn trong in trng bt k. trong in trng bt k. Yu cu hc sinh thc hin C1. Yu cu hc sinh thc hin C2. Thc hin C1. Thc hin C2.

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Trng THPT Bnh Sn

GV : Nguyn Vn ng

Hot ng 3 (15 pht) : Tm hiu th nng ca mt in tch trong in trng. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Th nng ca mt in tch trong in trng 1. Khi nim v th nng ca mt in tch trong in trng Yu cu hc sinh nhc li khi Nhc li khi nim th nng Th nng ca in tch t ti mt nim th nng trng trng. trng trng. im trong in trng c trng cho Gii thiu th nng ca in Ghi nhn khi nim. kh nng sinh cng ca in trng tch t trong in trng. khi t in tch ti im . 2. S ph thuc ca th nng WM vo in tch q Gii thiu th nng ca in Ghi nhn mi kin h gia th Th nng ca mt in tch im q tch t trong in trng v s nng v cng ca lc in. t ti im M trong in trng : ph thuc ca th nng ny vo WM = AM = qVM in tch. Th nng ny t l thun vi q. 3. Cng ca lc in v gim th nng ca in tch trong in trng Cho in tch q di chuyn Tnh cng khi in tch q di AMN = WM - WN trong in trng t im M chuyn t M n N ri ra . Khi mt in tch q di chuyn t n N ri ra . Yu cu hc im M n im N trong mt in sinh tnh cng. Rt ra kt lun. trng th cng m lc in trng tc Cho hc sinh rt ra kt lun. dng ln in tch sinh ra s bng Thc hin C3. gim th nng ca in tch q trong Yu cu hc sinh thc hin in trng. C3. Hot ng 6 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 4, 5, 6, 7 Ghi cc bi tp v nh. trang 25 sgk v 4.7, 4.9 sbt. IV. RUT KINH NGHIEM TIET DAY

- 12 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 7. IEN THE. HIEU IEN THEI. MUC TIEU 1. Kin thc - Trnh by c ngha, nh ngha, n v, c im ca in th v hiu in th. - Nu c mi lin h gia hiu in th v cng in trng. - Bit c cu to ca tnh in k. 2. K nng - Gii Bi tnh in th v hiu in th. - So snh c cc v tr c in th cao v in th thp trong in trng. II. CHUAN B 1. Gio vin - c SGK vt l 7 bit HS c kin thc g v hiu in th. - Thc k, phn mu. - Chun b phiu cu hi. 2. Hc sinh c li SGK vt l 7 v vt l 9 v hiu in th. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu c im cng ca lc in trng khi in tch di chuyn. Hot ng 2 (15 pht) : Tm hiu khi nim in th. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. in th Yu cu hc sinh nhc li 1. Khi nim in th cng thc tnh th nng ca Nu cng thc. in th ti mt im trong in in tch q ti im M trong trng c trng cho in trng v in trng. Ghi nhn khi nim. phng din to ra th nng ca in a ra khi nim. tch. Ghi nhn khi nim. 2. nh ngha Nu nh ngha in th. in th ti mt im M trong in trng l i lng c trng cho in trng v phng din to ra th nng khi t ti mt in tch q. N c xc nh bng thng s ca cng ca lc in tc dng ln in tch q khi q di chuyn t M ra xa v cc v ln ca q Ghi nhn n v. AM VM = Nu n v in th. q Nu c im ca in th. n v in th l vn (V). Yu cu hc sinh nu c 3. c im ca in th im ca in th. Thc hin C1. in th l i lng i s. Thng Yu cu hc sinh thc hin chn in th ca t hoc mt im C1. v cc lm mc (bng 0). Hot ng 3 (20 pht) : Tm hiu khi nim hiu in th. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Hiu in th 1. nh ngha Nu nh ngha hiu in th. Ghi nhn khi nim. Hiu in th gia hai im M, N - 13 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

trong in trng l i lng c trng cho kh nng sinh cng ca in trng trong s di chuyn ca mt in tch t M n N. N c xc nh bng thng s gia cng ca lc in tc dng ln in tch q trong s di chuyn ca q t M n N v ln Yu cu hc sinh nu n v Nu n v hiu in th. ca q. hiu in th. AMN UMN = VM VN = q Gii thiu tnh in k. Quan st, m t tnh in k. 2. o hiu in th o hiu in th tnh in bng tnh in k. 3. H thc lin h gia hiu in th Hng dn hc sinh xy dng Xy dng mi lin h gia v cng in trng mi lin h gia E v U. hiu in th v cng in U trng. E= d Hot ng 4 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 5, 6, 7, 8, Ghi cc bi tp v nh. 9 trang 29 sgk v 5.8, 5.9 sbt. IV. RUT KINH NGHIEM TIET DAY

- 14 -

Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Ngay soan : 23/08/2011 Ngay day : 31/08/2011 Ti t 8. BI TP V CNG CA LC IN. IN TH HIU IN TH I. Mc tiu : 1.kin thc -Cng c khc su kin thc v cng ca lc in -Cng c khc su kin thc v in th Hiu in th 2.k nng : -Bit vn dng cc cng thc trong bi gii mt s bi tp II .Chun b GV : - Chun b mt s bi tp HS : - On v lm bi tp SGK v SBT III .T chc hot ng hc tp : Hot ng 1 : Nhc li cc kin thc c lin quanHot ng gio vin -GV t cc cu hi cng c kin thc c Hot ng hc sinh Ni dung

-HS t li cc cu hi ca GV +in th ti mt im M trong in trng l g ? +nh ngha v biu thc tnh HT ?

I.Ni dung : 1.in th : VM = AM q

-in th ti 1 im c chn lm mc in th bng 0 2.Hiu in th : A UMN = VM VN = MN q=> AMN = UMN.q

Hot ng 2 : Gii mt s cu trc nghim Cu 1 : Cng thc lin h gia cng ca lc in v hiu in th l : q A.UMN =AMN.q B. U MN = AMN U MN C. AMN =UMN.q D. AMN = q Cu 2 .Biu thc no di y biu din mt i lng c n v l vn ? A.q.E.d B.qE C.Ed D.Khng c biu thc no Cu 3 chn pht biu sai A.Trong vt dn lun c in tch B.in trng ca mt in tch im l in trng u C.Cng in trng c trng v mt tc dng lc ca in trng D.Hiu in th c trng cho kh nng thc hin cng ca in trng Cu 4 : Th nng tnh in ca mt electron ti M trong in trng ca mt in tch im l 6,4.10-19J Mc tnh th nng xa v cc .in th ti M: A.4V B.-4V C.6,4V D.-6,4V Cu5 :C UMN = -15V .Hi ng thc no sau y l ng ? A.VM=-15v B.VN = -15V C.VM-VN = 15V D.VN-VM=15V - 15 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Hot ng gio vin Hot ng hc sinh Ni dung -GV pht phiu t chn 4 v -HS lm cc bi tp trc nghim Y/C HS lm bi tp trc nghim v gii thch la chn Hot ng 3 : Gii cc bi tp t lun Bi 1 : Bn 1 electron vi vn tc u 10-6m/s vo mt in trng u ca t in phng electron C cng chiu vi cc ng sc in a)tnh hiu in th gia hai bn t sao cho electron va vn khng n c bn m b)Tnh cng in trng trong t in ,bit rng khong cch gia 2 bn l 1cm Bi 2 mt electron c bn vo in trng u gia ghai bn kim loi phng .song song tch in tri du vi vn tc ban u 106m/s,theo phng song song ngc chiu cc wongsf sc in a)Tnh HT gia hai bn sao cho khi n bn i din elctrron c vn tc 107m/s b)Bit khong cch gia 2 bn d= 1cm .Tnh cng in trng gia 2 bn . Hot ng gio vin Hot ng hc sinh Ni dung -Y/C HS c nh hng gii -HS c v nh hng cch Bi 1 : gii a)p dng nh l bin thin a.S dng nh l bin thin ng nng ta c : ng nng (v=0). mv 2 mv 2 0 A= e.U = (v=0) b.S dung cng thc : E= U/d 2 2 -Gi mt HS ln bng tnh by -Mt HS i din ln bng mv 2 0 -Nhn xt -lng nghe ghi nhn => U = =2,84 V 2e b.Cng in trng ca t in : U E= =284 V/m d -HS c v nh hng cch Bi 2 : gii a.p dng nh l bin thin ng nng ta c : a.S dng nh l bin thin mv 2 mv 2 0 A= e.U = -Y/C HS c nh hng gii ng nng . 2 2 => U = -281,5V b.S dung cng thc : E= U/d b. Cng in trng ca t U -Gi mt HS ln bng tnh by -Mt HS i din ln bng in : E= =28.150V/m d -Nhn xt -lng nghe ghi nhn Hot ng 4 : Cng c , dn d Hot ng gio vin -Nhn xt gi hc -Ra bi tp v nh Hot ng hc sinh -Lng nghe , ghi nhn -Nhn nhim v hc tp :Mt m electron C dc theo mt on dy dn thng AB di 40Cm.HT gia 2 u dy l UAB=10V a.m electron C theo chiu no ? b.Tnh cng in trung trong dy dn ,cho rng in trng trong dy dn l in trng u ?

IV. RUT KINH NGHIEM TIET DAY Ngay soan : 29/08/2011 Ngay day : 05/09/2011 - 16 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Tiet 9. TU IENI. MUC TIEU 1. Kin thc - Trnh by c cu to ca t in, cch tch in cho t. - Nu r ngha, biu thc, n v ca in dung. - Vit c biu thc tnh nng lng in trng ca t in v gii thch c ngha cc i lng trong biu thc. 2. K nng - Nhn ra mt s loi t in trong thc t. - Gii bi tp t in. II. Chun b 1. Gio vin - Mt s loi t in thc t, c bit l t xoay trong my thu thanh. - Dng c: Thc k, phn mu. 2. Hc sinh: - Chun b Bi mi. - Su tm cc linh kin in t. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu nh ngha hiu in th v mi lin h gia hiu in th vi cng in trng. Hot ng 2 (15 pht) : Tm hiu t in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. T in 1. T in l g ? Gii thiu mch c cha t Ghi nhn khi nim. T in l mt h hai vt dn t gn in t gii thiu t in. nhau v ngn cch nhau bng mt lp cch in. Mi vt dn gi l mt bn ca t in. T in dng cha in tch. Gii thiu t in phng. Quan st, m t t in phng. T in phng gm hai bn kim loi phng t song song vi nhau v ngn Gii thiu k hiu t in trn cch nhau bng mt lp in mi. cc mch in. Ghi nhn k hiu. K hiu t in 2. Cch tch in cho t in Yu cu hc sinh nu cch Nu cch tch in cho t Ni hai bn ca t in vi hai cc tch in cho t in. in. ca ngun in. Yu cu hc sinh thc hin ln in tch trn mi bn ca t C1. Thc hin C2. in khi tch in gi l in tch ca t in. Hot ng 3 (20 pht) : Tm hiu in dung ca t in, cc loi t v nng lng in trng trong t in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. in dung ca t in 1. nh ngha Gii thiu in dung ca t Ghi nhn khi nim. in dung ca t in l i lng in. c trng cho kh nng tch in ca t in mt hiu in th nht nh. N c xc nh bng thng s ca in tch ca t in v hiu in th - 17 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng gia hai bn ca n.

Ghi nhn n v in dung v Gii thiu n v in dung v cc c ca n. cc c ca n. Ghi nhn cng thc tnh. Nm Gii thiu cng thc tnh in vng cc i lng trong . dung ca t in phng. Quan st, m t. Gii thiu cc loi t. Hiu c cc s liu ghi trn Gii thiu hiu in th gii v ca t in. hn ca t in. Quan st, m t. Gii thiu t xoay. Nm vng cng thc tnh Gii thiu nng lng in nng lng in trng ca t trng ca t in tch in. in c tch din.

Q U n v in dung l fara (F). in dung ca t in phng : S C= 9.10 9.4d 2. Cc loi t in Thng ly tn ca lp in mi t tn cho t in: t khng kh, t giy, t mi ca, t s, t gm, Trn v t thng ghi cp s liu l in dung v hiu in th gii hn ca t in. Ngi ta cn ch to t in c in dung thay i c gi l t xoay. 3. Nng lng ca in trng trong t in Nng lng in trng ca t in c tch in 1 1 Q2 1 W = QU = = CU2 2 2 C 2 C=

Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 5, 6, 7, 8 Ghi cc bi tp v nh. trang 33 sgk v 6.7, 6.8, 6.9 sbt. IV. RUT KINH NGHIEM TIET DAY

- 18 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 10. BAI TAPI. MUC TIEU 1. Kin thc : - Cng ca lc in - in th, hiu in th, lin h gia hiu in th v cng in trng. - T in, in dung ca t in, nng lng ca t in c tch in. 2. K nng : - Gii c cc bi ton tnh cng ca lc in. - Gii c cc bi ton tnh hiu in th, lin h gia E, U v A. - Gii c cc bi ton v mi lin h gia Q, C, U v W II. CHUAN B Gio vin - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii + c im ca cng ca lc in. + Biu thc tnh cng ca lc in. + Khi nim in th, hiu in th, lin h gia U v E. + Cc cng thc ca t in. Hot ng 2 (15 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 4 trang 25 : D Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 5 trang 25 : D Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 5 trang 29 : C Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 6 trang 29 : C Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 7 trang 29 : C Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 5 trang 33 : D Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 6 trang 33 : C Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 4.6 : D Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 5.2 : C Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 5.3 : D Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 6.3 : D Hot ng 3 (20 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 7 trang 25 Yu cu hc sinh vit biu Vit biu thc nh l ng Theo nh l v ng nng ta c : thc nh l ng nng. nng. E2 E1 = A Hng dn hc sinh tnh M v1 = 0 => E1 = 0 v A = qEd ng nng ca electron khi Lp lun, thay s tnh E2. E2 = qEd = - 1,6.10-19.103.(- 10-2) n n p vo bn dng. = 1,6.10-18(J) Bi trang Hng dn hc sinh tnh Cng ca lc in khi electron cng ca lc in khi Tnh cng ca lc in. chuyn ng t M n N : - 19 Gio n Vt L 11CB

Trng THPT Bnh Sn electron chuyn ng t M n N. Yu cu hc sinh tnh tch ca t in. Yu cu hc sinh tnh tch ti a ca t in.

GV : Nguyn Vn ng A = q.UMN = -1,6.10-19.50 = - 8. 10-18(J) Bi 7 trang33 a) in tch ca t in : in Vit cng thc, thay s v tnh q = CU = 2.10-5.120 = 24.10-4(C). ton. b) in tch ti a m t in tch c qmax = CUmax = 2.10-5.200 in Vit cng thc, thay s v tnh = 400.10-4(C). ton. Bi 8 trang 33 a) in tch ca t in : in Vit cng thc, thay s v tnh q = CU = 2.10-5.60 = 12.10-4(C). ton. b) Cng ca lc in khi U = 60V hiu A = q.U = 12.10-7.60 = 72.10-6(J) Tnh cng ca lc in khi . q 2 Yu cu hc sinh tnh cng. Tnh U khi q = c) Cng ca lc in khi U = U = 2

Yu cu hc sinh tnh tch ca t in. Lp lun xem nh in th khng i. Yu cu hc sinh tnh cng.

Yu cu hc sinh tnh hiu in th U. Yu cu hc sinh tnh cng.

30V A = q.U = 12.10-7.30 = 36.10-6(J)


- 20 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

CHNG II. DONG IEN KHONG OITiet 11. DONG IEN KHONG OI. NGUON IENI. MUC TIEU 1. Kin thc - Pht biu c nh ngha cng dng in v vit c cng thc th hin nh ngha ny. - Nu c iu kin c dng in. - Pht biu c sut in ng ca ngun in v vit c cng thc th hin nh ngha ny. - M t c cu to chung ca cc pin in ho v cu to ca pin Vn-ta. - M t c cu to ca acquy ch. 2. K nng - Gii thch c v sao ngun in c th duy tr hiu in th gia hai cc ca n. A q q - Gii c cc bi ton c lin quan n cc h thc : I = ; I = v E = . q t t - Gii thch c s to ra v duy tr hiu in th gia hai cc ca pin Vn-ta. - Gii thch c v sao acquy l mt pin in ho nhng li c th s dng c nhiu ln. II. CHUAN B 1. Gio vin - Xem li nhng kin thc lin quan n bi dy. - Chun b dng c th nghim hnh 7.5. - Mt pin L-clan-s bc sn cho hc sinh quan st cu to bn trong. - Mt acquy. - V phng to cc hnh t 7.6 n 7.10. - Cc vn k cho cc nhm hc sinh. 2. Hc sinh: Mi nhm hc sinh chun b - Mt na qu chanh hay qut c bp nhn. - Hai mnh kim loi khc loi. III. TIEN TRNH DAY HOC Hot ng 1 (15 pht) : Tm hiu v dng in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. Dng in t cc cu hi v tng vn Nu nh ngha dng in. + Dng in l dng chuyn ng c cho hc sinh thc hin. hng ca cc in tch. Nu bn cht ca dng din + Dng in trong kim loi l dng trong kim loi. chuyn ng c hng ca cc electron t do. Nu qui c chiu dng + Qui c chiu dng in l chiu in. chuyn ng ca cc din tch dng (ngc vi chiu chuyn ng ca cc in tch m). + Cc tc dng ca dng in : Tc Nu cc tc dng ca dng dng t, tc dng nhit, tc dng hoc in. hc, tc dng c hc, sinh l, - 21 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

+ Cng dng in cho bit mc mnh yu ca dng in. o cng Cho bit tr s ca i dng in bng ampe k. n v lng no cho bit mc cng dng in l ampe (A). mnh yu ca dng in ? Dng c no o n ? n v ca i lng . Hot ng 2 (15 pht) : Tm hiu cng dng in, dng in khng i. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Cng dng in. Dng in khng i 1. Cng dng in Yu cu hc sinh nhc li Nu nh ngha cng Cng dng in l i lng c nh ngha cng dng dng in hc lp 9. trng cho tc dng mnh, yu ca in. dng in. N c xc nh bng thng s ca in lng q dch chuyn qua tit din thng ca vt dn trong khong thi gian t v khong thi gian . q I= t Thc hin C1. 2. Dng in khng i Yu cu hc sinh thc hin Dng in khng i l dng in c C1. chiu v cng khng i theo thi Thc hin C2. gian. Cng dng in ca dng in Yu cu hc sinh thc hin q C2. khng i: I = . t 3. n v ca cng dng in v Ghi nhn n v ca cng ca in lng dng in v ca in lng. n v ca cng dng in trong h SI l ampe (A). Gii thiu n v ca cng Thc hin C3. 1C dng in v ca in 1A = 1s lng. Thc hin C4. n v ca in lng l culng (C). 1C = 1A.1s Yu cu hc sinh thc hin C3. Yu cu hc sinh thc hin C4. Hot ng 3 (15 pht) : Tm hiu v ngun in. Hot ng ca gio vin Hot ng ca hc sinh Yu cu hc sinh thc hin C5. Yu cu hc sinh thc hin C6. Thc hin C5. Thc hin C6. Thc hin C7. - 22 -

Ni dung c bn III. Ngun in 1. iu kin c dng in iu kin c dng in l phi c mt hiu in th t vo hai u vt dn in. 2. Ngun in + Ngun in duy tr hiu in th Gio n Vt L 11CB

Trng THPT Bnh Sn Yu cu hc sinh thc hin C7. Yu cu hc sinh thc hin C8. Yu cu hc sinh thc hin C9. Thc hin C8. Thc hin C9.

GV : Nguyn Vn ng gia hai cc ca n. + Lc l bn trong ngun in: L nhng lc m bn cht khng phi l lc in. Tc dng ca lc l l tch v chuyn electron hoc ion dng ra khi mi cc, to thnh cc m (tha nhiu electron) v cc dng (thiu hoc tha t electron) do duy tr c hiu in th gia hai cc ca n.


- 23 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 12. DONG IEN KHONG OI. NGUON IENI. MUC TIEU 1. Kin thc - Pht biu c nh ngha cng dng in v vit c cng thc th hin nh ngha ny. - Nu c iu kin c dng in. - Pht biu c sut in ng ca ngun in v vit c cng thc th hin nh ngha ny. - M t c cu to chung ca cc pin in ho v cu to ca pin Vn-ta. - M t c cu to ca acquy ch. 2. K nng - Gii thch c v sao ngun in c th duy tr hiu in th gia hai cc ca n. A q q - Gii c cc bi ton c lin quan n cc h thc : I = ; I = v E = . q t t - Gii thch c s to ra v duy tr hiu in th gia hai cc ca pin Vn-ta. - Gii thch c v sao acquy l mt pin in ho nhng li c th s dng c nhiu ln. II. CHUAN B 1. Gio vin - Xem li nhng kin thc lin quan n bi dy. - Chun b dng c th nghim hnh 7.5. - Mt pin L-clan-s bc sn cho hc sinh quan st cu to bn trong. - Mt acquy. - V phng to cc hnh t 7.6 n 7.10. - Cc vn k cho cc nhm hc sinh. 2. Hc sinh: Mi nhm hc sinh chun b - Mt na qu chanh hay qut c bp nhn. - Hai mnh kim loi khc loi. III. TIEN TRNH DAY HOC Hot ng 4 (15 pht) : Tm hiu sut in ng ca ngun in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn IV. Sut in ng ca ngun in 1. Cng ca ngun in Gii thiu cng ca ngun Ghi nhn cng ca Cng ca cc lc l thc hin lm in. ngun in. dch chuyn cc in tch qua ngun c gi l cng ca ngun in. 2. Sut in ng ca ngun in a) nh ngha Sut in ng E ca ngun in l Gii thiu khi nim sut in Ghi nhn khi nim. i lng c trng cho kh nng thc ng ca ngun in. hin cng ca ngun in v c o bng thng s gia cng A ca lc l thc hin khi dch chuyn mt in tch dng q ngc chiu in trng v ln ca in tch . b) Cng thc A E = Gii thiu cng thc tnh sut Ghi nhn cng thc. q in ng ca ngun in. c) n v - 24 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

n v ca sut in ng trong h Gii thiu n v ca sut in Ghi nhn n v ca sut SI l vn (V). ng ca ngun in. in ng ca ngun in. S vn ghi trn mi ngun in cho bit tr s ca sut in ng ca ngun in . Sut in ng ca ngun in c gi Yu cu hc sinh nu cch o Nu cch o sut in tr bng hiu in th gia hai cc ca sut in ng ca ngun in. ng ca ngun in. n khi mch ngoi h. Mi ngun in c mt in tr gi Gii thiu in tr trong ca Ghi nhn in tr trong l in tr trong ca ngun in. ngun in. ca ngun in. Hot ng 5 (25 pht) : Tm hiu cc ngun in ho hc: Pin v acquy. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn V. Pin v acquy 1. Pin in ho Hng dn hc sinh thc hin Thc hin C10. Cu to chung ca cc pin in ho C10. l gm hai cc c bn cht khc nhau c ngm vo trong cht in phn. a) Pin Vn-ta V hnh 7.6 gii thiu pin VnV hnh, ghi nhn cu Pin Vn-ta l ngun in ho hc ta. to v hot ng ca pin gm mt cc bng km (Zn) v mt Vn-ta. cc bng ng (Cu) c ngm trong dung dch axit sunfuric (H2SO4) long. Do tc dng ho hc thanh km tha electron nn tch in m cn thanh ng thiu electron nn tch in dng. Sut in ng khong 1,1V. b) Pin Lclngs + Cc dng : L mt thanh than bao V hnh 7.8 gii thiu pin V hnh, ghi nhn cu bc xung quanh bng mt hn hp Lclngs. to v hot ng ca pin mangan ixit MnO2 v graphit. Lclngse + Cc m : Bng km. + Dung dch in phn : NH4Cl. + Sut in ng : Khong 1,5V. + Pin Lclngs kh : Dung dch NH4Cl c trn trong mt th h c ri ng trong mt v pin bng km, v pin ny l cc m. 2. Acquy a) Acquy ch Bn cc dng bng ch ixit V hnh 7.9 gii thiu acquy V hnh, ghi nhn cu (PbO2) cc m bng ch (Pb). Cht ch. to v hot ng ca in phn l dnng dch axit sunfuric acquy ch. (H2SO4) long. Sut in ng khong 2V. Acquy l ngun in c th np li s dng nhiu ln da trn phn ng ho hc thun nghch: n tch tr nng lng di dng ho nng khi - 25 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

np v gii phng nng lng y di dng in nng khi pht in. Khi sut in ng ca acquy gim xung ti 1,85V th phi np in li. b) Acquy kim Acquy caimi-kn, cc dng c Ghi nhn cu to v sut lm bng Ni(OH)2, cn cc m lm in ng ca acquy bng Cd(OH)2 ; cc cc dc kim. nhng trong dung dch kim KOH hoc NaOH. Gii thiu cu to v sut in Sut in ng khong 1,25V. ng ca acquy kim. Acquy kim c hiu sut nh hn acquy axit nhng li rt tin li v nh Ghi nhn nhng tin li hn v bn hn. ca acquy kim. Nu cc tin li ca acquy kim. Hot ng 6 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 6 n 12 Ghi cc bi tp v nh. trang 45 sgk. IV. RUT KINH NGHIEM TIET DAY

- 26 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 13. BAI TAPI. MUC TIEU 1. Kin thc : Cc khi nim v dng in, dng in khng i, cng dng in, ngun in, sut in ng v in tr trong ca ngun in. Cu to, hot ng ca cc ngun in ho hc. 2. K nng : Thc hin c cc cu hi v gii c cc bi ton lin quan n dng in, cng dng in, sut in ng ca ngun in. II. CHUN B Gio vin : + Xem, gii cc bi tp sgk v sch bi tp. + Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh : + Gii cc cu hi trc nghim v bi tp thy c ra v nh. + Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii. + Dng in, cng dng in, dng in khng i. + Lc l bn trong ngun in. + Sut in ng v in tr trong ca ngun in. + Cu to chung ca pin in ho. + Cu to v hot ng ca pin V-ta, ca acquy ch. Hot ng 2 (20 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin Hot ng ca hc Ni dung c bn sinh Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 6 trang 45 : D Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 7 trang 45 : B Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 8 trang 45 : B Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 9 trang 45 : D Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 10 trang 45 : C Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 7.3 : B Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 7.4 : C Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 7.5 : D Yu cu hs gii thch ti sao chn D. Gii thch la chn. Cu 7.8 : D Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 7.9 : C Hot ng 3 (15 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 13 trang 45 Yu cu hc sinh vit cng Vit cng thc v thay s Cng dng in chy qua thc v thay s tnh tnh cng dng in. dy dn: cng dng in. q 6.10 3 I= = 2.10-3 (A) = 2 = 1 3 (mA) Yu cu hc sinh vit cng Vit cng thc, suy ra v thay Bi 14 trang 45 thc, suy ra v thay s s tnh in lng. in lng chuyn qua tit din tnh in lng. thng ca dy dn ni vi ng c t lnh: q Yu cu hc sinh vit cng Vit cng thc, suy ra v thay Ta c: I = t thc, suy ra v thay s s tnh cng ca lc l. => q = I. t = 6.0,5 = 3 (C) tnh cng ca lc l. Bi 15 trang 45 - 27 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng Cng ca lc l: A Ta c: E = q => A = E .q = 1,5.2 = 3 (J)


- 28 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 14. IEN NANG. CONG SUAT IENI. MUC TIEU 1. Kin thc - Nu c cng ca dng in l s o in nng m on mch tiu th khi c dng in chy qua. Ch ra c lc no thc hin cng y. - Ch ra c mi lin h gia cng ca lc l thc hin bn trong ngun in v in nng tiu th trong mch kn 2. K nng - Tnh c in nng tiu th v cng sut in ca mt on mch theo cc i lng lin quan v ngc li. - Tnh c cng v cng sut ca ngun in theo cc i lng lin quan v ngc li. II. CHUAN B 1. Gio vin: c sch gio khoa Vt l lp 9 bit hc sinh hc nhng g v cng, cng sut ca dng in, nh lut Jun Len-x v chun b cc cu hi hng dn hc sinh n tp. 2. Hc sinh: n tp phn ny lp 9 THCS v thc hin cc cu hi hng dn m gio vin t ra. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu cu to chung ca pin in ho. So snh pin in ho v acquy. Hot ng 2 (10 pht) : Tm hiu in nng tiu th v cng sut in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. in nng tiu th v cng sut in Gii thiu cng ca lc in. Ghi nhn khi nim. 1. in nng tiu th ca on Yu cu hc sinh thc hin Thc hin C1. mch C1. Thc hin C2. A = Uq = UIt Yu cu hc sinh thc hin Thc hin C3. in nng tiu th ca mt on C2. mch bng tch ca hiu in th gia Yu cu hc sinh thc hin hai u on mch vi cng dng C3. in v thi gian dng in chy qua Ghi nhn khi nim. on mch . Thc hin C4. 2. Cng sut in Cng sut in ca mt on mch Gii thiu cng sut in. bng tch ca hiu in th gia hai Yu cu hc sinh thc hin u on mch v cng dng in C4. chy qua on mch . A P = = UI t Hot ng 3 (15 pht) : Tm hiu cng sut to nhit ca vt dn khi c dng in chy qua. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Cng sut to nhit ca vt dn khi c dng in chy qua 1. nh lut Jun Len-x Gii thiu nh lut. Ghi nhn nh lut. Nhit lng to ra mt vt dn t l thun vi in tr ca vt dn, vi bnh phng cng dng in v vi thi gian dng in chy qua vt dn - 29 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng Q = RI2t 2. Cng sut to nhit ca vt dn khi c dng in chy qua Cng sut to nhit vt dn khi c dng in chy qua c xc nh bng nhit lng to ra vt dn trong mt n v thi gian. Q P = = UI2 t Ni dung c bn III. Cng v cng sut ca ngun in 1. Cng ca ngun in Cng ca ngun in bng in nng tiu th trong ton mch. Ang = qE = E Tt 2. Cng sut ca ngun in Cng sut ca ngun in bng cng sut tiu th in nng ca ton mch. A P ng = ng = E T t

Gii thiu cng sut to nhit ca vt dn. Yu cu hc sinh thc hin C5.

Ghi nhn khi nim. Thc hin C5.

Hot ng 4 (10 pht) : Tm hiu cng v cng sut ca ngun in. Hot ng ca gio vin Hot ng ca hc sinh Gii thiu cng ca ngun in. Ghi nhn khi nim.

Ghi nhn khi nim. Gii thiu cng sut ca ngun in.

Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 5 n 10 Ghi cc bi tp v nh. trang 49 sgk v 8.3, 8.5, 8.7 sbt. IV. RUT KINH NGHIEM TIET DAY

- 30 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 15. IEN NANG. CONG SUAT IENI. MUC TIEU 1. Kin thc - Nu c cng ca dng in l s o in nng m on mch tiu th khi c dng in chy qua. Ch ra c lc no thc hin cng y. - Ch ra c mi lin h gia cng ca lc l thc hin bn trong ngun in v in nng tiu th trong mch kn 2. K nng - Tnh c in nng tiu th v cng sut in ca mt on mch theo cc i lng lin quan v ngc li. - Tnh c cng v cng sut ca ngun in theo cc i lng lin quan v ngc li. II. CHUAN B 1. Gio vin: c sch gio khoa Vt l lp 9 bit hc sinh hc nhng g v cng, cng sut ca dng in, nh lut Jun Len-x v chun b cc cu hi hng dn hc sinh n tp. 2. Hc sinh: n tp phn ny lp 9 THCS v thc hin cc cu hi hng dn m gio vin t ra. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Nu cu to chung ca pin in ho. So snh pin in ho v acquy. Hot ng 2 (10 pht) : Tm hiu in nng tiu th v cng sut in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. in nng tiu th v cng sut in Gii thiu cng ca lc in. Ghi nhn khi nim. 1. in nng tiu th ca on Yu cu hc sinh thc hin Thc hin C1. mch C1. Thc hin C2. A = Uq = UIt Yu cu hc sinh thc hin Thc hin C3. in nng tiu th ca mt on C2. mch bng tch ca hiu in th gia Yu cu hc sinh thc hin hai u on mch vi cng dng C3. in v thi gian dng in chy qua Ghi nhn khi nim. on mch . Thc hin C4. 2. Cng sut in Cng sut in ca mt on mch Gii thiu cng sut in. bng tch ca hiu in th gia hai Yu cu hc sinh thc hin u on mch v cng dng in C4. chy qua on mch . A P = = UI t Hot ng 3 (15 pht) : Tm hiu cng sut to nhit ca vt dn khi c dng in chy qua. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Cng sut to nhit ca vt dn khi c dng in chy qua 1. nh lut Jun Len-x Gii thiu nh lut. Ghi nhn nh lut. Nhit lng to ra mt vt dn t l thun vi in tr ca vt n, vi bnh phng cng dng in v vi thi gian dng in chy qua vt dn - 31 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng Q = RI2t 2. Cng sut to nhit ca vt dn khi c dng in chy qua Cng sut to nhit vt dn khi c dng in chy qua c xc nh bng nhit lng to ra vt dn trong mt n v thi gian. Q P = = UI2 t Ni dung c bn III. Cng v cng sut ca ngun in 1. Cng ca ngun in Cng ca ngun in bng in nng tiu th trong ton mch. Ang = qE = E Tt 2. Cng sut ca ngun in Cng sut ca ngun in bng cng sut tiu th in nng ca ton mch. A P ng = ng = E T t

Gii thiu cng sut to nhit ca vt dn. Yu cu hc sinh thc hin C5.

Ghi nhn khi nim. Thc hin C5.

Hot ng 4 (10 pht) : Tm hiu cng v cng sut ca ngun in. Hot ng ca gio vin Hot ng ca hc sinh Gii thiu cng ca ngun in. Ghi nhn khi nim.

Ghi nhn khi nim. Gii thiu cng sut ca ngun in.

Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 5 n 10 Ghi cc bi tp v nh. trang 49 sgk v 8.3, 8.5, 8.7 sbt. IV. RUT KINH NGHIEM TIET DAY

- 32 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 16. BAI TAPI. MUC TIEU 1. Kin thc : + in nng tiu th v cng sut in. + Nhit nng v cng sut to nhit ca vt dn khi c dng in chy qua. + Cng v cng sut ca ngun in. 2. K nng : + Thc hin c cc cu hi lin quan n in nng v cng sut in. + Gii c cac bai tap lien quan en ien nang va cong suat ien, II. CHUAN B Gio vin - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii. + Biu thc tnh in nng tiu th trn mt on mch : A = Uit + Biu thc tnh cng sut in trn mt on mch : P = UI + Biu thc tnh nhit to ra v cng sut to nhit trn vt dn khi c dng din chy qua : U2 Q = RI2t ; P = RI2 = R + Cng v cng sut ca ngun in : Ang = E It ; Png = E I Hot ng 2 (10 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 5 trang 49 : B Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 6 trang 49 : B Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 8.1 : C Yu cu hs gii thch ti sao chn C. Gii thch la chn. Cu 8.2 : B Hot ng 3 (25 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 8 trang 49 Gii thiu hiu in th Ghi nhn khi nim. a) 220V l hiu in th nh mc ca nh mc v cng sut nh m in. 1000W l cng sut nh mc mc. ca m in. Tnh nhit lng c ch. b) Nhit lng c ch un si 2 lt Yu cu hc sinh tnh nhit nc lng cn thit un si 2 Q = Cm(t2 t1) = 4190.2.(100 25) lt nc. Tnh nhit lng ton phn. = 628500 (J). Yu cu hc sinh tnh nhit Nhit lng ton phn cn cung cp lng ton phn (k c nhit Q' Q' 628500 = Ta c : H = => Q = lng hao ph). Q H 0,9 Tnh thi gian un si nc. = 698333 (J) Yu cu hc sinh tnh thi Thi gian un si nc gian un si nc.

- 33 -

Gio n Vt L 11CB

Trng THPT Bnh Sn Tnh cng ca ngun. Ta c : P =

GV : Nguyn Vn ng Q Q 698333 => t = = t P 1000 = 698 (s) Tnh cng sut ca ngun. Bi 9 trang 49 Cng ca ngun in sn ra trong 15 pht A = E It = 12. 0,8.900 = 8640 (J) Tnh in nng tiu th ca n Cng sut ca ngun in khi ng. P = E I = 12.0,8 = 9,6 (W) Bi 8.6 Tnh in nng tiu th ca in nng m n ng tiu th trong bng n dy tc. thi gian cho l : A1 = P 1.t = 40.5.3600.30 = 21600000 (J) Tnh s tin in tit kim = 6 (kW.h). c in nng m bng n dy tc tiu th trong thi gian ny l : A2 = P2.t = 100.5.3600.30 = 54000000 (J) = 15 (kW.h). S tin in gim bt l : M = (A2 - A1).700 = (15 - 6).700 = 6300

Y/c h/s tnh cng ca ngun in sn ra trong 15 pht. Yu cu hc sinh tnh cng sut ca ngun. Yu cu hc sinh tnh in nng tiu th ca n ng trong thi gian cho. Yu cu hc sinh tnh in nng tiu th ca n dy tc trong thi gian cho. Yu cu hc sinh tnh s tin in tit kim c


- 34 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 17. NH LUAT OM OI VI TOAN MACHI. MUC TIEU 1. Kin thc - Pht biu c quan h sut in ng ca ngun v tng gim th trong v ngoi ngun - Pht biu c ni dung nh lut m cho ton mch. - T suy ra c nh lut m cho ton mch t nh lut bo ton nng lng. - Trnh by c khi nim hiu sut ca ngun in. 2. K nng - Mc mch in theo s . - Gii cc dng Bi tp c lin quan n nh lut m cho ton mch. II. CHUAN B 1. Gio vin - Dng cu: Thc k, phn mu. - B th nghim nh lut m cho ton mch. - Chun b phiu cu hi. 2. Hc sinh: c trc bi hc mi. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Cng v cng sut to nhit ca vt dn khi c dng in chy qua ? Cng v cng sut ca ngun in ? Hot ng 2 (15 pht) : Thc hin th nghim ly s liu xy dng nh lut. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. Th nghim Mc mch in. Quan st mch in. Thc hin th nghim. c cc s liu.

Ghi bng s liu.

Lp bng s liu.

I(A) 0 0,1 0,2 0,3 0,4 0,5 U(V) 3,2 3,0 2,8 2,6 2,4 2,2 Ni dung c bn II. nh lut m i vi ton mch X l s liu rt ra kt qu. Ghi nhn kt qu. Th nghim cho thy : Yu cu thc hin C1. Thc hin C1. UN = U0 aI = E - aI (9.1) Vi UN = UAB = IRN (9.2) gi l gim th mch ngoi. Nu kt qu th nghim. Ghi nhn kt qu. Th nghim cho thy a = r l in tr trong ca ngun in. Do : Yu cu thc hin C2. Thc hin C2. E = I(RN + r) = IRN + Ir (9.3) Yu cu hc sinh rt ra kt Rt ra kt lun. Vy: Sut in ng c gi tr bng lun. tng cc gim in th mch ngoi v mch trong. Bin i tm ra biu thc T h thc (9.3) suy ra : T h thc (9.3) cho hc sinh (9.5). UN = IRN = E It (9.4) - 35 Gio n Vt L 11CB Hot ng 3 (10 pht) : Tm hiu nh lut m i vi ton mch. Hot ng ca gio vin Hot ng ca hc sinh

Trng THPT Bnh Sn rt ra biu thc nh lut. Pht biu nh lut. v I=

GV : Nguyn Vn ng E (9.5) RN + r Cng dng in chy trong mch in kn t l thun vi sut in ng ca ngun in v t l nghch vi in tr ton phn ca mch .

Yu cu hc sinh pht biu nh lut . Thc hin C3. Yu cu hc sinh thc hin C3. Hot ng 4 (10 pht) : Tm hiu hin tng on mch, mi lin h gia nh lut m vi ton mch v nh lut bo ton v chuyn ho nng lng, hiu sut ca ngun in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn III. Nhn xt 1. Hin tng on mch Gii thiu hin tng on Ghi nhn hin tng on Cng dng in trong mch kn mch. mch. t gi tr ln nht khi RN = 0. Khi ta ni rng ngun in b on mch Yu cu hc sinh thc hin v C4. Thc hin C4. E I= (9.6) r 2. nh lut m i vi ton mch v nh lut bo ton v chuyn ho Lp lun cho thy c s Ghi nhn s ph hp giac nng lng ph hp giac nh lut m i nh lut m i vi ton mch Cng ca ngun in sn ra trong vi ton mch v nh lut bo v nh lut bo ton v chuyn thi gian t : ton v chuyn ho nng lng. ho nng lng. A = E It (9.7) Nhit lng to ra trn ton mch : Q = (RN + r)I2t (9.8) Theo nh lut bo ton nng lng th A = Q, do t (9.7) v (9.8) ta suy ra E I= RN + r Nh vy nh lut m i vi ton mch hon ton ph hp vi nh lut Gii thiu hiu sut ngun Ghi nhn hiu sut ngun bo ton v chuyn ho nng lng. in. in. 3. Hiu sut ngun in Yu cu hc sinh thc hin Thc hin C5. U C5. H= N E Hot ng 6 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp t 4 n 7 Ghi cc bi tp v nh. trang 54 sgk v 9.3, 9.4 sbt. IV. RUT KINH NGHIEM TIET DAY

- 36 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 18. BAI TAPI. MUC TIEU 1. Kin thc : + Nm c nh lut m i vi ton mch. + Nm c hin tng on mch. + Nm c hiu sut ca ngun in. 2. K nng : Thc hin c cc cu hi v gii c cc bi tp lin quan n nh lut m i vi ton mch. II. CHUAN B Gio vin - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii. E + nh lut m i vi ton mch : I = RN + r + gim th mch ngoi : UN = IRN = E - Ir. E + Hin tng on mch : I = r U + Hiu sut ca ngun in : H = N E Hot ng 2 (10 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Yu cu hs gii thch ti sao chn A. Gii thch la chn. Cu 4 trang 54 : A Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 9.1 : B Yu cu hs gii thch ti sao chn B. Gii thch la chn. Cu 9.2 : B Hot ng 3 (20 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 5 trang 54 a) Cng dng in chy trong Yu cu hc sinh tm biu Tnh cng dng in chy mch: thc tnh cng dng trong mch. Ta c UN = I.RN in chy trong mch. U N 8,4 = => I = = 0,6(A) Yu cu hc sinh tnh sut Tnh sut in ng ca ngun R N 14 in ng ca ngun in. in. Sut in ng ca ngun in: Ta c E = UN + I.r = 8,4 + 0,6.1 = Yu cu hc sinh tnh cng Tnh cng sut mch ngoi. 9(V) sut mch ngoi v cng b) Cng sut mch ngoi: sut ca ngun. Tnh cng sut ca ngun. P N = I2.RN = 0,62.14 = 5,04(W) Cng sut ca ngun: Yu cu hc sinh tnh Tnh cng dng in nh P = E .I = 9.0,6 = 5,4(W) cng dng in nh mc ca bng n. Bi 6 trang 54 mc ca bng dn. - 37 Gio n Vt L 11CB

Trng THPT Bnh Sn Yu cu hc sinh tnh in tr ca bng n. Tnh in tr ca bng n.

GV : Nguyn Vn ng

a) Cng dng in nh mc ca Pdm 5 = = 0,417(A) bng n: Idm = U dm 12 in tr ca bng n U2 12 2 Rd = dm = = 28,8() Pdm 5 Yu cu hc sinh tnh Tnh cng dng in thc Cng dng in qua n cng dng in chy t chy qua n. E 12 = I= = 0,416(A) qua n. So snh v kt lun. RN + r 28,8 + 0,06 Yu cu hc sinh so snh I Idm nn n sng gn nh bnh v rt ra kt lun. Tnh cng sut tiu th thc t. thng Yu cu hc sinh tnh cng Cng sut tiu th thc t ca n sut tiu th thc t ca PN = I2.Rd = 0,4162.28,8 = 4,98(W) bng n. Tnh hiu sut ca ngun. b) Hiu sut ca ngun in: Yu cu hc sinh tnh hiu U I .Rd 0,416.28,8 sut ca ngun in. = H= N = = 0,998 E E 12 Tnh in tr mch ngoi. Bi 7 trang 54 Yu cu hc sinh tnh in a) in tr mch ngoi tr mch ngoi v cng R1 .R2 6.6 dng in chy trong mch Tnh cng dng in chy = RN = = 3() chnh. trong mch chnh. R1 + R2 6 + 6 Cng dng in chy trong mch Tnh hiu in th gia hai u E 3 = Cho hc sinh tnh hiu in mi bng n. chnh: I = = 0,6(A) RN + r 3 + 2 th gia hai u mi bng. Hiu in th gia 2 u mi bng Tnh cng sut tiu th ca mi n: Cho hc sinh tnh cng sut bng n. UN = U1 = U2 = I.RN = 0,6.3 = 1,8(V) tiu th ca mi bng n. Cng sut tiu th ca mi bng n U 12 1,8 2 Lp lun rre rt ra kt lun. = P1 = P2 = = 0,54(W) Cho hc sinh lp lun R1 6 rt ra kt lun.. b) Khi tho bt mt bng n, in tr mch ngoi tng, hiu in th mch ngoi trc l hiu in th gia hai u bng n cn li tng nn bng n cn lt sng hn trc. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 19 GHEP CAC NGUON IEN THANH BOI. MUC TIEU + nu c chiu dng in chy qua on mch cha ngun in. + Nhn bit c cc loi b ngun ni tip, song song, hn hp i xng. + Vn dng c nh lut m i vi on mch c cha ngun in, + Tnh c sut in ng v in tr trong ca cc loi b ngun ghp. II. CHUAN B Gio vin + Bn pin c sut in ng 1,5V. + Mt vn k c gii hn o 10V v c chia nh nht 0,2V. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Pht biu, vit biu thc nh lut m cho ton mch, vit biu thc tnh hiu in th mch ngoi, cng sut tiu th trn mch ngoi v trn ton mch, Hot ng 2 (15 pht) : Tm hiu on mch c cha ngun in. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. on mch c cha ngun in V mch 10.1. V hnh. on mch c cha ngun in, dng Yu cu hc sinh thc hin Thc hin C1. in c chiu i ti cc m v i ra t C1. V hnh. cc dng. V hnh 10.2. Ghi nhn ngun v biu thc UAB = E I(r + R) Gii thiu cch nhn bit nh lut m cho on mch. E U AB E U AB = Hay I = ngun v biu thc nh lut Thc hin C2. r+R R AB m. Yu cu hc sinh thc hin C2. Hot ng 3 ( pht) : Tm hiu cc b ngun ghp. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Ghp cc ngun thnh b V hnh 10.3. V hnh. 1. B ngun ghp ni tip Gii thiu b ngun ghp Nhn bit c b ngun ni tip. ghp ni tip. Gii thiu cch tnh sut Tnh c sut in ng v Eb = E1 + E2 + + En in ng v in tr trong in tr trong ca b ngun. ca b ngun ghp ni tip. Tnh c sut in ng v Rb = r1 + r2 + + rn Gii thiu trng hp ring. in tr trong ca b ngun Trng hp ring, nu c n ngun c sut gm cc ngun ging nhau in ng e v in tr trong r ghp ni tip th : Eb = ne ; rb = nr ghp ni tip. 2. B ngun song song V hnh 10.4. V hnh. Gii thiu b ngun ghp Nhn bit c b ngun song song. gp song song. Gii thiu cch tnh sut Tnh c sut in ng in ng v in tr trong v in tr trong ca b ca b ngun ghp song ngun. song. Nu c m ngun ging nhau mi ci c - 39 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng sut in ng e v in tr trong r ghp r song song th : Eb = e ; rb = m 3. B ngun hn hp i xng

V hnh 10.5. V hnh. Gii thiu b ngun ghp Nhn bit c b ngun hn hp i xng. ghp hn hp i xng. Gii thiu cch tnh sut Tnh c sut in ng in ng v in tr trong v in tr trong ca b ca b ngun ghp hn hp ngun. i xng.

Nu c m dy, mi dy c n ngun mi ngun c sut in ng e, in tr trong r nr ghp ni tip th : Eb = ne ; rb = m

Hot ng 6 ( pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin Hot ng ca hc sinh Cho hc sinh tm tt nhng kin thc c bn Tm tt nhng kin thc c bn. hc trong bi. Yu cu hc sinh v nh lm cc bi tp 4, 5, 6 Ghi cc bi tp v nh. trang 58 sgk v 10.5, 10.6, 10.7 sbt. IV. RUT KINH NGHIEM TIET DAY

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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 20. PHNG PHAP GIAI MOT SO BAI TOAN VE TOAN MACHI. MUC TIEU + Vn dng nh lut m gii cc bi ton v ton mch. + Vn dng cc cng thc tnh in nng tiu th, cng sut tiu th in nng v cng sut to nhit ca mt on mch ; cng, cng sut v hiu sut ca ngun in. + Vn dng c cc cng thc tnh sut in ng v in tr trong ca b ngun ni tip, song song v hn hp i xng gii cc bi ton v tom mch. II. CHUAN B 1. Gio vin + Nhc nh hc sinh n tp cc ni dung kin thc nu trong cc mc tiu trn y ca tit hc ny. + Chun b mt s bi tp ngoi cc bi tp nu trong sgk ra thm cho hc sinh kh. 2. Hc sinh: n tp cc ni dung kin thc m thy c yu cu. III. TIEN TRNH DAY HOC Hot ng 1 (5 pht) : Kim tra bi c : Pht biu v vit biu thc nh lut m cho ton mch. Hot ng 2 (15 pht) : Tm hiu phng php gii mt s bi ton v ton mch. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn I. Nhng lu trong phng php Yu cu hc sinh nu cng Nu cng thc tnh sut in gii thc tnh sut in ng v in ng v in tr trong ca cc + Cn phi nhn dng loi b ngun tr trong ca cc loi b ngun. loi b ngun hc. v p dng cng thc tng ng tnh sut in ng v in tr trong Yu cu hc sinh thc hin Thc hin C1. ca b ngun C1. Thc hin C2. + Cn phi nhn dng cc in tr Yu cu hc sinh thc hin mch ngoi c mc nh th no C2. tnh in tr tng ng ca mch Nu cc cng thc tnh cng ngoi. dng in trong mch chnh, + p dng nh lut m cho ton mch Yu cu hc sinh nu cc cng hiu in th mch ngoi, cng tm cc n s theo yu cu ca ra thc tnh cng dng in v cng sut ca ngun. + Cc cng thc cn s dng : trong mch chnh, hiu in th E I= ; E = I(RN + r) ; mch ngoi, cng v cng sut RN + r ca ngun. U = IRN = E Ir ; Ang = EIt ; Png = EI ; A = UIt ; P = UI Hot ng 3 (20 pht) : Gii cc bi tp v d. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn II. Bi tp v d Bi tp 1 V li on mch. a) in tr mch ngoi Yu cu hc sinh thc hin Thc hin C3. RN = R1 + R2 + R3 = 5 + 10 + 3 = 18 C3. b) Cng dng in chy qua Tnh cng dng in chy ngun in (chy trong mch chnh) Yu cu hc sinh tnh cng trong mch chnh. E 6 = I= = 0,3(A) dng in chy trong mch RN + r 18 + 2 chnh. Tnh hiu in th mch Hiu in th mch ngoi ngoi. - 41 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Yu cu hc sinh tnh hiu U = IRN = 0,3.18 = 5,4(V) in th mch ngoi. Tnh hiu in th gia hai c) Hiu in th gia hai u R1 Yu cu hc sinh tnh hiu u R1. U1 = IR1 = 0,3.5 = 1,5(V) in th gia hai u R1. Bi tp 2 in tr v cng dng in Thc hin C4. nh mc ca cc bng n 2 Yu cu hc sinh tr l C4. Tnh in tr v cng U dm1 12 2 Yu cu hc sinh tnh in tr dng in nh mc ca cc RD1 = P = 6 = 24() dm1 v cng dng in nh bng n. 2 U dm 2 6 2 mc ca cc bng n. = RD2 = = 8() Pdm 2 4,5 Pdm1 6 = = 0,5(A) Idm1 = U dm1 12 Pdm 2 4,5 = Idm2 = = 0,75(A) U dm 2 6 in tr mch ngoi RD1 ( Rb + RD 2 ) 24(8 + 8) = RN = Yu cu hc sinh tnh in tr Tnh in tr mch ngoi. RD1 + RB + RD 2 24 + 8 + 8 mch ngoi. = 9,6() Cng dng in trong mch Yu cu hc sinh tnh cng Tnh cng dng in chy chnh E 12,5 dng in chy trong mch trong mch chnh. = I= = 1,25(A) RN + r 9,6 + 0,4 chnh. Tnh cng dng in chy Cng dng in chy qua cc Yu cu hc sinh tnh cng qua tng bng n. bng dng in chy qua tng IR U 1,25.9,6 = N = ID1 = = 0,5(A) bng n. RD1 RD1 24 So snh cng dng in ID1 = U = IRN = 1,25.9,6 RD1 Rb + RD1 8+8 Yu cu hc sinh so snh thc vi cng dng in cng dng in thc vi nh mc qua tng bng n v = 0,75(A) cng dng in nh mc rt ra kt lun. a) ID1 = Idm1 ; ID2 = Idm2 nn cc bng n qua tng bng n v rt ra kt Tnh cng sut v hiu sut 1 v 2 sng bnh thng lun. ca ngun. b) Cng sut v hiu sut ca ngun Yu cu hc sinh tnh cng Png = EI = 12,5.1,12 = 15,625 (W) sut v hiu sut ca ngun. U IRN 1,25.9,6 = = H = = 0,96 = E E 12,5 V mch in. 96% Thc hin C8. Bi tp 3 Yu cu hc sinh v mch a) Sut in ng v in tr trong in. ca b ngun Yu cu hc sinh thc hin Ynh in tr ca bng n. 4r C8. Eb = 4e = 6 (V) ; rb = = 2r = 2() 2 in tr ca bng n 2 U dm 6 2 Yu cu hc sinh tnh in tr Tnh cng dng in chy = R = = 6() = RN ca bng n. trong mch chnh. Pdm 6 b) Cng dng in chy qua n - 42 Gio n Vt L 11CB

Trng THPT Bnh Sn Tnh cng sut ca bng n. Yu cu hc sinh tnh cng dng in chy trong mch chnh v cng sut ca bng n khi . I=

GV : Nguyn Vn ng E 6 = = 0,75(A) RN + r 6 + 2 Cng sut ca bng n khi P = I2R = 0,752.6 = 3,375(W) c) Cng sut ca b ngun, cng sut ca mi ngun v gia hai cc mi ngun Pb = EbI = 6.0,75 = 4,5(W) P 4,5 Pi = b = = 0,5625(W) 8 8 I 0,75 .1 = 1,125 (V) Ui = e - r = 1,5 2 2

Thc hin C9.

Yu cu hc sinh thc hin C9.


- 43 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 21. BAI TAPI. MUC TIEU 1. Kin thc : Nm c cch xc nh sut in ng v in tr trong ca cc loi b ngun ghp. 2. K nng : Gii c cc bi ton v mch in c b ngun ghp v mch ngoi c cc in tr v bng n. II. CHUAN B Gio vin - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc. Hc sinh - Xem li nhng kin thc v on mch c cc in tr ghp vi nhau hc THCS. - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIEN TRNH DAY HOC Hot ng 1 (10 pht) : Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii : + Vit cc cng thc xc nh sut in ng v in tr trong ca cc loi b ngun ghp hc. + Vit cc cng thc xc nh cng dng in, hiu in th v in tr tng ng ca on mch gm cc in tr ghp ni tip v on mch gm cc in tr ghp song song. Hot ng 2 (35 pht) : Gii cc bi tp t lun. Hot ng ca gio vin Hot ng ca hc sinh Ni dung c bn Bi 4 trang 58 Yu cu hc sinh tnh in Tnh in tr ca bng n. in tr ca bng n tr ca bng n. U2 62 R = dm = = 12() = RN Pdm 3 Yu cu hc sinh tnh Tnh cng dng in chy Cng dng in chy trong mch E 6 cng dng in chy trong mch = I= = 0,476(A) RN + r 12 + 0,6 trong mch Tnh hiu in th gia hai cc Hiu in th gia hai cc ca acquy Yu cu hc sinh tnh hiu acquy. U = E Ir = 6 0,476.0,6 = 5,7(V) in th gia hai cc acquy. Bi 6 trang 58 Tnh sut in ng v in tr Sut in ng v in tr trong ca Yu cu hc sinh tnh sut trong ca b ngun. b ngun : Eb = 2E = 3V ; rb = 2r = 2 in ng v in tr trong in tr ca cc bng n ca b ngun. Tnh in tr ca bng n. U2 32 RD = dm = = 12() Yu cu hc sinh tnh in Pdm 0,75 tr ca bng n. Tnh in tr mch ngoi. in tr mch ngoi Yu cu hc sinh tnh in R 12 tr mch ngoi. RN = D = = 6() 2 2 Tnh cng dng in chy Cng dng in chy trong mch Yu cu hc sinh tnh trong mch chnh. chnh cng dng in chy Eb 3 = I= = 0,375(A) trong mch chnh. RN + rb 6 + 2 Tnh cng dng in chy Cng dng in chy qua mi Yu cu hc sinh tnh qua mi bng n. I 0,375 cng dng in chy bng n : ID = = = 0,1875(A) 2 2 qua mi bng n. Tnh cng dng in nh - 44 Gio n Vt L 11CB

Trng THPT Bnh Sn Yu cu hc sinh tnh mc ca mi bng n. cng dng in nh mc ca mi bng n. So snh v rt ra lt lun. Yu cu hc sinh so snh v rt ra lt lun. Tnh hiu sut ca ngun. Yu cu hc sinh tnh hiu sut ca ngun. Tnh hiu in th gia hai cc Yu cu hc sinh tnh hiu ca mi ngun. in th gia hai cc ca mi ngun. Lp lun rt ra kt lun. Hng dn hc sinh tm ra kt lun.

GV : Nguyn Vn ng Cng dng in nh mc ca Pdm 0,75 = mi bng n : Idm = = U dm 3 0,25(A) a) ID < Idm : n sng yu hn bnh thng b) Hiu sut ca b ngun U IRN 0,375.6 = = H = = 0,75 = E E 3 75% c) Hiu in th gia hai cc ca mi ngun : Ui = E Ir = 1,5 0,375.1 = 1,125(V) d) Nu tho bt mt bng n th in tr mch ngoi tng, hiu in th mch ngoi, cng l hiu in th gia hai u bng n cn li tng nn n cn li sng mnh hn trc . Bi 2 trang 62 Sut in ng v in tr trong ca b ngun Eb = E1 + E2 = 12 + 6 = 18V ; rb = 0 in tr mch ngoi RN = R1 + R2 = 4 + 8 = 12() a) Cng dng in chy trong mch Eb 18 = I= = 1,5(A) RN + rb 12 + 0 b) Cng sut tiu th ca mi in tr P1 = I2R1 = 1,52.4 = 9(W) P2 = I2R2 = 1,52.8 = 18(W) c) Cng sut v nng lng ca mi acquy cung cp trong 5 pht PA1 = E1I = 12.1,5 = 18(W) AA1 = E1Tt = 12.1,5.60 = 1080(J) PA2 = E2I = 6.1,5 = 9(W) AA2 = E2Tt = 6.1,5.60 = 540(J)

Tnh sut in ng v in tr Yu cu hc sinh tnh sut trong ca b ngun. in ng v in tr trong ca b ngun. Tnh in tr mch ngoi. Yu cu hc sinh tnh in tr mch ngoi. Tnh cng dng in chy Yu cu hc sinh tnh trong mch chnh. cng dng in chy trong mch chnh. Tnh cng sut tiu th ca mi Yu cu hc sinh tnh cng in tr. sut tiu th ca mi in tr. Tnh cng sut ca mi acquy. Yu cu hc sinh tnh cng Tnh nng lng mi acquy sut ca mi acquy. cung cp trong 5 pht. Yu cu hc sinh tnh nng lng mi acquy cung cp trong 5 pht.


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Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet 22. THC HANH: XAC NH SUAT IEN ONG VA IEN TR TRONG CUA MOT PIN IEN HOAI. MUC TIEU 1. Kin thc + Bit cch kho st s ph thuc ca hiu in th U gia hai u on mch cha ngun vo cng dng in I chy trong mch . + Bit cch kho st s ph thuc ca cng dng in I chy trong mch kn vo in tr R ca mch ngoi. + Bit cch chn phng n th nghim tin hnh kho st cc quan h ph thuc gia cc i lng U, I hoc I, R. T c th xc nh chnh xc sut in ng v in tr trong ca mt pin in ho. 2. K nng + Bit cch la chn v s dng mt s dng c in thch hp v mc chng thnh mch in kho st s ph thuc ca hiu in th U gia hai u on mch cha ngun vo cng dng in I chy trong mch . + Bit cch biu din cc s liu o c ca cng dng in I chy trong mch v hiu in th U gia hai u on mch di dng mt bng s liu. II. CHUAN B 1. Giao vien + Pho bien cho hoc sinh noi dung can chuan b trc trong buoi thc hanh. + Kiem tra hoat ong cua cac dung cu th nghiem can thiet. 2. Hoc sinh: + oc k noi dung bai thc hanh.. + Chuan b mau bao cao th nghiem. III. TIEN TRNH DAY HOC Tiet 1 Hoat ong 1 (5 phut) : Tm hieu muc ch th nghiem. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh I. Muc ch th nghiem Gii thieu muc ch Ghi nhan muc ch 1. Ap dung he thc hieu th nghiem. cua th nghiem. ien the cua oan mach cha nguon ien va nh luat Om oi vi toan mach e xac nh suat ien ong va ien tr trong cua mot pin ien hoa. 2. S dung cac ong ho o ien a nang hien so e o hieu ien the va cng o dong ien trong cac mach ien. Hoat ong 2 (10 phut) : Tm hieu dung cu th nghiem. Hoat ong cua Hoat ong cua hoc Noi dung c ban - 46 Gio n Vt L 11CB

Trng THPT Bnh Sn giao vien sinh

GV : Nguyn Vn ng

II. Dung cu th nghiem Gii thieu dung cu Ghi nhan cac dung 1. Pin ien hoa. th nghiem. cu th nghiem. 2. Bien tr num xoay R. 3. ong ho o ien a nang hien so. 5. ien tr bao ve R0. 6. Bo day dan noi mach. 7. Khoa ong ngat ien K. Hoat ong 3 (15 phut) : Tm hieu c s l thuyet. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh III. C s l thuyet Ve hnh 12.2 Xem hnh 12.2. + Khi mach ngoai e h Yeu cau hoc sinh Thc hien C1. hieu ien the ga hai cc thc hien C1. cua nguon ien bang suat ien ong cua Xem hnh 12.3. nguon ien. Ve hnh 12.3. Viet bieu thc nh o UMN khi K ngat : UMN = E Yeu cau hoc sinh luat Om cho oan + nh luat Om cho oan viet bieu thc nh mach MN. mach MN co cha nguon : luat Om cho oan UMN = U = E I(R0 - r) mach co cha Thc hien C2. o UMN va I khi K ong, nguon. Viet bieu thc nh Biet E va R0 ta tnh c r. Yeu cau hoc sinh luat Om cho toan + nh luat Om oi vi thc hien C2. mach trong mach ien toan mach : Yeu cau hoc sinh mac lam th nghiem. E I= viet bieu thc nh R + R A + R0 + r luat Om cho toan Tnh toan va so sanh vi mach. ket qua o. Hoat ong 4 (15 phut) : Gii thieu dung cu o. Hoat ong cua Hoat ong cua hoc giao vien sinh Gii thieu ong ho Ghi nhan cac chc o ien a nang hien nang cua ong ho so DT-830B. o ien a nang hien so DT-830B. Noi dung c ban IV. Gii thieu dung cu o 1. ong ho o ien a nang hien so ong ho o ien a nang hien so DT-830B co nhieu thang o ng vi cac chc nang khac nhau nh : o ien ap, o cng o dong ien 1 chieu, xoay chieu, o ien tr, .

Neu nhng iem Ghi nhan nhng can chu y khi s iem can chu y khi dung ong ho o s dung ong ho o 2. Nhng iem can chu ien a nang hien ien a nang hien y khi thc hien - 47 Gio n Vt L 11CB

Trng THPT Bnh Sn so. so.

GV : Nguyn Vn ng + Van num xoay cua no en v tr tng ng vi chc nang va thang o can chon. Sau o noi cac cc cua ong ho vao mach roi gat nut bat tat sang v tr ON. + Neu cha biet ro gia tr gii han cua ai lng can o, ta phai chon thang o co gia tr ln nhat phu hp vi chc nang a chon. + Khong do cng o dong ien va hieu ien the vt qua thang o a chon. + Khong chuyen oi chc nang thang o khi ang co dong ien chay qua no. + Khong dung nham thang o cng o dong ien e o hieu ien the. + Khi s dung xong cac phep o phai gat nut bat tat ve v tr OFF + Phai thay pin 9V ben trong no khi pin yeu (goc phai hien th k hieu ) + Phai thao pin ra khoi ong ho khi khong s dung trong thi gian dai.

Yeu cau hoc sinh thc hien C3.

Thc hien C3.


- 48 -

Gio n Vt L 11CB


GV : Nguyn Vn ng

Tiet23. THC HANH: XAC NH SUAT IEN ONG VA IEN TR TRONG CUA MOT PIN IEN HOAI. MUC TIEU 1. Kin thc + Bit cch kho st s ph thuc ca hiu in th U gia hai u on mch cha ngun vo cng dng in I chy trong mch . + Bit cch kho st s ph thuc ca cng dng in I chy trong mch kn vo in tr R ca mch ngoi. + Bit cch chn phng n th nghim tin hnh kho st cc quan h ph thuc gia cc i lng U, I hoc I, R. T c th xc nh chnh xc sut in ng v in tr trong ca mt pin in ho. 2. K nng + Bit cch la chn v s dng mt s dng c in thch hp v mc chng thnh mch in kho st s ph thuc ca hiu in th U gia hai u on mch cha ngun vo cng dng in I chy trong mch . + Bit cch biu din cc s liu o c ca cng dng in I chy trong mch v hiu in th U gia hai u on mch di dng mt bng s liu. II. CHUAN B 1. Giao vien + Pho bien cho hoc sinh noi dung can chuan b trc trong buoi thc hanh. + Kiem tra hoat ong cua cac dung cu th nghiem can thiet. 2. Hoc sinh: + oc k noi dung bai thc hanh.. + Chuan b mau bao cao th nghiem. III. TIEN TRNH DAY HOC Hoat ong 5 (25 phut) : Tien hanh th nghiem. Hoat ong cua giao vien Hoat ong cua hoc sinh Chu y hoc sinh ve an toan trong th Lap mach theo s o. nghiem. Kiem tra mach ien va thang o Theo doi hoc sinh. ong ho. Bao cao giao vien hng dan. Hng dan tng nhom. Tien hanh ong mach va o cac gia tr can thiet. Ghi chep so lieu. Hoan thanh th ngiem, thu don thiet b. Hoat ong 6 (15 phut) : X l ket qua, bao cao th nghiem. Hoat ong cua giao vien Hoat ong cua hoc sinh Hng dan hoc sinh hoan thanh Tnh toan, nhan xet e hoan bao cao. thanh bao cao. Nop bao cao. Hoat ong 7 ( phut) : Cung co, giao nhiem vu ve nha. Hoat ong cua giao vien Hoat ong cua hoc sinh - Cho HS nhan xet ve moi lien he - Nhan xet ve moi lien he gia UN gia UN va R. va R. - 49 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

- Yeu cau HS nhan xet cau thc - Nhan xet cau thc hien cua ban. hien cua ban. - Dan HS ve nha on tap chuan b kiem tra 1 tiet IV. RUT KINH NGHIEM TIET DAY

- 50 -

Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Ngay soan : 07/11/2011 Tun : 13 Ngay day : 08/11/2011 CHNG III. DONG IEN TRONG CAC MOI TRNG Tiet 25. DONG IEN TRONG KIM LOAI I. MUC TIEU + Neu c tnh chat ien chung cua cac kim loai, s phu thuoc cua ien tr suat cua kim loai theo nhiet o. + Neu c noi dung chnh cua thuyet electron ve tnh dan ien cua kim loai va cong thc tnh ien tr suat cua kim loai. Neu c cap o ln cua cac ai lng a noi en trong thuyet nay. + Giai thch c mot cach nh tnh cac tnh chat ien chung cua kim loai da tren thuyet electron ve tnh dan ien cua kim loai. II. CHUAN B 1. Giao vien + Chuan b th nghiem a mo ta trong sgk. + Chuan b th nghiem ve cap nhiet ien. 2. Hoc sinh On lai : + Phan noi ve tnh dan ien cua kim loai trong sgk lp 9. + Dong ien trong kim loai tuan theo nh luat Om. III. TIEN TRNH DAY HOC Hoat ong 1 (15 phut) : Tm hieu ban chat cua dong ien trong kim loai. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh I. Ban chat cua dong Yeu cau hoc sinh Neu mang tinh the ien trong kim loai nhac lai mang tinh kim loai va chuyen + Trong kim loai, cac the kim loai va ong nhiet cua cac nguyen t b mat electron chuyen ong nhiet ion nut mang. hoa tr tr thanh cac ion cua no. dng. Cac ion dng lien ket vi nhau mot cach co trat t tao thanh mang Ghi nhan hat mang tinh the kim loai. Cac ion Gii thieu cac dien t do trong kim dng dao ong nhiet xung electron t do trong kim loai va chuyen ong quanh nut mang. loai va chuyen ong cua chung khi cha + Cac electron hoa tr nhiet cua chung. co ien trng. tach khoi nguyen t thanh cac electron t do vi mat o n khong oi. Ghi nhan s chuyen Chung chuyen ong hon Gii thieu s ong cua cac electron loan toa thanh kh electron chuyen ong cua khi chu tac dung cua t do choan toan bo the cac electron t do lc ien trng. tch cua khoi kim loai va di tac dung cua Neu nguyen nhan khong sinh ra dong ien lc ien trng. gay ra ien tr cua nao. Yeu cau hoc sinh kim loai. + ien trng E do nguon neu nguyen nhan ien ngoai sinh ra, ay kh gay ra ien tr cua Neu loai hat tai electron troi ngc chieu - 51 Gio n Vt L 11CB

Trng THPT Bnh Sn kim loai. Yeu cau hoc sinh neu loai hat tai ien trong kim loai. Yeu cau hoc sinh neu ban chat dong ien trong kim loai. ien trong kim loai.

GV : Nguyn Vn ng ien trng, tao ra dong ien. Neu ban chat dong + S mat trat t cua ien trong kim loai. mang tinh the can tr chuyen ong cua electron t do, la nguyen nhan gay ra ien tr cua kim loai Hat tai ien trong kim loai la cac electron t do. Mat o cua chung rat cao nen chung dan ien rat tot. Dong ien trong kim loai la dong chuyen di co hng cua cac electron t do di tac dung cua ien trng . : Tm hieu s phu thuoc cua ien tr suat cua kim Noi dung c ban

Hoat ong 2 (5 phut) loai theo nhiet o. Hoat ong cua Hoat ong cua hoc giao vien sinh

II. S phu thuoc cua ien tr suat cua kim Gii thieu ien tr Ghi nhan khai niem. loai theo nhiet o suat cua kim loai va Ghi nhan s phu ien tr suat cua kim s phu thuoc cua no thuoc cua ien tr loai tang theo nhiet o vao nhiet o. suat cua kim loai vao gan ung theo ham bac Gii thieu khai nhiet o. nhat : niem he so nhiet Ghi nhan khai niem. = 0(1 + (t - t0)) ien tr. He so nhiet ien tr Yeu cau hoc sinh Thc hien C1. khong nhng phu thuoc thc hien C1. vao nhiet o, ma vao ca o sach va che o gia cong cua vat lieu o. Hoat ong 3 (10 phut) : Tm hieu ien tr cua kim loai nhiet o thap va hien tng sieu dan. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh III. ien tr cua kim loai nhiet o thap Yeu cau hoc sinh Giai thch. va hien tng sieu giai thch tai sao khi dan nhiet o giam th Khi nhiet o giam, ien ien tr kim loai Ghi nhan hien tng. tr suat cua kim loai giam. giam lien tuc. en gan Gii thieu hien 00K, ien tr cua kim loai tng sieu dan. sach eu rat be. Ghi nhan cac ng Mot so kim loai va hp - 52 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

dung cua day sieu kim, khi nhiet o thap hn dan. mot nhiet o ti han Tc Gii thieu cac ng Thc hien C2. th ien tr suat ot ngot dung cua hien tng giam xuong bang 0. Ta sieu dan. noi rang cac vat lieu ay Yeu cau hoc sinh a chuyen sang trang thai thc hien C2. sieu dan. Cac cuon day sieu dan c dung e tao ra cac t trng rat manh. Hoat ong 4 (10 phut) : Tm hieu hien tng nhiet ien. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh IV. Hien tng nhiet Gii thieu hien Ghi nhan hien tng. ien tng nhiet ien. Neu lay hai day kim loai khac nhau va han hai au vi nhau, mot moi han gi nhiet o cao, mot Ghi nhan khai niem. moi han gi nhiet o Gii thieu suat ien thap, th hieu ien the ong nhiet ien. gia au nong va au lanh cua tng day khong giong nhau, trong mach co mot suat ien ong E. E Neu cac ng dung goi la suat ien ong Yeu cau hoc sinh cua cap nhiet ien. nhiet ien, va bo hai day neu cac ng dung dan han hai au vao nhau cua cap nhiet ien. goi la cap nhiet ien. Suat ien ong nhiet ien : E = T(T1 T2) Cap nhiet ien c dung pho bien e o nhiet o. Hoat ong 5 (5 phut) : Cung co, giao nhiem vu ve nha. Hoat ong cua giao vien Hoat ong cua hoc sinh Cho hoc sinh tom tat nhng kien Tom tat nhng kien thc c ban. thc c ban a hoc trong bai. Yeu cau hoc sinh ve nha lam cac Ghi cac bai tap ve nha. bai tap t 5 en 9 trang 78 sgk va 13.10, 13.11 sbt. IV. RUT KINH NGHIEM TIET DAY

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Trng THPT Bnh Sn

GV : Nguyn Vn ng

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Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Ngay soan : 12/11/2011 Tun : 13 Ngay day : 13/11/2011 Tiet 26. DONG IEN TRONG CHAT IEN PHAN I. MUC TIEU + Thc hien c cau hoi the nao la chat ien phan, hien tng ien phan, neu c ban chat dong ien trong chat ien phan va trnh bay c thuyet ien li. + Phat bieu c nh luat Faraday ve ien phan. + Van dung c kien thc e giai thch cac ng dung c ban cua hien tng ien phan va giai c cac bai tap co van dung nh luat Faraday. II. CHUAN B 1. Giao vien + Chuan b th nghiem bieu dien cho hoc sinh ve dan ien cua nc tinh khiet (nc cat hoac nc ma), nc pha muoi ; ve ien phan. + Chuan b mot bang he thong tuan hoan cac nguyen to hoa hoc e tien dung khi lam bai tap. 2. Hoc sinh: On lai : + Cac kien thc ve dong ien trong kim loai. + Kien thc ve hoa hoc, cau tao cac axit, baz, va lien ket ion. Khai niem ve hoa tr. III. TIEN TRNH DAY HOC Hoat ong 1 (5 phut) : Kiem tra bai cu : Neu loai hat tai ien trong kim loai, ban chat dong ien trong kim loai, nguyen nhan gay ra ien tr cua kim loai. Hoat ong 2 (15 phut) : Tm hieu thuyet ien li. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh I. Thuyet ien li Cho hoc sinh neu cau Neu cau tao cua Trong dung dch, cac hp tao cua axit, baz va axit, baz va muoi. chat hoa hoc nh axit, baz muoi. va muoi b phan li (mot phan hoac toan bo) thanh ion : anion mang ien am la goc axit hoac nhom (OH), con cation mang Ghi nhan s hnh ien dng la cac ion kim Gii thieu s phan li thanh cac hat tai loai, ion H+ hoac mot so cua cac phan t ien trong chat ien nhom nguyen t khac. axit, baz va muoi. phan. Cac ion dng va am von a ton tai san trong cac phan t axit, baz va muoi. Chung lien ket chat vi nhau bang lc hut Cu-long. Khi tan vao Yeu cau hoc sinh Neu loai hat tai trong nc hoac dung moi neu hat tai ien ien trong chat ien khac, lc hut Cu-long yeu trong chat ien phan. phan. i, lien ket tr nen long Gii thieu chat ien Ghi nhan khai niem. leo. Mot so phan t b - 55 Gio n Vt L 11CB

Trng THPT Bnh Sn phan trong thc te.

GV : Nguyn Vn ng

chuyen ong nhiet tach thanh cac ion. Ion co the chuyen ong t do trong dung dch va tr thanh hat tai ien. Ta goi chung nhng dung dch va chat nong chay cua axit, baz va muoi la chat ien phan. Hoat ong 3 (10 phut) : Tm hieu ban chat dong ien trong chat ien phan. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh Yeu cau hoc sinh II. Ban chat dong ien neu hien tng xay Neu hien tng. trong chat ien phan ra khi nhung hai ien Dong ien trong chat cc vao mot bnh Neu ban chat dong ien phan la dong ien phan. ien trong chat ien chuyen di co hng cua Yeu cau hoc sinh phan. cac ion trong ien trng. neu ban chat dong Giai thch. Chat ien phan khong ien trong chat ien dan ien tot bang kim phan. loai. Yeu cau hoc sinh Dong ien trong chat giai thch tai sao chat Ghi nhan hien tng. ien phan khong ch tai ien phan khong Thc hien C1. ien lng ma con tai ca dan ien tot bang vat chat i theo. Ti ien kim loai. cc ch co cac electron co the i tiep, con lng Gii thieu hien vat chat ong lai ien tng ien phan. cc, gay ra hien tng Yeu cau hoc sinh ien phan. thc hien C1. Hoat ong 4 (15 phut) : Tm hieu cac hien tng dien ra ien cc va hien tng dng cc tan. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh III. Cac hien tng dien Gii thieu phan Ghi nhan khai niem. ra ien cc. Hien ng phu trong hien tng dng cc tan tng ien phan. Cac ion chuyen ong ve Theo doi e hieu cac ien cc co the tac Trnh bay hien tng c cac hien tng dung vi chat lam ien xay ra khi ien phan xay ra. cc hoac vi dung moi tao dung dch muoi ong nen cac phan ng hoa vi anot band ong Ghi nhan khai niem. hoc goi la phan ng phu Gii thieu hien trong hien tng ien tng dng cc tan. phan. Hien tng dng cc tan xay ra khi cac anion i ti - 56 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng anot keo cac ion kim loai cua dien cc vao trong dung dch.


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GV : Nguyn Vn ng

Ngay soan : 14/11/2011 Tun : 14 Ngay day : 15/11/2011 Tiet 27. DONG IEN TRONG CHAT IEN PHAN I. MUC TIEU + Thc hien c cau hoi the nao la chat ien phan, hien tng ien phan, neu c ban chat dong ien trong chat ien phan va trnh bay c thuyet ien li. + Phat bieu c nh luat Faraday ve ien phan. + Van dung c kien thc e giai thch cac ng dung c ban cua hien tng ien phan va giai c cac bai tap co van dung nh luat Faraday. II. CHUAN B 1. Giao vien + Chuan b th nghiem bieu dien cho hoc sinh ve dan ien cua nc tinh khiet (nc cat hoac nc ma), nc pha muoi ; ve ien phan. + Chuan b mot bang he thong tuan hoan cac nguyen to hoa hoc e tien dung khi lam bai tap. 2. Hoc sinh: On lai : + Cac kien thc ve dong ien trong kim loai. + Kien thc ve hoa hoc, cau tao cac axit, baz, va lien ket ion. Khai niem ve hoa tr. III. TIEN TRNH DAY HOC Hoat ong 5 (25 phut) : Tm hieu cac nh luat Fa-ra-ay. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh IV. Cac nh luat Fa-raLap luan e a ra Nghe, ket hp vi ay noi dung cac nh xem sgk e hieu. * nh luat Fa-ra-ay th luat. Thc hien C2. nhat Yeu cau hoc sinh Ghi nhan nh luat. Khoi lng vat chat c thc hien C2. giai phong ien cc Gii thieu nh luat cua bnh ien phan t le Fa-ra-ay th nhat. thuan vi ien lng chay Ghi nhan nh luat. qua bnh o. M = kq Gii thieu nh luat k goi la ng lng hoa Fa-ra-ay th hai. hoc cua chat c giai phong ien cc. * nh luat Fa-ra-ay th hai Ghi nhan so lieu. ng lng ien hoa k Thc hien C3. cua mot nguyen to t le Gii thieu so Fa-raA vi ng lng gam cua ay. n Yeu cau hoc sinh nguyen to o. He so t thc hien C3. Ket hp hai nh luat 1 , trong o F goi la so e a ra cong thc le F Fa-ra-ay. Fa-ra-ay. - 58 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Yeu cau hoc sinh Ghi nhan n v cua 1 A k= . ket hp hai nh luat m e s dung khi giai F n e a ra cong thc cac bai tap. Thng lay F = 96500 Fa-ra-ay. C/mol. Gii thieu n v * Ket hp hai nh luat Facua m khi tnh theo ra-ay, ta c cong thc cong thc tren. Fa-ra-ay : 1 A m = . It F n m la chat c giai phong ien cc, tnh bang gam. Hoat ong 6 (15 phut) : Tm hieu cac ng dung cua hien tng ien phan. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh V. ng dung cua hien Gii theu cac ng Ghi nhan cac ng tng ien phan dung cua cac hien dung cua hien tng Hien tng ien phan co tng ien phan. ien phan. nhieu ng dung trong thc te san xuat va i song nh luyen nhom, tinh luyen ong, ieu che clo, xut, Gii thieu cach Ghi nhan cach luyen ma ien, uc ien, luyen nhom. nhom. 1. Luyen nhom Da vao hien tng ien Yeu cau hoc sinh Neu cach lay bac phan quang nhom nong neu cach lay bac (Ag) ra khoi mot chiec chay. (Ag) ra khoi mot coc ma bac b hong. Be ien phan co cc chiec coc ma bac b dng la quang nhom hong. nong chay, cc am bang than, chat ien phan la muoi nhom nong chay, Gii thieu cach ma dong ien chay qua 4 ien. Neu cach ma vang khoang 10 A. mot chiec nhan 2. Ma ien Yeu cau hoc sinh ong. Be ien phan co anot neu cach ma vang la mot tam kim loai e mot chiec nhan ma, catot la vat can ma. ong. Chat ien phan thng la dung dch muoi kim loai e ma. Dong ien qua be ma c chon mot cach thch hp e am bao chat lng cua lp ma. Hoat ong 7 (5 phut) : Cung co, giao nhiem vu ve nha. Hoat ong cua giao vien Hoat ong cua hoc sinh Cho hoc sinh tom tat nhng kien Tom tat nhng kien thc c ban. thc c ban a hoc trong bai. - 59 Gio n Vt L 11CB

Trng THPT Bnh Sn Yeu cau hoc sinh ve nha lam cac bai tap t 8 en 11 trang 85 sgk va 14.4, 14.6, 14.8 sbt. IV. RUT KINH NGHIEM TIET DAY

GV : Nguyn Vn ng Ghi cac bai tap ve nha.

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Gio n Vt L 11CB

Trng THPT Bnh Sn Ngay soan : 16/11/2011 14 Ngay day : 18/11/2011 Tiet 28. BAI TAP

GV : Nguyn Vn ng Tun :

I. MUC TIEU 1. Kien thc : + Nam c ban chat dong ien trong kim loai, nguyen nhan gay ra ien tr cua kim loai, s phu thuoc cua ien tr cua kim loai vao nhiet o, hien tng sieu dan va hien tng nhiet ien. + Nam c hien tng ien li, ban chat dong ien trong chat ien phan, hien tng dng cc tan, cac nh luat Fa-ra-ay va cac ng dung cua hien tng ien phan. 2. Ky nang : + Thc hien c cac cau hoi lien quan en dong ien trong kim loai va dong ien trong chat ien phan. + Giai c cac bai toan lien quan en dong ien trong kim loai. + Giai c cac bai toan lien quan en nh luat Fa-ra-ay. II. CHUAN B Giao vien: + Xem, giai cac bai tap sgk va sach bai tap. + Chuan b them not so cau hoi trac nghiem va bai tap khac. Hoc sinh: + Giai cac cau hoi trac nghiem va bai tap thay co a ra ve nha. + Chuan b san cac van e ma mnh con vng mac can phai hoi thay co. III. TIEN TRNH DAY HOC Hoat ong 1 (10 phut) : Kiem tra bai cu va tom tat nhng kien thc lien quan en cac bai tap can giai. Hoat ong 2 (15 phut) : Giai cac cau hoi trac nghiem. Hoat ong cua giao Hoat ong cua Noi dung c ban vien hoc sinh Yeu cau hs giai thch tai Giai thch la chon. Cau 5 trang 78 : B sao chon B. Giai thch la chon. Cau 6 trang 78 : D Yeu cau hs giai thch tai Giai thch la chon. Cau 8 trang 85 : C sao chon D. Giai thch la chon. Cau 9 trang 85 : D Yeu cau hs giai thch tai Giai thch la chon. Cau 14.4 : D sao chon C. Giai thch la chon. Cau 14.6 : C Yeu cau hs giai thch tai sao chon D. Yeu cau hs giai thch tai sao chon D. Yeu cau hs giai thch tai sao chon C. Hoat ong 3 (20 phut) : Giai cac bai tap t luan. Hoat ong cua Hoat ong cua hoc Noi dung c ban giao vien sinh Bai 7 trang 78 - 61 Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Yeu cau hoc sinh Tnh ien tr cua ien tr cua den khi tnh ien tr cua bong en khi thap thap sang bong en khi thap sang. U 2 220 2 R= = 484() = sang. P 100 Tnh ien tr cua ien tr cua en khi Yeu cau hoc sinh bong en khi khong khong thap sang tnh ien tr cua thap sang. Ta co : R = R0(1 + (t t0)) bong en khi khong R thap sang. R0 = 1 + (t t 0 ) 484 = = 49() 3 1 + 4,5.10 (2000 20) Bai 8 trang 78 Tnh the tch cua a) The tch cua 1 mol ong Yeu cau hoc sinh 1mol ong. A 64.10 3 = V = = 7,2.10tnh the tch cua 3 D 8,9.10 1mol ong. 6 3 Tnh mat o electron (m /mol) Mat o electron t do trong Yeu cau hoc sinh trong ong. ong tnh mat o electron N A 6,023.10 23 trong ong. = n = = V 7,2.10 6 Tnh so electron qua 8,4.1028(m-3) Yeu cau hoc sinh tiet dien thang cua b) So electron t do qua tiet tnh so electron qua day dan trong 1 giay dien thang cua day dan tiet dien thang cua va viet cong thc trong 1 giay: N = vSn day dan trong 1 tnh cng o dong Cng o dong ien qua giay va viet cong ien theo no. day dan: thc tnh cng o I = eN = evSn dong ien theo no. Tnh van toc troi => v = Cho hoc sinh suy ra cua electron. I 10 = va tnh v. 19 eSn 1,6.10 .10 5.8,4.10 28 = 7,46.10-5(m/s) Tnh khoi lng ong Bai 11 trang 85 Yeu cau hoc sinh muon boc i. Khoi lng ong muon tnh khoi lng ong muon boc i. Viet cong thc Fa- boc i m = V = dS = 8,9.103.10ra-ay. 5 .10-4 Yeu cau hoc sinh = 8,9.10-6(kg) = 8,9.10-3(g) viet cong thc Fa1 A ra-ay. Tnh thi gian ien Ma m = . .It F n phan. Cho hoc sinh suy ra m.F .n 8,9.10 3.96500 .2 = t= va tnh t. A.I 64.10 2 = 2680(s) IV. RUT KINH NGHIEM TIET DAY

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Trng THPT Bnh Sn

GV : Nguyn Vn ng

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Gio n Vt L 11CB

Trng THPT Bnh Sn

GV : Nguyn Vn ng

Ngay soan : 21/11/2011 Tun : 15 Ngay day : 22/11/2011 Tiet 29. DONG IEN TRONG CHAT KH I. MUC TIEU + Phan biet c s dan ien khong t lc va su dan ien t lc trong chat kh. + Phan biet c hai qua trnh dan ien t lc quan trong trong khong kh la ho quang ien va tia la ien. + Trnh bay c cac ng dung chnh cua qua trnh phong ien trong chat kh. II. CHUAN B 1. Giao vien: Chuan b cac thiet b th nghiem e lam cac th nghiem. 2. Hoc sinh: On lai khai niem dong ien trong cac moi trng, la dong cac ien tch chuyen ong co hng. III. TIEN TRNH DAY HOC Hoat ong 1 (5 phut) : Kiem tra bai cu : Neu loai hat tai ien trong chat ien phan, nguyen nhan tao ra chung va ban chat cua dong ien trong chat ien phan. Hoat ong 2 (8 p

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