TRNG A HC
TRNG I HC K THUT CNG NGHIP
KHOA IN TB mn: o lng v iu khin T ngNGN HNG CU HI THI KT THC HC
PHNHC PHN: K THUT O LNG 1b(4 TN CH)
DNG CHO O TO BC I HC THEO HC CH TN CHCC NGNH IU KHIN T NGTHI
NGUYN - 7/2007
TRNG I HC
K THUT CNG NGHIP
KHOA IN TB mn: o lng & KTCNG HA X HI CH NGHA VIT NAM
C LP T DO HNH PHCThi nguyn ngy 03 thng 08 nm 2007
NGN HNG CU HI THIK THUT O LNG 1bS dng cho h i hc theo cc chuyn
ngnh: iu khin T ng1.NI DUNG NH GI THI KT THC HC PHN:
Sinh vin nm c v nguyn l ca cc thit b o lng, cch nh gi sai s,
phng php o cc i lng in v mt s ni dung v qun l in nng, th nghim in.
2. PHNG PHP NH GI
Thi kt thc hc phn l thi vit vi thi lng 120 pht, chm im theo
thang im 10.3. NGUYN TC T HP THI
Mi thi c 4 cu hi
Mi thi c t hp t 2 cu hi l thuyt (Phn: 4.1; 4.2) v 2 cu hi bi tp
(Phn: 4.3; 4.4).4. NGN HNG CU HI
4.1. CU HI LOI 1 (2 IM)
1. Trnh by s cu trc thit b o kiu so snh.2. Sai s ph l g, cho 2 v
d minh ho.3. Trnh by nguyn l lm vic ca c cu o t in.
4. Trnh by nguyn l lm vic ca c cu o in ng.5. Trnh by mch bin i t
c s 10 sang ch th 7 thanh.6. Tnh ton sai s ngu nhin vi s ln o c hn
(n 30 ).7. Tnh ton sai s gin tip, cho v d.8. Trnh by nguyn l lm vic
ca c cu o cm ng.9. Trnh by nguyn l lm vic ca c cu o in t10. Yu cu v
in tr khi o dng v p.
11. Cc phng php m rng gii hn o khi o in p
4.2. CU HI LOI 2 (2 IM)1. Trnh by nguyn l lm vic ca in th k t ng
t ghi.
2. Nguyn l lm vic ca Volmet s chuyn i trc tip.3. Nguyn l lm vic
ca Fazomet in t.4. Nguyn l lm vic ca tn s k ch th s.5. ngha yu cu
ca vic o in tr.6. Trnh by nguyn l cu kp7. iu kin cn bng cu xoay
chiu.8. o in dung bng cu xoay chiu
9. o in cm v h cm
10. Phng php xc nh v tr chp cp
11. o in tr tip a
4.3. CU HI LOI 3 (3 IM)1.V s kt hp Bu; Bi v cng t 3 pha o nng
lng tc dng v phn khng cho li 3 pha cao th. Yu cu: Cng t tc dng 3
pha 2 phn t c cun dng cc pha A,B cng t phn khng 3 pha 2 phn t c R0
to gc lch pha 600, cun dng cc pha A,C
2.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
B,C cng t phn khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc
pha A,C
3.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
A,B cng t phn khng 3 pha 2 phn t c cun dy ni tip ph pha B.
4.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu Cng t tc dng 3 pha 2 phn t c cun dng cc pha
A,B cng t phn khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc
pha B,A
5.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
B,C cng t phn khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc
pha B,A
6.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
C,A cng t phn khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc
pha B,A
7.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
A,B cng t phn khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc
pha C,B8.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng
cho li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc
pha B,C cng t phn khng 3 pha 2 phn t c cun dy ni tip ph pha C.
9.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng cho
li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc pha
A,B cng t phn khng 3 pha 3 phn t.
10.V s kt hp Bu; Bi v cng t 3 pha o nng lng tc dng v phn khng
cho li 3 pha cao th. Yu cu: Cng t tc dng 3 pha 2 phn t c cun dng cc
pha A,C cng t phn khng 3 pha 3 phn t. 11.V s kt hp Bu; Bi v cng t 3
pha o nng lng tc dng v phn khng cho li 3 pha cao th. Yu cu: Cng t
tc dng 3 pha 2 phn t c cun dng cc pha B,C cng t phn khng 3 pha 2
phn t c R0 to gc lch pha 600, cun dng cc pha C,B
12. Cng t tc dng 3 pha 2 phn t c cun dng cc pha A,C cng t phn
khng 3 pha 2 phn t c R0 to gc lch pha 600, cun dng cc pha C,B
4.3. CU HI LOI 4 (3 IM)1. Cho mt h tiu th in c 2 ph ti
+ 01 ng c 3 pha c Um =380V; Im = 250A; cos(m =
+ 01 my hn mt pha c Um =380V; Im = 150A; cos(m = 0.9
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 2 cng t 1 pha c Um = 380V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn. Chn t s bin cho my bin dng (KI)
- Tnh s ch ca mi cng t trong thi gian mt thng bit rng ng c lun
lm vic ch nh mc cn my hn c 50% thi gian lm vic ch nh mc; 50% thi
gian lm vic ch non ti c U=Um; I=0.2Im; cos( = 0.35 (my hn mc vo cc
pha B v C)2. Cho mt h tiu th in c 2 ph ti
+ Chiu sng:
Pha A gm 50 bng n; pha B gm 60 bng n; pha C gm 80 bng n
Thng s mi bng: P=100w; Um=220 V
+ 01 my hn mt pha c Um =380V; Im = 100A; cos(m =
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 3 cng t 1 pha c Um = 220V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn.Chn t s bin cho my bin dng (KI )
- Tnh s ch ca mi cng t trong thi gian 100 gi bit rng my hn c 60%
thi gian lm vic ch nh mc; 40% thi gian lm vic ch non ti c U=Um;
I=0.2Im; cos( = 0.4 (my hn mc vo cc pha B v C)
3. Mt ng c in 3 pha xoay chiu c s u dy nh hnh v
+ Nu tn cc phng php o cc gi tr RA, RB, RC bit trong l lch
[RA] = [RB] = [RC] = 20 (m().
+ Biu thc xc nh c th RA, RB, RC
+ V 2 s dng phng php gin tip, ngun 1 chiu o cc in tr trn.
Tnh sai s ph cho mi s bit RA = 0,05(; RV = 100K(4. Cho mt h tiu
th in c 2 ph ti
+ 01 ng c 3 pha c Um =380V; Im = 50A; cos(m =
+ 01 my hn mt pha c Um =380V; Im = 50A; cos(m = 0.9
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 2 cng t 1 pha c Um = 380V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn. Chn t s bin cho my bin dng (KI)
- Tnh s ch ca mi cng t trong thi gian mt thng bit rng ng c lun
lm vic ch nh mc cn my hn c 60% thi gian lm vic ch nh mc; 40% thi
gian lm vic ch non ti c U=Um; I=0.2Im; cos( = 0.3 (my hn mc vo cc
pha B v C)5.Cho mt h tiu th in c 2 ph ti
+ Chiu sng:
Pha A gm 150 bng n; pha B gm 40 bng n; pha C gm 120 bng n
Thng s mi bng: P=100w; Um=220 V
+ 01 my hn mt pha c Um =380V; Im = 100A; cos(m =
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 3 cng t 1 pha c Um = 220V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn.Chn t s bin cho my bin dng (KI )
- Tnh s ch ca mi cng t trong thi gian 100 gi bit rng my hn c 60%
thi gian lm vic ch nh mc; 40% thi gian lm vic ch non ti c U=Um;
I=0.2Im; cos( = 0.4 (my hn mc vo cc pha A v C)
6.Cho mt h tiu th in c 2 ph ti
+ Chiu sng:
Pha A gm 150 bng n; pha B gm 160 bng n; pha C gm 80 bng n
Thng s mi bng: P=75w; Um=220 V
+ 01 my hn mt pha c Um =380V; Im = 100A; cos(m =
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 3 cng t 1 pha c Um = 220V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn.Chn t s bin cho my bin dng (KI )
- Tnh s ch ca mi cng t trong thi gian 100 gi bit rng my hn c 60%
thi gian lm vic ch nh mc; 40% thi gian lm vic ch non ti c U=Um;
I=0.2Im; cos( = 0.35 (my hn mc vo cc pha B v A)7. Cho mt h tiu th
in c 2 ph ti
+ 01 ng c 3 pha c Um =380V; Im = 100A; cos(m =0.9
+ 01 my hn mt pha c Um =380V; Im = 50A; cos(m =
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 2 cng t 1 pha c Um = 380V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn. Chn t s bin cho my bin dng (KI)
- Tnh s ch ca mi cng t trong thi gian mt thng bit rng ng c lun
lm vic ch nh mc cn my hn c 60% thi gian lm vic ch nh mc; 40% thi
gian lm vic ch non ti c U=Um; I=0.2Im; cos( = 0.4 (my hn mc vo cc
pha A v C)
8. Mt ng c in 3 pha xoay chiu c s u dy nh hnh v
+ Nu tn cc phng php o cc gi tr RA, RB, RC bit trong l lch
[RA] = [RB] = [RC] = 120 (m().
+ Biu thc xc nh c th RA, RB, RC
+ V 2 s dng phng php gin tip, ngun 1 chiu o cc in tr trn.
Tnh sai s ph cho mi s bit RA = 0,25(;
RV = 100K(9. Cho mt h tiu th in c 2 ph ti
+ 01 ng c 3 pha c Um =380V; Im = 100A; cos(m =0.85
+ 01 my hn mt pha c Um =380V; Im = 50A; cos(m =
Bit: Ngun 3 pha i xng c Ud = 380V
Yu cu: - V s kt hp BI v 2 cng t 1 pha c Um = 380V, Im =5 A o nng
lng tc dng cho c 2 ph ti trn. Chn t s bin cho my bin dng (KI)
- Tnh s ch ca mi cng t trong thi gian mt thng bit rng ng c lun
lm vic ch nh mc cn my hn c 60% thi gian lm vic ch nh mc; 40% thi
gian lm vic ch non ti c U=Um; I=0.2Im; cos( = 0.4 (my hn mc vo cc
pha A v B)
10. Tnh kt qu o v sai s ngu nhin vi mt xc sut ng tin p=0.98 ca
mt php o in tr bng cu kp vi kt qu nh sau (n v tnh = m()
140,25; 140,5; 141,75; 139,25; 139,5; 140,25; 140; 126,75;
141,15; 142,25; 140,75; 144,15; 140,15; 142,75. Bit sai s ngu nhin
c phn b chun.
11. Tnh kt qu o v sai s ngu nhin vi mt xc sut ng tin p=0.99 ca
mt php o in tr bng cu kp vi kt qu nh sau (n v tnh = m()
141,25; 142,5; 140,75; 139,75; 139,5; 140,25; 140; 171,75;
141,15; 142,25; 140,75; 144,15; 140,15; 140,75. Bit sai s ngu nhin
c phn b chun
THNG QUA B MN
TRNG B MN
THNG QUA HI NG
KHOA HC GIO DC KHOA IN T
CH TCH
TS. Nguyn Hu CngTS. Nguyn Hu Cng
RC
RB
RA
C
B
A
RC
RB
RA
C
B
A
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_1249815299.unknown
