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{an}n=1

an

= 2n

bn

= n2 + 2n1 cn= (1)nn2 dn= (1 + 1n

)n

e1 = 0 ; en=en

1+ 2, n 2 f1 =

1; fn=

2fn

1, n 2

g1= 1; g2 = 1; gn+2 = gn+gn+1

2n2

n2+1

2nn2+1

4

(1)n

n

sen

1n

n21n

en

n

en

n/2

(1)nn

en

2n

nn

(n!)2

(2n)!

n cos

n

2

senn

n

{(23

)n} {(32

)n} {n} {n}

rn

|r|> 1

|r|< 1

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an

= n1n

bn

= n

cn

=n dn= (1)nn

952n3n7

n24n+5

n

2

n3+1

(1)n n

n3+1

n22

n+1

1n3n2

n

n3+1

n+ 1n

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