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contoh simulasi monte carlo dengan menggunakan excel spreadsheet
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Tujuan Minimasi biaya dalam mengatur inventoryVariabel 1 Permintaan Ace DrillVariabel 2 Pemesanan BarangInventory cost = ordering, holding, reordering PERCOBAAN 10 HARI
Stok inventory awal 10 unitACE DRILL DEMAND asumsi order drill dilakukan ketika drill tinggal 5 unitSelama 300 hari ke belakang setiap order menghasilkan 10 unit
DEMAND DAY
0 15 0.05 0 0.05 0 11 30 0.1 0.05 0.15 1 22 60 0.2 0.15 0.35 2 33 120 0.4 0.35 0.75 3 44 45 0.15 0.75 0.9 4 5 105 30 0.1 0.9 1 5 6
300 7HISTORY 50 HARI PEMESANAN 8LEAD TIME 9
LEAD TIME LEAD TIME 10 10
1 10 0.2 0 0.2 12 25 0.5 0.2 0.7 2 DIKETAHUI3 15 0.3 0.7 1 3 BIAYA PEMESANAN = $10/PEMESANAN
50 BIAYA SIMPAN = $0.03/UNIT/DAYBIAYA KEHABISAN STOK = $8TOTAL BIAYA INVENTORY
RANDOM NUMBER0.49934316 0.60326 0.3625450.54039644 0.209093 0.6578890.35429525 0.855033 0.7561880.13651746 0.203508 0.8089720.94047246 0.241244 0.4160720.95358878 0.348298 0.8972280.97797672 0.702049 0.2893050.26002363 0.357271 0.2439450.49615397 0.81743 0.844375
0.5420849 0.309103 0.2886250.24180418 0.9267170.71995046 0.2134780.33486738 0.2436920.31596219 0.8592230.34811561 0.853809
DEMAND FOR ACE
DRILLFREQUEN
CYPROBABIL
ITY LOWER PROB
CUM PROB
UNIT RECEIVED
FREQUENCY
PROBABILITY
LOWER PROB
CUM PROB
PERCOBAAN 10 HARIStok inventory awal 10 unitorder drill dilakukan ketika drill tinggal 5 unitsetiap order menghasilkan 10 unit
DEMAND ORDER
10 0.60326 3 7 0 NO7 0.209093 2 5 0 YES 0.362545 25 0.855033 4 1 0 NO1 0.203508 2 0 1 NO
10 0.241244 2 8 0 NO8 0.348298 2 6 0 NO6 0.702049 3 3 0 YES 0.657889 23 0.357271 3 0 0 NO0 0.81743 4 0 4 NO
10 0.309103 2 8 0 NO
AVERAGE 3.8 0.5 0.2DIKETAHUIBIAYA PEMESANAN = $10/PEMESANAN 2BIAYA SIMPAN = $0.03/UNIT/DAY 0.114BIAYA KEHABISAN STOK = $8 4TOTAL BIAYA INVENTORY 6.114
BEGINNING INVENTORY
RANDOM NUMBER
ENDING INVENTORY
LOST SALE
RANDOM NUMBER
LEAD TIME
Tujuan evaluasi DELAY COST, IDLE COST, LABOR COST, (PERLU TAMBAHPERCOBAAN 15 HARIVariabel 1 ARRIVAL RATEVariabel 2 SERVICE RATE asumsidi hari pertama tidak ada delaytotal expected cost = waiting cost + service cost
ARRIVAL RATES
DEMAND DAY ARRIVAL
0 0.13 0 0.13 0 1 0 0.637102 31 0.17 0.13 0.3 1 2 0 0.802764 42 0.15 0.3 0.45 2 3 2 0.361376 23 0.25 0.45 0.7 3 4 1 0.144254 14 0.2 0.7 0.9 4 5 0 0.869963 45 0.1 0.9 1 5 6 1 0.591417 3
7 1 0.772293 4SERVICE RATE 8 0 0.216433 1
90
0.826381 41 0.05 0 0.05 1 10 0 0.379267 22 0.15 0.05 0.2 2 11 2 0.74815 43 0.5 0.2 0.7 3 12 4 0.1624 14 0.2 0.7 0.9 4 13 1 0.165075 15 0.1 0.9 1 5 14 0 0.774512 4
15 1 0.160719 1AVERAGE 0.866667 2.6
DELAY COST LAMDARANDOM NUMBER WAITING COST0.080321 0.881773 0.637102 0.552656 JAM KERJA X LAMDA X Wq X COST0.132044 0.546779 0.802764 0.142623 SERVICE COST
0.77792 0.92684 0.361376 0.590218 JAM KERJA X JUMLAH SERVER X COST0.192348 0.322299 0.144254 0.1379830.978935 0.901825 0.869963 0.470637 TOTAL COST = WAITING COST + SERVICE COST0.877698 0.45023 0.591417 0.2293640.264188 0.607036 0.772293 0.9007210.747728 0.497647 0.216433 0.0690180.066129 0.233708 0.826381 0.7714210.059857 0.281495 0.379267 0.7295910.090175 0.730843 0.74815 0.1509830.050939 0.816152 0.1624 0.8964450.055247 0.508334 0.165075 0.7203580.659399 0.781036 0.774512 0.3916360.096281 0.196934 0.160719 0.77093
NUMBER OF
ARRIVALPROBABIL
ITY LOWER PROB
CUM PROB
PREVIOUSLY DELAY
RANDOM NUMBER
DAILY UNLOADING RATE
PROBABILITY
LOWER PROB
CUM PROB
UNLOADING
3 0.552656 34 0.142623 24 0.590218 32 0.137983 24 0.470637 34 0.229364 35 0.900721 51 0.069018 2
4 0.771421 42 0.729591 46 0.150983 25 0.896445 42 0.720358 44 0.391636 32 0.77093 4
3.2MIU
TOTAL TO BE
UNLOADED
RANDOM NUMBER
NUMBER UNLOADE
D
Tujuan evaluasi BIAYA PERBAIKAN DAN BIAYA PEGAWAI (PERLU NAMBAH ATAU TIDAK)Variabel 1 kerusakan mesinVariabel 2 perbaikan mesin
KERUSAKAN MESIN ASUMSI SIMULASI MULAI PADA JAM 0:00Selama 100 hari ke belakang
DEMAND
0.5 5 0.05 0 0.05 0.5 1 0.6693791 6 0.06 0.05 0.11 1 2 0.579264
1.5 16 0.16 0.11 0.27 1.5 3 0.8166672 33 0.33 0.27 0.6 2 4 0.862039
2.5 21 0.21 0.6 0.81 2.5 5 0.5376173 19 0.19 0.81 1 3 6 0.734955
100 7 0.530438 0.859114
Selama 100 hari ke belakang 9 0.537039WAKTU PERBAIKAN 10 0.981195
WAKTU PERBAIKAN PERBAIKAN 11 0.75523
1 28 0.28 0 0.28 1 12 0.3266682 52 0.52 0.28 0.8 2 13 0.5096323 20 0.2 0.8 1 3 14 0.834067
100 15 0.16493
DUA HARI MULAI PUKUL 00:00 BERAKHIR PULUK 15:30 = 39.5 JAMBIAYA MAINTENANCE $30/JAM
0.850149 0.491604 0.669379 0.612992 BIAYA KERUSAKAN $75/JAM0.098215 0.484755 0.579264 0.815624 TOTAL COST
0.33982 0.144113 0.816667 0.2183950.656337 0.181854 0.862039 0.0727660.038371 0.815144 0.537617 0.609501
0.93734 0.545785 0.734955 0.1177740.718935 0.778008 0.53043 0.4458950.181151 0.551988 0.859114 0.7107040.170324 0.989135 0.537039 0.7966960.543697 0.36131 0.981195 0.1266130.939774 0.866466 0.75523 0.7397520.459669 0.192136 0.326668 0.5324910.871619 0.820997 0.509632 0.361710.844439 0.317826 0.834067 0.941320.899776 0.854215 0.16493 0.7022360.066151 0.0070640.574537 0.9451880.376892 0.866299
0.17134 0.222978
LAMA KERUSAKAN (JAM)
FREQUENCY
PROBABILITY
LOWER PROB
CUM PROB
JUMLAH KERUSAK
ANRANDOM NUMBER
FREQUENCY
PROBABILITY
LOWER PROB
CUM PROB
SIMULASI MULAI PADA JAM 0:00
2.5 2:30 2:30 0.612992 2 4:30 22 4:30 4:30 0.815624 3 7:30 33 7:30 7:30 0.218395 1 8:30 13 10:30 10:30 0.072766 1 11:30 12 12:30 12:30 0.609501 2 14:30 2
2.5 15:00 15:00 0.117774 1 16:00 12 17:00 17:00 0.445895 2 19:00 23 20:00 20:00 0.710704 2 22:00 22 22:00 22:00 0.796696 2 0:00 23 1:00 1:00 0.126613 1 2:00 1
2.5 3:30 3:30 0.739752 2 5:30 2
2 5:30 5:30 0.532491 2 7:30 22 7:30 7:30 0.36171 2 9:30 23 10:30 10:30 0.94132 3 13:30 3
1.5 12:00 13:30 0.702236 2 15:30 3.529.5
DUA HARI MULAI PUKUL 00:00 BERAKHIR PULUK 15:30 = 39.5 JAMBIAYA MAINTENANCE $30/JAM 1185BIAYA KERUSAKAN $75/JAM 2212.5
3397.5
LAMA KERUSAK
AN
WAKTU KERUSAK
AN
WAKTU BEBAS MULAI
PERBAIKAN
RANDOM NUMBER
LAMA PERBAIKA
N DIBUTUH
KAN
WAKTU SELESAI
PERBAIKAN
LAMA MESIN MATI
DEMAND WEEK SUPPLY
4 6 0.12 0 0.12 4 1 8 0.15 5 0.1 0.12 0.22 5 2 8 0.246 9 0.18 0.22 0.4 6 3 8 0.037 12 0.24 0.4 0.64 7 4 8 0.328 8 0.16 0.64 0.8 8 5 8 0.239 7 0.14 0.8 0.94 9 6 8 0.59
10 3 0.06 0.94 1 10 7 8 0.9550 8 8 0.34
EXPECTED VALUE 9 8 0.346.88 10 8 0.51
11 8 0.0812 8 0.4813 8 0.6614 8 0.9715 8 0.0316 8 0.9617 8 0.4618 8 0.7419 8 0.7720 8 0.44
HEATER SALES
FREQUENCY
PROBABILTY
LOWER PROB
CUMMULATIVE PROB
RANDOM NUMBER DEMAND
DEMAND
4 46 24 46 26 27 1
10 -26 26 27 14 47 18 0
10 -24 4
10 -27 18 08 07 1
6.75
LOST SALE
Interval DEMAND DAY
0 0.13 0 0.13 1 13 0 1 01 0.17 0.13 0.3 14 30 1 2 02 0.15 0.3 0.45 31 45 2 3 03 0.25 0.45 0.7 46 70 3 4 04 0.2 0.7 0.9 71 90 4 5 05 0.1 0.9 1 91 100 5 6 0
7 0
Interval 8 0
1 0.03 0 0.03 1 3 1 9 02 0.12 0.03 0.15 4 15 2 10 03 0.4 0.15 0.55 16 55 3 11 14 0.28 0.55 0.83 56 83 4 12 05 0.12 0.83 0.95 84 95 5 13 26 0.05 0.95 1 96 100 6 14 2
15 1AVERAGE 0.4
NUMBER OF
ARRIVALPROBABIL
ITY LOWER PROB
CUM PROB
PREVIOUSLY DELAY
DAILY UNLOADING RATE
PROBABILITY
LOWER PROB
CUM PROB
UNLOADING
ARRIVAL
37 2 2 69 477 4 4 84 513 0 0 12 210 0 0 94 52 0 0 51 3
18 1 1 36 331 2 2 17 3
19 1 1 2 1
32 2 2 15 285 4 4 29 331 2 3 16 394 5 5 52 381 4 6 56 443 2 4 43 331 2 3 26 3
2.066667 3.133333
RANDOM NUMBER
TOTAL TO BE
UNLOADED
RANDOM NUMBER
NUMBER UNLOADE
D
DEMAND DAY
0 0.2 0 0.2 0 1 5 0.603261 0.4 0.2 0.6 1 2 3 0.2090932 0.2 0.6 0.8 2 3 2 0.8550333 0.15 0.8 0.95 3 4 0 0.2035084 0.05 0.95 1 4 5 10 10 0.241244
6 9 0.348298HISTORY 50 HARI PEMESANAN 7 8 0.702049LEAD TIME 8 6 0.357271
LEAD TIME LEAD TIME 9 5 0.81743
1 0.15 0 0.15 1 10 2 0.3091032 0.35 0.15 0.5 23 0.5 0.5 1 3 STOCKOUT COST $40/STOCKOUT
HOLDING COST $1/WEEK
0.284176 0.020736 0.657611 0.632885
DEMAND FOR
REFRIGIRATOR
PROBABILITY
LOWER PROB
CUM PROB
UNIT RECEIVED
BEGINNING
INVENTORY
RANDOM NUMBER
PROBABILITY
LOWER PROB
CUM PROB
DEMAND ORDER
2 3 0 NO1 2 0 NO3 0 1 YES 0.020736 11 0 1 NO1 9 0 NO1 8 0 NO2 6 0 NO1 5 0 NO
3 2 0 YES0.632885
3
1 1 0 NOAVERAGE 3.6 0.2 0.2
STOCKOUT COST $40/STOCKOUT 83.6
ENDING INVENTO
RYLOST SALE
RANDOM NUMBER
LEAD TIME