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Математикийн багш
Ц. Отгонжаргал
2 =
243 · 2=(200+40+3) · 2=200 · 2 +40 · 2 +3 · 2=400+80+6=486
4c
B E C
A F D
3a 2b
B E C
A F D
4c
3a 2b
4c
E
F
a(b±c±d)=ab±ac±ad
(2a3-5a2b+b2) îëîí ãèø¿¿íòèéã 3ab ãýñýí íýã ãèø¿¿íòýýð ¿ðæ¿¿ë.
(2a3-5a2b+b2)*3ab=6a4b-15a3b2+3ab3