Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 1 Ngy17thng 10 nm 2011 Tit 16.NH LUT M I VI TON MCH I. MC TIU: 1. Kin thc: - Pht biu c quan h sut in ng ca ngun v tng gim th trong v ngoi ngun - Pht biu c ni dung nh lut m cho ton mch. - Suy ra c nh lut m cho ton mch t nh lut bo ton nng lng. - Trnh by c khi nim hiu sut ca ngun in. 2. K nng: - Gii cc dng bi tp c lin quan n nh lut m cho ton mch. 3. Thi : S tp trung trong cng vic II. CHUN B: 1. Gio vin: - Dng c: Thc k, phn mu. - Chun b phiu cu hi. 2. Hc sinh: c trc bi hc mi. III. TIN TRNH DYHC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) :Kim tra bi c :1. Cng v cng sut to nhit ca vt dn khi c dng in chy qua ?2. Cng v cng sut ca ngun in ? Hot ng 2 ( 15 pht) : Gii thiuth nghim ly s liu xy dng nh lut. Hot ng ca gio vinhc sinhNi dung c bn - GV gii thiu v ton mch v nh lut m cho ton mch - GV gii thiu phng n th nghim tm nh lut m cho ton mch - GV gii thiu th nghim v kt qu th nghim, hng dn hc sinh tm hiu nh lut I. Th nghim: I(A)00,10,20,30,40,5 (V)3,23,02,82, 2,42,2 Hot ng 3(10 pht) :Tm hiu nh lut m i vi ton mch. Hot ng ca gio vin, hc sinh Ni dung c bn - GV: X l th rt ra kt qu. GV yu cu hc sinh nhn xt dng th v vit phng trnh biu din s ph thuc GV phn tch hc sinh nhn ra in tr II. nh lut m i vi ton mch: E= I(RN + r) = IRN + Ir(9.3) Vy: Sut in ng c gi tr bng tng cc gim in th mch ngoi v mch trong. T h thc (9.3) suy ra :Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 2 trong ca ngun. - HS: Thc hin C1. - GV hng dn hc sinh vit biu thc ca U(I) v ngha ca cc i lng trong cng thc: gim in th mch ngoi, mch trong GV:Yu cu thc hin C2. GV:Yu cu hc sinh rt ra kt lun.

GV:T h thc (9.3) cho hc sinh rt ra biu thc nh lut. HS: Bin i tm ra biu thc (9.5). GV:Yu cu hc sinh pht biu nh lut. HS: Thc hin C3. UN = IRN = E Ir(9.4) vI = r REN + (9.5) nh lut:Cng dng in chy trong mch in kn t l thun vi sut in ng ca ngun in v t l nghch vi in tr ton phn ca mch . Hot ng 4 (10 pht) : Tm hiu hin tng on mch. Hot ng ca gio vin hc sinhNi dung c bn GV:Gii thiu hin tng on mch. HS: Ghi nhn hin tng on mch. GV gii thiu hin tng on mch xy ra pin v acquy GV:Yu cu hc sinh thc hin C4. GV lu mt s ngun in cn ch trnh hin tng on mch III. Nhn xt: 1. Hin tng on mch: Cng dng in trong mch kn t gi tr ln nht khi RN = 0. Khi ta ni rng ngun in b on mch v I = rE (9.6) Hot ng 5 (5 pht) :Cng c, giao nhim v v nh. Hot ng ca gio vinvhc sinhNi dung c bn GV: Cho hc sinh tm tt nhng kin thc c bn hc trong bi. HS: Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp t 4 n 7 trang 54 sgkv 9.3, 9.4 sbt. HS:Ghi cc bi tp v nh. nh lut m cho ton mch: I = r REN +

Hin tng on mch: RN = 0, cng dng in t gi tr cc iImax = rE IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 3 Ngy 18 thng10 nm 2011 Tit 17: NH LUT M I VI TON MCH (TIT 2) I. MC TIU 1.Kin thc: - T suy ra c nh lut m cho ton mch t nh lut bo ton nng lng. - Trnh by c khi nim hiu sut ca ngun in. 2.K nng - Gii cc bi tp n gin lin quan n nh lut m cho ton mch. -Chracsphhpcanhlutmvnhlutbotonvchuynhanng lng 3. Thi : S tp trung, gn l thuyt vi thc tinII. CHUN B Gio vin: Cc cu hi hng dn. Hc sinh: Chun b bi m. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1Kim tra bi c: (5 pht) 1. Pht biu v vit biu thc nh lut m cho ton mch 2. Hin tng on mch Hot ng 2 (20 pht) Tm hiu mi quan h gia nh lut bo ton nng lng v nh lut m cho ton mch. Hiu sut ca ngun Hot ng ca gio vin v hc sinhNi dung c bn GV t cu hi nu vn : - Trong mch kn c s chuyn ha nng lng nh th no? - Nhit nng c nng lng no chuyn thnh? - p dng nh lut bo ton nng lng rt ra biu thc ton hc? HS tho lun nhm xc nh cng ca ngun in, nhit lng ta ra trn in tr ngoi v trong. p dng nh lut bo ton nng lng - GV nu cu hi xc nh hiu sut ca ngun in Gi : Trong ton mch in b phn no tiu th nng lng c ch. Nng lng ton phn? HS tho lun v a ra cng thc tnh hiu 2. nh lut Ohm i vi ton mch v nh lut bo ton chuyn ha nng lng. - Cng ca ngun in sn ra trong thi gian t: A = cIt (*) - Trong thi gian nhit lng ta ra mch ngai v mch trong: Q = (RN +r)I2t (**) T (*) & (**) ( )NNI R rIR rcc= +=+ 3. Hiu sut ca ngun in EUEItIt UHN N= =Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 4 sut ca ngun in Hot ng 3 ( 15 pht) p dng nh lut m cho ton mch Hot ng ca gio vin v hc sinhNi dung c bn GV hng dn hc sinh tm tt v lm bi tp 5 sgk Gi:Mchngoicmcnhth no? - Hiu in th mch ngoi? - Cng sut mch ngoi? - Cng sut ca ngun in? HS tho lun nhanh v hot ng c nhn gii ton Bi 5/54sgk Gii :a. Cd chy trong mch 8, 40, 6NUI AR= = =14 S ca ngun in c = IRN + Ir = UN + Ir = 8,4 + 0.6x1= 9V b. Cng sut mch ngai P = UNI = 8,4.0,6= 5.04W Cng sut ca ngun in Png = cI = 9.0,6 = 5.4W Hot ng 4( 5 pht)Cng c v dn d GV yu cu lm cc bi tp phn nh lut m cho ton mch - V nh c mc em c bit? - Tm tt nhng kin thc c bn hc trong bi. - V nh lm cc bi tpt4 n 7 trang 54 sgkv 9.3, 9.4 sbt IV. Rt kinh nghim Ngy 21thng 10nm 2011 Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 5 Tit 18. BI TP I. MC TIU 1. Kin thc :+ Nm c nh lut m i vi ton mch. + Nm c hin tng on mch. + Nm c hiu sut ca ngun in. 2. K nng :Thc hin c cc cu hi v gii c cc bi tp lin quan n nh lut m i vi ton mch. 3. Thi : Nghim tc trong hc tp II. CHUN B: 1.Gio vin: - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm mt s cu hi trc nghim v bi tp khc.2.Hc sinh: - Gii cc cu hi trc nghim v bi tp v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hiIII. TIN TRNH DYHC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (10 pht) : Kim tra bi c : nh lut m cho ton mch. Hiu sut ca ngun in? v tm tt nhng kin thc lin quan n cc bi tp cn gii. + nh lut m i vi ton mch : I = r REN + + gim th mch ngoi : UN = IRN = E- Ir. + Hin tng on mch : I = rE + Hiu sut ca ngun in : H = EUN Hot ng 2(7 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin v hc sinhNi dung c bn GV:Yu cu hs a ra p n v gii thch ti sao chnp n . HS: a ra p n v gii thch. Cu 4 trang 54 : A Cu9.1 : B Cu9.2 : B Hot ng 3 (25 pht) : Gii cc bi tp t lun. Hot ng ca gio vin v hc sinhNi dung c bn GV: yu cu hc sinh tho lun nhm bn gii bi tp s 6 sgk trang 54 HS tho lun theo nhm GV gi :+ n sng bnh thng l nh th no? + in trbng n tnh nh th no? HS:trao i tnh in tr v cng dng in thc t chy qua n. GV: Yu cu hc sinh so snh v rt ra kt Bi 6 trang 54: Tm tt: r =0,06 O; E =12V; :12V -5W a) Cng dng in nh mc ca bng n:Idm = 125=dmdmUP= 0,417(A) in tr ca bng n Rd = 5122 2=dmdmPU= 28,8(O) Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 6 lun. HS da vo kt qu tnh c so snh cng dng in thc t v dng in nh mc. Kt lun n sng gn nh bnh thng - Hiu sut ca ngun in? - GV yu cu tho lun gii bi tp 7 sgk trang 54 + Lm th no tnh cng sut ca cc bng n + Nu mc hai bng n nh nhau song song vi nhau th cng dng in qua cc n v hiu in th hai u mi n nh th no? HS tho lun nhm v tm cch gii GV: Yu cu hc sinh tnh in tr mch ngoi v cng dng in chy trong mch chnh.GV: Cho hc sinh tnh hiu in th gia hai u mi bng.GV: Cho hc sinh tnh cng sut tiu th ca mi bng n.+ Khi tho mt bng n ra in tr ca mch ngoi thay i nh th no? Cng dng in qua n thay i nh th no? HS suy lun xc nh cng dng in qua n tng n sng hn trc. Cng dng in qua n I = 06 , 0 8 , 2812+=+ r REN= 0,416(A) I ~ Idm nn n sng gn nh bnh thng Cng sut tiu th thc t ca n PN = I2.Rd = 0,4162.28,8 = 4,98(W) b) Hiu sut ca ngun in: H = 128 , 28 . 416 , 0 .= =ER IEUd N = 0,998=99,8% Bi 7 trang54: a) in tr mch ngoi RN = 6 66 . 6 .2 12 1+=+ R RR R= 3(O) Cng dng in chy trong mch chnh:I = 2 33+=+ r REN= 0,6(A) Hiu in th gia 2 u mi bng n: UN = U1 = U2 = I.RN = 0,6.3= =1,8(V) Cng sut tiu th ca mi bng n P1 = P2 = 68 , 12121=RU = 0,54(W) b) Khi tho bt mt bng n, in tr mch ngoi tng, hiu in th mch ngoil hiu in th gia hai u bng n cn li tng nn bng n cn li sng hn trc: UN=I R (R=6O) Hot ng 4:(3 pht)Cng c dn d: -Nhc hc sinh xem li cc bi tp cha. - Hs xem trc bi mi v chun b mt cp pin/ nhm - Xem li nh lut m cho on mch ch cha in trR Bi tp v nh:Cho mch in gm ngun inc E= 12 V , r=3O mch ngoi c R1 ni tip vi on gm R2 song song R3. Tnh cng dng in chy trong ton mch , chy qua R2, R3, R1 . Hiu in th hai u mi in tr bit R2=3O , R3=, 4O,R1 =2O IV. Rt kinh nghim

Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 7 Ngy 25 thng 10 nm 2011 Tit 19.GHP CC NGUN IN THNH B I. MC TIU: 1. Kin thc + Nu c chiu dng in chy qua on mch cha ngun in. + Nhn bit c cc loi b ngun ni tip, song song, hn hp i xng. 2. K nng + Vn dng c nh lut m i vi on mch c cha ngun in, + Tnh c sut in ng v in tr trong ca cc loi b ngun ghp. 3. Thi : Kh nng p dng vo thc tin cuc sng kin thc hc c II. CHUN B: 1.Gio vin: + Bn pin c sut in ng 1,5V. + in k chng minh, mt s dy ni 2.Hc sinh: +Quan st cc qu pin khi lp trong n pin. III. TIN TRNH DY HC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) : Kim tra bi c :- Pht biu, vit biu thc nh lut m cho ton mch?- Vit biu thc tnh hiu in th mch ngoi,? - Cng sut tiu th trn mch ngoi v trn ton mch? Hot ng 2 ( 5 pht) :Tm hiu on mch c cha ngun in. Hot ng ca gio vin vhc sinhNi dung c bn GV gii thiu v ngun pht in v my thu: nh lut m cho on mch cha ngunin hnh 10.2a. - Ch cho hs vcch lydu ca s v gim in th I(r + R). - Yu cu hs hon thnh C3. GV:giithiuchoHSvonmchccha ngun in GV:Giithiucchnhnbitngunvbiu thc nh lut m. GV m rng thm cho on mch cha my thu v on mch cha c ngun, my thu I. on mch c cha ngun in: on mch c cha ngun in, dng in c chiu i ti cc m v i ra t cc dng. UAB = E I(r + R) Hay I = ABAB ABRU ER rU E =+ on mch cha my thu in: R rUIpp AB+= Tng qut: r RUIAB++=

+ Ngunin:>0:chiudngit cc m n cc dng. + Mythu:r2 im cn tm gnq2 v r1=2r20,25 im Nn ta c r1=6 cm0,25 im Cu 2: Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 19 a. Pm= Um.Im=2/dm dU R26dmddmURP = = O 1 im 212. 4.62, 6 54 6dABdR RR RR R= + = + = O+ +1 im b. 1835 1ABABEI AR r= = =+ +0,5 im 23dI I A + = 0,5 im 2232ddR II R= = 1, 2dI A =n sng qu mc bnh thng 1 im IV. Rt kinh nghim ............................................................................................................................................................. ............................................................................................................................................................. Ngy7 thng 11nm 2011 CHNG III. DNG IN TRONG CC MI TRNG Tit 25.DNG IN TRONG KIM LOI I. MC TIU 1. Kin thc: -Nuctnhchtinchungcacckimloi,sphthuccaintrsutca kim loi theo nhit . - Nu c ni dung chnh ca thuyt electron v tnh dn in ca kim loi v cng thc tnh in tr sut ca kim loi. Nu c cp ln ca cc i lng 2. K nng: - Gii thch c mt cch nh tnh cc tnh cht in chung ca kim loi da trn thuyt electron v tnh dn in ca kim loi. 3. Thi : -Yu thch b mn, nghim tc trong hc tp. 4. Trng tm: - Bn cht dng in trong kim loi II. CHUN B 1. Gio vin + Chun b th nghim m t trong sgk. + Chun b th nghim v cp nhit in. 2. Hc sinh+v tnh dn in ca kim loi trong sgk lp 9. + Dng in trong kim loi tun theo nh lut m. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2.Bimi:tvn:Chungtabitrngkimloicsdngdnin.Tisaokim loi c s dng rng ri nh vy? Bi hc ngy hm nay chng ta s gii thch iu ny. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 20 Hot ng 1 (15 pht) : Tm hiu bn cht ca dng in trong kim loi. Hot ng ca gio vin v hc sinhNi dung c bn -GV:Yu cu hc sinh nhc li mng tinh th kim loi v chuyn ng nhit ca n.+ Electron t do trong kim loi c hnh thnh nh th no? -HS:Nu mng tinh th kim loi v chuyn ng nhit ca cc ion nt mng xc nh s hnh thnh cc electron t do GV:Gii thiu cc electron t do trong kim loi v chuyn ng nhit ca chng. + t vo kim loi mt in trng, di tc dng ca in trng cc electron t do s chuyn ng nh th no? + Khi cc ht mang in chuyn ng c hng to ra dng in. Bn cht ca dng in trong kim loi? + Nguyn nhn gy ra in tr ca kim loi? GV b sung kin thc: Ngoi ra c s mo mng tinh th do bin dng c hc, s ln cc nguyn t l ca kim loi cn tr chuyn ng ca cc electron t do. - GV gii thch ti sao kim loi dn in tt. I. Bn cht ca dng in trong kim loi + Trong kim loi, cc nguyn t b mt electron ho tr tr thnh cc ion dng. Cc ion dng lin kt vi nhau mt cch c trt t to thnh mng tinh th kim loi. Cc ion dng dao ng nhit xung quanh nt mng. + Cc electron ho tr tch khi nguyn t thnh cc electron t do vi mt n khng i. Chng chuyn ng hn lon to thnh kh electron t do chon ton b th tch ca khi kim loi v khng sinh ra dng in no. + in trng Edo ngun in ngoi sinh ra, y kh electron tri ngc chiu in trng, to ra dng in. + S mt trt t ca mng tinh th cn tr chuyn ng ca electron t do, l nguyn nhn gy ra in tr ca kim loi Ht ti in trong kim loi l cc electron t do. Mt ca chng rt cao nn chng dn in rt tt.

Bn cht ca dng in trong kim loi:l dng chuyn di c hng ca cc electron t do di tc dng ca in trng( electron t do dch chuyn ngc chiu in trng) . Hot ng 2(5 pht) : Tm hiu s ph thuc ca in tr sut ca kim loi theo nhit . Hot ng ca gio vin v hc sinhNi dung c bn + in tr ca kim loi thay i nh th no khi nhit tng? Gii thch? GV:Gii thiu in tr sut ca kim loi v s ph thuc ca n vo nhit .GV: Gii thiu cc i lng trong biu thc, bng 13.1 v in tr sut ca mt s kim loi. II. S ph thuc ca in tr sut ca kim loi theo nhit in tr sut ca kim loi tng theo nhit gn ng theo hm bc nht : = 0(1 + o(t - t0)) Lu : H s nhit in tr khng nhng ph thuc vo nhit , m vo c sch v ch gia cng Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 21 GV:Yu cu hc sinh thc hin C1. ca vt liu . Hot ng 3 (10 pht) : Tm hiu in tr ca kim loi nhit thp v hin tng siu dn. Hot ng ca gio vin v hc sinhNi dung c bn GV:Yu cu hc sinh gii thch ti sao khi nhit gim th in tr kim loi gim.- HS tho lun gii thch s gimin tr kim loi theo nhit GV: Gii thiu hin tng siu dn. GV:Gii thiu cc ng dng ca hin tng siu dn. - HS c sgk tm hiu thm v hin tng siu dn GV:Yu cu hc sinh thc hin C2.III. in tr ca kim loi nhit thp v hin tng siu dn Khi nhit gim, in tr sut ca kim loi gim lin tc. n gn 00K, in tr ca kim loi sch u rt b. Mt s kim loi v hp kim, khi nhit thp hn mt nhit ti hn Tc th in tr sut t ngt gim xung bng 0. Ta ni rng cc vt liu y chuyn sang trng thi siu dn.

Hot ng 4 (10 pht) : Tm hiu hin tng nhit in. Hot ng ca gio vin v hc sinhNi dung c bn - Nu si dy kim loi c mt u nng v mt u lnh th cc electron t do s chuyn ng nh th no? -GV:Gii thiu th nghim hin tng nhit in.- HS:quan st hin tng xy ra v nhn xt kt qu. + Hin tng g xy ra khi tng chnh lch nhit cahai mi hn? - GV thng bo dng nhit in v sut in ng nhit in. - GV gii thch s hnh thnh sut in ng nhit in. + Hin tng nhit in l g? -GV gii thiu cng thc sut in ng nhit in. V mt s cp nhit in thng dng, ng dngIV. Hin tng nhit in Nu ly hai dy kim loi khc nhau v hn hai u vi nhau, mt mi hn gi nhit cao, mt mi hn gi nhit thp, th hiu in th gia u nng v u lnh ca tng dy khng ging nhau, trong mch c mt sut in ng E. E gi l sut in ng nhit in, v b hai dy dn hn hai u vo nhaugi l cp nhit in. Sut in ng nhit in : E = oT(T1 T2) Cp nhit in c dng ph bin o nhit . Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinhNi dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn hc trong bi.GV:Yu cu hc sinh v nh lm cc bi tp t 5 n 9 trang 78 sgkv 13.10, 13.11 sbt.HS:Ghi cc bi tp v nh.

IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 22 Ngy 9 thng 11 nm 2011 Tit 26. DNG IN TRONG CHT IN PHN I. MC TIU 1. Kin thc - Hiu c hin tng in phn, bn cht ca dng in trong cht in phn, phn ng ph trong hin tng in phn, hin tng dng cc tan - Tham gia thit k cc phng n th nghim v hin tng in phn 2. K nng - Rn luyn k nng logic ton hc xy dng cng thc vt l - Vn dng c kin thc gii thch cc ng dng c bn ca hin tng in phn- Quan st gio vin tin hnh th nghim t rt ra cc kt lun. 3. Thi - Nghim tc trong hc tp, quan st k cc hin tng xy ra II. CHUN B; 1. Gio vin + Chun b th nghim biu din cho hc sinh v dn in ca nc tinh khit (nc ct hoc nc ma), nc pha mui, v in phn. + Chun b bng h thng tun hon cc nguyn t ho hc tin dng khi lm bi tp. 2. Hc sinh: n li :+ Cc kin thc v dng in trong kim loi + Kin thc v ho hc, cu to cc axit, baz, v lin kt ion. Khi nim v ho tr. III. TIN TRNH DY HC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) :Kim tra bi c :Nu loi ht ti in trong kim loi, bn cht dng in trong kim loi, nguyn nhn gy ra in tr ca kim loi t vn : tng v p v chng g cho cc mn hng ngy bng kim loi ngi ta thng m mt lp kim loi tr nh vng, bc, niken ln b mt ca chng. lm c iu ngi ta p dng cng ngh in phn, vy cng ngh in phn l g? Hot ng 2(20 pht) : Tm hiu bn cht dng in trong cht in phn. Hot ng ca gio vin v hc sinhNi dung c bn + Nc ct v cc dung dch nhaxit, ba d, mui c dn in khng?. Hy thit k phng n th nghim kim tra - HS tho lun tm phng n th nghim kim tra: - Dng bnh thy tinh ng nc ct vi hai in cc, miliampe k, ngun in to thnh mch kn - GV tin hnh th nghim ln lt i vi nc ct, dung dchmui - HS quan st th nghim v rt ra nh xt s dn in ca nc ct, mui... Gi : Da vo iu kin c dng II. Bn cht dng in trong cht in phn: 1. Th nghim a, Th nghim 1: Nc ct khng dn in b, Th nghim 2 Dung dch NaCl dn in Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 23 Hot ng ca gio vin v hc sinhNi dung c bn in, thuyt in ly gii thch s dn in ca axit, bazo, mui + Ht ti in trong cht in phn l g? + Khi cha c in trng t vo cc ht ti in chuyn ng nh th no? + Khi c in trng cc ht ti in chuyn ng nh th no? - GV yu cu hc sinh nu bn cht dng in trong cht in phn. - GV: Yu cu hc sinh gii thch ti sao cht in phn khng dn in tt bng kim loi.- HS tho lun nhm so snh mt , s linh ng ca cc ht ti in trong cht in phn v kim loi gii thch kim loi dn in tt hn cht in phn. - GV: Gii thiu hin tng in phn. - HS tr li C1 2.Bn cht dng in trong cht in phn : L dng chuyn di c hng ca: + Ion dng cng chiu in trng + Ion m ngc chiu in trng Chuyen ong cua cac ion trong chat ien phan khi cha coien trng Na+ Na+ Cl- Cl - A Dung dch NaCl K Cl- Cl- Na+ Na+ E Chuyen ong cua cac ion trong chat ien phan khi coien trng Cht in phn khng dn in tt bng kim loi. Hot ng 4 (15 pht) : Tm hiu hin tng din ra in cc v hin tng dng cc tan. Hot ng ca gio vin v hc sinhNi dung c bn GV:Gii thiu phn ng ph trong hin tng in phn.+ Hin tng g s xy ra trn cc in cc ca th nghim trn nu ta s dng mui ng Sunphat v hai in cc bng ng ? - GV gi : Khi cc ion v ti cc in cc chng trao i in tch vi cc in cc nh th no? - HS tho lun nhm xc nh cc hin tng din ra cc in cc + catt xy ra phn ng:Cu2+ + 2e = Cu bm vo (K) + ant xy ra phn ng: III. Cc hin tng din ra in cc. Hin tng dng cc tan: Cl- Na+ e- A Hien tng cc dng tan K SO42- Cu2+ E SO42- Cu2+ Cu e- e-e- Dung dch CuSO4 Cc ion chuyn ng v cc in cc c th Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 24 Cu = 2e + Cu2+ i vo dung dch. Kt qu l (A) tan dn vo dung dch nn gi l hin tng dng cc tan GV: Tin hnh th nghim hin tng xy ra khi in phn dung dch mui ng vi ant bng ngHS:Theo di hiu c cc hin tng xy ra. GV:Gii thiu hin tng dng cc tan.GV b sung: Hin tng dng cc tan ch xy ra khi in phn dung dch mui c cc dng c lm bng kim loi ca chnh mui . - GV lu : Cc hin tng din ra Anotv Ktot trong bnh in phn ny l cng phn ng cn bng, in nng khng b tiu hao trong qu trnh phn tch cc cht, ch b tiu hao v ta nhit. Bnh in phn ng vai tr l in tr - GV yu cu hc sinh c sgk tm hiu thm v cc hin tng din ra cc in cc ( kh bay ln in cc...) tc dng vi cht lm in cc hoc vi dung mi to nn cc phn ng ho hc gi l phn ng ph trong hin tng in phn. iu kin xy ra dng cc tan: Hin tng dng cc tan xy ra in phn mui ca kim loi lm Anot 2. Hin tng kh bay ln in cc Hot ng5 : (5 pht)Cng c, giao nhim v v nh. Hot ng ca gio vinHot ng ca hc sinh GV:Cho hc sinh tm tt nhng kin thc c bn hc trong bi. GV:Yu cu hc sinh v nh lm cc bi tp trang 85 sgk HS:Tm tt nhng kin thc c bn. HS:Ghi cc bi tp v nh. IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 25 Ngy 12 thng 11 nm 2011 Tit 27. DNG IN TRONG CHT IN PHN I. MC TIU: 1. Kin thc + Pht biu c nh lut Faraday v in phn. + Nu c mt s ng dng ca hin tng in phn 2. K nng + Vn dng c kin thc gii thch cc ng dng c bn ca hin tng in phn v gii c cc bi tp c vn dng nh lut Faraday. II. CHUN B; 1. Gio vin + Chun b mt bng h thng tun hon cc nguyn t ho hc tin dng khi lm bi tp. 2. Hc sinh: + Cc kin thc v dng in trongcht in phn + Kin thc v ho hc, cu to cc axit, baz, v lin kt ion. Khi nim v ho tr. III. TIN TRNH DY HC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc 3 . Bi c: Bn cht ca dng in trong cht in phn?. Hin tng dng cc tan, iu kin xy ra dng cc tan?(3 pht) Hot ng 5 (25 pht) : Tm hiu cc nh lut Fa-ra-y. Hot ng ca gio vin v hc sinhNi dung c bn - GV nhc li th nghim in phn dung dch ng Sunfat vi in cc bng ng, c lng ng bm vo in cc Katot. Thay i thi gian in phn hoc thay i cng dng in qua bnh in phn th lng Cu bm vo cng thay i. GV: Lp lun a ra ni dung cc nh lut.HS:Nghe, kt hp vi xem sgk hiu.GV:Yu cu hc sinh thc hin C2.HS:Thc hin C2. GV:Gii thiu cc nh lut Fa-ra-y GV:Gii thiu s Fa-ra-y.HS: Ghi nhn s liu. GV:Yu cu hc sinh thc hin C3. IV. Cc nh lut Fa-ra-y: nh lut I Fa-ra-y + Ni dung: Khi lng m ca cht gii phng ra in cc ca bnh in phn t l vi in lng q chy qua bnh m= k.q k: ng lng in ho k= 1,118.10-6 kg/C b) nh lut II Fa-ra- y ng lng in ho K ca mt nguyn t t l vi dng lng gam A/n ca nguyn t Ak cn=c) Cng thc Fa- ra - y v in phn 1.Am qF n=hoc 1.Am ItF n=Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 26 GV:Yu cu hc sinh kt hp hai nh lut a ra cng thc Fa-ra-y.HS:Kt hp hai nh lut a ra cng thc Fa-ra-y. GV:Gii thiu n v ca m khi tnh theo cng thc trn. Hot ng 6 (12 pht) : Tm hiu cc ng dng ca hin tng in phn. Hot ng ca gio vin v hc sinhNi dung c bn GV:Gii thiu cc ng dng ca cc hin tng in phn. HS:Ghi nhn cc ng dng ca hin tng in phn. GV:Gii thiu cch luyn nhm. GV:Yu cu hc sinh nu cch ly bc (Ag) ra khi mt chic cc m bc b hng.HS: Nu cch ly bc (Ag) ra khi mt chic cc m bc b hng. GV:Gii thiu cch m in. GV:Yu cu hc sinh nu cch m vng mt chic nhn ng.HS:Nu cch m vng mt chic nhn ng. V. ng dng ca hin tng in phn: Hin tng in phn c nhiu ng dng trong thc t sn xut v i sng nh luyn nhm, tinh luyn ng, iu ch clo, xt, m in, c in,1. Luyn nhm: Da vo hin tng in phn qung nhm nng chy. B in phn c cc dng l qung nhm nng chy, cc m bng than, cht in phn l mui nhm nng chy, dng in chy qua khong 104A. 2. M in: B in phn c ant l mt tm kim loi m, catt l vt cn m. Cht in phn thng l dung dch mui kim loi m. Dng in qua b m c chn mt cch thch hp m bo cht lng ca lp m. Hot ng 7 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinhNi dung kin thc GV:Cho hc sinh tm tt nhng kin thc c bn hc trong bi. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp t 8 n 11 trang 85 sgkv 14.4, 14.6, 14.8 sbt. HS:Ghi cc bi tp v nh. IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 27 Ngy 16thng 11 nm 2011 Tit 28.BI TP I. MC TIU 1. Kin thc :+ Nm c bn cht dng in trong kim loi, nguyn nhn gy ra in tr ca kim loi, s ph thuc ca in tr ca kim loi vo nhit , hin tng siu dn v hin tng nhit in. + Nm c hin tng in li, bn cht dng in trong cht in phn, hin tng dng cc tan, cc nh lut Fa-ra-ay v cc ng dng ca hin tng in phn. 2. K nng : + Thc hin c cc cu hi lin quan n dng in trong kim loi v dng in trong cht in phn. + Gii c cc bi ton lin quan n dng in trong kim loi. + Gii c cc bi ton lin quan n nh lut Fa-ra-y. 3. Thi : + Tinh thn hot ng tp th + thc t chc k lut trong hc tp, hot ng nhm II. CHUN B Gio vin: + Xem, gii cc bi tp sgk v sch bi tp. + Chun b thm mt s cu hi trc nghim v bi tp khc. Hc sinh: + Gii cc cu hi trc nghim v bi tp thy c ra v nh. + Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (8 pht) : Kim tra bi c v tm tt nhng kin thc lin quan Bi c:- Bn cht ca dng in trong kim loi, cht in phn - S ph thuc ca in tr sut ca kim loi theo nhit - Hin tng nhit in, sut in ng nhit in? - nh lut Faraday + in tr sut ca kim loi tng theo nhit gn ng theo hm bc nht : = 0(1 + o(t - t0)) +Sut in ng nhit in : E = oT(T1 T2) + nh lut Faraday m = nAF.1It m l cht c gii phng in cc, tnh bng gam. Hot ng 2(15 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin, hc sinhNi dung c bn GV:Yu cu hs a ra p n v gii thch ti sao chn p n . HS: Gii thch la chn. Cu 5 trang 78 : B Cu 6 trang 78 : D Cu 8 trang 85 : C Cu 9 trang 85 : D Cu 14.4 : D Cu 14.6 : C Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 28 Hot ng 3 (20 pht) : Gii cc bi tp t lun. Hot ng ca gio vin , hc sinhNi dung c bn GV:Yu cu hc sinh tnh in tr ca bng n khi thp sng. HS:Tnh in tr ca bng n khi thp sng. GV:Yu cu hc sinh tnh in tr ca bng n khi khng thp sng. HS: Tnh in tr ca bng n khi khng thp sng. GV:Yu cu hc sinh tnh th tch ca 1mol ng. HS: Tnh th tch ca 1mol ng. GV:Yu cu hc sinh tnh mt electron trong ng. HS: Tnh mt electron trong ng. GV:Yu cu hc sinh tnh s electron qua tit din thng ca dy dn trong 1 giy v vit cng thc tnh cng dng in theo n. HS:Tnh s electron qua tit din thng ca dy dn trong 1 giy v vit cng thc tnh cng dng in theo n. GV: Cho hc sinh suy ra v tnh v.HS: Tnhtc tri ca electron. GV:Yu cu hc sinh tnh khi lng ng mun bc i.HS: Tnh khi lng ng mun bc i. GV:Yu cu hc sinh vit cng thc Fa-ra-y.HS: Vit cng thc Fa-ra-y. GV:Cho hc sinh suy ra v tnh t. HS:Tnh thi gian in phn. Bi 7 trang 78 in tr ca dn khi thp sng R = 1002202 2=PU = 484(O) in tr ca n khi khng thp sng Ta c : R = R0(1 + o(t t0)) R0 = ) ( 10t tR +o = ) 20 2000 ( 10 . 5 , 4 14843 += 49(O) Bi 8trang 78 a) Th tch ca 1 mol ng V = 3310 . 9 , 810 . 64=DA = 7,2.10-6(m3/mol) Mt electron t do trong ng n = 62310 . 2 , 710 . 023 , 6=VNA = 8,4.1028(m-3) b) S electron t do qua tit din thng ca dy dn trong 1 giy: N = vSn Cng dng in qua dy dn: I = eN = evSn=> v = 28 5 1910 . 4 , 8 . 10 . 10 . 6 , 110 =eSnI = 7,46.10-5(m/s)

Bi 11 trang 85 Khi lng ng mun bc i m = V = dS = 8,9.103.10-5.10-4

= 8,9.10-6(kg) = 8,9.10-3(g) M m = nAF.1.Itt = 2310 . 642 . 96500 . 10 . 9 , 8.. .=I An F m

= 2680(s) Hot ng 4: (2 pht) Cng c dn d:-Nhc hc sinh xem li cc bi tp cha. -Hs xem trc bi mi. IV. Rt kinh nghim ............................................................................................................................................................. ............................................................................................................................................................. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 29 Ngy 19 thng 11 nm 2011 Tit 29 DNG IN TRONG CHT KH I. MC TIU: 1. Kin thc + Phn bit c s dn in khng t lc v dn in t lc trong cht kh. + Hs hiu c mi trng cht kh khng c ht ti in v cch a cc ht ti in vo mi trng . + Gii thch c ng c tuyn V Aca qu trnh dn in khng t lc ca cht kh. S dn in ca cht kh trong iu kin thng. + Nm c bn cht dng in trong cht kh. 2. K nng + Quan st hin tng rt ra nhn xt 3. Thi + Tp trung ch , s tinh t trong quan st II. CHUN B 1. Gio vin:- Chun b th nghim 15.1 - Hnh v 15.2 a,b,c . 2. Hc sinh: n li khi nim dng in trong cc mi trng, l dng cc in tch chuyn ng c hng. III. TIN TRNH DY HC: 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) : Kim tra bi c : Nu loi ht ti in trong cht in phn, nguyn nhn to ra chng v bn cht ca dng in trong cht in phn. Hot ng 2 (8 pht) : Tm hiu tnh cch in ca cht kh. Hot ng ca gio vin v hc sinhNi dung c bn GV: Yu cu hc sinh nu c s khng nh cht kh l mi trng cch in. HS:Gii thch ti sao cht kh l mi trng cch in. GV: Yu cu hc sinh thc hin C1.HS: Thc hin C1. I. Cht kh l mi trng cch in Cht kh khng dn in v cc phn t kh u trng thi trung ho in, do trong cht kh khng c cc ht ti in. Hot ng 3(7 pht) : Tm hiu s dn in trong cht kh trong iu kin thng. Hot ng ca gio vin v hc sinhNi dung c bn *Gio vin nhn mnh: iu kin bnh thng khng kh khng dn in v mt httiintrongchtkhrtnh, xem nh khng ng k. Vy c dng in trong cht kh, ngha l phi c in tch t do th phi cn mt c mt c ch g? - GV: V hnh 15.2 gii thiu cc dng II. S dn in trong cht kh trong iu kin thng Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 30 c, cng dng ca chng trong hnh v - GV:Trnh by th nghim hnh 15.2 - HS:ch quan st lng nghe v ghi nhn cc kt qu th nghim. + Ban du cht kh c ht ti in t do khng? + Khi c ngn la chiu vo dng in trong cht kh tng ln iu chng t iu g? + Tia t ngoi c tc dng nh n ga khng? + Vai tr ca ngn la v n thy ngn?( lm xut hin cc ht ti in trong cht kh) + iu kin bnh thng: khng c dng in. + Kh b t nng, chiu ngn n thy ngn...: c dng in. Hot ng 4 (20 pht) : Tm hiu bn cht dng in trong cht kh. Hot ng ca gio vin v hc sinhNi dung c bn * GV nhn mnh: Cc tc ng nh n thy ngn, ngn la ng vai tr to ra ht ti in trong cht kh, l nhng ht no, c ch to ra ht in ? -GV:Gii thiu tc nhn ion ho v s ion ho cht kh. -HS:Ghi nhn khi nim. -GV:Yu cu hc sinh nu hin tng xy ra i vi khi kh b ion ho khi cha c v khi c in trng. -HS:Nu hin tng xy ra i vi khi kh b ion ho khi cha c v khi c in trng. +Bn cht dng in trong cht kh ? - HS tho lun nhm nu bn cht dng in trong cht kh. + Hin tng g xy ra i vi khi kh khi mt tc nhn ion ha? - HS:Nu hin tng xy ra trong khi kh khi mt tc nhn ion ho. - GV Phn tch cho hs hiu th no l qu trnh dn in khng t lc. GV:Gii thiu ng c trng V A ca dng in trong cht kh. - M t ng c trng V A ca dng III. Bn cht dng in trong cht kh 1. S ion ho cht kh v tc nhn ion ho e- e- e- e- a) b) c)d) Sion hoa chat kh vastai hp - Nhng tc ng bn ngoi lm xut hin cc ht ti in gi l tc nhn ion ha - Qu trnh bin cc nguyn t, phn t trung ha thnh cc ion gi l s ion ha b. Bn cht ca dng in trong cht kh: l dng chuyn di c hng + Cc ion dng theo chiu in trng + Cc ion m ngc chiu in trng. 2. Qu trnh dn in khng t lc ca cht kh + Qu trnh dn in ca cht kh nh c tc nhn ion ho gi l qu trnh dn in khng t lc. + N ch tn ti khi ta to ra ht ti in trong khi kh gia hai bn cc v bin mt khi ta ngng vic to ra ht ti in. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 31 in trong cht kh? GV:Yu cu hc sinh thc hin C3. GV:Yu cu hc sinh gii thch ti sao dng in trong cht kh khng tun theo nh lut m. - HS Kt hp SGK v s hng dn ca GV phn tch hnh 15.4 SGK. +Qu trnh dn din khng t lc khng tun theo nh lut m. O UC Ibh UbU (V) I (A) ac tuyen Von Ampecua chat kh Hot ng 8 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vinHot ng ca hc sinh GV: Cho hc sinh tm tt nhng kin thc c bn hc trong bi. HS:Tm tt nhng kin thc c bn. GV: Yu cu hs c bi nh (tit sau) HS: Ghi nh. - So snh dng in trong kim loi, dng in trong cht kh (ht ti in, dng in ) - c trc v tm hiu v qu trnh dn in t lc ca cht kh ( tia la in, h quang in) IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 32 Ngy 23 thng 11 nm 2011 Tit 30DNG IN TRONG CHT KH I. MC TIU: 1. Kin thc: - Nu c cch to ra ht ti in trong qu trnh dn in t lc. - Tr li c cu hi tia la in l g? iu kin to ra tia la in v ng dng. - Bit c hin tng h quang in. iu kin to ra h quang in v ng dng. 2. K nng: - Nhn ra hin tng phng in trong cht kh. - Phn bit c tia la in v h quang in. 3. Thi : - Rn kh nng t duy, so snh vi dng in, cht in phn. II. CHUN B 1. Gio vin: Chun b cc thit b th nghim lm cc th nghim. 2. Hc sinh: n li khi nim dng in trong cc mi trng, l dng cc in tch chuyn ng c hng. III. TIN TRNH DY HC: 1. Kim tra s s v n nh lp - Bn cht ca dng in trong cht kh? - Qu trnh dn in khng t lc ca cht kh? 2. Ni dung bi hc Tit 2 Hot ng 5 (15 pht) : Tm hiu qu trnh dn in t lc trong cht kh. Hot ng ca gio vin v hc sinhNi dung c bn GV: Gii thiu qu trnh phng in t lc. HS:Ghi nhn khi nim. GV:Gii thiu cc cch chnh dng in c th to ra ht ti in mi trong cht kh. HS:Ghi nhn cc cch dng in c th to ra ht ti in mi trong cht kh. IV. Qu trnh dn in t lc trong cht kh v iu kin to ra qu trnh dn in t lc Qu trnh phng in t lc trong cht kh l qu trnh phng in vn tip tc gi c khi khng cn tc nhn ion ho tc ng t bn ngoi. Hot ng 6 (15 pht) : Tm hiu tia la in v iu kin to ra tia la in. Hot ng ca gio vin v hc sinhNi dung c bn GV: Gii thiu th nghim v mt s hnh nh v tia la in. -YucuhscSGKmcVvcho bit: tia la in l g?- c im ca tia la in? - HS Kt hp SGK v s hng dn ca GVtngktiukinctiala in. V. Tia la in v iu kin to ra tia la in 1. nh ngha Tia la in l qu trnh phng in t lc trong cht kh t gia hai in cc khi in trng mnh bin phn t kh trung ho thnh ion dng v electron t do. 2. iu kin to ra tia la in Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 33 GV gii thiu bng15.1 v hiu in th gia hai cc pht sinh tia la in - GV gii thiu mt s ng dung ca tia la in. + Gii thch hin tng st ( Khi c cn ging, cc m my gn mt t tch in m v mt t tch in dng. Gia m my v mt t hnh thnh hiu in th ln = c s phng in) - GV gii thch thm v ting sm, st. Hiu in th U(V) Khong cch gia 2 cc (mm) Cc phng Mi nhn 20 0006,115,5 40 00013,745,5 100 00036,7220 00 00075,3410 300 0001146 0 3. ng dng Dng t hn hp xng khng kh trong ng c xng. Gii thch hin tng st trong t nhin. Hot ng 7(10 pht) : Tm hiu h quang in v iu kin to ra h quang in. Hot ng ca gio vin v hc sinhNi dung c bn - GV:Cho hc sinhm t vic hn in. HS:M t vic hn in. GV:Gii thiu phim v mt s hnh nh h quang in. GV:Yu cu hs nu cc hin tng km theo khi c h quang.in. HS:theo di on phim v xc nh cc hin tng km theo khi c h quang.in. GV:Gii thiu iu kin c h quang in. GV:Yu cu hc sinh nu cc ng dng ca h quang in. HS:Nu cc ng dng ca h quang in. VI. H quang in v iu kin to ra h quang in 1. nh ngha H quang in l qu trnh phng in t lc xy ra trong cht kh p sut thng hoc p sut thp t gia hai in cc c hiu in th khng ln. H quang in c th kn theo to nhin v to sng rt mnh. 2. iu kin to ra h quang in Dng in qua cht kh gi c nhit cao ca catt catt pht c electron bng hin tng pht x nhit electron. 3. ng dng H quang din c nhiu ng dng nh hn in, lm n chiu sng, un chy vt liu, Hot ng 8 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vinHot ng ca hc sinh GV:Cho hc sinh tm tt nhng kin thc c bn hc trong bi. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp t 6 n 9 trang 93 sgk. HS:Ghi cc bi tp v nh. - So snh tia la in v h quang in? - iu kin xy ra tia la in, h quang in? IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 34 Ngy 24thng 11 nm 2011 Tit 31 DNG IN TRONG CHT BN DN I. MC TIU 1. Kin thc: - Nm c cc khi nim ca cht bn dn, c im cht bn dn - Cc ht ti in trong cht bn dn. - C ch to thnh ht ti in (electron t do v l trng) trong bn dn tinh khit v bn . dn pha tp - Qu trnh hnh thnh lp tip xc. 2. Knng: - So snh bn cht dng in trong cc mi trng hc. 3. Thi : -Yu thch b mn. 4. Trng tm - Cc ht ti in trong bn dn ( electron t do v l trng) II. CHUN B 1. Gio vin:+ Chun b hnh 17.1, 17.2, 17.3, 17.4, 17.5 v bng 17.1 sgk ra giy to. +Chunbmtslinhkinbndnthngdngnhitbndn,tranzito,LED,Nu c linh kin hng th bc v ra ch cho hc sinh xem ming bn dn linh kin y. 2. Hc sinh: n tp cc kin thc quan trng chnh: + Thuyt electron v tnh dn in ca kim loi. +Vithngsquantrngcakimloinhintrsut,hsnhitintr,mt electron t do. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Tit 1 Hot ng 1 (5 pht) : Kim tra bi c :- Dng in trong kim loi, cht in phn, cht kh? -i lng c trng cho tnh dn in ca cc cht? t vn : Cc linh kin bn dn nh ddiot, tranzito... c mt trong cc thit b in t, trong khoa hc k thut..Chng c cu to t cc cht bn dn. Vy cht bn dn c tnh cht g c bit? Hot ng 2 (15 pht) :Tm hiu cht bn dn v tnh cht. Hot ng ca gio vin v hc sinh Ni dung c bn - GV yu cu hc sinh c sgk tm hiu tnh cht ca cht bn dn. + So snh in tr sut ca bn dn vi in tr sut ca kim loi, in mi + in tr ca bn dn thay i nh th no khi thay i nhit ca bn dn? HS: Cho bit ti sao c nhng cht c gi l bn dn. GV:Gii thiu mt s bn dn thng I. Cht bn dn v tnh cht Cht bn dn l cht c in tr sut nm trong khong trung gian gia kim loi v cht in mi. + nhit thp, in tr sut ca cht bn dn siu tinh khit rt ln. Khi nhit tng, in tr sut gim nhanh, h s nhit in tr c gi tr m. + in tr sut ca cht bn dn gim rt mnh khi pha mt t tp cht. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 35 dng. GV:Gii thiu cc c im ca bn dn tinh khit v bn dn c pha tp cht. + in tr ca bn dn gim ng k khi b chiu sng hoc b tc dng ca cc tc nhn ion ha khc. T p O Ban danKim loaiien trsuat cua kim loai vaban dan phuthuoc khac nhau vao nhiet o Hot ng 3 (20 pht) : Tm hiu ht ti in trong cht bn dn, bn dn loi n v bn dn loi p. Hot ng ca gio vin vhc sinhNi dung c bn + Mun xc nh ht ti in trong bn dn mang in tch g ta lm nh th no? - GV:Gii thiu bn dn loi n v bn dn loi p. GV:Gii thiu s hnh thnh electron dn v l trng trong bn dn tinh khit. + Hy cho bit s lin kt ca cc nguyn t Si trong mng tinh th? Gi : + Nguyn t Si ha tr bng bao nhiu? + Xung quanh tn ti bao nhiu nguyn t lin kt? + Tnh bn vng ca cc nguyn t Si trong mng tinh th? + nhit thp, trong mng tinh th c ht ti in t do khng? + Mun c ht ti in t do trong mng tinh th ca bn dn tinh khit phi lm th no?( cung cp nng lng cho cc electron di dng nhit nng) + Khi ht ti in trong mng tinh th l ht no? - HS c sgk kt hp tho lun nhm tr li cc cu hi. - HS theo di s hnh v v thuyt ging ca Gv tm hiu s hnh thnh cc electron t do v l trng. - GV b sung thm mt s kin thc v l trng. + Khi t vo bn dn mt in trng, II. Ht ti in trong cht bn dn, bn dn loi n v bn dn loi p 1. Bn dn loi n v bn dn loi p Bn dn c ht ti in m gi l bn dn loi n. Bn dn c ht ti in dng gi l bn dn loi p. 2. Electron v l trng Cht bn dn c hai loi ht ti in l electron v l trng.Dng in trong bn dn l dng cc electron dn chuyn ng ngc chiu in trng v dng cc l trng chuyn ng cng chiu in trng. Tinh theSi nhiet orat thap th khong cohat mang dien tdo SiSi SiSi Tap chat P tao them electron SiSi P+ Si el ectron tdo Tap chat B taothem lo trong SiSi B- Si Lo trong Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 36 electron v l trng s chuyn ng th no? - GV:Yu cu hc sinh nu bn cht dng in trong bn dn tinh khit. - GV:Gii thiu tp cht cho v s hnh thnh bn dn loi n. GV:Yu cu hc sinh gii thch s to nn electron dn ca bn dn loi n. GV:Gii thiu tp cht nhn v s hnh thnh bn dn loi p. + Ht ti in c bn trong bn dn loi n v bn dn loi p? GV:Yu cu hc sinh thc hin C1. 3. Tp cht cho (no) v tp cht nhn (axepto) + Khi pha tp cht l nhng nguyn t c nm electron ha tr vo trong tinh th silic th mi nguyn t tp cht ny cho tinh th mt electron dn. Ta gi chng l tp cht cho hay no. Bn dn c pha no l bn dn loi n, ht ti in ch yu l electron. + Khi pha tp cht l nhng nguyn t c ba electron ha tr vo trong tinh th silic th mi nguyn t tp cht ny nhn mt electron lin kt v sinh ra mt l trng, nn c gi l tp cht nhn hay axepto. Bn dn c pha axepto l bn n loi p, ht ti in ch yu l cc l trng. Hot ng 4 (5 pht)Cng c v vn dng GV yu cu hc sinh nhc li : + Tnh cht ca bn dn + Cc ht ti in trong bn dn tinh khit? + So snh bn dn loi n vi bn dn loi p ? ( electron t do, l trng) + Dng in trong cht bn dn? Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 37 Ngy 28thng 11 nm 2011 Tit 32DNG IN TRONG CHT BN DN I. MC TIU1. V kin thc - Nm c lp chuyn tip l g v s hnh thnh lp chuyn tip P-N - Nu c c im c bn ca dng in chy qua lp chuyn tip P-N - Nm c cu to v hot ng ca cc linh kin bn dn . 2.V k nng - Rn luyn cho hc sinh k nng nhn bit v c th thay th lp t mt s mch bn dn n gin trong cc thit b c s dng bn dn trong phng th nghim cng nh trong gia nh. II. CHUN B 1. GV: Hnh v lp chuyn tip P-N, th c tuyn Vn- Ampe ca iot bn dn 2. HS: Nm kin thc v dng in trong cht bn dn, cc loi ht ti in III. HOT NG DY HC 1. n nh lp 2. Kim tra bi c (5 pht) Tnh cht ca cht bn dn, cc loi bn dn v cc ht mang in c bn trong mi loi? 3. Bi mi Hot ng 1 (25 pht) :Tm hiu lp chuyn tip p-n. Hot ng ca gio vin v hc sinhNi dung c bn + Hin tng g s xy ra khi cho hai mu bn dn loi n v bn dn loi p tip xc vi nhau? -Hcsinhlmvictheonhm,tholun trlicuhitheoyucucagio vin. - GV gii thiu lp chuyn tip P-N Gi : + Khi tip xc, l trng ca bn dn loi p v electron ca bn dn loi n chuyn ng nh th no? + Electron ca bn dn loi p v l trngca bn dn loi n chuyn ng nh th no? - HS da vo s tng tc gia cc in tch gii tch ti sao lp chuyn tip p-n c rt t cc ht ti in. *Giovinnhnmnh:Lpkhngcht tiinchtipxcgillpngho. in tr ca lp ngho rt ln. - GV:Yu cu hc sinh thc hin C2. * Nu t mt in trngc chiu t bn dnloipsangbndnlointhintr III. Lp chuyn tip p-n Lp chuyn tip p-n l ch tip xc ca min mang tnh dn p v min mang tnh dn n c to ra trn 1 tinh th bn dn. 1. Lp ngho lp chuyn tip p-n khng c hoc c rt t cc ht ti in, gi l lp ngho. lp ngho, v pha bn dn n c cc ion no tch in dng v v pha bn dn p c cc ion axepto tch in m. in tr ca lp ngho rt ln.

p n Lp chuyen tiep p n mac vao nguon ien theo chieu thuanEt En 2. Dng in chy qua lp ngho Dng din chy qua lp ngho ch yu t p sang n. Ta gi dng in qua lp ngho t p sang n l chiu thun, chiu t n sang p l chiu ngc. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 38 ca lp ngho thay i nh th no? + Lp ngho c dn in khng? +Nucthdngincchiunhth no? * Gio vin nhnmnh: Ngi ta gi dng incchiutpsangnldngin thun.- GV:Gii thiu v hng dn hc sinh gii thch s dn in ch yu theo mt chiu ca lp chuyn tip p-n. - HS tho lun nhm di s hng dn ca gio vin nm bt s dn in mt chiu ca lp chuyn tip P-N GV: Gii thiu hin tng phun ht ti in3. Hin tng phun ht ti in Khi dng in i qua lp chuyn tip p-n theo chiu thun, cc ht ti in i vo lp ngho c th i tip sang min i din. s phun ht ti in. Hot ng 2 (10 pht) : Tm hiu it bn dn v mch chnh lu dng it bn dn. Hot ng ca gio vin v hc sinhNi dung c bn + Lm th no thit k mt thit b in chnh lu dng in xoay chiu thnh dng in mt chiu? - HS tho lun a ra phng n da vo tnh dn in mt chiu ca lp chuyn tip P-N. - Gio vin gi :+Trongmtchukcadnginxoay chiuthmtnachuksaudnginc chiu ngc vi chiuca dng introng na chu k u?.+Munchnhludnginxoaychiu cn phi c thit b ch cho dng in chy quatrongmtnachuk,nachukcn li khng cho dng in chy qua? -Gio vin nhn mnh: * Thit b c cu to l mt lp tip xc pncgildiodebndn.Ngita sdngmtdiodebndnchnhlu mtnachukcadnginxoaychiu thnh dng in mt chiu.Ngoi ra ngi ta cn dng diode bn dn chnhluhainachukcadngin xoay chiu thnh dng in mt chiu. HS:Xem hnh 17.7. Ghi nhn hot ng chnh lu ca mch. IV. it bn dn v mch chnh lu dng it bn dn it bn dn thc cht l mt lp chuyn tip p-n. N ch cho dng in i qua theo chiu t p sang n. Ta ni it bn dn c tnh chnh lu. N c dng lp mch chnh lu, bin in xoay chiu thnh in mt chiu.

Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 39 Hot ng 3 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinhNi dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn hc trong bi. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh thc hin cc cu hi lm cc bi tptrang 6, 7 sgk. HS:Ghi cc bi tp v nh. Bi tp v nh- Tr li cc cu hi v lm cc bi tp SGK. - c thm mc em c bit trang 107. - Chun b bo co th nghim theo mu cho sn cui bi thc hnh - Ht ti in trong cht bn dn: electron t do v l trng - Bn dn loi n cha ht ti in ch yu l electron, bn dn loi p cha ht ti in ch yu l l trng - Lp chuyn tip P-N l ch tip xc gia hai min mang tnh dn in p v n trn mt tinh th bn dn. Dng in ch chy qua c lp chuyntip P-N theo chiu t P sang N nn lp chuyn tip P-N c dng l it bn dn chnh lu dng in xoay chiu. - Mt s ng dng ca bn dn: it IV. Rt kinh nghim ............................................................................................................................................................. ............................................................................................................................................................. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 40 Ngy 30thng 11 nm 2011 Tit 33.BI TP I. MC TIU 1. Kin thc : + Nm c bn cht dng in trong cht kh, s dn in khng t lc v t lc, cc hin tng phng in trong cht kh. + Nm c bn cht ca dng in trong cht bn dn, hai loi bn dn n v p, cng dng ca it bn dn v trandio. 2. K nng : Gii c cc cu hi trc nghim v bi tp lin quan n dng in trong cht kh v trong cht bn dn. II. CHUN B 1.Gio vin: - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm mt s cu hi trc nghim v bi tp khc.2. Hc sinh: - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) : Kim tra bi c: Lp bng so snh dng in trong cc mi trng v: ht ti in, nguyn nhn to ra ht ti in, bn cht dng in. Hot ng 2(10 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin vhc sinhNi dung c bn GV:Yu cu hs gii thch ti sao chn D. HS:Gii thch la chn. Cu 6 trang 93 : D Cu 7 trang 93 : B Cu 6 trang 106 : D Cu 7 trang 106 : D Hot ng 3 (25 pht) :Gii cc bi tp t lun. Hot ng ca gio vin v hc sinhNi dung c bn - GV yu cu tm tt bi - GV lu trong thc t, dng in cc khng ng l cc phng hay l mi nhn. V vy ta tnh hiu in th l trung bnh cng ca trng hp hai cc phng v hai cc mi nhn. - HS hot ng c nhn xem bng 15.1 sgk tnh ton - GV hng dn hc sinh xc nh hiu in th nh la ca Bugi xe my khi chy bnh thng. (tia la in di khong 5mm l c) - HS tho lun theo nhm xc nh hiu in th hai cc Bugi. Bi 8 trang 93 a, - Nu ngn cy v m my u c xem l mi nhn: U1 = 7300000.1909, 5.100, 6V =- Nu ngn cy v m my u c xem l mt phng : U2 = 8300000.1905.100,114V = Nh vy U vo khong 108 V b, Khi th xem b in ca xe my c tt khng ngi th thng cho phng in t dy in (mi nhn) - ra v my( mt phng). Tia la in di khong 5mm l c - Trng hp hai mi nhn: U1 = 20000.5645015, 5V =Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 41 - GV hng dn hc sinh tm khong cch gn nht khi ng gn dy in cao th 120kV cn an ton

- GV khuyn co khng c ng gn dy in cao th. Phi ng cch ng dy in cao th mt khong ln hn 0,35m - Trng hp hai cc phng U2 = 20000.1901640061V = Nh vy U vo khong 108 V C, Trng hp dy cao th 120kV hiu in th ln nht c th n 170V. V dy tiu chun nn ly trng hp hai cc l mi nhn d = 170000.0, 410, 35200000m =Hot ng4:( 5 pht)Cng c dn d:-Nhc hc sinh xem li cc bi tp cha. - Hs xem trc bi mi. IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 42 Ngy 4thng 12 nm 2011 Tit 34. THC HNH: KHO ST C TNH CHNH LU CAIT BN DN V C TNH KHUCH I CA TRANZITO I. MC TIU 1. Kin thc + Bit c cu to ca it bn dn v gii thch c tc dng chnh lu dng in ca n. + Bit cch kho st c tnh chnh lu dng in ca it bn dn. T nh gi c tc dng chnh lu ca it bn dn. 2. K nng + Bit cch la chn, s dng cc dng c in, cc linh kin in thch hp v mc chng thnh mt mch in tin hnh kho st c tnh chnh lu dng in ca it bn dn + Bit cch o v ghi kt qu o lp bng s liu hoc v th biu din c tnh chnh lu dng in ca it bn dn v c tnh khuch i dng ca tranzito. 3. Thi :S say m tm hiu vt l, thc t gic tinh thn hc tp nhm II. CHUN B 1. Gio vin + Ph bin cho hc sinh nhng ni dung cn phi chun b trc bui thc hnh. + Kim tra cc dng c th nghim cn thit cho bi thc hnh. Lm th trc cc ni dung thc hnh. 2. Hc sinh: +c k ni dung bi thc hnh. + Chun b bo co th nghim theo mu cho sn cui bi thc hnh. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Tit 1 A. KHO ST C TNH CHNH LU CA IT BN DN Hot ng 1 (10 pht) : Tm hiu c s l thuyt. + Gio vin gi hc sinh nu tnh cht c bit ca lp tip xc n-p ca cht bn dn v nu nhn xt. + Mt hc sinh khc nhn xt mi quan h gia U v I khi s dng it thun v it ngc v d on th U(I) trong hai trng hp. Hot ng 2 (10 pht) : Gii thiu dng c o. + Gii thiu cch s dng ng h a nng hin s. + Gii thiu cc dng c th nghim trn hnh v 18.3; 18.4 sgk. Hot ng 3 (25 pht) : Tin hnh th nghim. Hot ng ca gio vinHot ng ca hc sinh 1. Kho st dng in thun chy qua it Hng dn cch mc mch in nh hnh 18.3 sgk (ch cch t thang o ca ampe k v vn k). Theo di, hng dn, kim tra vic lp rp ca hs. Theo gii cc ng tc, phng php lp rp th nghim ca thy c. Lp rp th nghim theo nhm. Cho mch hot ng, c v ghi s liu vo bng s liu 18.1 sgk chun b sn. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 43 Yu cu hc sinh cho mch hot ng, c v ghi s liu vo bng s liu 18.1 chun b. 2. Kho st dng in ngc chy qua it Hng dn cch mc mch in nh hnh 18.4 sgk (ch cch t thang o ca ampe k v vn k). Theo gii, hng dn, kim tra vic lp rp ca hs. Yu cu hc sinh cho mch hot ng, c v ghi s liu vo bng s liu 18.1 chun b. Theo gii cc ng tc, phng php lp rp th nghim ca thy c. Lp rp th nghim theo nhm. Cho mch hot ng, c v ghi s liu vo bu liu 18.1 sgk chun b sn. IV. Rt kinh nghim ............................................................................................................................................................. ............................................................................................................................................................. Ngy 5thng 12 nm 2011 Tit 35 A. KHO ST TNH KHUCH I CA TRANZITO Hot ng 1 (10 pht) : Tm hiu c s l thuyt. + Gio vin gi hc sinh nu tnh cht c bit ca lp tip xc n-p-N ca cht bn dn v nu nhn xt. + Mt hc sinh khc nhn xt v cch phn cc cho tranzito (hnh 18.7). + Gii thiu cc dng c th nghim trn hnh v 18.8 sgk.Hot ng 2 (20 pht) :Tin hnh th nghim. Hot ng ca gio vinHot ng ca hc sinh Hng dn cho hc sinh cch mc tranzito v cc thit b khc theo s hnh 18.8 sgk. Lu hc sinh cch mc ngun, in tr, bin tr. Theo di, kim tra cch mc ca cc nhm. Hng dn hc sinh thc hin C5. Hng dn hc sinh tin hnh bn bc Mc s 18.8 theo s hng dn ca thy c. Ch : V tr ca b ngun 6V mt chiu, mc bin tr theo kiu phn p, mc ng cc v tr ca cc microampe k A1, A2. Thc hin C5 Thc hin cc bc th nghim theo sgk v hng dn ca thy c. c v ghi cc s liu vo bng s liu 18.2. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 44 th nghim nh sch gio khoa. Yu cu hc sinh c v ghi s liu vo bng. Hot ng 3 (15 pht):Bo co th nghim. Hot ng ca gio vinHot ng ca hc sinh Hng dn mi hc sinh lm mt bng bo co ghi y cc mc: + H, tn, lp + Mc tiu th nghim + C s l thuyt + Cch tin hnh + Kt qu + Nhn xt Lm bng bo co y cc mc theo hng dn ca thy c. Phn kt qu ghi y s kiu v tnh ton vo cc bng nh cc trang 113, 114. Nhn xt v: chnh xc, nguyn nhn, cch khc phc. Thc hin phn nhn xt v kt lun. IV. Rt kinh nghim ............................................................................................................................................................. ............................................................................................................................................................. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 45 Ngy 19thng 12 nm 2011 Tit 37.KIM TRA HC K I (Kim tra hc k thi chung)

I. MC TIU 1Kinthc:Kimtramcnmbtkinthcvvndngkinthccahstrong chng IV v chng V 2.K nng: Rn luyn k nng t duy ,k nng tnh ton. 3.Thi :Rn luyn thi nghim tctrong kim tra II. CHUN B Gio vin: + Mt kim tra . + Mt p n v biu im Hc sinh: n li ni dung 2 chng IV v V. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 46 Ngy 21 thng 12 nm 2011 CHNG IV. T TRNG Tit 38. T TRNG I. MC TIU 1. Kin thc + Bit c t trng l g v nu ln c nhng vt no gy ra t trng. + Bit cch pht hin s tn ti ca t trng trong nhng trng hp thng thng. + Nu c cch xc nh phng v chiu ca t trng ti mt im. + Pht biu c nh ngha v nu c bn tnh cht c bn ca ng sc t. 2. K Nng + Xc nh chiu cc ng sc t ca: dng in chy trong dy dn thng di, dng in chy trong dy dn un thnh vng trn. + Xc nh mt Nam hay mt Bc ca mt dng in chy trong mch kn. + Quan st th nghim v nhn xt, phn tch tng hp. II. CHUN B Gio vin: Chun b cc th nghim chng minh v: tng tc t, t ph: nam chm thng, bin th hc sinh Hc sinh: n li phn t trng Vt l lp 9. III. HOT NG DYHC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1:Gii thiu chng trnh hc k II v nhng ni dung s nghin cu trong chng T trng. (5 pht) Hot ng 2 :(10 pht) Tm hiu nam chm. Tm hiu t tnh ca dy dn c dng in. Hot ng ca gio vin v hc sinhNi dung c bn - GV gii thiu v nam chm. - Yu cuthc hin C1. -Nucimcanamchm(niv cc cc ca n)? - GV lu s cc ca Nam chm lun l s chn. - GV gii thiu lc t, t tnh. -GV:LnlttinhnhTNgianam chm vi nam chm, gia nam chm vi dnginvgiadnginvidng in. -HSquanst,tholun(2HS)vnhn xt hin tng ? - GV: t cu hi: Cc em c nhn xt g v bn cht ca cc tng tc trong ba th nghim trn? (GV gi HS thy rng cc tng tc kia c cng bn cht, l tng tc t, I. Nam chm +Loivtliucthhtcstvngil nam chm. + Mi nam chm c hai cc: bc v nam. + Cc cc cng tn ca nam chm y nhau, cc cc khc tn ht nhau. Lc tng tc gia cc nam chm gi l lc t v cc nam chm c t tnh. II. T tnh ca dy dn c dng in + Gia nam chm vi nam chm, gia nam chm vidngin,giadnginvidnginc s tng tc t.= Dng in v nam chm c t tnh. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 47 Hot ng 3: ( 10 pht)Tm hiu t trng. Hot ng ca gio vin vhc sinhNi dung c bn -GVaracuhigigiphc sinh suy lun: +Mtvtgyralchpdnth xungquanhvtctrnghpdn, mtvtgyralcinthxungquanh vtcintrng.Theoccem xungquanhmtvtgyralctth sao? -GVnhnxtsuyluncaHS,khng nh suy lun ng -GVluchoHSrngnamchmv dng in u gy ra lc t,- HS a ra kt lun v s tn ti ca t trngxungquanhnamchmvdng in -GVnucuhi:Tnhchtcbnca t trng l g?-GVtvnvstnticat trngvhngdnhcsinhcchxc nh t trng. - GV nhnmnh:xc nh s tn ti cattrngtrongmtkhongkhng gianno,ngitasdngkimnam chm nh, t ti t trng +Hng ca t trng? -GV hng dn hc sinh s dng nam chm th xc nh t trng. III. T trng1. nh ngha T trng l mt dng vt cht tn ti trong khng gian m biu hin c th l s xut hin ca ca lc t tc dng ln mt dng in hay mt nam chm t trong n. 2. Hng ca t trngT trng nh hng cho cho cc nam chm nh. Qui c: Hng ca t trng ti mt im l hng Nam Bc ca kim nam chm nh nm cn bng ti im . Hot ng 4 (10 pht) Tm hiu ng sc t. Hot ng ca gio vin vhc sinhNi dung c bn - GV:Cho hc sinh nhc li khi nim ng sc in trng.- GV nh hng cho hc sinh n tp kin thc c v ng sc in trng, xy dng ng sc t. - Yu cu HS nghin cu SGK pht biu nh ngha ng sc t. - GV lu cho HS l i vi nam chm th,taquyclychiutccnam sangccbclchiucangcm ng t. - HS quan st hnh 19.6 thy hnh dng v chiu ng sc thng qua cch sp xp ca nam chm th. IV. ng sc t 1. nh nghang sc t l nhng ng v trong khng gian c t trng, sao cho tip tuyn ti mi im c hng trng vi hng ca t trng ti im . Qui c: Chiu ca ng sc t ti mi im l chiu ca t trng ti im . 2. Cc v d v ng sc t + Dng in thng rt di - C ng sc t l nhng ng trn nm trong nhng mt phng vung gc vi dng in v c tm nm trn dng in. - Chiu ng sc t c xc nh theo qui tc nm tay phi: bn tay phi sao cho ngn Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 48 -Gii thiu dng ng sc t ca dng in thng di. + Nu quy tc nm tay phi xc nh chiu ng sc t ca dng in thng ? - GV a ra v d c th hc sinh p dng qui tc. - GV: Gii thiu mt Nam, mt Bc ca dng in trn, quy c ng sc t ca dng in trn. - HS quan st hnh v sgk xc nh cc mt Nam Bc ca dng in trnGV:Gii thiu cch xc nh chiu ca ng sc t ca dng in chy trong dy dn trn.-HS:Ghi nhn dng ng sc t. -GV: Yu cu hc sinh thc hin C3.

-HSquanstngsc,nu&gii thch cc tnh cht ca ng sc t ci nm dc theo dy dn v ch theo chiu dng in, khi cc ngn tay kia khum li ch chiu cang sc t. + Dng in trn

- Qui c: Mt Nam ca dng in trn l mt khi nhn vo ta thy dng in chy theo chiu kim ng h, cn mt Bc th ngc li. - Cc ng sc t ca dng in trn c chiu i vo mt Nam v i ra mt Bc ca dng in trn y. 3. Cc tnh cht ca ng sc t + Qua mi im trong khng gian ch v c mt ng sc. + Cc ng sc t l nhng ng cong khp kn hoc v hn hai u. + Chiu ca ng sc t tun theo nhng qui tc xc nh. + Qui c v cc ng sc mau (dy) ch c t trng mnh, tha ch c t trng yu. Hot ng 5 : Tm hiu t trng Tri t.(Hc sinh t tm hiu.) Hot ng 6 :(3 pht)Cng c, giao nhim v v nh. Hot ng ca gio vin vhc sinhNi dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp 5 n 8trang 124sgkv 19.3; 19.5 v 19.8sbt. HS:Ghi cc bi tp v nh. IV. Rt kinh nghim Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 49 Ngy 21 thng 12 nm 2011 Tit 39.LC T. CM NG T I. MC TIU 1. Kin thc: - Pht biu c nh ngha vc t cm ng t, n v ca cm ng t. - M t c mt th nghim xc nh vc t cm ng t. - Pht biu c nh ngha vc t phn t dng in. - Nm c quy tc xc nh lc tc dng ln phn t dng in. 2. K nng: -Vn dng kin thc gii cc bi ton c lin quan. - Xc nh c vc t lc t tc dng ln on dy dn thng di c dng in chy qua - Xc nh quan h v chiu gia dng in, vect cm ng t v vct lc t - Quan st th nghim nhn xt, nh gi, tng hp 3. Thi : - Nghim tc trong hc tp, hng th vi mn hc. - Rn kh nng t duy, kh nng quan st thc t, t duy lgic khoa hc. II. CHUN B Gio vin:Chun b cc th nghim v lc t. Hc sinh:n li v tch vc t. III. TIN TRNH DY HC 1. n nh t chc 2. Ni dung bi hc Hot ng 1 (5 pht) : Kim tra bi c : - in trng l g? i lng c trng cho in trng - Nu nh ngha v tnh cht ca ng sc t. t vn : Trong bi hc trc chng ta bit biu hin ca t trng l tc dng lc t ln dng in hay nam chm t trong . Vy lc t c xc nh nh th no? V i lng no c trng v phng din tc dng lc t ca t trng? Hot ng 2 (20 pht) : Tm hiu lc t. Hot ng ca gio vin vhc sinhNi dung c bn -GVchoHSthamkhoSGKnunh ngha t trng u. - GV cho HS quan st li hnh nh t ph ca nam chm hnh ch U HS thy rng ccngmtsclccnggnnh songsongvcchunhau,yucuHS kt hp vi tnh cht ca ng sc t araktlunvngsctcat trng u - GV gii thiut trng u. c im ca t trng u. Gio vin: xc nh lc t do t trng utcdngvodydncdngin chayquattrongn,tatinhnhth nghim nh sau: - GV: B tr th nghim hnh 27.1.-GV:tinhnhthnghimnhtrong I. Lc t 1. T trng u T trng u l t trng m c tnh ca n ging nhau ti mi im; cc ng sc t l nhng ng thng song song, cng chiu v cch u nhau. 2. Lc t do t trng u tc dng ln mt on dy dn mang dng in Th nghim: C D D C BFTrng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 50 SGK, yu cu HS quan st v nhn xt. Gio vin phn tch cc trng hp xy ra - GV nu cu hi: + Ti sao khung li b ko xung? +Quatthcakhungdytrongth nghim,tacthktlungvphng ca lc t tc dng ln on dng in - Hc sinh lm vic theo nhm,phn tch cclctcdnglnondydnvvit phngtrnhcnbnglctcdngln on dy dn khi dy dn trng thi cn bng, xc nh phng ca lc t. - HS a ra kt lun v phng ca lc t tc dng ln on dng in - GV gii thiu quy tc bn tay tri xc nh chiu ca lc t. - GV yu cu hc sinh lm vic theo nhm trlicuhitheoyucucagio vin. - Gio vin cho mt s bi tp n gin v xcnhchiucattrng,lctv chiu ca dng in,- Hc sinh lm vic theo nhm tr li cu hi theo yu cu ca gio vin. - HS theo di th nghim v thuyt ging ca gio vin tm hiu mi quan h gia lc t, t trng ( ng sc t), dng in. - GV: Cho hc sinh thc hin C1, C2. - GV d dng nhn thy hng ca t trng, dng in, lc t tun theo quy tc bn tay tri +Pht biu quy tc bn tay tri ? +c im ca lc t tc dng ln dy dn mang dng in? Lc t tc dng ln mt on dy dn mang dng in t trong t trng u: + c phng vung gc vi cc ng sc t v vung gc vi on dy dn, + c ln ph thuc vo t trng v cng dng in chay qua dy dn. Quy tc bn tay tri: t bn tay tri dui thng sao cho cc ng cm ng t m xuyn vo lng bn tay, chiu t c tay n cc u ngn tay trng vi chiu ca dng in trong dy dn, khi ngn tay ci choi ra 90o ch chiu ca lc t tc dng ln on dy Hot ng 3(15 pht) :Tm hiu cm ng t. t vn :Dng in t trong t trng chu tc dng ca lc t ca t trng. Vy i lng no c trng cho t trng v phng din tc dng lc? Hot ng ca gio vin v hc sinhNi dung c bn -GVnhnxtktquthnghimtrnv t vn cc thay i ca cng dng inIvchiudiondydnltrong II. Cm ng t 1. Cm ng t

Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 51 trng hp on dy t vung gc vi t trng,tdndthcsinhhnhthnh khi nim v cm ng t. -GVgiithiunvcmngthoc gi cho hc sinh thng qua biu thc xc nh n v cm ng t. -GV:Cmngtlmtilngc hng(hayilngvector).hnhthnh c im ca vector cm ng tB v im t, phng, chiu v ln. -GVyucuhcsinhtmmilinh gia cm ng tBv lc tF? -GVsdnghnhv20.4/sgk,phntch v dn dt hc sinh tm thy c mi lin h . + Nhn xt v chiu ca ba vector lc t, cm ng t v phn t dng in ? - GV kt lun vn nh sch gio khoa: Lc tF c im t ti trung im ca on dy dn, c phng vung gc viB , Il c chiu tun theo quy tc bn tay tri v c ln c xc nh bng biu thc: F = IlBsino. . Cm ng t ti mt im trong t trng l i lng c trng cho mnh yu ca t trng v c o bng thng s gia lc t tc dng ln mt on dy dn mang dng din t vung gc ving cm ng t ti im v tch ca cng dng in v chiu di on dy dn . B = IlF 2. n v cm ng t Trong h SI n v cm ng t l tesla (T).1T = m AN1 . 11 3. Vc t cm ng t Vc t cm ng t B ti mt im: + C hng trng vi hng ca t trng ti im . + C ln l: B = IlF 4. Biu thc tng qut ca lc t Lc t F tc dng ln phn t dng in l I t trong t trng u, ti c cm ng t l B : + C im t ti trung im ca l; + C phng vung gc vi l v B ; + C chiu tun theo qui tc bn tay tri; + C ln F = IlBsin Hot ng 4 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinhNi dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp t 4 n7 trang 128 sgkv 20.8, 20.9 sbt. HS:Tm tt nhng kin thc c bn. HS:Ghi cc bi tp v nh. IV. Rt kinh nghim ............................................................................................................................................................. Ngy 21 thng 12 nm 2011 B+ ITrng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 52 Tit 40 BI TP V LC T I. MC TIU: 1. Kin thc: -Cngcvkhcsukinthcvcmngt,lctcattrngtcdnglnmt on dy dn c dng in chy qua, - Cch xc nh cc vector lc t, cm ng t v chiu ca dng in trong mt s trng hp c bn n tng qut. 2. K nng: - Vn dng quy tc nm bn tay phi, quy tc nam thun bc ngc xc nh chiu ca ng sc t v cm ng t ti mt im trong t trng do dng in trong dy dn thng di, dng in trn gy ra; - Vn dng cng thc tnh cm ng t B = IF v cng thc xc nh lc t tc dng ln mt on dy dn c dng in chy qua (cng thc Ampre) F = IlBsino. 3. Gio dc thi : II. CHUN B1. Gio vin: Bi tp c chn lc v phng php gii; 2. Hc sinh: Gii trc mt s bi tp theo yu cu ca gio vin. II. TIN TRNH DY HC 1. n nh lp v kim tra s s 2. Kim tra bi c: ( 2 pht) - Phng, chiu ca lc t tc dng ln dy dn mang dng in t trong t trng?- Quy tc bn tay tri. Yu cu HS dng quy tc bn tay tri xc nh chiu ca lc t tc dng ln on dng in trong cc trng hp sau: I I BB Hot ng 1 (2 pht) : Tm tt nhanh nhng kin thc lin quan n cc bi tp cn gii - Vit cng thc tnh ln cm ng t ti mt im trong t trng? .FBI l= - c im ca lc t tc dng ln dy dn mang dng in + im t: Ti trung im ca on dy; + Phng: Vung gc vi mt phng cha dy dn v ng cm ng t ct dy dn; + Chiu: Tun theo quy tc bn tay tri+ ln: F = BIlsino Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 53 Hot ng 2 (30 pht) :Gii bi tp t lunXc nh lc t trong cc trng hp sau:

Hot ng ca gio vin, hc sinhNi dung c bn -GVyucuhcsinhckvtm tt -HStholunvhotngcnhnvn dngcngthclctxcnhln cm ng t ? - GV a ra bi ton yu cu hc sinh c vtmttbiton(xcnhyucu bi) - HS hot ng c nhn tnh lc t -Giovinyucuhcsinhlmvic theonhm,tmktqutheoyucuca 1.TrongttrngucanamchmchU,t ondydndi20cmvunggcvittrng vcdnginchyqual1,5Athlcttc dng ln on dy l 3N. Tnh ln ca cm ng t? Gii: ln ca cm ng t: 310. 1, 5.0, 2FB TI l= = = 2.Trongttrngutondydndi5cm c dng in chy qua l 2 A v vung gc vi t trng, bit ln ca cm ng t l 20T. a) Lc t tc dng ln on dy l bao nhiu? b)Nudngintrongondyhpvit trngmtgco =300thlcttcdngln on dy l bao nhiu? Gii: a) =900: F = I. l.B sin = 2.0,05.20 = 2N b) = 300 : F = I. l.B sin= 2.0,05.20.sin 300 = 1N 3.Mtdydncchiudilttrongmtt trnguclncacmngB=5Tdng in c cng I = 0,2A hp vi t trng mt gc 600 th lc t tc dng ln on dy c ln F =2N. Hi chiu di ca on dy? Gii: Chiu di ca on dy: I B B I B I + B Id/c/ b/a/ Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 54 bi ton; - Gio vin nh hng: + Lc no tc dng ln thanh CD? +Lctchngnhthno?Lm thnoxcnhhngcalcttc dng ln thanh CD? +Phng trnh nh lut II Newton c vit nh th no? +Vythanhchuynngtheochiu no? Cho bit trng thi chuyn ng ca thanh? + Lm th no tnh ln ca gia tc trong chuyn ng ca thanh CD? -Giovinyucuhcsinhtinhnh tng t tm kt qu cu b. . . .sin. .sin245.0, 2.0, 5F B I lFlB Imoo= == = 4. Mt thanh kim loi CD c chiu di 20cm, khi lng100gtvunggcvihaithanhraysong songvnivinguninchiuinthU. Tonhthngttrongttrnguhngln trn(hnhv)ccmngtB=0,2T.Lyg= 10m/s2. a.DnginiquaCDl10A,tnhgiatcca thanh CD. Bit h s ma st l 0,2. b.Nnghaiuthanhlncaosaochohaithanh rayhpvimtphngnmngangmtgc30o. thanh CD trt ln vi gia tc nh trn (cu a) thdngintrongonmchcgitrlbao nhiu? Gii: Cc lc tc dng ln thanh: msF , F , N , P . Lcttcdnglnthanhtuntheoquytcbn tay tri, c chiu t phi sang tri. * Theo nh lut II Newton:a m F F N Pms = + + +(*) * Chiu phng trnh (*) ln h trc Oxy, ta c: a = mmg BImF Fms = =2m/s2. Hot ng 3 (6 pht) : Gii bi tp trc nghimHot ng ca gio vin, hc sinhNi dung c bn Cho HS tho lun v gii thch la chn Cu 1, Lc t tc dng ln mt on dy dn c dng in t trong mt t trng khng ph thuc yu t no sau y? a, Cng dng in.b, T trng. c, Gc hp bi dy v t trng. d, Bn cht ca dy dn. Cu 2, Mt on dy l c dng in cng I t trong mt t trng u c cm ng B hp vi dy mt gco . Lc t tc dng ln on dy c gi tr ln nht khi: a, o= 090c, o= 0108 b, o= 00 d, c b v c u ng Cu 3, Trong quy tc bn tay tri th theo th t, chiu ca ngn gia, ca ngn ci ch chiu ca yu t no? Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 55 a, Dng in, t trngc, Dng in, lc t b, T trng, lc td, T trng, dng in Hot ng4 (5pht) Giao nhim v v nh HOT NG CA G.VHOT NG CA HS Cho HS ghi tham kho v nh lm : - Gio vin khc su phng php gii cc bi ton lin quan n lc t; -Giovinkhcsuphngphpng lchcpdngtrongnhngtrng hp c th; -Giovinyucuhcsinhvnhlm cc bi tp lin quan n lc t. -Giovinyucuhcsinhxemtrc ni dung bi mi. Bitp:ThanhMNcchiudil=20cmkhi lng 10g c treo ngang bng hai dy dn mnh songsongAMvBN.ThanhdnMNct trong t trng u thng ng hng ln c cm ng t B=0,2T. Khi cho dng in chy qua thanh MNccng2,5Athncvtrcnbng mi,khihaidytreoAMvBNhpvi phngthngngmtgco.Lyg=10m/s2. Tnh gc o. RUT KINH NGHIEM Ngy 24 thng 12 nm 2011 Tit 41. Bi 21T TRNG CA DNG IN CHY TRONG CC DY DNC HNH DNG C BIT I. MC TIU 1. Kin thc Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 56 - Trnh by c v: +Dng cc ng sc t v quy tc xc nh chiu cc ng sc t ca dng in thng di, dng in trn. +Dng cc ng sc t bn trong v bn ngoi mt ng dy c dng in, quy tc xc nh chiu ca cc ng sc t bn trong ng dy - Vit ng cng thc tnh cm cm ng t ca dng in thng, dng in trn v cng thc xc nh chiu cc ng cm ng t bn trong ng dy di mang dng in. 2.K nng - p dng c cc quy tc v c cc ng sc t biu din t trng ca dng in thng di, dng in trn, ca ng dy c dng in chy qua. - Xc nh c ln, phng, chiu ca vect cm ng t ti mt im trong t trng gy bi dng in thng di, ti tm dng in trn v ti mt im trong long ng dy c dng in chy qua. II. CHUN B 1. GV - Dng c th nghim: khung dy trn, kim nam chm, ng dy, mt st, dng in thng. - Mt s hnh nh trong SGK, mt s on phim th nghim trn my vi tnh. 2. HS: n li kin thc v t trng, ng sc t, cm ng t. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp 2. Ni dung bi hc Hot ng 1 (5 pht) : Kim tra bi c : -Nu nh ngha v phng chiu, n v ca cm ng t. Hot ng 2 (5 pht) : Gii thiu cm ng t ti mt im cho trc trong t trng ca mt dng in chy trong dy dn c hnh dng nht nh. Cm ng t B ti mt im M: + T l vi cng dng in I gy ra t trng; + Ph thuc vo dng hnh hc ca dy dn; + Ph thuc vo v tr ca im M; + Ph thuc vo mi trng xung quanh. Hot ng 3 (8 pht) : Tm hiu t trng ca dng din chy trong dy dn thng di. Hot ng ca gio vin v hc sinhNi dung c bn - GV gii thiu dng in thng l dng in chy trong dy dn thng. - Gii thiu dng c TN v dng in thng v hn ch ca TN. - HS quan st hnh nh ca t ph phng to (gii thiu li cch to ra t ph).Gii thiu dng ng sc t v chiu ng sc t ca dng in thng di. - HS quan st, tho lun v rt ra nhn xt v dng ng sc t ca dng in thng. + Xt mt im M trn ng sc t bt k, gio vin yu cu hc sinh xc nh im t, phng chiu ca vector cm ng t do dng in trong dy dn thng I. T trng ca dng din chy trong dy dn thng di + ng sc t l nhng ng trn nm trong nhng mt phng vung gc vi dng in v c tm nm trn dy dn. + im t: Ti im ang xt. +Phng:Vunggcvionthngniim ang xt vi dy dn; + Chiu: Tun theo quy tc nm bn tay phi. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 57 di gy ra ti im . - HS tho lun nhm da vo c im ng sc t xc nh phng, chiu ca cm ng t B -GV: ln ca cm ng t ti im M phthucvocngdnginv khong cch t im n dy dn. -GVthngbohcsinhbiuthc lncacmngttiimM,t giovinyucuhcsinhrtrac cimcavectorcngin trng ti M. + ln cm ng t ti im cch dy dn mt khong r: B =2.10-7Ir. Hot ng 4(8 pht) : Tm hiu t trng ca dng in chy trong dy dn un vng trn. Hot ng ca gio vin v hc sinh Ni dung c bn - GV gii thiu dng in trn: Dng in chy trong dy dn trn. - GV chiu hoc treo tranh v hnh nh t ph ca dng in trn yu cu hc sinh nhn xt dng ng sc t. - HS quan st hnh nh t ph v nhn xt dng ca ng sc t

Nhn xt cu tr li ca HS, b sung, kt lun: ng sc t l nhng ng cong.Cng gn tm O cong cng gim. Ti O ng sc t l ng thng. - HS:V hnh.Ghi nhn dng ng cm ng t ca dng din trn. - GV gii thiu quy tc xc nh chiu ng sc t ca dng in trn. - GV: Yu cu hc sinh xc nh chiu ca ng cm ng t trong mt s trng hp.- GV nhn mnh ng sc t i qua tm l ng thng v gii thiu cng thc tnh t trng ti tm O II. T trng ca dng in chy trong dy dn un thnh vng trn + ng sc t i qua tm O ca vng trn l ng thng v hn hai u cn cc ng khc l nhng ng cong c chiuvo mt Nam v i ra mt Bc ca dng in trn . + im t: ti tm vng dy; + Phng: Vung gc vi mt phng cha vng dy; +Chiu:TuntheoquytcNamthun-Bc ngc. + ln cm ng t ti tm O ca vng dy: B = 2t.10-7IR Ch : Nu khung dy trn c to bi N vng dy st nhau th : 72 .10IB NRt=Hot ng 5(7 pht) : Tm hiu t trng ca dng in chy trong ng dy dn hnh tr. Hot ng ca gio vin vhc sinhNi dung c bn Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 58 GV gii thiu hnh nh t ph v cho HS tho lun, nhn xt v dng ca cc ng sc t bn trong v bn ngoi ng dy ( Gi xt bn trong v bn ngoi ng dy ng sc c c im g?) - HS quan st hnh v xc nh dng ng cm ng t trong lng ng dy. - GV nhn mnh: T trng bn trong ng dy l t trng u, t gio vin hnh thnh tng nghin cu t trng ti mt im trong ng dy. - GV a ra cng thc tnh t trng trong lng ng dy. - GV yu cu hc sinh nhn xt v im t, phng, chiu ca vector cm ng t - GV yu cu hc sinh ch ra cc cc ca ng dy. - HS vn dng kin thc v t trng dng in trn ch ra cc cc ca ng dy - Gio vin yu cu hc sinh tho lun theo nhm tr li cu hi C2; - Gio vin dn dt hc sinh kt lun vn . III. T trng ca dng in chy trong ng dy dn hnh tr + Trong ng dy cc ng sc t l nhng ng thng song song cng chiu v cch u nhau. + Cm ng t trong lng ng dy: B = 4t.10-7lNI = 4t.10-7n.I Hot ng 6 (6 pht) : Tm hiu t trng ca nhiu dng in. Hot ng ca gio vin v hc sinh Ni dung c bn GV:Yu cu hc sinh nhc li nguyn l chng cht in trng. Gii thiu nguyn l chng cht t trng. HS:Nhc li nguyn l chng cht in trng. Ghi nhn nguyn l chng cht t trng. IV. T trng ca nhiu dng in Vc t cm ng t ti mt im do nhiu dng in gy ra bng tng cc vc t cm ng t do tng dng in gy ra ti im y + + + =nB B B B ...2 1 Hot ng 7(6 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinh Ni dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tp t 3 n 7 trang 133 sgkv 21.6 ; 21.7 sbt. HS: Tm tt nhng kin thc c bn. HS:Ghi cc bi tp v nh. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 59 GV lu cch xc nh phng, chiu v ln ca cm ng t B trong cc trng hp thng qua hai quy tc vo Nam ra Bc v nm tay phi Ngy 1 thng 1 nm 2012 Tit 42LC LO-REN-X I. MC TIU 1.Kin thc : - Pht biu c lc Lo-ren-x l g v nu c cc c trng v phng, chiu v vit c cng thc tnh lc Lo-ren-x. - Nu c cc c trng c bn ca chuyn ng ca ht mang in tch trong t trng u; vit c cng thc tnh bn knh vng trn qu o. 2.K nng : - Vn dng kin thc c bn gii cc bi tp c bn c lin quan. 3.Thi : - Nghim tc trong hc tp. 4.Trng tm : -Cc c im ca lc Loren x II. CHUN B 1.Gio vin:Chun b cc dng dy hc v chuyn ng ca ht tch in trong t trng u. 2.Hc sinh:n li v chuyn ng trn u, lc hng tm v nh l ng nng, cng vi thuyt electron v dng in trong kim loi. III. HOT NG DY HC 1. Kim tra s s v n nh lp hc 2.Ni dungHot ng 1 (5 pht) : Kim tra bi c : - Lc t tc dng ln mt on dy dn mang dng in t trong t trng.? - Quy tc bn tay tri? Hot ng 2 (7 pht) : Tm hiu lc Lo-ren-x. Hot ng ca gio vin v hc sinhNi dung c bn -Gvyucuhcsinhnhclikhinim dng in. - Hs : Lp lun a ra nh ngha lc Lo-ren-x. -Gv:Giithiuhnhv22.1.Hngdn hc sinh t tm ra kt qu. - a ra kt lun y v c im ca lc I. Lc Lo-ren-x 1. nh ngha lc Lo-ren-x Mihtmangintchchuynngtrong mtttrng,uchutcdngcalct. Lc ny c gi l lc Lo-ren-x. 2. Xc nh lc Lo-ren-x Lc Lo-ren-x do t trng c cm ng t Btcdnglnmthtintchq0chuynng vi vn tc v : + C phng vung gc vi v v B ; Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 60 Lo-ren-x. Yu cu hc sinh thc hin C1.C2. + C chiu theo qui tc bn tay tri: bn tay tri m rng sao cho t trng hng vo lng bn tay, chiu t c tay n ngn gia l chiu ca v khiq0>0vngcchiu v khiq0 BMmax th y = xxa2+ t gi tr min. Theo bt ng thc Couchy: y = xxa2+ a => ymin = a khi x = a = 10cm Khi BMmax = 2.10-5T *Hcsinhchpbitp2:Mtintchc khilng1,6.10-27kg,cintchq1=-e chuyn ng vo vng t trng u c cm ng t B = 0,4T vi vn tc v1 = 10-6 (m/s). Bit rng vector vn tc vung gc vi vector cm ng t. a. Tnh bn knh qu o ca in tch; b.Mtintchthhaickhilng9,6.10-27kg,intchq2=2ebayvunggcvit trng trn s c bn knh qu o gp 2 ln in tch th nht. Tnh vn tc ca in tch th hai. Hot ng : Cng c bi hc - nh hng nhim v hc tp tip theo. HOT NG CA GIO VINHOT NGCA HC SINH *Giovinhngdnhcsinhphntch v tr li cc cu hi sch gio khoa trang 138; *Hc sinh tho lun theo nhm tr li cc cu hi theo yu cu ca gio vin; *Hcsinhquanstmhnhchuynngca Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 64 *Giovingiithiumhnhchuyn ng trn u ca electron trong t trng ukhicvectorvntcvunggcvi vector cm ng t. *Gio vin yu cu hc sinh lm thm cc bi tp sch bi tp. electrontrongttrngubngmhnhth nghim o. *Hcsinhghinhnnhimvhctptheoyu cu ca gio vin. Ngy 22 thng 1 nm 2011 Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 65 CHNG V. CM NG IN T Tit 44 T THNG. CM NG IN T I. MC TIU 1.Kin thc: -Vit c cng thc v hiu c ngha vt l ca t thng. -Pht biu c nh ngha v hiu c khi no th c hin tng cm ng in t. -Pht biu c nh lut Len-x theo nhng cch khc nhau v bit vn dng xc nh chiu ca dng in cm ng trong cc trng hp khc nhau. 2.K nng: -Nm vng kin thc vn dng vo gii cc bi tp c bn 3.Thi :-Nghim tc trong hc tp, yu thch b mn. 4.Trng tm: -Hin tng cm ng in t.T thng. II. CHUN B Gio vin: + Chun b cc hnh v v cc ng sc t trong nhiu v d khc nhau. + Chun b cc th nghim v cm ng t. Hc sinh: + n li v ng sc t. + So snh ng sc in v ng sc t. III. TIN TRNH DY HC 1. Kim tra s s v n nh lp hc 2.Ni dung bi mi Tit 1 Hot ng 1 (5 pht) : Gii thiu chng 5 CM NG IN T Hot ng 2 ( pht) : Tm hiu t thng. Hot ng ca gio vin vhc sinh Ni dung c bn GV:V hnh 23.1 v hng dn hc sinh tm hiu khi nim t thng - Gi s c mt phng din tch S t trong t trng u B . Vc t php tuyn n. Vi o l gc gia php tuyn nv B . Th i lng xc nh bi cng thc u = BScoso gi l t thng qua mt S GV lu : Nu khng c nhng iu kin bt buc i vi php tuyn nth chn sao cho o nhn - ngha ca t thng l g?( dng khi nim t thng din t s ng sc t xuyn qua mt tit din no ) HS:Ghi nhn khi nim. -Cho bit khi no th t thng c gi tr dng, m hoc bng 0? I. T thng1. nh nghaT thng qua mt din tch S t trong t trng u: u = BScoso Vi o l gc gia php tuyn nv B . 2. n v t thngTrong h SI n v t thng l vbe (Wb).1Wb = 1T.1m2. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 66 GV:Gii thiu n v t thng. Hot ng 3( pht) :Tm hiu hin tng cm ng in t. Hot ng ca gio vin v hc sinhNi dung c bn Gv tin hnh cc th nghim xc nh kim tra xem t trng c sinh ra dng in hay khng. GV:Gii thiu cc th nghim. HS: Quan st th nghim.Gii thch s bin thin ca t thng trong th nghim 1 GV:Cho hc sinh nhn xt qua tng th nghim. HS:Gii thch s bin thin ca t thng trong th nghim 2. HS:Gii thch s bin thin ca t thng trong th nghim 3. GV:Yu cu hc sinh thc hin C2. HS:Thc hin C2. GV:Yu cu hc sinh rt ra nhn xt chung. II. Hin tng cm ng in t 1. Th nghim a) Th nghim 1 Cho nam chm dch chuyn li gn vng dy kn (C) ta thy trong mch kn (C)xut hin dng in. b) Th nghim 2 Cho nam chm dch chuyn ra xa mch kn (C) ta thy trong mch kn (C) xut hin dng in ngc chiu vi th nghim 1. c) Th nghim 3 Gi cho nam chm ng yn v dch chuyn mch kn (C) ta cng thu c kt qu tng t. d) Th nghim 4 Thay nam chm vnh cu bng nam chm in. Khi thay i cng dng in trong nam chm in th trong mch kn (C) cng xut hin dng in. 2. Kt lun a) Tt c cc th nghim trn u c mt c im chung l t thng qua mch kn (C) bin thin. Da vo cng thc nh ngha t thng, ta nhn thy, khi mt trong cc i lng B, S hoc o thay i Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 67 HS:Da vo s thay i s ng sc t qua S nhn xt s bin i ca t thng qua S GV gii thiu hin tng cm ng in t - T cc th nghim hy xc nh iu kin xy ra hin tng cm ng in t? th t thng u bin thin. b) Kt qu ca th nghim chng t rng: + Mi khi t thng qua mch kn (C) bin thin th trong mch kn (C) xut hin mt dng in gi l hin tng cm ng in t. + Hin tng cm ng in t ch tn ti trong khong thi gian t thng qua mch kn bin thin. Hot ng 4 ( pht) : Tm hiu nh lut Len-x v chiu dng in cm ng. Hot ng ca gio vin vhc sinhNi dung c bn GV:Trnh by phng php kho st qui lut xc nh chiu dng in cm ng xut hin trong mch kn HS:Nghe v lin h vi trng hp cc th nghim va tin hnh. GV:Gii thiu nh lut. HS:Ghi nhn nh lut. GV:Yu cu hc sinh thc hin C3. HS:Ghi nhn nh lut. GV:Gii thiu trng hp t thng qua (C) bin thin do kt qu ca chuyn ngGii thiu nh lut.. HS:Ghi nhn cch pht biu nh lut trong trng hp t thng qua (C) bin thin do kt qu ca chuyn ng. III. nh lut Len-x v chiu dng in cm ng Dng in cm ng xut hin trong mch kn c chiu sao cho t trng cm ng c tc dng chng li s bin thin ca t thng ban u qua mch kn. Khi t thng qua mch kn (C) bin thin do kt qu ca mt chuyn ng no th t trng cm ng c tc dng chng li chuyn ng ni trn. Hot ng 5Cng c v hng dn v nh Gv cng c kin thc v t thng v lu gc ochiu dng in cm ng CU HI TRC NGHIM Cu 1. T thng c tnh theo biu thc: a. u = BScosob. u = BSsinoc.cosBS| o = d.cosSB| o =Cu 2: Chn pht biu ng. Dng in cm ng: a.xut hin trong cun dy dn kn trong thi gian c s bin thin ca cc ng cm ng t qua tit din S ca cun dy. b.xut hin trong cun dy dn kn khi c cc ng cm ng t gi qua tit din S ca cun dy. c.cng ln khi tit ca cun dy cng nh. d.tng khi s ng cm ng t gi qua tit din S ca cun dy tng v gim khi cc ng cm ng t gi qua tit din S ca cun dy gim. Ngy 22 thng 1 nm 2011 Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 68 Tit 45. T THNG. CM NG IN T I. MUC TIEU 1.Kin thc: -Phat bieu c nh luat Len-x theo nhng cach khac nhau va biet van dung e xac nh chieu cua dong ien cam ng trong cac trng hp khac nhau. -Phat bieu c nh ngha va neu c mot so tnh chat cua dong ien Fu-co. 2.K nng: -Nm vng kin thc vn dng vo gii cc bi tp c bn 3.Thi :-Nghim tc trong hc tp, yu thch b mn. 4.Trng tm: -nh lut Len v dng Fuco. II. CHUAN B Giao vien: + Chuan b cac hnh ve ve cac ng sc t trong nhieu v du khac nhau. + Chuan b cac th nghiem ve cam ng t. Hoc sinh: + On lai ve ng sc t. + So sanh ng sc ien va ng sc t. III. HOT NG DY HC 1. Kim tra s s v n nh lp hc 2.Ni dung Kim tra bi c: Hin tng cm ng in t l g? nh lut Len x v chiu dng in ? (Gv a ra mt s bi ton yu cu hc sinh xc nh chiu dng in) Hot ng 1 ( pht) : Tm hiu dng in Fu-c. Hot ng ca gio vin vhc sinhNi dung c bn GV gii thiu dng in Fuco l dng in cm ng xut hin trong khi kim loi c GV:Gii thiu hnh v 23.6 v th nghim 1. HS:Quan st th nghim, rt ra nhn xt. GV:Gii thiu hnh v 23.6 v th nghim 2. HS:Quan st th nghim, rt ra nhn xt. IV. Dng in Fu-c 1. Th nghim 1 Mt bnh xe kim loi c dng mt a trn quay xung quanh trc O ca n trc mt nam chm in. Khi cha cho dng in chy vo nam chm, bnh xe quay bnh thng. Khi cho dng in chy vo nam chm bnh xe quay chm v b hm dng li. 2. Th nghim 2 Mt khi kim loi hnh lp phng c t gia hai cc ca mt nam chm in. Khi y c treo bng mt si dy mt u c dnh; trc khi a khi vo trong nam chm in, si dy treo c xon nhiu vng. Nu cha c dng in vo nam chm in, khi th ra khi kim loi quay nhanh xung quanh mnh n. Nu c dng in i vo nam chm in, khi th ra khi kim loi quay chm v b hm dng li. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 69 GV:Yu cu hc sinh gii thch kt qu cc th nghim. HS:Gii thch kt qu cc th nghim. GV:Gii thch y hin tng v gii thiu dng Fu-c. HS:Ghi nhn khi nim. GV:Gii thiu tnh cht ca dng Fu-c gy ra lc hm in t. HS:Ghi nhn tnh cht. GV:Yu cu hc sinh nu ng dng. HS:Ghi nhn tc dng c hi ca dng in Fu-c. GV:Gii thiu tnh cht ca dng Fu-c gy ra hiu ng ta nhit. GV:Yu cu hc sinh nu cc ng dng ca tnh cht ny. HS:Nu ng dng GV:Gii thiu tc dng c hi ca dng in Fu-c.Yu cu hc sinh nu cc cch lm gim in tr ca khi kim loi. HS:Nu cc cch lm gim in tr ca khi kim loi. 3. Gii thch cc th nghim trn, khi bnh xe v khi kim loi chuyn ng trong t trng th trong th tch ca chng cut hin dng in cm ng nhng dng in Fu-c. Theo nh lut Len-x, nhng dng in cm ng ny lun c tc dng chng li s chuyn di, v vy khi chuyn ng trong t trng, trn bnh xe v trn khi kim loi xut hin nhng lc t c tc dng cn tr chuyn ng ca chng, nhng lc y gi l lc hm in t. 4. Tnh cht v cng dng ca dng Fu-c + Mi khi kim loi chuyn ng trong t trng u chu tc dng ca nhng lc hm in t. Tnh cht ny c ng dng trong cc b phanh in t ca nhng t hng nng. + Dng in Fu-c gy ra hiu ng ta nhit Jun Len-x trong khi kim loi t trong t trng bin thin. Tnh cht ny c ng dng trong cc l cm ng nung nng kim loi. + Dng Fu-c cng c ng dng trong mt s l ti kim loi. + Trong nhiu trng hp dng in Fu-c gy nn nhng tn hao nng lng v ch. gim tc dng ca dng Fu-c, ngi ta c th tng in tr ca khi kim loi. Hot ng 2 ( pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinhNi dung c bn GV:Cho hc sinh tm tt nhng kin thc c bn. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh thc hin cc cu hi v lm cc bi tptrang 147, 148 sgk cc bi tp 23.1, 23.6 sbt. HS:Ghi cc bi tp v nh.

Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 70

Ngy 25 thng 1 nm 2011 Tit 46. BI TP I. MC TIU 1. Kin thc : + Nm c nh ngha v pht hin c khi no c hin tng cm ng in t. + Pht biu c nh lut Len-xtheo cc cch v vn dng xc nh chiu dng in cm ng trong cc trng hp khc nhau. Gii cc bi tp lin quan. 2. K nngVn dng thnh tho nh lut Len-x xc nh chiu dng in cm ng. II. CHUN B Gio vin:- Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc.Hc sinh: - Gii cc cu hi trc nghim v bi tp thy c ra v nh. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 71 - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIN TRNH DY HC Hot ng 1 (10 pht) : Nu cc lu khi gii bi tp v hin tng cm ng in t: + Trong mt t trng u B , t thng qua mt din tch S gii hn bi mt vng dy kn phng c xc nh bi biu thc: u = BScoso + Khi gii bi tp cn xc nh c gc o hp bi vc t cm ng t Bv php tuyn n ca mt phng vng dy. Lu , s ng sc t xuyn qua din tch S cng nhiu th t thng | cng ln. Khi mt mch in chuyn ng trong t trng th cng ca cc lc in t tc dng ln mch in c o bng tch ca cng dng in vi bin thin t thng qua mch: AA = IBS = I.Au Hot ng 2(10 pht) : Gii cc cu hi trc nghim. Hot ng ca gio vin vahc sinhNi dung c bn GV: Yu cu hs gii thch ti sao chn . HS:Gii thch la chn. Cu 3 trang 147 : D Cu 4 trang 148 : A Cu23.1 : D Hot ng 3 (25 pht) : Gii cc bi tp t lun. Hot ng ca gio vin v hc sinhNi dung c bn GV:V hnh trong tng trng hp v cho hc sinh xc nh chiu ca dng in cm ng. HS:Xc nh chiu dng in cm ng trong tng trng hp. GV:Yu cu hc sinh vit cng thc xc nh t thng u. HS:Vit cng thc xc nh t thng u. GV:Yu cu hc sinh xc nh gc gia Bv ntrong tng trng hp v HS:Xc nh gc gia Bv ntrong tng trng hp v thay s tnh u trong tng trng hp o Bi 5 trang148 a) Dng in trong (C) ngc chiu kim ng h. b) Dng in trong (C) cng chiu kim ng h. c) Trong (C) khng c dng in. d) Trong (C) c dng in xoay chiu. Bi 23.6a) u = BScos1800 = - 0,02.0,12

=- 2.10-4(Wb). b) u = BScos00 =0,02.0,12 = 2.10-4(Wb). c) u = 0 d) u = Bscos450 =0,02.0,12.22

=2 .10-4(Wb). e) u = Bscos1350 =- 0,02.0,12.22

= -2 .10-4(Wb). Hot ng 4 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinh GV:Cho hc sinh tm tt nhng kin thc c bn. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh c bi mi HS: Ghi nh Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 72 Ngy 4 thng 2 nm 2011 Tit 47.SUT IN NG CM NG I. MC TIU + Vit c cng thc tnh sut in ng cm ng. +Vndngcccngthchctnhcsutinngcmngtrongmts trng hp n gin.II. CHUN B Gio vin: Chun b mt s th nghim v sut in ng cm ng. Hc sinh: n li khi nim v sut in ng ca mt ngun in. III. TIN TRNH DY HC Hot ng 1 (5 pht) : Kim tra bi c : Pht biu cc nh ngha: dng in cm ng, hin tng cm ng in t, t trng cm ng. Hot ng 2 (20 pht) : Tm hiu sut in ng cm ng trong mch kn. Hot ng ca gio vin vhc sinh Ni dung c bn GV:Yu cu hc sinh thc hin C1. HS:Thc hin C1. GV:Nu khi nim sut in ng cm ng, HS:Ghi nhn khi nim. GV:Cn c hnh 24.2 lp lun lp cng thc xc nh sut in ng cm ng. HS:Nghe cch t vn ca thy c thc hin mt s bin i. GV:Yu cu hc sinh vit biu thc xc nh ln ca eC v pht biu nh lut.HS:Vit biu thc xc nh ln ca eC v pht biu nh lut.GV:Yu cu hc sinh thc hin C2. HS:Thc hin C2. I. Sut in ng cm ng trong mch kn 1. nh nghaSut in ng cm ng l sut in ng sinh ra dng in cm ng trong mch kn. 2. nh lut Fa-ra-y Sut in ng cm ng: eC = - t AAu Nu ch xt v ln ca eC th: |eC| = |t AAu| ln ca sut in ng cm ng xut hin trong mch kn t l vi tc bin thin t thng qua mch kn . Hot ng 3(10 pht) : Tm hiu quan h gia sut in ng cm ng v nh lut Len-x. Hot ng ca gio vin vhc sinhNi dung c bn GV:Nhn xt v tm mi quan h gia sut in ng cm ng v nh lut Len-x.Hng dn cho hc sinh nh hng cho (C) v chn chiu php tuyn dng tnh t thng. HS:Nm c cch nh hng cho (C)v chn chiu dng ca php tuyn. II. Quan h gia sut in ng cm ng v nh lut Len-x S xut hin du (-) trong biu thc ca eC

l ph hp vi nh lutLen-x. Trc ht mch kn (C) phi c nh hng. Da vo chiu chn trn (C), ta chn chiu php tuyn dng tnh t thng qua mch kn. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 73 GV:Yu cu hc sinh xc nh chiu ca dng in cm ng xut hin trong (C) khi u tng v khi u gim. HS:Xc nh chiu ca dng in cm ng xut hin trong (C) khi u tng v khi u gim. GV:Yu cu hc sinh thc hin C3. HS:Thc hin C3. Nu u tng th eC < 0: chiu ca sut in ng cm ng (chiu ca dng in cm ng) ngc chiu vi chiu ca mch. Nu u gim th eC > 0: chiu ca sut in ng cm ng (chiu ca dng in cm ng) cng chiu vi chiu ca mch. Hot ng 4 (5 pht) : Tm hiu s chuyn ha nng lng hin tng cm ng in t. Hot ng ca gio vin vhc sinhNi dung c bn GV:Phn tch cho hc sinh thy bn cht ca hin tng cm ng in t v s chuyn ha nng lng trong hin tng cm ng in t. HS:Nm c bn cht ca hin tng cm ng in t. Bit cch l gii cc nh lut cm ng in t bng nh lut bo ton v chuyn ha nng lng. GV:Nu ngha to ln ca nh lut Fa-ra-y. HS:Nm c ngha to ln ca nh lut Fa-ra-y. III. Chuyn ha nng lng trong hin tng cm ng in t Xt mch kn (C) t trong t trng khng i, to ra s bin thin ca t thng qua mch (C), phi c mt ngoi lc tc dng vo (C) thc hin mt dch chuyn no ca (C) v ngoi lc ny sinh mt cng c hc. Cng c hc ny lm xut hin sut in ng cm ng trong mch, ngha l to ra in nng. Vy bn cht ca hin tng cm ng in t nu trn l qu trnh chuyn ha c nng thnh in nng. Hot ng 5 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin v hc sinh GV:Cho hc sinh tm tt nhng kin thc c bn. HS:Tm tt nhng kin thc c bn. GV:Yu cu hc sinh v nh lm cc bi tptrang 152 sgkv 24.3, 24.4 sbt. HS:Ghi cc bi tp v nh. Ngy 6 thng 2 nm 2011 Tit 48. T CM I. MC TIU + Pht biu c nh ngha t thng rin v vit c cng thc t cm ca ng dy hnh tr. + Pht biu c nh ngha hin tng t cm v gii thch c hin tng t cm khi ng v ngt mch in. + Vit c cng thc tnh sut in ng t cm. + Nu c bn cht v vit c cng thc tnh nng lng ca ng dy t cm. II. CHUN B Gio vin: Cc th nghim v t cm. Hc sinh: n li phn cm ng in t v sut in ng t cm. III. TIN TRNH DY HC Hot ng 1 (5 pht) : Kim tra bi c : Nu cng thc xc nh t thng qua din tch S t trong t trng u.Pht biu v vit biu thc ca nh lut Fa-ra-y. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 74 Hot ng 2 (8 pht) : Tm hiu t thng ring qua mt mch kn. Hot ng ca gio vin v hc sinhNi dung c bn

GV:Lp lun a ra biu thc tnh t thng ring HS:Ghi nhn khi nim GV:Lp lun a ra biu thc tnh t cm ca ng dHS: Ghi nhn biu thc tnh t cm ca ng dy. GV:Gii thiu n v t cm. HS:Ghi nhn n v ca t cm. GV: Yu cu hc sinh tm mi lin h gia n v ca t cm c cc n v khc. HS:Tm mi lin h gia n v ca t cm c cc n v khc. I. T thng ring qua mt mch kn

T thng ring ca mt mch kn c dng in chy qua: u = Li

t cm ca mt ng dy: L = 4t.10-7..lN2.S n v ca t cm l henri (H) 1H = AWb11 Hot ng 3(15 pht) : Tm hiu hin tng t cm. Hot ng ca gio vin ca hc sinhNi dung c bn

GV:Gii thiu hin tng t cm. HS:Ghi nhn khi nim GV:Trnh by th nghim 1. HS:Quan st th nghim. M t hin tng. GV:Yu cu hc sinh gii thch. HS:Gii thch. GV:Trnh by th nghim 2. HS:Quan st th nghim. M t hin tng. GV:Yu cu hc sinh gii thch. II. Hin tng t cm 1. nh nghaHin tng t cm l hin tng cm ng in t xy ra trong mt mch c dng in m s bin thin ca t thng qua mch c gy ra bi s bin thin ca cng dng in trong mch. 2. Mt s v d v hin tng t cm a) V d 1 Khi ng kha K, n 1 sng ln ngay cn n 2 sng ln t t. Gii thch: Khi ng kha K, dng in qua ng dy v n 2 tng ln t ngt, khi trong ng dy xut hin sut in ng t cm c tc dng cn tr s tng ca dng in qua L. Do dng in qua L v n 2 tng ln t t. b) V d 2 Khi t ngt ngt kha K, ta thy n sng bng ln trc khi tt. Gii thch: Khi ngt K, dng in iL gim t ngt xung 0. Trong ng dy xut hin dng in cm ng cng chiu vi iL ban u, dng in ny chy qua n v v K ngt t ngt nn cng dng cm ng kh ln, lm cho n sng bng ln trc khi tt. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 75 HS:Gii thch. GV:Yu cu hc sinh thc hin C2. HS:Thc hin C2. Hot ng 4 (8 pht) : Tm hiu sut in ng t cm. Hot ng ca gio vin ca hc sinhNi dung c bn

GV:Gii thiu sut in ng t cm. HS:Ghi nhn khi nim. GV:Gii thiu biu thc tnh sut in ng t cm. HS:Ghi nhn biu thc tnh sut in ng t cm. GV:Yu cu hc sinh gii thch du (-) trong biu thc). HS:gii thch du (-) trong biu thc). GV:Gii thiu nng lng t trng HS: Ghi nhn khi nim. GV:Yu cu hc sinh thc hin C3. HS:Thc hin C3. III. Sut in ng t cm 1. Sut in ng t cm Sut in ng cm ng trong mch xut hin do hin tng t cm gi l sut in ng t cm. Biu thc sut in ng t cm: etc = - LtiAA Sut in ng t cm c ln t l vi tc bin thin ca cng dng in trong mch. 2. Nng lng t trng ca ng dy t cm W = 21Li2. Hot ng 5 (4 pht) : Tm hiu ng dng ca hin tng t cm. Hot ng ca gio vin ca hc sinhNi dung c bn

GV:Yu cu hc sinh nu mt s ng dng ca hin tng t cm. HS:Nu mt s ng dng ca hin tng t cm m em bit. GV:Gii thiu cc ng dng ca hin tng t cm. HS:Ghi nhn cc ng dng ca hin tng t cm. IV. ng dng Hin tng t cm c nhiu ng dng trong cc mch in xoay chiu. Cun cm l mt phn t quan trng trong cc mch in xoay chiu c mch dao ng v cc my bin p. Hot ng 6 (5 pht) : Cng c, giao nhim v v nh. Hot ng ca gio vin hc sinh GV:Cho hc sinh tm tt nhng kin thc c bn. HS:Tm tt nhng kin thc c bn. GV:Ra bi tp v nh: Cc bttrang 157 sgkv 25.5, 25.7. HS:Ghi cc bi tp v nh. Trng THPT Lng 2Vt l 11 Gio vin : Nguyn Vn Phc Nm hc 2011-2012 76 Ngy 18 thng 2 nm 2011 Tit 49. BI TP I. MC TIU: 1. Kin thc : Nm c nh ngha v biu thc tnh sut in ng cm ng, nm c quan h gia sut in ng cm ng v nh lut Len-x, nm c hin tng t cm v biu thc tnh sut in ng t cm. 2. K nng :Bit cch tnh sut in ng cm ng v sut in ng t cm, tnh nng lng in trng ca ng dy c dng in chy qua. II. CHUN B: 1.Gio vin: - Xem, gii cc bi tp sgk v sch bi tp. - Chun b thm nt s cu hi trc nghim v bi tp khc.2.Hc sinh: - Gii cc cu hi trc nghim v bi tp thy c ra v nh. - Chun b sn cc vn m mnh cn vng mc cn phi hi thy c. III. TIN TRNH DY HC: Hot ng 1: Kim tra bi c v tm tt nhng kin thc lin quan n cc bi tp cn gii: Sut in ng cm ng: eC = - t AAu.