Bai Tap Vat Ly 11 CA Nam

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangPhn mt: in - in t hc

Chng I: in tch - in trng.Phn mt: in - in t hc

Chng I: in tch - in trng.1. in tch nh lut Cu Lng1.1 C hai in tch im q1 v q2, chng y nhau. Khng nh no sau y l ng? A. q1> 0 v q2 < 0. B. q1< 0 v q2 > 0. C. q1.q2 > 0. D. q1.q2 < 0. 1.3 Pht biu no sau y l ng? A. Khi nhim in do tip xc, electron lun dch chuyn t vt nhim in sang vt khng nhim in. B. Khi nhim in do tip xc, electron lun dch chuyn t vt khng nhim in sang vt nhim in. C. Khi nhim in do hng ng, electron ch dch chuyn t u ny sang u kia ca vt b nhim in. D. Sau khi nhim in do hng ng, s phn b in tch trn vt b nhim in vn khng thay i. 1. 4 ln ca lc tng tc gia hai in tch im trong khng kh A. t l vi bnh phng khong cch gia hai in tch. B. t l vi khong cch gia hai in tch. C. t l nghch vi bnh phng khong cch gia hai in tch. D. t l nghch vi khong cch gia hai in tch. 1.6 Khong cch gia mt prton v mt lectron l r = 5.10 -9 (cm), coi rng prton v lectron l cc in tch im. Lc tng tc gia chng l: A. lc ht vi F = 9,216.10-12 (N). B. lc y vi F = 9,216.10-12 (N). C. lc ht vi F = 9,216.10-8 (N). D. lc y vi F = 9,216.10-8 (N). 1.7 Hai in tch im bng nhau t trong chn khng cch nhau mt khong r = 2 (cm). Lc y gia chng l F = 1,6.10-4 (N). ln ca hai in tch l: A. q1 = q2 = 2,67.10-9 (C). B. q1 = q2 = 2,67.10-7 (C). C. q1 = q2 = 2,67.10-9 (C). D. q1 = q2 = 2,67.10-7 (C). 1.8 Hai in tch im bng nhau t trong chn khng cch nhau mt khong r1 = 2 (cm). Lc y gia chng l F1 = 1,6.10-4 (N). lc tng tc gia hai in tch bng F2 = 2,5.10-4 (N) th khong cch gia chng l: A. r2 = 1,6 (m). B. r2 = 1,6 (cm).C. r2 = 1,28 (m). D. r2 = 1,28 (cm). 1.9 Hai in tch im q1 = +3 ( C) v q2 = -3 ( C),t trong du ( = 2) cch nhau mt khong r = 3 (cm). Lc tng tc gia hai in tch l: A. lc ht vi ln F = 45 (N). B. lc y vi ln F = 45 (N). C. lc ht vi ln F = 90 (N). D. lc y vi ln F = 90 (N). 1.10 Hai in tch im bng nhau c t trong nc ( = 81) cch nhau 3 (cm). Lc y gia chng bng 0,2.10 -5 (N). Hai in tch A. tri du, ln l 4,472.10-2 ( C). B. cng du, ln l 4,472.10-10 ( C). C. tri du, ln l 4,025.10-9 ( C). D. cng du, ln l 4,025.10-3 ( C). 1.11 Hai qu cu nh c in tch 10-7 (C) v 4.10-7 (C), tng tc vi nhau mt lc 0,1 (N) trong chn khng. Khong cch gia chng l: A. r = 0,6 (cm). B. r = 0,6 (m). C. r = 6 (m). D. r = 6 (cm). -6 -6 1.12* C hai in tch q1 = + 2.10 (C), q2 = - 2.10 (C), t ti hai im A, B trong chn khng v cch nhau mt khong 6 (cm). Mt in tch q3 = + 2.10-6 (C), t trn ng trung trc ca AB, cch AB mt khong 4 (cm). ln ca lc in do hai in tch q1 v q2 tc dng ln in tch q3 l: A. F = 14,40 (N). B. F = 17,28 (N). C. F = 20,36 (N). D. F = 28,80 (N).

2. Thuyt Electron. nh lut bo ton in tch1.13 Pht biu no sau y l khng ng?

Ti liu n tp Vt L lp 11 nm hc 2010-2011

Trang 1

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. Ht lectron l ht c mang in tch m, c ln 1,6.10-19 (C). B. Ht lectron l ht c khi lng m = 9,1.10-31 (kg). C. Nguyn t c th mt hoc nhn thm lectron tr thnh ion. D. lectron khng th chuyn ng t vt ny sang vt khc. 1.14 Pht biu no sau y l khng ng? A. Theo thuyt lectron, mt vt nhim in dng l vt thiu lectron. B. Theo thuyt lectron, mt vt nhim in m l vt tha lectron. C. Theo thuyt lectron, mt vt nhim in dng l vt nhn thm cc ion dng. D. Theo thuyt lectron, mt vt nhim in m l vt nhn thm lectron. 1.15 Pht bit no sau y l khng ng? A. Vt dn in l vt c cha nhiu in tch t do. B. Vt cch in l vt c cha rt t in tch t do. C. Vt dn in l vt c cha rt t in tch t do. D. Cht in mi l cht c cha rt t in tch t do. 1.16 Pht biu no sau y l khng ng? A. Trong qu trnh nhim in do c st, lectron chuyn t vt ny sang vt kia. B. Trong qu trnh nhim in do hng ng, vt b nhim in vn trung ho in. C. Khi cho mt vt nhim in dng tip xc vi mt vt cha nhim in, th lectron chuyn t vt cha nhim in sang vt nhim in dng. D. Khi cho mt vt nhim in dng tip xc vi mt vt cha nhim in, th in tch dng chuyn t vt vt nhim in dng sang cha nhim in. 1.17 Khi a mt qu cu kim loi khng nhim in li gn mt qu cu khc nhim in th A. hai qu cu y nhau. B. hai qu cu ht nhau. C. khng ht m cng khng y nhau. D. hai qu cu trao i in tch cho nhau. 1.18 Pht biu no sau y l khng ng? A. Trong vt dn in c rt nhiu in tch t do. B. Trong in mi c rt t in tch t do. C. Xt v ton b th mt vt nhim in do hng ng vn l mt vt trung ho in. D. Xt v ton b th mt vt nhim in do tip xc vn l mt vt trung ho in.

3. in trng1.19 Pht biu no sau y l khng ng? A. in trng tnh l do cc ht mang in ng yn sinh ra. B. Tnh cht c bn ca in trng l n tc dng lc in ln in tch t trong n. C. Vct cng in trng ti mt im lun cng phng, cng chiu vi vect lc in tc dng ln mt in tch t ti im trong in trng. D. Vct cng in trng ti mt im lun cng phng, cng chiu vi vect lc in tc dng ln mt in tch dng t ti im trong in trng. 1.20 t mt in tch dng, khi lng nh vo mt in trng u ri th nh. in tch s chuyn ng: A. dc theo chiu ca ng sc in trng. B. ngc chiu ng sc in trng. C. vung gc vi ng sc in trng. D. theo mt qu o bt k. 1.21 t mt in tch m, khi lng nh vo mt in trng u ri th nh. in tch s chuyn ng: A. dc theo chiu ca ng sc in trng. B. ngc chiu ng sc in trng. C. vung gc vi ng sc in trng. D. theo mt qu o bt k. 1.22 Pht biu no sau y v tnh cht ca cc ng sc in l khng ng? A. Ti mt im trong in tng ta c th v c mt ng sc i qua. B. Cc ng sc l cc ng cong khng kn. C. Cc ng sc khng bao gi ct nhau. D. Cc ng sc in lun xut pht t in tch dng v kt thc in tch m. 1.23 Pht biu no sau y l khng ng?


Trang 2

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. in ph cho ta bit s phn b cc ng sc trong in trng. B. Tt c cc ng sc u xut pht t in tch dng v kt thc in tch m. C. Cng c khi ng sc in khng xut pht t in tch dng m xut pht t v cng. D. Cc ng sc ca in trng u l cc ng thng song song v cch u nhau. 1.24 Cng thc xc nh cng in trng gy ra bi in tch Q < 0, ti mt im trong chn khng, cch in tch Q mt khong r l:9 A. E = 9.10

Q r2

9 B. E = 9.10

Q r2

9 C. E = 9.10

Q r

9 D. E = 9.10

Q r

1.25 Mt in tch t ti im c cng in trng 0,16 (V/m). Lc tc dng ln in tch bng 2.10-4 (N). ln in tch l: A. q = 8.10-6 ( C). B. q = 12,5.10-6 ( C). C. q = 1,25.10-3 (C). D. q = 12,5 ( C). 1.26 Cng in trng gy ra bi in tch Q = 5.10 -9 (C), ti mt im trong chn khng cch in tch mt khong 10 (cm) c ln l: A. E = 0,450 (V/m). B. E = 0,225 (V/m). C. E = 4500 (V/m). D. E = 2250 (V/m). 1.27 Ba in tch q ging ht nhau c t c nh ti ba nh ca mt tam gic u c cnh a. ln cng in trng ti tm ca tam gic l:9 A. E = 9.10

Q a2

9 B. E = 3.9.10

Q a2

9 C. E = 9.9.10

Q a2

D. E = 0.

1.28 Hai in tch q1 = 5.10-9 (C), q2 = - 5.10-9 (C) t ti hai im cch nhau 10 (cm) trong chn khng. ln cng in trng ti im nm trn ng thng i qua hai in tch v cch u hai in tch l: A. E = 18000 (V/m). B. E = 36000 (V/m). C. E = 1,800 (V/m). D. E = 0 (V/m). 1.29 Hai in tch q1 = q2 = 5.10-16 (C), t ti hai nh B v C ca mt tam gic u ABC cnh bng 8 (cm) trong khng kh. Cng in trng ti nh A ca tam gic ABC c ln l: A. E = 1,2178.10-3 (V/m). B. E = 0,6089.10-3 (V/m). C. E = 0,3515.10-3 (V/m). D. E = 0,7031.10-3 (V/m). 1.30 Hai in tch q1 = 5.10-9 (C), q2 = - 5.10-9 (C) t ti hai im cch nhau 10 (cm) trong chn khng. ln cng in trng ti im nm trn ng thng i qua hai in tch v cch q1 5 (cm), cch q2 15 (cm) l: A. E = 16000 (V/m). B. E = 20000 (V/m). C. E = 1,600 (V/m). D. E = 2,000 (V/m). -16 -16 1.31 Hai in tch q1 = 5.10 (C), q2 = - 5.10 (C), t ti hai nh B v C ca mt tam gic u ABC cnh bng 8 (cm) trong khng kh. Cng in trng ti nh A ca tam gic ABC c ln l: A. E = 1,2178.10-3 (V/m). B. E = 0,6089.10-3 (V/m). C. E = 0,3515.10-3 (V/m). D. E = 0,7031.10-3 (V/m). 4. Cng ca lc in. Hiu in th 1.32 Cng thc xc nh cng ca lc in trng lm dch chuyn in tch q trong in trng u E l A = qEd, trong d l: A. khong cch gia im u v im cui. B. khong cch gia hnh chiu im u v hnh chiu im cui ln mt ng sc. C. di i s ca on t hnh chiu im u n hnh chiu im cui ln mt ng sc, tnh theo chiu ng sc in. D. di i s ca on t hnh chiu im u n hnh chiu im cui ln mt ng sc. 1.33 Pht biu no sau y l khng ng? A. Cng ca lc in tc dng ln mt in tch khng ph thuc vo dng ng i ca in tch m ch ph thuc vo v tr im u v im cui ca on ng i trong in trng. B. Hiu in th gia hai im trong in trng l i lng c trng cho kh nng sinh cng ca in trng lm dch chuyn in tch gia hai im .


Trang 3

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. Hiu in th gia hai im trong in trng l i lng c trng cho in trng tc dng lc mnh hay yu khi t in tch th ti hai im . D. in trng tnh l mt trng th. 1.35 Hai im M v N nm trn cng mt ng sc ca mt in trng u c cng E, hiu in th gia M v N l UMN, khong cch MN = d. Cng thc no sau y l khng ng? A. UMN = VM VN. B. UMN = E.d C. AMN = q.UMN D. E = UMN.d 1.36 Mt in tch q chuyn ng trong in trng khng u theo mt ng cong kn. Gi cng ca lc in trong chuyn ng l A th A. A > 0 nu q > 0. B. A > 0 nu q < 0. C. A = 0 trong mi trng hp. D. A 0 cn du ca A cha xc nh v cha bit chiu chuyn ng ca q. 1.37 Hai tm kim loi song song, cch nhau 2 (cm) v c nhim in tri du nhau. Mun lm cho in tch q = 5.10 10 (C) di chuyn t tm ny n tm kia cn tn mt cng A = 2.10 -9 (J). Coi in trng bn trong khong gia hai tm kim loi l in trng u v c cc ng sc in vung gc vi cc tm. Cng in trng bn trong tm kim loi l: A. E = 2 (V/m). B. E = 40 (V/m). C. E = 200 (V/m). D. E = 400 (V/m). 1.38 Mt lectron chuyn ng dc theo ng sc ca mt in trng u. Cng in trng E = 100 (V/m). Vn tc ban u ca lectron bng 300 (km/s). Khi lng ca lectron l m = 9,1.10 -31 (kg). T lc bt u chuyn ng n lc vn tc ca lectron bng khng th lectron chuyn ng c qung ng l: A. S = 5,12 (mm). B. S = 2,56 (mm). C. S = 5,12.10-3 (mm). D. S = 2,56.10-3 (mm). 1.39 Hiu in th gia hai im M v N l UMN = 1 (V). Cng ca in trng lm dch chuyn in tch q = - 1 ( C) t M n N l: A. A = - 1 ( J). B. A = + 1 ( J). C. A = - 1 (J). D. A = + 1 (J). 1.40 Mt qu cu nh khi lng 3,06.10-15 (kg), mang in tch 4,8.10-18 (C), nm l lng gia hai tm kim loi song song nm ngang nhim in tri du, cch nhau mt khong 2 (cm). Ly g = 10 (m/s 2). Hiu in th t vo hai tm kim loi l: A. U = 255,0 (V). B. U = 127,5 (V). C. U = 63,75 (V). D. U = 734,4 (V). 1.41 Cng ca lc in trng lm di chuyn mt in tch gia hai im c hiu in th U = 2000 (V) l A = 1 (J). ln ca in tch l A. q = 2.10-4 (C). B. q = 2.10-4 ( C). C. q = 5.10-4 (C). D. q = 5.10-4 ( C). 1.42 Mt in tch q = 1 ( C) di chuyn t im A n im B trong in trng, n thu c mt nng lng W = 0,2 (mJ). Hiu in th gia hai im A, B l: A. U = 0,20 (V). B. U = 0,20 (mV). C. U = 200 (kV). D. U = 200 (V).

5. Bi tp v lc Cu lng v in trng 1.43 Cho hai in tch dng q1 = 2 (nC) v q2 = 0,018 ( C) t c nh v cch nhau 10 (cm). t thm in tch thba q0 ti mt im trn ng ni hai in tch q1, q2 sao cho q0 nm cn bng. V tr ca q0 l A. cch q1 2,5 (cm) v cch q2 7,5 (cm). B. cch q1 7,5 (cm) v cch q2 2,5 (cm). C. cch q1 2,5 (cm) v cch q2 12,5 (cm). D. cch q1 12,5 (cm) v cch q2 2,5 (cm). -2 -2 1.44 Hai in tch im q1 = 2.10 ( C) v q2 = - 2.10 ( C) t ti hai im A v B cch nhau mt on a = 30 (cm) trong khng kh. Lc in tc dng ln in tch q0 = 2.10-9 (C) t ti im M cch u A v B mt khong bng a c ln l: A. F = 4.10-10 (N). B. F = 3,464.10-6 (N). C. F = 4.10-6 (N). D. F = 6,928.10-6 (N). 1.45 Hai in tch im q1 = 0,5 (nC) v q2 = - 0,5 (nC) t ti hai im A, B cch nhau 6 (cm) trong khng kh. Cng in trng ti trung im ca AB c ln l: A. E = 0 (V/m). B. E = 5000 (V/m). C. E = 10000 (V/m). D. E = 20000 (V/m). 1.46 Hai in tch im q1 = 0,5 (nC) v q2 = - 0,5 (nC) t ti hai im A, B cch nhau 6 (cm) trong khng kh. Cng


Trang 4

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang in trng ti im M nm trn trung trc ca AB, cch trung im ca AB mt khong l = 4 (cm) c ln l: A. E = 0 (V/m). B. E = 1080 (V/m). C. E = 1800 (V/m). D. E = 2160 (V/m). 1.47 Cho hai bn kim loi phng t song song tch in tri du, mt lectron bay vo in trng gi hai bn kim loi ni trn, vi vn tc ban u v 0 vung gc vi cc ng sc in. B qua tc dng ca trong trng. Qu o ca lectron l: A. ng thng song song vi cc ng sc in. B. ng thng vung gc vi cc ng sc in. C. mt phn ca ng hypebol. D. mt phn ca ng parabol. 1.48 Cho hai bn kim loi phng t song song tch in tri du, th mt lectron khng vn tc ban u vo in trng gi hai bn kim loi trn. B qua tc dng ca trng trng. Qu o ca lectron l: A. ng thng song song vi cc ng sc in. B. ng thng vung gc vi cc ng sc in. C. mt phn ca ng hypebol. D. mt phn ca ng parabol. -7 1.49 Mt in tch q = 10 (C) t ti im M trong in trng ca mt in tch im Q, chu tc dng ca lc F = 3.10-3 (N). Cng in trng do in tch im Q gy ra ti im M c ln l: A. EM = 3.105 (V/m). B. EM = 3.104 (V/m). C. EM = 3.103 (V/m). D. EM = 3.102 (V/m). 1.50 Mt in tch im dng Q trong chn khng gy ra ti im M cch in tch mt khong r = 30 (cm), mt in trng c cng E = 30000 (V/m). ln in tch Q l: A. Q = 3.10-5 (C). B. Q = 3.10-6 (C). C. Q = 3.10-7 (C). D. Q = 3.10-8 (C). 1.51 Hai in tch im q1 = 2.10-2 ( C) v q2 = - 2.10-2 ( C) t ti hai im A v B cch nhau mt on a = 30 (cm) trong khng kh. Cng in trng ti im M cch u A v B mt khong bng a c ln l: A. EM = 0,2 (V/m). B. EM = 1732 (V/m). C. EM = 3464 (V/m). D. EM = 2000 (V/m).

7. T in1.59 Pht biu no sau y l khng ng? A. T in l mt h hai vt dn t gn nhau nhng khng tip xc vi nhau. Mi vt gi l mt bn t. B. T in phng l t in c hai bn t l hai tm kim loi c kch thc ln t i din vi nhau. C. in dung ca t in l i lng c trng cho kh nng tch in ca t in v c o bng thng s gia in tch ca t v hiu in th gia hai bn t. D. Hiu in th gii hn l hiu in th ln nht t vo hai bn t in m lp in mi ca t in b nh thng. 1.60 in dung ca t in khng ph thuc vo: A. Hnh dng, kch thc ca hai bn t. B. Khong cch gia hai bn t. C. Bn cht ca hai bn t. D. Cht in mi gia hai bn t. 1.65 Mt t in c in dung 500 (pF) c mc vo hiu in th 100 (V). in tch ca t in l: A. q = 5.104 (C). B. q = 5.104 (nC). C. q = 5.10-2 (C). D. q = 5.10-4 (C). 1.66 Mt t in phng gm hai bn c dng hnh trn bn knh 3 (cm), t cch nhau 2 (cm) trong khng kh. in dung ca t in l: A. C = 1,25 (pF). B. C = 1,25 (nF). C. C = 1,25 ( F). D. C = 1,25 (F). 1.67 Mt t in phng gm hai bn c dng hnh trn bn knh 5 (cm), t cch nhau 2 (cm) trong khng kh. in trng nh thng i vi khng kh l 3.105(V/m). Hu in th ln nht c th t vo hai bn cc ca t in l: A. Umax = 3000 (V). B. Umax = 6000 (V). C. Umax = 15.103 (V). D. Umax = 6.105 (V). 1.70 Mt t in phng c mc vo hai cc ca mt ngun in c hiu in th 50 (V). Ngt t in ra khi ngun ri ko cho khong cch gia hai bn t tng gp hai ln th hiu in th gia hai bn t c gi tr l: A. U = 50 (V). B. U = 100 (V). C. U = 150 (V). D. U = 200 (V).

8. Nng lng in trng1.79 Pht biu no sau y l ng? A. Sau khi np in, t in c nng lng, nng lng tn ti di dng ho nng.


Trang 5

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangB. Sau khi np in, t in c nng lng, nng lng tn ti di dng c nng. C. Sau khi np in, t in c nng lng, nng lng tn ti di dng nhit nng. D. Sau khi np in, t in c nng lng, nng lng l nng lng ca in trng trong t in. 1.80 Mt t in c in dung C, c np in n hiu in th U, in tch ca t l Q. Cng thc no sau y khng phi l cng thc xc nh nng lng ca t in? A. W =

1 Q2 2 C

B. W =

1 U2 2 C

C. W =

1 CU 2 2

D. W =

1 QU 2

1.81 Mt t in c in dung C, c np in n hiu in th U, in tch ca t l Q. Cng thc xc nh mt nng lng in trng trong t in l: A. w =

1 Q2 2 C

B. w =

1 CU 2 2

C. w =

1 QU 2

D. w =

E 2 9.10 9.8

P N CHNG 1 : IN TCH- IN TRNG 1C 16D 31D 46D 61B 76C 2B 17B 32C 47D 62C 77A 3C 18D 33C 48A 63B 78B 4C 19C 34B 49B 64A 79D 5D 20A 35D 50C 65C 80B 6C 21B 36A 51D 66A 81D 7C 22D 37C 52D 67B 82C 8B 23B 38B 53B 68C 83A 9A 24B 39A 54C 69A 84B 10D 25C 40B 55B 70B 85A 11D 26C 41C 56D 71B 86B 12B 27D 42D 57A 72A 87C 13D 28B 43A 58D 73D 88D 14C 29A 44C 59D 74D 89A 15C 30A 45C 60C 75D 90B 91C

Chng II. Dng in khng iDng in khng i. Ngun in2.1 Pht biu no sau y l khng ng? A. Dng in l dng cc in tch dch chuyn c hng. B. Cng dng in l i lng c trng cho tc dng mnh, yu ca dng in v c o bng in lng chuyn qua tit din thng ca vt dn trong mt n v thi gian. C. Chiu ca dng in c quy c l chiu chuyn dch ca cc in tch dng. D. Chiu ca dng in c quy c l chiu chuyn dch ca cc in tch m. 2.2 Pht biu no sau y l khng ng? A. Dng in c tc dng t. V d: nam chm in. B. Dng in c tc dng nhit. V d: bn l in. C. Dng in c tc dng ho hc. V d: acquy nng ln khi np in. D. Dng in c tc dng sinh l. V d: hin tng in git. 2.3 Pht biu no sau y l ng? A. Ngun in l thit b to ra v duy tr hiu in th nhm duy tr dng in trong mch. Trong ngun in di tc dng ca lc l cc in tch dng dch chuyn t cc dng sang cc m. B. Sut in ng ca ngun in l i lng c trng cho kh nng sinh cng ca ngun in v c o bng thng s gia cng ca lc l thc hin khi lm dch chuyn mt in tch dng q bn trong ngun in t cc m n cc dng v ln ca in tch q . C. Sut in ng ca ngun in l i lng c trng cho kh nng sinh cng ca ngun in v c o bng thng s gia cng ca lc l thc hin khi lm dch chuyn mt in tch m q bn trong ngun in t cc m n cc dng v ln ca in tch q . D. Sut in ng ca ngun in l i lng c trng cho kh nng sinh cng ca ngun in v c o bng


Trang 6

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giangthng s gia cng ca lc l thc hin khi lm dch chuyn mt in tch dng q bn trong ngun in t cc dng n cc m v ln ca in tch q . 2.4 in tch ca lectron l - 1,6.10-19 (C), in lng chuyn qua tit din thng ca dy dn trong 30 (s) l 15 (C). S lectron chuyn qua tit din thng ca dy dn trong thi gian mt giy l A. 3,125.1018. B. 9,375.1019. C. 7,895.1019. D. 2,632.1018. 2.6 Sut in ng ca ngun in c trng cho A. kh nng tch in cho hai cc ca n. B. kh nng d tr in tch ca ngun in. C. kh nng thc hin cng ca lc l bn trong ngun in. D. kh nng tc dng lc in ca ngun in. 2.7 on mch gm in tr R1 = 100 ( ) mc ni tip vi in tr R2 = 300 ( ), in tr ton mch l: A. RTM = 200 ( ). B. RTM = 300 ( ). C. RTM = 400 ( ). D. RTM = 500 ( ). 2.8 Cho on mch gm in tr R1 = 100 ( ), mc ni tip vi in tr R2 = 200 ( ), hiu in th gia hai u on mch l 12 (V). Hiu in th gia hai u in tr R1 l A. U1 = 1 (V). B. U1 = 4 (V). C. U1 = 6 (V). D. U1 = 8 (V). 2.9 on mch gm in tr R1 = 100 ( ) mc song song vi in tr R2 = 300 ( ), in tr ton mch l: A. RTM = 75 ( ). B. RTM = 100 ( ). C. RTM = 150 ( ). D. RTM = 400 ( ). 2.10 Cho on mch gm in tr R1 = 100 ( ), mc ni tip vi in tr R2 = 200 ( ). t vo hai u on mch mt hiu in th U khi hiu in th gia hai u in tr R1 l 6 (V). Hiu in th gia hai u on mch l: A. U = 12 (V). B. U = 6 (V). C. U = 18 (V). D. U = 24 (V). 2.13 Trong ngun in lc l c tc dng A. lm dch chuyn cc in tch dng t cc dng ca ngun in sang cc m ca ngun in. B. lm dch chuyn cc in tch dng t cc m ca ngun in sang cc dng ca ngun in. C. lm dch chuyn cc in tch dng theo chiu in trng trong ngun in. D. lm dch chuyn cc in tch m ngc chiu in trng trong ngun in. 12. in nng v cng sut in. nh lut Jun Lenx 2.15 Pht biu no sau y l khng ng? A. Cng ca dng in chy qua mt on mch l cng ca lc in trng lm di chuyn cc in tch t do trong on mch v bng tch ca hiu in th gia hai u on mch vi cng dng in v thi gian dng in chy qua on mch . B. Cng sut ca dng in chy qua on mch bng tch ca hiu in th gia hai u on mch v cng dng in chy qua on mch . C. Nhit lng to ra trn mt vt dn t l thun vi in tr ca vt, vi cng dng in v vi thi gian dng in chy qua vt. D. Cng sut to nhit vt dn khi c dng in chy qua c trng cho tc to nhit ca vt dn v c xc nh bng nhit lng to ra vt n trong mt n v thi gian. 2.16 Nhit lng to ra trn vt dn khi c dng in chy qua A. t l thun vi cng dng in chy qua vt dn. B. t l thun vi bnh phng cng dng in chy qua vt dn. C. t l nghch vi cng dng in chy qua vt dn. D. t l nghch vi bnh phng cng dng in chy qua vt dn. 2.17 Pht biu no sau y l khng ng? A. Nhit lng to ra trn vt dn t l thun vi in tr ca vt. B. Nhit lng to ra trn vt dn t l thun vi thi gian dng in chy qua vt. C. Nhit lng to ra trn vt dn t l vi bnh phng cng dng in cy qua vt.


Trang 7

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangD. Nhit lng to ra trn vt dn t l nghch vi hiu in th gia hai u vt dn. 2.18 Sut phn in ca my thu c trng cho s A. chuyn ho in nng thnh nhit nng ca my thu. B. chuyn ho nhit nng thnh in nng ca my thu. C. chuyn ho c nng thnh in nng ca my thu. D. chuyn ho in nng thnh dng nng lng khc, khng phi l nhit ca my thu. 2.20 Dng mt dy dn mc bng n vo mng in. Dy tc bng n nng sng, dy dn hu nh khng sng ln v: A. Cng dng in chy qua dy tc bng n ln hn nhiu cng dng in chy qua dy dn. B. Cng dng in chy qua dy tc bng n nh hn nhiu cng dng in chy qua dy dn. C. in tr ca dy tc bng n ln hn nhiu so vi in tr ca dy dn. D. in tr ca dy tc bng n nh hn nhiu so vi in tr ca dy dn. 2.22 Cng ca dng in c n v l: A. J/s B. kWh C. W D. kVA 2.23 Cng sut ca ngun in c xc nh theo cng thc: A. P = EIt. B. P = UIt. C. P = Ei. D. P = UI. 2.24 Hai bng n 1( 220V 25W), 2 (220V 100W) khi sng bnh thng th A. cng dng in qua bng n 1 ln gp hai ln cng dng in qua bng n 2. B. cng dng in qua bng n 2 ln gp bn ln cng dng in qua bng n 1. C. cng dng in qua bng n 1 bng cng dng in qua bng n 2. D. in tr ca bng n 2 ln gp bn ln in tr ca bng n 1. 2.26 bng n loi 120V 60W sng bnh thng mng in c hiu in th l 220V, ngi ta phi mc ni tip vi bng n mt in tr c gi tr A. R = 100 ( ). B. R = 150 ( ). C. R = 200 ( ). D. R = 250 ( ). 13. nh lut m cho ton mch 2.27 i vi mch in kn gm ngun in vi mch ngoi l in tr th hiu in th mch ngoi A.t l thun vi cng dng in chy trong mch. B. tng khi cng dng in trong mch tng. C. gim khi cng dng in trong mch tng. D. t l nghch vi cng dng in chy trong mch. 2.28 Pht biu no sau y l khng ng? A. Cng dng in trong on mch ch cha in tr R t l vi hiu in th U gia hai u on mch v t l nghch vi in tr R. B. Cng dng in trong mch kn t l thun vi sut in ng ca ngun in v t l nghch vi in tr ton phn ca mch. C. Cng sut ca dng in chy qua on mch bng tch ca hiu in th gia hai u on mch v cng dng in chy qua on mch . D. Nhit lng to ra trn mt vt dn t l thun vi in tr ca vt, vi cng dng in v vi thi gian dng in chy qua vt. 2.30 Mt ngun in c in tr trong 0,1 ( ) c mc vi in tr 4,8 ( ) thnh mch kn. Khi hiu in th gia hai cc ca ngun in l 12 (V). Cng dng in trong mch l A. I = 120 (A). B. I = 12 (A). C. I = 2,5 (A). D. I = 25 (A). 2.31 Mt ngun in c in tr trong 0,1 ( ) c mc vi in tr 4,8 ( ) thnh mch kn. Khi hiu in th gia hai cc ca ngun in l 12 (V). Sut in ng ca ngun in l: A. E = 12,00 (V). B. E = 12,25 (V). C. E = 14,50 (V). D. E = 11,75 (V).


Trang 8

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang2.32 Ngi ta mc hai cc ca ngun in vi mt bin tr c th thay i t 0 n v cc. Khi gi tr ca bin tr rt ln th hiu in th gia hai cc ca ngun in l 4,5 (V). Gim gi tr ca bin tr n khi cng dng in trong mch l 2 (A) th hiu in th gia hai cc ca ngun in l 4 (V). Sut in ng v in tr trong ca ngun in l: A. E = 4,5 (V); r = 4,5 ( ). B. E = 4,5 (V); r = 2,5 ( ). C. E = 4,5 (V); r = 0,25 ( ). D. E = 9 (V); r = 4,5 ( ). 2.33 Mt ngun in c sut in ng E = 6 (V), in tr trong r = 2 ( ), mch ngoi c in tr R. cng sut tiu th mch ngoi l 4 (W) th in tr R phi c gi tr A. R = 1 ( ). B. R = 2 ( ). C. R = 3 ( ). D. R = 6 (v). 2.34 Dng mt ngun in thp sng ln lt hai bng n c in tr R1 = 2 ( ) v R2 = 8 ( ), khi cng sut tiu th ca hai bng n l nh nhau. in tr trong ca ngun in l: A. r = 2 ( ). B. r = 3 ( ). C. r = 4 ( ). D. r = 6 ( ). 2.35 Mt ngun in c sut in ng E = 6 (V), in tr trong r = 2 (), mch ngoi c in tr R. cng sut tiu th mch ngoi l 4 (W) th in tr R phi c gi tr A. R = 3 ( ). B. R = 4 ( ). C. R = 5 ( ). D. R = 6 ( ). 2.36 Mt ngun in c sut in ng E = 6 (V), in tr trong r = 2 (), mch ngoi c in tr R. cng sut tiu th mch ngoi t gi tr ln nht th in tr R phi c gi tr A. R = 1 ( ). B. R = 2 ( ). C. R = 3 ( ). D. R = 4 ( ). 2.37 Bit rng khi in tr mch ngoi ca mt ngun in tng t R1 = 3 ( ) n R2 = 10,5 ( ) th hiu in th gia hai cc ca ngun tng gp hai ln. in tr trong ca ngun in l: A. r = 7,5 ( ). B. r = 6,75 ( ). C. r = 10,5 ( ). D. r = 7 ( ). 2.38 Cho mt mch in kn gm ngun in c sut in ng E = 12 (V), in tr trong r = 2,5 ( ), mch ngoi gm in tr R1 = 0,5 ( ) mc ni tip vi mt in tr R. cng sut tiu th mch ngoi ln nht th in tr R phi c gi tr A. R = 1 ( ). B. R = 2 ( ). C. R = 3 ( ). D. R = 4 ( ). 2.39* Cho mt mch in kn gm ngun in c sut in ng E = 12 (V), in tr trong r = 2,5 ( ), mch ngoi gm in tr R1 = 0,5 ( ) mc ni tip vi mt in tr R. cng sut tiu th trn in tr R t gi tr ln nht th in tr R phi c gi tr A. R = 1 ( ). B. R = 2 ( ). C. R = 3 ( ). D. R = 4 ( ). 2.43 Ngun in vi sut in ng E, in tr trong r, mc vi in tr ngoi R = r, cng dng in trong mch l I. Nu thay ngun in bng 3 ngun in ging ht n mc ni tip th cng dng in trong mch l: A. I = 3I. B. I = 2I. C. I = 2,5I. D. I = 1,5I. 2.44 Ngun in vi sut in ng E, in tr trong r, mc vi in tr ngoi R = r, cng dng in trong mch l I. Nu thay ngung in bng 3 ngun in ging ht n mc song song th cng dng in trong mch l: A. I = 3I. B. I = 2I. C. I = 2,5I. D. I = 1,5I. 15. Bi tp v nh lut m v cng sut in 2.47 Cho mt on mch gm hai in tr R1 v R2 mc song song v mc vo mt hiu in th khng i. Nu gim tr s ca in tr R2 th A. st th trn R2 gim. B. dng in qua R1 khng thay i. C. dng in qua R1 tng ln. D. cng sut tiu th trn R2 gim. 2.48 Cho mt mch in kn gm ngun in c sut in ng E = 12 (V), in tr trong r = 2 (), mch ngoi gm in tr R1 = 6 () mc song song vi mt in tr R. cng sut tiu th mch ngoi ln nht th in tr R phi c gi tr A. R = 1 (). B. R = 2 (). C. R = 3 (). D. R = 4 (). 2.49 Khi hai in tr ging nhau mc ni tip vo mt hiu in th U khng i th cng sut tiu th ca chng l 20 (W). Nu mc chng song song ri mc vo hiu in th ni trn th cng sut tiu th ca chng l: A. 5 (W). B. 10 (W). C. 40 (W). D. 80 (W). 2.50 Khi hai in tr ging nhau mc song vo mt hiu in th U khng i th cng sut tiu th ca chng l 20


Trang 9

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang(W). Nu mc chng ni tip ri mc vo hiu in th ni trn th cng sut tiu th ca chng l: A. 5 (W). B. 10 (W). C. 40 (W). D. 80 (W). 2.51 Mt m in c hai dy dn R1 v R2 un nc. Nu dng dy R1 th nc trong m s si sau thi gian t1 = 10 (pht). Cn nu dng dy R2 th nc s si sau thi gian t2 = 40 (pht). Nu dng c hai dy mc song song th nc s si sau thi gian l: A. t = 4 (pht). B. t = 8 (pht). C. t = 25 (pht). D. t = 30 (pht). 2.52 Mt m in c hai dy dn R1 v R2 un nc. Nu dng dy R1 th nc trong m s si sau thi gian t1 = 10 (pht). Cn nu dng dy R2 th nc s si sau thi gian t 2 = 40 (pht). Nu dng c hai dy mc ni tip th nc s si sau thi gian l: A. t = 8 (pht). B. t = 25 (pht). C. t = 30 (pht). D. t = 50 (pht). 2.53** Cho mt mch in kn gm ngun in c sut in ng E = 12 (V), in tr trong r = 3 (), mch ngoi gm in tr R1 = 6 () mc song song vi mt in tr R. cng sut tiu th trn in tr R t gi tr ln nht th in tr R phi c gi tr A. R = 1 (). B. R = 2 (). C. R = 3 (). D. R = 4 (). 16. Thc hnh: o sut in ng v in tr trong ca ngun in 2.54 i vi mch in kn gm ngun in vi mch ngoi l in tr th hiu in th mch ngoi A. gim khi cng dng in trong mch tng. B.t l thun vi cng dng in chy trong mch. C. tng khi cng dng in trong mch tng. D. t l nghch vi cng dng in chy trong mch. 2.55 Biu thc no sau y l khng ng? A. I =

E R+r

B. I =

U R

C. E = U Ir

D. E = U + Ir

2.57 Ngi ta mc hai cc ca ngun in vi mt bin tr c th thay i t 0 n v cc. Khi gi tr ca bin tr rt ln th hiu in th gia hai cc ca ngun in l 4,5 (V). Gim gi tr ca bin tr n khi cng dng in trong mch l 2 (A) th hiu in th gia hai cc ca ngun in l 4 (V). Sut in ng v in tr trong ca ngun in l: A. E = 4,5 (V); r = 4,5 (). B. E = 4,5 (V); r = 2,5 (). C. E = 4,5 (V); r = 0,25 (). D. E = 9 (V); r = 4,5 (). P N CHNG 2 : DNG IN KHNG I 1D 16B 31B 46B 2C 17D 32C 47B 3B 18D 33A 48C 4A 19D 34C 49D 5A 20C 35B 50A 6C 21A 36B 51B 7C 22B 37D 52D 8B 23C 38B 53B 9A 24B 39C 54A 10C 25C 40D 55C 11C 26C 41B 56D 12D 27C 42A 57C 13B 28D 43D 58C 14C 29C 44D 15C 30C 45B

Chng III. Dng in trong cc mi trng17. Dng in trong kim loi3.1 Khi nhit ca dy kim loi tng, in tr ca n s A. Gim i. B. Khng thay i. C. Tng ln. D. Ban u tng ln theo nhit nhng sau li gim dn. 3.2 Nguyn nhn gy ra hin tng to nhit trong dy dn khi c dng in chy qua l: A. Do nng lng ca chuyn ng c hng ca electron truyn cho ion(+) khi va chm. B. Do nng lng dao ng ca ion (+) truyn cho eclectron khi va chm.


Trang 10

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. Do nng lng ca chuyn ng c hng ca electron truyn cho ion (-) khi va chm. D. Do nng lng ca chuyn ng c hng ca electron, ion (-) truyn cho ion (+) khi va chm. 3.3 Nguyn nhn gy ra in tr ca kim loi l: A. Do s va chm ca cc electron vi cc ion (+) cc nt mng. B. Do s va chm ca cc ion (+) cc nt mng vi nhau. C. Do s va chm ca cc electron vi nhau. D. C B v C ng. 3.4 Khi nhit tng th in tr sut ca thanh kim loi cng tng do: A. Chuyn ng v nhit ca cc electron tng ln. B. Chuyn ng nh hng ca cc electron tng ln. C. Bin dao ng ca cc ion quanh nt mng tng ln. D. Bin dao ng ca cc ion quanh nt mng gim i. 3.5 Mt si dy ng c in tr 74 500 C, c in tr sut = 4,1.10-3K-1. in tr ca si dy 1000 C l: A. 86,6 B. 89,2 C. 95 D. 82 3.6 Pht biu no sau y l khng ng? A. Ht ti in trong kim loi l electron. B. Dng in trong kim loi tun theo nh lut m nu nhit trong kim loi c gi khng i C. Ht ti in trong kim loi l in dng v in m. D. Dng in chy qua dy dn kim loi gy ra tc dng nhit. 3.7 Mt si dy bng nhm c in tr 120 nhit 200C, in tr ca si dy 1790C l 204. in tr sut ca nhm l: A. 4,8.10-3K-1 B. 4,4.10-3K-1 C. 4,3.10-3K-1 D. 4,1.10-3K-1 3.8 Pht biu no sau y l ng? Khi cho hai thanh kim loi c bn cht khc nhau tip xc vi nhau th: A. C s khuch tn electron t cht c nhiu electron hn sang cht c t electron hn. B. C s khuch tn in t kim loi ny sang kim loi kia. C. C s khuch tn eletron t kim loi c mt electron ln sang kim loi c mt electron nh hn. D. Khng c hin tng g xy ra. 18. Hin tng siu dn 3.10 Hai thanh kim loi c ni vi nhau bi hai u mi hn to thnh mt mch kn, hin tng nhit in ch xy ra khi: A. Hai thanh kim loi c bn cht khc nhau v nhit hai u mi hn bng nhau. B. Hai thanh kim loi c bn cht khc nhau v nhit hai u mi hn khc nhau. C. Hai thanh kim loi c bn cht ging nhau v nhit hai u mi hn bng nhau. D. Hai thanh kim loi c bn cht ging nhau v nhit hai u mi hn khc nhau. 3.11 Sut in ng nhit in ph thuc vo: A. Hiu nhit (T1 T2) gia hai u mi hn. B. H s n di v nhit . C. Khong cch gia hai mi hn. D. in tr ca cc mi hn. 3.12 Pht biu no sau y l khng ng? A. Cp nhit in gm hai dy dn in c bn cht khc nhau hn ni vi nhau thnh mt mch kn v hai mi hn ca n c gi hai nhit khc nhau. B. Nguyn nhn gy ra sut in ng nhit in l do chuyn ng nhit ca cc ht ti in trong mch in c nhit khng ng nht. C. Sut in ng nhit in E t l nghch vi hiu nhit (T1 T2) gia hai u mi hn ca cp nhit in.


Trang 11

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangD. Sut in ng nhit in E xp x t l vi hiu nhit (T1 T2) gia hai u mi hn ca cp nhit in. 3.13 Pht biu no sau y l khng ng? A. i vi vt liu siu dn, c dng in chy trong mch ta lun phi duy tr mt hiu in th trong mch. B. in tr ca vt siu dn bng khng. C. i vi vt liu siu dn, c kh nng t duy tr dng in trong mch sau khi ngt b ngun in. D. i vi vt liu siu dn, nng lng hao ph do to nhit bng khng. 3.14 Mt mi hn ca mt cp nhit in c h s T = 65 (V/K) c t trong khng kh 200C, cn mi hn kia c nung nng n nhit 2320C. Sut in ng nhit in ca cp nhit khi l A. E = 13,00mV. B. E = 13,58mV. C. E = 13,98mV. D. E = 13,78mV. 3.15 Mt mi hn ca mt cp nhit in c h s T = 48 (V/K) c t trong khng kh 20 0C, cn mi hn kia c nung nng n nhit t0C, sut in ng nhit in ca cp nhit khi l E = 6 (mV). Nhit ca mi hn cn l: A. 1250C. B. 3980K. C. 1450C. D. 4180C. 3.16 Mt mi hn ca mt cp nhit in c h s nhit in tr c t trong khng kh 200C, cn mi hn kia c nung nng n nhit 5000C, sut in ng nhit in ca cp nhit khi l E = 6 (mV). H s khi l: A. 1,25.10-4 (V/K) B. 12,5 (V/K) C. 1,25 (V/K) D. 1,25(mV/K)

19. Dng in trong cht in phn. nh lut Fa-ra-y 3.17 Pht biu no sau y l ng? A. Dng in trong cht in phn l dng chuyn dch c hng ca cc in m, electron i v ant v in dng i v catt. B. Dng in trong cht in phn l dng chuyn dch c hng ca cc electron i v ant v cc in dng i v catt. C. Dng in trong cht in phn l dng chuyn dch c hng ca cc in m i v ant v cc in dng i v catt. D. Dng in trong cht in phn l dng chuyn dch c hng ca cc electron i v t catt v ant, khi catt b nung nng. 3.18 Cng thc no sau y l cng thc ng ca nh lut Fara-y? A. m = F

A I .t n

B. m = D.V

C. I =

m.F .n t. A

D. t =

m.n A.I .F

3.19 Mt bnh in phn ng dung dch AgNO3, cng dng in chy qua bnh in phn l I = 1 (A). Cho AAg=108 (vc), nAg= 1. Lng Ag bm vo catt trong thi gian 16 pht 5 giy l: A. 1,08 (mg). B. 1,08 (g). C. 0,54 (g). D. 1,08 (kg). 3.20 Mt bnh in phn dung dch CuSO4 c ant lm bng ng, in tr ca bnh in phn R = 8 (), c mc vo hai cc ca b ngun E = 9 (V), in tr trong r =1 (). Khi lng Cu bm vo catt trong thi gian 5 h c gi tr l: A. 5 (g). B. 10,5 (g). C. 5,97 (g). D. 11,94 (g). 3.23 Pht biu no sau y l ng? A. Khi ho tan axit, baz hc mui vo trong nc, tt c cc phn t ca chng u b phn li thnh cc in. B. S cp in c to thnh trong dung dch in phn khng thay i theo nhit . C. Bt k bnh in phn no cng c sut phn in. D. Khi c hin tng cc dng tan, dng in trong cht in phn tun theo nh lut m. 3.24 Pht biu no sau y l khng ng khi ni v cch m mt huy chng bc? A. Dng mui AgNO3. B. t huy chng gia ant v catt. C. Dng ant bng bc. D. Dng huy chng lm catt.


Trang 12

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang20. Bi tp v dng in trong kim loi v cht in phn 3.25 Cho dng in chy qua bnh in phn ng dung dch mui ca niken, c ant lm bng niken, bit nguyn t khi v ha tr ca niken ln lt bng 58,71 v 2. Trong thi gian 1h dng in 10A sn ra mt khi lng niken bng: A. 8.10-3kg. B. 10,95 (g). C. 12,35 (g). D. 15,27 (g). 3.26 Cho dng in chy qua bnh in phn cha dung dch CuSO4, c ant bng Cu. Bit rng ng lng ha ca ng k =

1 A . = 3,3.10 7 kg/C. trn catt xut hin 0,33 kg ng, th in tch chuyn qua bnh phi bng: F nB. 106 (C). C. 5.106 (C). D. 107 (C).

A. 105 (C).

3.32 Mt bnh in phn ng dung dch bc nitrat vi ant bng bc. in tr ca bnh in phn l R= 2 (). Hiu in th t vo hai cc l U= 10 (V). Cho A= 108 v n=1. Khi lng bc bm vo cc m sau 2 gi l: A. 40,3g B. 40,3 kg C. 8,04 g D. 8,04.10-2 kg 22. Dng in trong cht kh 3.42 Bn cht dng in trong cht kh l: A. Dng chuyn di c hng ca cc in dng theo chiu in trng v cc in m, electron ngc chiu in trng. B. Dng chuyn di c hng ca cc in dng theo chiu in trng v cc in m ngc chiu in trng. C. Dng chuyn di c hng ca cc in dng theo chiu in trng v cc electron ngc chiu in trng. D. Dng chuyn di c hng ca cc electron theo ngc chiu in trng. 3.43 Pht biu no sau y l ng? A. Ht ti in trong cht kh ch c cc cc in dng v ion m. B. Dng in trong cht kh tun theo nh lut m. C. Ht ti in c bn trong cht kh l electron, in dng v in m. D. Cng dng in trong cht kh p sut bnh thng t l thun vi hiu in th. 3.45 Hin tng h quang in c ng dng A. trong k thut hn in. B. trong k thut m in. C. trong it bn dn. D. trong ng phng in t. 3.46 Cch to ra tia la in l A. Nung nng khng kh gia hai u t in c tch in. B. t vo hai u ca hai thanh than mt hiu in th khong 40 n 50V. C. To mt in trng rt ln khong 3.106 V/m trong chn khng. D. To mt in trng rt ln khong 3.106 V/m trong khng kh. 3.47 Khi to ra h quang in, ban u ta cn phi cho hai u thanh than chm vo nhau A. To ra cng in trng rt ln. B. Tng tnh dn in ch tip xc ca hai thanh than. C. Lm gim in tr ch tip xc ca hai thanh than i rt nh. D. Lm tng nhit ch tip xc ca hai thanh than ln rt ln. 3.48 Pht biu no sau y l ng? A. Hiu in th gy ra st ch c th ln ti hng triu vn. B. Hin tng h quang in ch xy ra khi hiu in th t vo cc cp cc ca thanh than khong 104V. C. Cng dng in trong cht kh lun lun tun theo nh lut m. D. Tia catt l dng chuyn ng ca cc electron bt ra t catt. 3.49 i vi dng in trong chn khng, khi catt b nung nng ng thi hiu in th gia hai u ant v catt ca bng 0 th A. Gia ant v catt khng c cc ht ti in. B. C cc ht ti in l electron, in dng v in m.


Trang 13

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. Cng dng in chy chy mch bng 0. D. Cng dng in chy chy mch khc 0. 23. Dng in trong bn dn 3.50 Pht biu no sau y v c im ca cht bn dn l khng ng? A. in tr sut ca cht bn dn ln hn so vi kim loi nhng nh hn so vi cht in mi. B. in tr sut ca cht bn dn gim mnh khi nhit tng. C. in tr sut ph thuc rt mnh vo hiu in th. D. Tnh cht in ca bn dn ph thuc nhiu vo cc tp cht c mt trong tinh th. 3.51 Bn cht ca dng in trong cht bn dn l: A. Dng chuyn di c hng ca cc electron v l trng ngc chiu in trng. B. Dng chuyn di c hng ca cc electron v l trng cng chiu in trng. C. Dng chuyn di c hng ca cc electron theo chiu in trng v cc l trng ngc chiu in trng. D. Dng chuyn di c hng ca cc l trng theo chiu in trng v cc electron ngc chiu in trng. 3.53 Cu no di y ni v phn loi cht bn dn l khng ng? A. Bn dn hon ton tinh khit l bn dn trong mt electron bng mt l trng. B. Bn dn tp cht l bn dn trong cc ht ti in ch yu c to bi cc nguyn t tp cht. C. Bn dn loi n l bn dn trong mt l trng ln hn rt nhiu mt electron. D. Bn dn loi p l bn dn trong mt electron t do nh hn rt nhiu mt l trng. 3.54 Chn cu ng? A. Electron t do v l trng u chuyn ng ngc chiu in trng. B. Electron t do v l trng u mang in tch m. C. Mt cc ht ti in ph thuc rt nhiu vo cc yu t bn ngoi nh nhit , mc chiu sng. D. linh ng ca cc ht ti in hu nh khng thay i khi nhit tng. 3.55 Pht biu no sau y l khng ng? A. Cu to ca it bn dn gm mt lp tip xc p-n. B. Dng electron chuyn qua lp tip xc p-n ch yu theo chiu t p sang n. C. in tr sut ca bn dn ph thuc vo nh sng chiu vo D. dn in ca cht in phn tng khi nhit tng. 3.57 Hiu in th ca lp tip xc p-n c tc dng: A. Tng cng s khuch tn ca cc ht c bn. B. Tng cng s khuch tn cc l trng t bn dn p sang bn dn n. C. Tng cng s khuch tn cc electron t bn dn n sang bn dn p. D. Tng cng s khuch tn cc electron t bn dn p sang bn dn n. 3.58 Khi lp tip xc p-n c phn cc thun, in trng ngoi c tc dng: A. Tng cng s khuch tn ca cc khng ht c bn. B. Tng cng s khuch tn cc l trng t bn dn n sang bn dn p. C. Tng cng s khuch tn cc electron t bn dn n sang bn dn p. D. Tng cng s khuch tn cc electron t bn dn p sang bn dn n. 3.59 Chn pht biu ng. A. Cht bn dn loi n nhim in m do s ht electron t do nhiu hn cc l trng. B. Khi nhit cng cao th cht bn dn nhim in cng ln. C. Khi mc phn cc ngc vo lp tip xc p-n th in trng ngoi c tc dng tng cng s khuch tn ca cc ht c bn. D. Dng in thun qua lp tip xc p - n l dng khuch tn ca cc ht c bn.


Trang 14

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang24. Linh kin bn dn 3.60 it bn dn c cu to gm: A. mt lp tip xc p n. B. hai lp tip xc p n. C. ba lp tip xc p n. D. bn lp tip xc p n. 3.61 it bn dn c tc dng: A. chnh lu. B. khuch i. C. cho dng in i theo hai chiu. D. cho dng in i theo mt chiu t catt sang ant. 3.62 Pht biu no sau y l khng ng? A. it bn dn c kh nng bin i dng in xoay chiu thnh dng in mt chiu. B. it bn dn c kh nng bin i dng in mt chiu thnh dng in xoay chiu. C. it bn dn c kh nng pht quang khi c dng in i qua. D. it bn dn c kh nng n nh hiu in th gia hai u it khi b phn cc ngc 3.63 Tranzito bn dn c cu to gm: A. mt lp tip xc p n. B. hai lp tip xc p n. C. ba lp tip xc p n. D. bn lp tip xc p n. 3.64 Tranzito bn dn c tc dng: A. chnh lu. B. khuch i. C. cho dng in i theo hai chiu. D. cho dng in i theo mt chiu t catt sang ant. 25. Thc hnh: Kho st c tnh chnh lu ca i t bn dn v c tnh khuch i ca Tranzito 3.65 Dng mt mini ampe k o cng dng in I qua it, v mt vn k o hiu in th U AK gia hai cc A(ant) v K(catt) ca it. Kt qu no sau y l khng ng? A. UAK = 0 th I = 0. B. UAK > 0 th I = 0. C. UAK < 0 th I = 0. D. UAK > 0 th I > 0. 3.66 Dng mt mini ampe k o cng dng in I qua it, v mt vn k o hiu in th U AK gia hai cc A(ant) v K(catt) ca it. Kt qu no sau y l khng ng? A. UAK = 0 th I = 0. B. UAK > 0 v tng th I > 0 v cng tng. C. UAK > 0 v gim th I > 0 v cng gim. D. UAK < 0 v gim th I < 0 v cng gim. 3.67 Dng mt mini ampe k o cng dng in I B qua cc baz, v mt ampe k o cng dng in I C qua clect ca tranzto. Kt qu no sau y l khng ng? A. IB tng th IC tng. B. IB tng th IC gim. C. IB gim th IC gim. D. IB rt nh th IC cng nh. 3.68 Dng mt mini ampe k o cng dng in IB qua cc baz, v mt vn k o hiu in th UCE gia clect v emint ca tranzto mc E chung. Kt qu no sau y l khng ng? A. IB tng th UCE tng. B. IB tng th UCE gim. C. IB gim th UCE tng. D. IB t bo ho th UCE bng khng.

P N CHNG 3 : 1C 18C 35C 52A 2A 19B 36B 53C 3A 20C 37D 54C 4C 21B 38C 55B 5A 22A 39C 56B 6C 23D 40B 57D 7A 24A 41A 58C

Dng in trong cc mi trng8C 25B 42A 59D 9B 26B 43C 60A 10B 27B 44C 61A 11A 28C 45A 62B 12C 29D 46D 63B 13A 30A 47D 64B 14D 31B 48D 65B 15C 32A 49C 66D 16B 33D 50C 67B 17C 34D 51D 68A

Chng IV. T trng26. T trng


Trang 15

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang4.1 Pht biu no sau y l khng ng? Ngi ta nhn ra t trng tn ti xung quanh dy dn mang dng in v: A. c lc tc dng ln mt dng in khc t song song cnh n. B. c lc tc dng ln mt kim nam chm t song song cnh n. C. c lc tc dng ln mt ht mang in chuyn ng dc theo n. D. c lc tc dng ln mt ht mang in ng yn t bn cnh n. 4.2 Tnh cht c bn ca t trng l: A. gy ra lc t tc dng ln nam chm hoc ln dng in t trong n. B. gy ra lc hp dn ln cc vt t trong n. C. gy ra lc n hi tc dng ln cc dng in v nam chm t trong n. D. gy ra s bin i v tnh cht in ca mi trng xung quanh. 4.3 T ph l: A. hnh nh ca cc ng mt st cho ta hnh nh ca cc ng sc t ca t trng. B. hnh nh tng tc ca hai nam chm vi nhau. C. hnh nh tng tc gia dng in v nam chm. D. hnh nh tng tc ca hai dng in chy trong hai dy dn thng song song. 4.4 Pht biu no sau y l khng ng? A. Qua bt k im no trong t trng ta cng c th v c mt ng sc t. B. ng sc t do nam chm thng to ra xung quanh n l nhng ng thng. C. ng sc mau ni c cm ng t ln, ng sc tha ni c cm ng t nh. D. Cc ng sc t l nhng ng cong kn. 4.5 Pht biu no sau y l khng ng? T trng u l t trng c A. cc ng sc song song v cch u nhau. B. cm ng t ti mi ni u bng nhau. C. lc t tc dng ln cc dng in nh nhau. D. cc c im bao gm c phng n A v B. 4.6 Pht biu no sau y l khng ng? A. Tng tc gia hai dng in l tng tc t. B. Cm ng t l i lng c trng cho t trng v mt gy ra tc dng t. C. Xung quanh mi in tch ng yn tn ti in trng v t trng. D. i qua mi im trong t trng ch c mt ng sc t. 4.7 Pht biu no sau y l ng? A. Cc ng mt st ca t ph chnh l cc ng sc t. B. Cc ng sc t ca t trng u c th l nhng ng cong cch u nhau. C. Cc ng sc t lun l nhng ng cong kn. D. Mt ht mang in chuyn ng theo qu o trn trong t trng th qu o chuyn ng ca ht chnh l mt ng sc t. 4.8 Dy dn mang dng in khng tng tc vi A. cc in tch chuyn ng. B. nam chm ng yn. C. cc in tch ng yn. D. nam chm chuyn ng.

27. Phng v chiu ca lc t tc dng ln dng in 4.9 Pht biu no sau y l ng? Mt dng in t trong t trng vung gc vi ng sc t, chiu ca lc t tc dng vo dng in s khng thay


Trang 16

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giangi khi A. i chiu dng in ngc li. B. i chiu cm ng t ngc li. C. ng thi i chiu dng in v i chiu cm ng t. D. quay dng in mt gc 900 xung quanh ng sc t. 4.10 Mt on dy dn c dng in I nm ngang t trong t trng c cc ng sc t thng ng t trn xung nh hnh v. Lc t tc dng ln on dy dn c chiu A. thng ng hng t trn xung. B. thng ng hng t di ln. C. nm ngang hng t tri sang phi. D. nm ngang hng t phi sang tri. 4.11 Chiu ca lc t tc dng ln on dy dn mang dng in, thng c xc nh bng quy tc: A. vn inh c 1. B. vn inh c 2. C. bn tay tri. D. bn tay phi. 4.12 Pht biu no sau y l khng ng? A. Lc t tc dng ln dng in c phng vung gc vi dng in. B. Lc t tc dng ln dng in c phng vung gc vi ng cm ng t. C. Lc t tc dng ln dng in c phng vung gc vi mt phng cha dng in v ng cm ng t. D. Lc t tc dng ln dng in c phng tip thuyn vi cc ng cm ng t. 4.13 Pht biu no sau y l khng ng? A. Lc t tc dng ln dng in i chiu khi i chiu dng in. B. Lc t tc dng ln dng in i chiu khi i chiu ng cm ng t. C. Lc t tc dng ln dng in i chiu khi tng cng dng in. D. Lc t tc dng ln dng in khng i chiu khi ng thi i chiu dng in v ng cm ng t.

28. Cm ng t. nh lut Ampe 4.14 Pht biu no sau y l khng ng? A. Cm ng t l i lng c trng cho t trng v mt tc dng lc B. ln ca cm ng t c xc nh theo cng thc B = on dy dn t trong t trng

F ph thuc vo cng dng in I v chiu di Il sin F khng ph thuc vo cng dng in I v Il sin

C. ln ca cm ng t c xc nh theo cng thc B =

chiu i on dy dn t trong t trng D. Cm ng t l i lng vect 4.15 Pht biu no sau y l khng ng? A. Lc t tc dng ln mt on dy dn mang dng in t trong t trng u t l thun vi cng dng in trong on dy. B. Lc t tc dng ln mt on dy dn mang dng in t trong t trng u t l thun vi chiu di ca on dy. C. Lc t tc dng ln mt on dy dn mang dng in t trong t trng u t l thun vi gc hp bi on dy v ng sc t. D. Lc t tc dng ln mt on dy dn mang dng in t trong t trng u t l thun vi cm ng t ti im t on dy. 4.16 Pht biu no di y l ng? Cho mt on dy dn mang dng in I t song song vi ng sc t, chiu ca dng in ngc chiu vi chiu ca ng sc t.


Trang 17

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. Lc t lun bng khng khi tng cng dng in. B. Lc t tng khi tng cng dng in. C. Lc t gim khi tng cng dng in. D. Lc t i chiu khi ta i chiu dng in. 4.17 Mt on dy dn di 5 (cm) t trong t trng u v vung gc vi vect cm ng t. Dng in chy qua dy c cng 0,75 (A). Lc t tc dng ln on dy l 3.10-2 (N). Cm ng t ca t trng c ln l: A. 0,4 (T). B. 0,8 (T). C. 1,0 (T). D. 1,2 (T). 4.18 Pht biu no sau y l khng ng? Mt on dy dn thng mang dng in I t trong t trng u th A. lc t tc dng ln mi phn ca on dy. B. lc t ch tc dng vo trung im ca on dy. C. lc t ch tc dng ln on dy khi n khng song song vi ng sc t. D. lc t tc dng ln on dy c im t l trung im ca on dy. 4.19 Mt on dy dn thng MN di 6 (cm) c dng in I = 5 (A) t trong t trng u c cm ng t B = 0,5 (T). Lc t tc dng ln on dy c ln F = 7,5.10-2(N). Gc hp bi dy MN v ng cm ng t l: A. 0,50 B. 300 C. 600 D. 900 4.20 Mt dy dn thng c dng in I t trong vng khng gian c t trng u nh hnh v. Lc t tc dng ln dy c A. phng ngang hng sang tri. B. phng ngang hng sang phi. C. phng thng ng hng ln. D. phng thng ng hng xung. I 29. T trng ca mt s dng in c dng n gin 4.21 Pht biu no di y l ng? A. ng sc t ca t trng gy ra bi dng in thng di l nhng ng thng song song vi dng in B. ng sc t ca t trng gy ra bi dng in trn l nhng ng trn C. ng sc t ca t trng gy ra bi dng in trn l nhng ng thng song song cch u nhau D. ng sc t ca t trng gy ra bi dng in thng di l nhng ng trn ng tm nm trong mt phng vung gc vi dy dn 4.22 Hai im M v N gn mt dng in thng di. Khong cch t M n dng in ln gp hai ln khong cch t N n dng in. ln ca cm ng t ti M v N l BM v BN th A. BM = 2BN B. BM = 4BN C. BM =

1 BN 2

D. BM =

1 BN 4

4.23 Dng in I = 1 (A) chy trong dy dn thng di. Cm ng t ti im M cch dy dn 10 (cm) c ln l: A. 2.10-8(T) B. 4.10-6(T) C. 2.10-6(T) D. 4.10-7(T) 4.24 Ti tm ca mt dng in trn cng 5 (A) cm ng t o c l 31,4.10-6(T). ng knh ca dng in l: A. 10 (cm) B. 20 (cm) C. 22 (cm) D. 26 (cm) 4.25 Mt dy dn thng di c dng in I chy qua. Hai im M v N nm trong cng mt mt phng cha dy dn, i xng vi nhau qua dy. Kt lun no sau y l khng ng? A. Vect cm ng t ti M v N bng nhau. B. M v N u nm trn mt ng sc t. C. Cm ng t ti M v N c chiu ngc nhau. D. Cm ng t ti M v N c ln bng nhau. 4.26 Mt dng in c cng I = 5 (A) chy trong mt dy dn thng, di. Cm ng t do dng in ny gy ra ti im M c ln B = 4.10-5 (T). im M cch dy mt khong A. 25 (cm) B. 10 (cm) C. 5 (cm) D. 2,5 (cm) 4.27 Mt dng in thng, di c cng 20 (A), cm ng t ti im M cch dng in 5 (cm) c ln l: A. 8.10-5 (T) B. 8.10-5 (T) C. 4.10-6 (T) D. 4.10-6 (T) 4.28 Mt dng in chy trong dy dn thng, di. Ti im A cch dy 10 (cm) cm ng t do dng in gy ra c


Trang 18

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giangln 2.10 (T). Cng dng in chy trn dy l: A. 10 (A) B. 20 (A) C. 30 (A) D. 50 (A) 4.29 Hai dy dn thng, di song song cch nhau 32 (cm) trong khng kh, cng dng in chy trn dy 1 l I1 = 5 (A), cng dng in chy trn dy 2 l I2. im M nm trong mt phng 2 dng in, ngoi khong 2 dng in v cch dng I2 8 (cm). cm ng t ti M bng khng th dng in I2 c A. cng I2 = 2 (A) v cng chiu vi I1 B. cng I2 = 2 (A) v ngc chiu vi I1 C. cng I2 = 1 (A) v cng chiu vi I1 D. cng I2 = 1 (A) v ngc chiu vi I1 4.30 Hai dy dn thng, di song song cch nhau 32 (cm) trong khng kh, dng in chy trn dy 1 l I1 = 5 (A), dng in chy trn dy 2 l I2 = 1 (A) ngc chiu vi I1. im M nm trong mt phng ca hai dy v cch u hai dy. Cm ng t ti M c ln l: A. 5,0.10-6 (T) B. 7,5.10-6 (T) C. 5,0.10-7 (T) D. 7,5.10-7 (T) 4.31 Hai dy dn thng, di song song cch nhau 32 (cm) trong khng kh, dng in chy trn dy 1 l I1 = 5 (A), dng in chy trn dy 2 l I2 = 1 (A) ngc chiu vi I1. im M nm trong mt phng ca 2 dng in ngoi khong hai dng in v cch dng in I1 8 (cm). Cm ng t ti M c ln l: A. 1,0.10-5 (T) B. 1,1.10-5 (T) C. 1,2.10-5 (T) D. 1,3.10-5 (T) 4.32 Hai dy dn thng, di song song cch nhau cch nhau 40 (cm). Trong hai dy c hai dng in cng cng I1 = I2 = 100 (A), cng chiu chy qua. Cm ng t do h hai dng in gy ra ti im M nm trong mt phng hai dy, cch dng I1 10 (cm), cch dng I2 30 (cm) c ln l: A. 0 (T) B. 2.10-4 (T) C. 24.10-5 (T) D. 13,3.10-5 (T) 30. Bi tp v t trng 4.33 Mt ng dy di 50 (cm), cng dng in chy qua mi vng dy l 2 (A). cm ng t bn trong ng dy c ln B = 25.10-4 (T). S vng dy ca ng dy l: A. 250 B. 320 C. 418 D. 497 4.34 Mt si dy ng c ng knh 0,8 (mm), lp sn cch in bn ngoi rt mng. Dng si dy ny qun mt ng dy c di l = 40 (cm). S vng dy trn mi mt chiu di ca ng dy l: A. 936 B. 1125 C. 1250 D. 1379 4.35 Mt si dy ng c ng knh 0,8 (mm), in tr R = 1,1 (), lp sn cch in bn ngoi rt mng. Dng si dy ny qun mt ng dy di l = 40 (cm). Cho dng in chy qua ng dy th cm ng t bn trong ng dy c ln B = 6,28.10-3 (T). Hiu in th hai u ng dy l: A. 6,3 (V) B. 4,4 (V) C. 2,8 (V) D. 1,1 (V) 4.36 Mt dy dn rt di cng thng, gia dy c un thnh vng trn bn knh R = 6 (cm), ti ch cho nhau dy dn c cch in. Dng in chy trn dy c cng 4 (A). Cm ng t ti tm vng trn do dng in gy ra c ln l: A. 7,3.10-5 (T) B. 6,6.10-5 (T) C. 5,5.10-5 (T) 4,5.10-5 (T) 4.37 Hai dng in c cng I1 = 6 (A) v I2 = 9 (A) chy trong hai dy dn thng, di song song cch nhau 10 (cm) trong chn khng I1 ngc chiu I2. Cm ng t do h hai dng in gy ra ti im M cch I 1 6 (cm) v cch I2 8 (cm) c ln l: A. 2,0.10-5 (T) B. 2,2.10-5 (T) C. 3,0.10-5 (T) D. 3,6.10-5 (T) 4.38 Hai dy dn thng di song song cch nhau 10 (cm) trong khng kh, dng in chy trong hai dy c cng cng 5 (A) ngc chiu nhau. Cm ng t ti im M cch u hai dng in mt khong 10 (cm) c ln l: A. 1.10-5 (T) B. 2.10-5 (T) C.-5

2 .10-5 (T)

D.

3 .10-5 (T)

31. Tng tc gia hai dng in thng song song. nh ngha ampe 4.39 Pht biu no sau y khng ng? A. Lc tng tc gia hai dng in thng song song c phng nm trong mt phng hai dng in v vung gc vi


Trang 19

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Gianghai dng in. B. Hai dng in thng song song cng chiu ht nhau, ngc chiu y nhau. C. Hai dng in thnh song song ngc chiu ht nhau, cng chiu y nhau. D. Lc tng tc gia hai dng in thng song song c ln t l thun vi cng ca hai dng in. 4.40 Khi tng ng thi cng dng in trong c hai dy dn thng song song ln 3 ln th lc t tc dng ln mt n v di ca mi dy s tng ln: A. 3 ln B. 6 ln C. 9 ln D. 12 ln 4.41 Hai dy dn thng, di song song v cch nhau 10 (cm) trong chn khng, dng in trong hai dy cng chiu c cng I1 = 2 (A) v I2 = 5 (A). Lc t tc dng ln 20 (cm) chiu di ca mi dy l: A. lc ht c ln 4.10-6 (N) B. lc ht c ln 4.10-7 (N) C. lc y c ln 4.10-7 (N) D. lc y c ln 4.10-6 (N) 4.42 Hai dy dn thng, di song song t trong khng kh. Dng in chy trong hai dy c cng cng 1 (A). Lc t tc dng ln mi mt chiu di ca mi dy c ln l 10-6(N). Khong cch gia hai dy l: A. 10 (cm) B. 12 (cm) C. 15 (cm) D. 20 (cm) 4.43 Hai dy dn thng song song mang dng in I 1 v I2 t cch nhau mt khong r trong khng kh. Trn mi n v di ca mi dy chu tc dng ca lc t c ln l:7 A. F = 2.10

I1I 2 r2

7 B. F = 2 .10

I1I 2 r2

7 C. F = 2.10

I1I 2 r

7 D. F = 2 .10

I1I 2 r2

4.44 Hai vng dy trn cng bn knh R = 10 (cm) ng trc v cch nhau 1(cm). Dng in chy trong hai vng dy cng chiu, cng cng I1 = I2 = 5 (A). Lc tng tc gia hai vng dy c ln l A. 1,57.10-4 (N) B. 3,14.10-4 (N) C. 4.93.10-4 (N) D. 9.87.10-4(N) 32. Lc Lorenx 4.45 Lc Lorenx l: A. lc t tc dng ln ht mang in chuyn ng trong t trng. B. lc t tc dng ln dng in. C. lc t tc dng ln ht mang in t ng yn trong t trng. D. lc t do dng in ny tc dng ln dng in kia. 4.46 Chiu ca lc Lorenx c xc nh bng: A. Qui tc bn tay tri. B. Qui tc bn tay phi. C. Qui tc ci inh c. D. Qui tc vn nt chai. 4.47 Chiu ca lc Lorenx ph thuc vo A. Chiu chuyn ng ca ht mang in. B. Chiu ca ng sc t. C. in tch ca ht mang in. D. C 3 yu t trn 4.48 ln ca lc Lorex c tnh theo cng thc A. f = q vB B. f = q vB sin C. f = qvB tan D. f = q vB cos 4.49 Phng ca lc Lorenx A. Trng vi phng ca vect cm ng t. B. Trng vi phng ca vect vn tc ca ht mang in. C. Vung gc vi mt phng hp bi vect vn tc ca ht v vect cm ng t. D. Trng vi mt phng to bi vect vn tc ca ht v vect cm ng t. 4.50 Chn pht biu ng nht. Chiu ca lc Lorenx tc dng ln ht mang in chuyn ng trn trong t trng A. Trng vi chiu chuyn ng ca ht trn ng trn. B. Hng v tm ca qu o khi ht tch in dng.


Trang 20

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. Hng v tm ca qu o khi ht tch in m. D. Lun hng v tm qu o khng ph thuc in tch m hay dng. 4.51 Mt electron bay vo khng gian c t trng u c cm ng t B = 0,2 (T) vi vn tc ban u v 0 = 2.105 (m/s) vung gc vi B . Lc Lorenx tc dng vo electron c ln l: A. 3,2.10-14 (N) B. 6,4.10-14 (N) C. 3,2.10-15 (N) D. 6,4.10-15 (N) 4.52 Mt electron bay vo khng gian c t trng u c cm ng t B = 10 -4 (T) vi vn tc ban u v0 = 3,2.106 (m/s) vung gc vi B , khi lng ca electron l 9,1.10-31(kg). Bn knh qu o ca electron trong t trng l: A. 16,0 (cm) B. 18,2 (cm) C. 20,4 (cm) D. 27,3 (cm) 6 4.53 Mt ht prtn chuyn ng vi vn tc 2.10 (m/s) vo vng khng gian c t trng u B = 0,02 (T) theo hng hp vi vect cm ng t mt gc 300. Bit in tch ca ht prtn l 1,6.10-19 (C). Lc Lorenx tc dng ln ht c ln l. A. 3,2.10-14 (N) B. 6,4.10-14 (N) C. 3,2.10-15 (N) D. 6,4.10-15 (N) 4.54 Mt electron bay vo khng gian c t trng u B vi vn tc ban u v0 vung gc cm ng t. Qu o ca electron trong t trng l mt ng trn c bn knh R. Khi tng ln ca cm ng t ln gp i th: A. bn knh qu o ca electron trong t trng tng ln gp i B. bn knh qu o ca electron trong t trng gim i mt na C. bn knh qu o ca electron trong t trng tng ln 4 ln D. bn knh qu o ca electron trong t trng gim i 4 ln 33. Khung dy c dng in t trong t trng 4.55 Mt khung dy dn mang dng in t trong t trng u. Kt lun no sau y l khng ng? A. Lun c lc t tc dng ln tt c cc cnh ca khung B. Lc t tc dng ln cc cnh ca khung khi mt phng khung dy khng song song vi ng sc t C. Khi mt phng khung dy vung gc vi vect cm ng t th khung dy trng thi cn bng D. Mmen ngu lc t c tc dng lm quay khung dy v trng thi cn bng bn 4.56 Mt khung dy dn phng, din tch S, mang dng in I t trong t trng u B, mt phng khung dy song song vi cc ng sc t. Mmen ngu lc t tc dng ln khung dy l: A. M = 0 B. M = IBS C. M = IB/S D. M = IS/B 4.57 Mt khung dy mang dng in I t trong t trng u, mt phng khung dy vung gc vi ng cm ng tI(Hnh v). Kt lun no sau y l ng v lc t tc dng ln cc cnh ca khung dy A. bng khng B. c phng vung gc vi mt phng khung dy C. nm trong mt phng khung dy, vung gc vi cc cnh v c tc dng ko dn khung D. nm trong mt phng khung dy, vung gc vi cc cnh v c tc dng nn khung 4.58 Mt khung dy mang dng in I t trong t trng u, mt phng khung dy cha cc ng cm ng t, khung c th quay xung quanh mt trc 00' thng ng nm trong 0 N mt phng khung (Hnh v). Kt lun no sau y l ng? M I A. lc t tc dng ln cc cnh u bng khng B. lc t tc dng ln cnh NP & QM bng khng C. lc t tc dng ln cc cnh trit tiu nhau lm cho khung dy ng cn bng D. lc t gy ra mmen c tc dng lm cho khung dy quay quanh trc 00' P 4.59 Khung dy dn hnh vung cnh a = 20 (cm) gm c 10 vng dy, dng in chy trong mi vng dy c cng Q 0' I = 2 (A). Khung dy t trong t trng u c cm ng t B = 0,2 (T), mt phng khung dy cha cc ng cm ng t. Mmen lc t tc dng ln khung dy c ln l:

B

B


Trang 21

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. 0 (Nm) B. 0,016 (Nm) C. 0,16 (Nm) D. 1,6 (Nm) 4.60 Chn cu sai Mmen ngu lc t tc dng ln mt khung dy c dng in t trong t trng u A. t l thun vi din tch ca khung. B. c gi tr ln nht khi mt phng khung vung gc vi ng sc t. C. c gi tr ln nht khi mt phng khung song song vi ng sc t. D. ph thuc vo cng dng in trong khung. 4.61 Mt khung dy phng nm trong t trng u, mt phng khung dy cha cc ng sc t. Khi gim cng dng in i 2 ln v tng cm ng t ln 4 ln th mmen lc t tc dng ln khung dy s: A. khng i B. tng 2 ln C. tng 4 ln D. gim 2 ln 4.62 Mt khung dy dn hnh ch nht ABCD t trong t trng u c cm ng t B = 5.10 -2 (T). Cnh AB ca khung di 3 (cm), cnh BC di 5 (cm). Dng in trong khung dy c cng I = 5 (A). Gi tr ln nht ca mmen ngu lc t tc dng ln khung dy c ln l: A. 3,75.10-4 (Nm) B. 7,5.10-3 (Nm) C. 2,55 (Nm) D. 3,75 (Nm) 4.63 Mt khung dy cng hnh ch nht c kch thc 2 (cm) x 3 (cm) t trong t trng u. Khung c 200 vng dy. Khi cho dng in c cng 0,2 (A) i vo khung th mmen ngu lc t tc dng vo khung c gi tr ln nht l 24.10-4 (Nm). Cm ng t ca t trng c ln l: A. 0,05 (T) B. 0,10 (T) C. 0,40 (T) D. 0,75 (T) 34. S t ho, cc cht st t 4.64 Pht biu no sau y l ng? A. Cht thun t l cht b nhim t rt mnh, cht nghch t l cht khng b nhim t B. Cht thun t v cht nghch t u b t ha khi t trong t trng v b mt t tnh khi t trng ngoi mt i. C. Cc nam chm l cc cht thun t. D. St v cc hp cht ca st l cc cht thun t. 4.65 Cc cht st t b nhim t rt mnh l do: A. trong cht st t c cc min nhim t t nhin ging nh cc kim nam chm nh B. trong cht st t c cc dng in phn t gy ra t trng C. cht st t l cht thun t D. cht st t l cht nghch t 4.66 Chn cu pht biu ng? A. T tnh ca nam chm vnh cu l khng i, khng ph thuc cc yu t bn ngoi B. Nam chm in l mt ng dy c li st, khi c dng in chy qua ng dy li st b nhim t, khi ngt dng in qua ng dy t tnh ca li st khng b mt i C. Nam chm in l mt ng dy c li st, khi c dng in chy qua ng dy li st b nhim t rt mnh, khi ngt dng in qua ng dy t tnh ca li st b mt i D. Nam chm vnh cu l cc nam chm c trong t nhin, con ngi khng to ra c 4.67 Pht biu no sau y l khng ng? A. Cc cht st t c ng dng ch to ra cc nam chm in v nam chm vnh cu. B. Cc cht st t c ng dng ch to li thp ca cc ng c, my bin th. C. Cc cht st t c ng dng ch to bng t ghi m, ghi hnh. D. Cc cht st t c ng dng ch to ra cc dng c o lng khng b nh hng bi t trng bn ngoi. 35. T trng Tri t 4.68 t thin l A. gc lch gia kinh tuyn t v mt phng nm ngang B. gc lch gia kinh tuyn t v mt phng xch o ca tri t


Trang 22

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. gc lch gia kinh tuyn t v kinh tuyn a l D. gc lch gia kinh tuyn t v v tuyn a l 4.69 Pht biu no sau y l ng? A. t thin dng ng vi trng hp cc bc ca kim la bn lch v pha ng, t thin m ng vi trng hp cc bc ca kim la bn lch v pha ty B. t thin dng ng vi trng hp cc bc ca kim la bn lch v pha ty, t thin m ng vi trng hp cc bc ca kim la bn lch v pha ng C. t thin dng ng vi trng hp cc bc ca kim la bn lch v pha bc, t thin m ng vi trng hp cc bc ca kim la bn lch v pha nam D. t thin dng ng vi trng hp cc bc ca kim la bn lch v pha nam, t thin m ng vi trng hp cc bc ca kim la bn lch v pha bc 4.70 t khuynh l: A. gc hp bi kim nam chm ca la bn v mt phng nm ngang B. gc hp bi kim nam chm ca la bn v mt phng thng ng C. gc hp bi kim nam chm ca la bn v kinh tuyn a l D. gc hp bi kim nam chm ca la M bn v mt phng xch o ca tri t 4.71 Pht biu no sau y l ng? A. t khuynh dng khi cc bc ca kim nam chm ca la bn nm P N di mt phng ngang, t khuynh m khi cc bc ca kim nam chm ca la bn nm pha trn mt phng ngang B. t khuynh dng khi cc bc ca kim nam chm ca la bn nm trn mt phng ngang, t khuynh m khi cc bc ca kim nam chm ca la bn nm pha di mt phng ngang C. t khuynh dng khi cc bc ca kim nam chm ca la bn lch v hng bc, t khuynh m khi cc bc ca kim nam chm ca la bn lch v hng nam D. t khuynh dng khi cc bc ca kim nam chm ca la bn lch v hng ng, t khuynh m khi cc bc ca kim nam chm ca la bn lch v hng nam 4.72 Chn cu pht biu khng ng. A. C t thin l do cc cc t ca tri t khng trng vi cc a cc B. t thin v t khuynh ph thuc v tr a l C. Bc cc c t khuynh dng, nam cc c t khuynh m

B


Trang 23

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangD. Bc cc c t khuynh m, nam cc c t khuynh dng 4.73 Pht biu no sau y l ng? A. Hin nay cc t bc ca tri t nm ti bc cc, cc t nam ca tri t nm ti nam cc B. Hin nay cc t bc ca tri t nm ti nam cc, cc t nam ca tri t nm ti bc cc C. Hin nay cc t bc ca tri t nm gn bc cc, cc t nam ca tri t nm gn nam cc D. Hin nay cc t bc ca tri t nm gn nam cc, cc t nam ca tri t nm gn bc cc 4.74 Chn cu pht biu khng ng. A. Bo t l s bin i ca t trng tri t xy ra trong mt khong thi gian rt di B. Bo t l s bin i ca t trng tri t xy ra trong mt khong thi gian ngn C. Bo t l s bin i ca t trng tri t trn qui m hnh tinh D. Bo t mnh nh hng n vic lin lc v tuyn trn hnh tinh 36. Bi tp v lc t 4.75 Mt dy dn c gp thnh khung dy c dng tam gic vung cn MNP. Cnh MN = NP = 10 (cm). t khung dy vo trong t trng u B = 10-2 (T) c chiu nh hnh v. Cho dng in I c cng 10 (A) vo khung dy theo chiu MNPM. Lc t tc dng vo cc cnh ca khung dy l A. FMN = FNP = FMP = 10-2 (N) M B. FMN = 10-2 (N), FNP = 0 (N), FMP = 10-2 (N) C. FMN = 0 (N), FNP = 10-2 (N), FMP = 10-2 (N) D. FMN = 10-3 (N), FNP = 0 (N), FMP = 10-3 (N) N

P

4.76 Mt dy dn c gp thnh khung dy c dng tam gic vung MNP. Cnh MN = 30 (cm), NP = 40 (cm). t khung dy vo trong t trng u B = 10 -2 (T) vung gc vi mt phng khung dy c chiu nh hnh v. Cho dng in I c cng 10 (A) vo khung dy theo chiu MNPM. Lc t tc dng vo cc cnh ca khung dy l A. FMN = 0,03 (N), FNP = 0,04 (N), FMP = 0,05 (N). Lc t tc dng ln cc cnh c tc dng nn khung B. FMN = 0,03 (N), FNP = 0,04 (N), FMP = 0,05 (N). Lc t tc dng ln cc cnh c tc dng ko dn khung C. FMN = 0,003 (N), FNP = 0,004 (N), FMP = 0,007 (N). Lc t tc dng ln cc cnh c tc dng nn khung D. FMN = 0,003 (N), FNP = 0,004 (N), FMP = 0,007 (N). Lc t tc dng ln cc cnh c tc dng ko dn khung khung

B

C D 4.77 Thanh MN di l = 20 (cm) c khi lng 5 (g) treo nm ngang bng hai si ch mnh CM v DN. Thanh nm trong t trng u c N M cm ng t B = 0,3 (T) nm ngang vung gc vi thanh c chiu nh hnh v. Mi si ch treo thanh c th chu c lc ko ti a l 0,04 (N). Dng in chy qua thanh MN c cng nh nht l bao nhiu th mt trong hai si ch treo thanh b t. Cho gia tc trng trng g = 9,8 (m/s2) A. I = 0,36 (A) v c chiu t M n N B. I = 0,36 (A) v c chiu t N n M C. I = 0,52 (A) v c chiu t M n N D. I = 0,52 (A) v c chiu t N n M 4.78 Mt ht tch in chuyn ng trong t trng u, mt phng qu o ca ht vung gc vi ng sc t. Nu Ti liu n tp Vt L lp 11 nm hc 2010-2011 Trang 24

B

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Gianght chuyn ng vi vn tc v1 = 1,8.106 (m/s) th lc Lorenx tc dng ln ht c gi tr f1 = 2.10-6 (N), nu ht chuyn ng vi vn tc v2 = 4,5.107 (m/s) th lc Lorenx tc dng ln ht c gi tr l A. f2 = 10-5 (N) B. f2 = 4,5.10-5 (N) C. f2 = 5.10-5 (N) D. f2 = 6,8.10-5 (N) 4.79 Ht c khi lng m = 6,67.10-27 (kg), in tch q = 3,2.10-19 (C). Xt mt ht c vn tc ban u khng ng k c tng tc bi mt hiu in th U = 106 (V). Sau khi c tng tc n bay vo vng khng gian c t trng u B = 1,8 (T) theo hng vung gc vi ng sc t. Vn tc ca ht trong t trng v lc Lorenx tc dng ln ht c ln l A. v = 4,9.106 (m/s) v f = 2,82.110-12 (N) B. v = 9,8.106 (m/s) v f = 5,64.110-12 (N) C. v = 4,9.106 (m/s) v f = 1.88.110-12 (N) D. v = 9,8.106 (m/s) v f = 2,82.110-12 (N) 4.80 Hai ht bay vo trong t trng u vi cng vn tc. Ht th nht c khi lng m 1 = 1,66.10-27 (kg), in tch q1 = - 1,6.10-19 (C). Ht th hai c khi lng m2 = 6,65.10-27 (kg), in tch q2 = 3,2.10-19 (C). Bn knh qu o ca ht th nht l R1 = 7,5 (cm) th bn knh qu o ca ht th hai l A. R2 = 10 (cm) B. R2 = 12 (cm) C. R2 = 15 (cm) D. R2 = 18 (cm)

P N CHNG 4 : T 1D 18B 35B 52B 69A 2A 19B 36A 53C 70A 3A 20A 37C 54B 71A 4B 21D 38A 55A 72D 5C 22C 39C 56B 73D 6C 23C 40C 57C 74A 7C 24B 41A 58D 75B 8C 25A 42D 59C 76A 9C 26D 43C 60B 77D 10D 27A 44B 61B 78C

trng11C 28A 45A 62A 79B 12D 29D 46A 63B 80C 13C 30B 47D 64B 14B 31C 48B 65A 15C 32C 49C 66C 16A 33D 50D 67D 17B 34C 51D 68C

Chng V. Cm ng in t38. Hin tng cm ng in t Sut in ng cm ng trong mch in kn 5.1 Mt din tch S t trong t trng u c cm ng t B, gc gia vect cm ng t v cect php tuyn l . T thng qua din tch S c tnh theo cng thc: A. = BS.sin B. = BS.cos C. = BS.tan D. = BS.ctan 5.2 n v ca t thng l: A. Tesla (T). B. Ampe (A). C. Vbe (Wb). D. Vn (V). 5.3 Pht biu no sau y l khng ng? A. Mt khung dy dn hnh ch nht, quay u trong mt t trng u quanh mt trc i xng OO song song vi cc ng cm ng t th trong khung c xut hin dng in cm ng. B. Mt khung dy dn hnh ch nht, quay u trong mt t trng u quanh mt trc i xng OO song song vi cc ng cm ng t th trong khung khng c dng in cm ng. C. Mt khung dy dn hnh ch nht, quay u trong mt t trng u quanh mt trc i xng OO vung vi cc ng cm ng t th trong khung c xut hin dng in cm ng. D. Mt khung dy dn hnh ch nht, quay u trong mt t trng u quanh mt trc i xng OO hp vi cc ng cm ng t mt gc nhn th trong khung c xut hin dng in cm ng. 5.4 Pht biu no sau y l ng? A. Mt khung dy hnh ch nht chuyn ng thng u trong t trng u sao cho mt phng khung lun song song vi cc ng cm ng t th trong khung xut hin dng in cm ng. B. Mt khung dy hnh ch nht chuyn ng thng u trong t trng u sao cho mt phng khung lun vung gc vi cc ng cm ng t th trong khung xut hin dng in cm ng.


Trang 25

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangC. Mt khung dy hnh ch nht chuyn ng thng u trong t trng u sao cho mt phng khung hp vi cc ng cm ng t mt gc nhn th trong khung xut hin dng in cm ng. D. Mt khung dy dn hnh ch nht, quay u trong mt t trng u quanh mt trc i xng OO hp vi cc ng cm ng t mt gc nhn th trong khung c xut hin dng in cm ng. 5.5 Pht biu no sau y l khng ng? A. Khi c s bin i t thng qua mt gii hn bi mt mch in, th trong mch xut hin sut in ng cm ng. Hin tng gi l hin tng cm ng in t. B. Dng in xut hin khi c s bin thin t thng qua mch in kn gi l dng in cm ng. C. Dng in cm ng c chiu sao cho t trng do n sinh ra lun ngc chiu vi chiu ca t trng sinh ra n. D. Dng in cm ng c chiu sao cho t trng do n sinh ra c tc dng chng li nguyn nhn sinh ra n. 5.6 ln ca sut in ng cm ng trong mt mch kn c xc nh theo cng thc: A. e c =

t

B. e c = .t

C. e c =

t

D. e c =

t N

5.7 Khung dy dn ABCD c t trong t trng u nh hnh v 5.7. Coi rng bn ngoi vng MNPQ khng c t trng. Khung chuyn ng M dc theo hai ng xx, yy. Trong khung s xut hin dng in cm ng x khi: x A. Khung ang chuyn ng ngoi vng NMPQ. B. Khung ang chuyn ng trong vng NMPQ. y C. Khung ang chuyn ng ngoi vo trong vng NMPQ. y D. Khung ang chuyn ng n gn vng NMPQ.

A D

B C P

Q

Hnh (Wb) 5.8 T thng qua mt khung dy bin i, trong khong thi gian 0,2 (s) t thng gim t 1,25.7 xung cn 0,4 (Wb). Sut in ng cm ng xut hin trong khung c ln bng: A. 6 (V). B. 4 (V). C. 2 (V). D. 1 (V). 5.9 T thng qua mt khung dy bin i, trong khong thi gian 0,1 (s) t thng tng t 0,6 (Wb) n 1,6 (Wb). Sut in ng cm ng xut hin trong khung c ln bng: A. 6 (V). B. 10 (V). C. 16 (V). D. 22 (V). 5.10 Mt hnh ch nht kch thc 3 (cm) x 4 (cm) t trong t trng u c cm ng t B = 5.10 -4 (T). Vect cm ng t hp vi mt phng mt gc 300. T thng qua hnh ch nht l: A. 6.10-7 (Wb). B. 3.10-7 (Wb). C. 5,2.10-7 (Wb). D. 3.10-3 (Wb). 5.11 Mt hnh vung cnh 5 (cm), t trong t trng u c cm ng t B = 4.10 -4 (T). T thng qua hnh vung bng 10-6 (Wb). Gc hp bi vect cm ng t v vect php tuyn vi hnh vung l: A. = 00. B. = 300. C. = 600. D. = 900. 5.12 Mt khung dy phng, din tch 20 (cm2), gm 10 vng dy t trong t trng u. Vect cm ng t lm thnh vi mt phng khung dy mt gc 300 v c ln B = 2.10 -4 (T). Ngi ta lm cho t trng gim u n khng trong khong thi gian 0,01 (s). Sut in ng cm ng xut hin trong khung dy trong khong thi gian t trng bin i l: A. 3,46.10-4 (V). B. 0,2 (mV). C. 4.10-4 (V). D. 4 (mV). 2 5.13 Mt khung dy phng, din tch 25 (cm ) gm 10 vng dy, khung dy c t trong t trng c cm ng t vung gc vi mt phng khung v c ln tng dn t 0 n 2,4.10 -3 (T) trong khong thi gian 0,4 (s). Sut in ng cm ng xut hin trong khung trong khong thi gian c t trng bin thin l: A. 1,5.10-2 (mV). B. 1,5.10-5 (V). C. 0,15 (mV). D. 0,15 (V). 5.14 Mt khung dy cng, t trong t trng tng dn u nh hnh v 5.14. Dng in cm ng trong khung c chiu: I I Ti liu n tp Vt L lp 11 nm hc 2010-2011 A B C I D I Trang 26

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang

Hnh 5.14 39. Sut in ng cm ng trong mt oan dy dn chuyn ng 5.15 Nguyn nhn gy ra sut in ng cm ng trong thanh dy dn chuyn ng trong t trng l: A. Lc ho hc tc dng ln cc lectron lm cc lectron dch chuyn t u ny sang u kia ca thanh. B. Lc Lorenx tc dng ln cc lectron lm cc lectron dch chuyn t u ny sang u kia ca thanh. C. Lc ma st gia thanh v mi trng ngoi lm cc lectron dch chuyn t u ny sang u kia ca thanh. D. Lc t tc dng ln on dy dn khng c dng in t trong t trng lm cc lectron dch chuyn t u ny sang u kia ca thanh. 5.16 Pht biu no sau y l ng? A. t bn tay tri hng cc ng sc t, ngn tay ci choi ra 900 hng theo chiu chuyn ng ca on dy, khi on dy dn ng vai tr nh mt ngun in, chiu t c tay n cc ngn tay ch chiu t cc m sang cc dng ca ngun in . B. t bn tay phi hng cc ng sc t, ngn tay ci choi ra 900 hng theo chiu chuyn ng ca on dy, khi on dy dn ng vai tr nh mt ngun in, chiu t c tay n cc ngn tay ch chiu t cc m sang cc dng ca ngun in . C. t bn tay phi hng cc ng sc t, chiu t c tay n cc ngn tay hng theo chiu chuyn ng ca on dy, khi on dy dn ng vai tr nh mt ngun in, ngn tay ci choi ra 90 0 ch chiu t cc m sang cc dng ca ngun in . D. t bn tay tri hng cc ng sc t, chiu t c tay n cc ngn tay hng theo chiu chuyn ng ca on dy, khi on dy dn ng vai tr nh mt ngun in, ngn tay ci choi ra 90 0 ch chiu t cc m sang cc dng ca ngun in . 5.17 Pht biu no sau y l ng? A. Mt thanh dy dn chuyn ng thng u trong mt t trng u sao cho thanh lun nm dc theo mt ng sc in th trong thanh xut hin mt in trng cm ng. B. Mt thanh dy dn chuyn ng dc theo mt ng sc t ca mt t trng u sao cho thanh lun vung gc vi ng sc t th trong thanh xut hin mt in trng cm ng. C. Mt thanh dy dn chuyn ng ct cc ng sc t ca mt t trng u sao cho thanh lun vung gc vi ng sc t th trong thanh xut hin mt in trng cm ng. D. Mt thanh dy dn chuyn ng theo mt qu o bt k trong mt t trng u sao cho thanh lun nm dc theo cc ng sc in th trong thanh xut hin mt in trng cm ng. 5.18 My pht in hot ng theo nguyn tc da trn: A. hin tng mao dn. B. hin tng cm ng in t. C. hin tng in phn. D. hin tng khc x nh sng. 5.19 Mt thanh dy dn di 20 (cm) chuyn ng tnh tin trong t trng u c B = 5.10 -4 (T). Vect vn tc ca thanh vung gc vi thanh, vung gc vi vect cm ng t v c ln 5 (m/s). Sut in ng cm ng trong thanh l: A. 0,05 (V). B. 50 (mV). C. 5 (mV). D. 0,5 (mV). 5.20 Mt thanh dn in di 20 (cm) c ni hai u ca n vi hai u ca mt mch in c in tr 0,5 (). Cho thanh chuyn ng tnh tin trong t trng u cm ng t B = 0,08 (T) vi vn tc 7 (m/s), vect vn tc vung gc vi cc ng sc t v vung gc vi thanh, b qua in tr ca thanh v cc dy ni. Cng dng in trong mch l: A. 0,224 (A). B. 0,112 (A). C. 11,2 (A). D. 22,4 (A).


Trang 27

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang5.21 Mt thanh dn in di 40 (cm), chuyn ng tnh tin trong t trng u, cm ng t bng 0,4 (T). Vect vn tc ca thanh vung gc vi thanh v hp vi cc ng sc t mt gc 300, ln v = 5 (m/s). Sut in ng gia hai u thanh l: A. 0,4 (V). B. 0,8 (V). C. 40 (V). D. 80 (V). 5.22 Mt thanh dn in di 40 (cm), chuyn ng tnh tin trong t trng u, cm ng t bng 0,4 (T). Vect vn tc ca thanh vung gc vi thanh v hp vi cc ng sc t mt gc 300. Sut in ng gia hai u thanh bng 0,2 (V). Vn tc ca thanh l: A. v = 0,0125 (m/s). B. v = 0,025 (m/s). C. v = 2,5 (m/s). D. v = 1,25 (m/s). 40. Dng in Fu-c 5.23 Pht biu no sau y l khng ng? A. Dng in cm ng c sinh ra trong khi vt dn khi chuyn ng trong t trng hay t trong t trng bin i theo thi gian gi l dng in Fuc. B. Dng in xut hin khi c s bin thin t thng qua mch in kn gi l dng in cm ng. C. Dng in Fuc c sinh ra khi khi kim loi chuyn ng trong t trng, c tc dng chng li chuyn ng ca khi kim loi . D. Dng in Fuc ch c sinh ra khi khi vt dn chuyn ng trong t trng, ng thi to nhit lm khi vt dn nng ln. 5.24 Mun lm gim hao ph do to nhit ca dng in Fuc gy trn khi kim loi, ngi ta thng: A. chia khi kim loi thnh nhiu l kim loi mng ghp cch in vi nhau. B. tng dn in cho khi kim loi. C. c khi kim loi khng c phn rng bn trong. D. sn ph ln khi kim loi mt lp sn cch in. 5.25 Khi s dng in, dng in Fuc s xut hin trong: A. Bn l in. B. Bp in. C. Qut in. D. Siu in. 5.26 Khi s dng in, dng in Fuc khng xut hin trong: A. Qut in. B. L vi sng. C. Ni cm in. D. Bp t. 5.27 Pht biu no sau y l khng ng? A. Sau khi qut in hot ng, ta thy qut in b nng ln. S nng ln ca qut in mt phn l do dng in Fuc xut hin trong li st ca ca qut in gy ra. B. Sau khi siu in hot ng, ta thy nc trong siu nng ln. S nng ln ca nc ch yu l do dng in Fuc xut hin trong nc gy ra. C. Khi dng l vi sng nng bnh, bnh b nng ln. S nng ln ca bnh l do dng in Fuc xut hin trong bnh gy ra. D. My bin th dng trong gia nh khi hot ng b nng ln. S nng ln ca my bin th ch yu l do dng in Fuc trong li st ca my bin th gy ra. 41. Hin tng t cm 5.28 Pht biu no sau y l khng ng? A. Hin tng cm ng in t trong mt mch in do chnh s bin i ca dng in trong mch gy ra gi l hin tng t cm. B. Sut in ng c sinh ra do hin tng t cm gi l sut in ng t cm. C. Hin tng t cm l mt trng hp c bit ca hin tng cm ng in t. D. Sut in ng cm ng cng l sut in ng t cm. 5.29 n v ca h s t cm l: A. Vn (V). B. Tesla (T). C. Vbe (Wb). D. Henri (H).


Trang 28

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang5.30 Biu thc tnh sut in ng t cm l: A. e = L

I t I t

B. e = L.I

C. e = 4. 10-7.n2.V

D. e = L

t I t I

5.31 Biu thc tnh h s t cm ca ng dy di l: A. L = e B. L = .I C. L = 4. 10-7.n2.V D. L = e

5.32 Mt ng dy c h s t cm L = 0,1 (H), cng dng in qua ng dy gim u n t 2 (A) v 0 trong khong thi gian l 4 (s). Sut in ng t cm xut hin trong ng trong khong thi gian l: A. 0,03 (V). B. 0,04 (V). C. 0,05 (V). D. 0,06 (V). 5.33 Mt ng dy c h s t cm L = 0,1 (H), cng dng in qua ng dy tng u n t 0 n 10 (A) trong khong thi gian l 0,1 (s). Sut in ng t cm xut hin trong ng trong khong thi gian l: A. 0,1 (V). B. 0,2 (V). C. 0,3 (V). D. 0,4 (V). 2 5.34 Mt ng dy di 50 (cm), din tch tit din ngang ca ng l 10 (cm ) gm 1000 vng dy. H s t cm ca ng dy l: A. 0,251 (H). B. 6,28.10-2 (H). C. 2,51.10-2 (mH). D. 2,51 (mH). 5.35 Mt ng dy c qun vi mt 2000 vng/mt. ng dy c th tch 500 (cm3). ng dy c mc vo mt mch in. Sau khi ng cng tc, dng in trong ng bin i theo thi gian nh trn hnh 5.35. Sut in ng t cm trong ng t sau khi ng cng tc n thi im 0,05 (s) l: A. 0 (V). B. 5 (V). C. 100 (V). D. 1000 (V). 5.36 Mt ng dy c qun vi mt 2000 vng/mt. ng dy c th tch 500 (cm3). dy c mc vo mt mch in. Sau khi ng cng tc, dng in trong ng bin i theo thi gian nh trn hnh 5.35. Sut in ng t cm trong ng t thi im 0,05 (s) v sau l: A. 0 (V). B. 5 (V). C. 10 (V). D. 100 (V). 42. Nng lng t trng 5.37 Pht biu no sau y l ng? A. Khi c dng in chy qua ng dy th trong ng dy tn ti mt nng lng di dng nng lng in trng. B. Khi c dng in chy qua ng dy th trong ng dy tn ti mt nng lng di dng c nng. C. Khi t in c tch in th trong t in tn ti mt nng lng di dng nng lng t trng. D. Khi c dng in chy qua ng dy th trong ng dy tn ti mt nng lng di dng nng lng t trng. 5.38 Nng lng t trng trong cun dy khi c dng in chy qua c xc nh theo cng thc: A. W = ng

1 CU 2 2 1 CU 2 2

B. W =

1 2 LI 2 1 2 LI 2

E 2 C. w = 9.10 9.8C. w =

D. w =

1 .10 7 B 2 V 8 1 .10 7 B 2 8

5.39 Mt nng lng t trng c xc nh theo cng thc: A. W = B. W =

E 2 9.10 9.8

D. w =

5.40 Mt ng dy c h s t cm L = 0,01 (H), c dng in I = 5 (A) chy ng dy. Nng lng t trng trong ng dy l: A. 0,250 (J). B. 0,125 (J). C. 0,050 (J). D. 0,025 (J). 5.41 Mt ng dy c h s t cm L = 0,01 (H). Khi c dng in chy qua ng, ng dy c nng lng 0,08 (J). Cng dng in trong ng dy bng: A. 2,8 (A). B. 4 (A). C. 8 (A). D. 16 (A).


Trang 29

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang5.42 Mt ng dy di 40 (cm) c tt c 800 vng dy. Din tch tit din ngang ca ng dy bng 10 (cm 2). ng dy c ni vi mt ngun in, cng dng in qua ng dy tng t 0 n 4 (A). Ngun in cung cp cho ng dy mt nng lng l: A. 160,8 (J). B. 321,6 (J). C. 0,016 (J). D. 0,032 (J). 43. Bi tp v cm ng in t 5.43 Mt khung dy dn hnh ch nht c kch thc 3 (cm) x 4 (cm) c t trong t trng u cm ng t B = 5.10 4 (T). Vect cm ng t hp vi mt phng khung mt gc 300. T thng qua khung dy dn l: A. 3.10-3 (Wb). B. 3.10-5 (Wb). C. 3.10-7 (Wb). D. 6.10-7 (Wb). 5.44 Mt khung dy phng c din tch 20 (cm2) gm 100 vng dy c t trong t trng u c vect cm ng t vung gc vi mt phng khung dy v c ln bng 2.10 -4 (T). Ngi ta cho t trng gim u n n 0 trong khong thi gian 0,01 (s). Sut in ng cm ng xut hin trong khung l: A. 40 (V). B. 4,0 (V). C. 0,4 (V). D. 4.10-3 (V). 5.45 Mt khung dy phng c din tch 25 (cm2) gm 100 vng dy c t trong t trng u c vect cm ng t vung gc vi mt phng khung dy v c ln bng 2,4.10-3 (T). Ngi ta cho t trng gim u n n 0 trong khong thi gian 0,4 (s). Sut in ng cm ng xut hin trong khung l: A. 1,5 (mV). B. 15 (mV). C. 15 (V). D. 150 (V). 5.46 Dng in qua mt ng dy gim u theo thi gian t I 1 = 1,2 (A) n I2 = 0,4 (A) trong thi gian 0,2 (s). ng dy c h s t cm L = 0,4 (H). Sut in ng t cm trong ng dy l: A. 0,8 (V). B. 1,6 (V). C. 2,4 (V). D. 3,2 (V). 5.47 Dng in qua ng dy tng dn theo thi gian t I1 = 0,2 (A) n I2 = 1,8 (A) trong khong thi gian 0,01 (s). ng dy c h s t cm L = 0,5 (H). Sut in ng t cm trong ng dy l: A. 10 (V). B. 80 (V). C. 90 (V). D. 100 (V). 5.48 Mt thanh dn in di 40 (cm), chuyn ng tnh tin trong t trng u, cm ng t bng 0,4 (T). Vect vn tc ca thanh vung gc vi thanh v hp vi cc ng sc t mt gc 300, ln v = 5 (m/s). Sut in ng gia hai u thanh l: A. 0,4 (V). B. 0,8 (V). C. 40 (V). D. 80 (V). P N CHNG 5 : 1B 17C 33A 2C 18B 34D 3A 19D 35C 4D 20A 36A 5C 21A 37D 6A 22C 38B 7C 23D 39D 8B 24A 40B

Cm ng in t9B 25C 41B 10B 26C 42C 11A 27B 43C 12B 28D 44D 13C 29D 45A 14A 30A 46B 15B 31C 47B 16B 32C 48A

Phn hai: Quang hc Chng VI. Khc x nh sng44. Khc x nh sng 6.1 Pht biu no sau y l ng? A. Chit sut t i ca mi trng chit quang nhiu so vi mi trng chit quang t th nh hn n v. B. Mi trng chit quang km c chit sut tuyt i nh hn n v. C. Chit sut t i ca mi trng 2 so vi mi trng 1 bng t s chit sut tuyt i n 2 ca mi trng 2 vi chit sut tuyt i n1 ca mi trng 1. D. Chit sut t i ca hai mi trng lun ln hn n v v vn tc nh sng trong chn khng l vn tc ln nht. 6.2 Vi mt tia sng n sc, chit sut tuyt i ca nc l n1, ca thu tinh l n2. Chit sut t i khi tia sng truyn t nc sang thu tinh l: A. n21 = n1/n2 B. n21 = n2/n1 C. n21 = n2 n1 D. n12 = n1 n2 6.3 Chn cu tr li ng. Trong hin tng khc x nh sng:


Trang 30

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. gc khc x lun b hn gc ti. B. gc khc x lun ln hn gc ti. C. gc khc x t l thun vi gc ti. D. khi gc ti tng dn th gc khc x cng tng dn. 6.4 Chit sut t i gia mi trng khc x vi mi trng ti A. lun ln hn 1. B. lun nh hn 1. C. bng t s gia chit sut tuyt i ca mi trng khc x v chit sut tuyt i ca mi trng ti. D. bng hiu s gia chit sut tuyt i ca mi trng khc x v chit sut tuyt i ca mi trng ti. 6.5 Chn cu ng nht. Khi tia sng i t mi trng trong sut n1 ti mt phn cch vi mi trng trong sut n2 (vi n2 > n1), tia sng khng vung gc vi mt phn cch th A. tia sng b gy khc khi i qua mt phn cch gia hai mi trng. B. tt c cc tia sng u b khc x v i vo mi trng n2. C. tt c cc tia sng u phn x tr li mi trng n1. D. mt phn tia sng b khc x, mt phn b phn x. 6.6 Chit sut tuyt i ca mt mi trng truyn nh sng A. lun ln hn 1. B. lun nh hn 1. C. lun bng 1. D. lun ln hn 0. 6.7 Chiu mt tia sng n sc i t khng kh vo mi trng c chit sut n, sao cho tia phn x vung gc vi tia khc x. Khi gc ti i c tnh theo cng thc A. sini = n B. sini = 1/n C. tani = n D. tani = 1/n 6.8 Mt b cha nc c thnh cao 80 (cm) v y phng di 120 (cm) v cao mc nc trong b l 60 (cm), chit sut ca nc l 4/3. nh nng chiu theo phng nghing gc 300 so vi phng ngang. di bng en to thnh trn mt nc l A. 11,5 (cm) B. 34,6 (cm) C. 63,7 (cm) D. 44,4 (cm) 6.9 Mt b cha nc c thnh cao 80 (cm) v y phng di 120 (cm) v cao mc nc trong b l 60 (cm), chit sut ca nc l 4/3. nh nng chiu theo phng nghing gc 300 so vi phng ngang. di bng en to thnh trn y b l: A. 11,5 (cm) B. 34,6 (cm) C. 51,6 (cm) D. 85,9 (cm) 6.10 Mt im sng S nm trong cht lng (chit sut n), cch mt cht lng mt khong 12 (cm), pht ra chm sng hp n gp mt phn cch ti im I vi gc ti rt nh, tia l truyn theo phng IR. t mt trn phng IR nhn thy nh o S ca S dng nh cch mt cht lng mt khong 10 (cm). Chit sut ca cht lng l A. n = 1,12 B. n = 1,20 C. n = 1,33 D. n = 1,40 6.11 Cho chit sut ca nc n = 4/3. Mt ngi nhn mt hn si nh S mn y mt b nc su 1,2 (m) theo phng gn vung gc vi mt nc, thy nh S nm cch mt nc mt khong bng A. 1,5 (m) B. 80 (cm) C. 90 (cm) D. 1 (m) 6.12 Mt ngi nhn hn si di y mt b nc thy nh ca n dng nh cch mt nc mt khong 1,2 (m), chit sut ca nc l n = 4/3. su ca b l: A. h = 90 (cm) B. h = 10 (dm) C. h = 15 (dm) D. h = 1,8 (m) 6.13 Mt ngi nhn xung y mt chu nc (n = 4/3). Chiu cao ca lp nc trong chu l 20 (cm). Ngi thy y chu dng nh cch mt nc mt khong bng A. 10 (cm) B. 15 (cm) C. 20 (cm) D. 25 (cm) 6.14 Mt bn mt song song c b dy 10 (cm), chit sut n = 1,5 c t trong khng kh. Chiu ti bn mt tia sng SI c gc ti 450 khi tia l khi bn s A. hp vi tia ti mt gc 450. B. vung gc vi tia ti. C. song song vi tia ti. D. vung gc vi bn mt song song. 6.15 Mt bn mt song song c b dy 10 (cm), chit sut n = 1,5 c t trong khng kh. Chiu ti bn mt tia sng SI c gc ti 450 . Khong cch gia gi ca tia ti v tia l l: A. a = 6,16 (cm). B. a = 4,15 (cm). C. a = 3,25 (cm). D. a = 2,86 (cm).


Trang 31

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang6.16 Mt bn hai mt song song c b dy 6 (cm), chit sut n = 1,5 c t trong khng kh. im sng S cch bn 20 (cm). nh S ca S qua bn hai mt song song cch S mt khong A. 1 (cm). B. 2 (cm). C. 3 (cm). D. 4 (cm). 6.17 Mt bn hai mt song song c b dy 6 (cm), chit sut n = 1,5 c t trong khng kh. im sng S cch bn 20 (cm). nh S ca S qua bn hai mt song song cch bn hai mt song song mt khong A. 10 (cm). B. 14 (cm). C. 18 (cm). D. 22(cm). 45. Phn x ton phn 6.18 Pht biu no sau y l khng ng? A. Khi c phn x ton phn th ton b nh sng phn x tr li mi trng ban u cha chm tia sng ti. B. Phn x ton phn ch xy ra khi nh sng i t mi trng chit quang sang mi trng km cht quang hn. C. Phn x ton phn xy ra khi gc ti ln hn gc gii hn phn x ton phn igh. D. Gc gii hn phn x ton phn c xc nh bng t s gia chit sut ca mi trng km chit quang vi mi trng chit quang hn. 6.19 Khi mt chm tia sng phn x ton phn ti mt phn cch gia hai mi trng th A. cng sng ca chm khc x bng cng sng ca chm ti. B. cng sng ca chm phn x bng cng sng ca chm ti. C. cng sng ca chm khc x b trit tiu. D. c B v C u ng. 6.20 Pht biu no sau y l khng ng? A. Ta lun c tia khc x khi tia sng i t mi trng c chit sut nh sang mi trng c chit sut ln hn. B. Ta lun c tia khc x khi tia sng i t mi trng c chit sut ln sang mi trng c chit sut nh hn. C. Khi chm tia sng phn x ton phn th khng c chm tia khc x. D. Khi c s phn x ton phn, cng sng ca chm phn x gn nh bng cng sng ca chm sng ti. 6.21 Khi nh sng i t nc (n = 4/3) sang khng kh, gc gii hn phn x ton phn c gi tr l: A. igh = 41048. B. igh = 48035. C. igh = 62044. D. igh = 38026. 6.22 Tia sng i t thu tinh (n1 = 1,5) n mt phn cch vi nc (n2 = 4/3). iu kin ca gc ti i khng c tia khc x trong nc l: A. i 62044. B. i < 62044. C. i < 41048. D. i < 48035. 6.23 Cho mt tia sng i t nc (n = 4/3) ra khng kh. S phn x ton phn xy ra khi gc ti: A. i < 490. B. i > 420. C. i > 490. D. i > 430. 6.24 Mt ming g hnh trn, bn knh 4 (cm). tm O, cm thng gc mt inh OA. Th ming g ni trong mt chu nc c chit sut n = 1,33. inh OA trong nc, cho OA = 6 (cm). Mt t trong khng kh s thy u A cch mt nc mt khong ln nht l: A. OA = 3,64 (cm). B. OA = 4,39 (cm). C. OA = 6,00 (cm). D. OA = 8,74 (cm). 6.25 Mt ming g hnh trn, bn knh 4 (cm). tm O, cm thng gc mt inh OA. Th ming g ni trong mt chu nc c chit sut n = 1,33. inh OA trong nc, cho OA = 6 (cm). Mt t trong khng kh, chiu di ln nht ca OA mt khng thy u A l: A. OA = 3,25 (cm). B. OA = 3,53 (cm). C. OA = 4,54 (cm). D. OA = 5,37 (cm). 46. Bi tp v khc x nh sng v phn x ton phn 6.26 Mt ngn n nh S t y mt b nc (n = 4/3), cao mc nc h = 60 (cm). Bn knh r b nht ca tm g trn ni trn mt nc sao cho khng mt tia sng no t S lt ra ngoi khng kh l: A. r = 49 (cm). B. r = 53 (cm). C. r = 55 (cm). D. r = 51 (cm). 6.27 Chiu mt chm tia sng song song trong khng kh ti mt nc ( n = 4/3) vi gc ti l 450. Gc hp bi tia khc x v tia ti l:


Trang 32

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin GiangA. D = 70 32. B. D = 450. C. D = 25032. D. D = 12058. 6.28 Mt chu nc cha mt lp nc dy 24 (cm), chit sut ca nc l n = 4/3. Mt t trong khng kh, nhn gn nh vung gc vi mt nc s thy y chu dng nh cch mt nc mt on bng A. 6 (cm). B. 8 (cm). C. 18 (cm). D. 23 (cm). 6.29* Mt ci chu t trn mt mt phng nm ngang, cha mt lp nc dy 20 (cm), chit sut n = 4/3. y chu l mt gng phng. Mt M cch mt nc 30 (cm), nhn thng gc xung y chu. Khong cch t nh ca mt ti mt nc l: A. 30 (cm). B. 45 (cm). C. 60 (cm). D. 70 (cm). P N CHNG 6 : 1A 16B 2B 17C 3D 18D 4C 19C 5D 20B 6A 21B 7C 22A0

Khc x nh sng9D 24A 10B 25B 11C 26B 12C 27D 13B 28C 14C 29B 15A

8B 23C

Bi tp B sung chng 6: S PHN X V KHC X NH SNGCh 1: NH LUT TRUYN THNG NH SNG. NH LUT PHN X NH SNG. GNG PHNG 1. Pht biu no sau y v vn dng nh lut truyn thng ca nh sng gii thch cc hin tng l khng ng? A. S xut hin vng bng en v vng na ti (bn d). B. Nht thc v nguyt thc. C. Giao thoa nh sng. D. ngm ng thng trn mt t dng cc cc tiu. 2. Ngi ta mun dng mt gng phng chiu mt chm tia sng mt tri xung y mt ging su, thng ng, hp. Bit cc tia sng mt tri nghing trn mt t mt gc 30o. Gc gia gng v mt phng nm ngang l A. 30o B. 60o C. 70o D. 45o 3. Mt ct in cao 5 m dng vung gc vi mt t. Tia sng mt tri chiu xung mt t vi gc 45 o so vi phng nm ngang th bng ca ct in c chiu di l A. 5,2 m. B. 5 m. C. 3 m. D. 6 m. 4. Pht biu no v s phn x nh sng l khng ng? A. Hin tng nh sng b i hng, tr li mi trng c khi gp mt b mt nhn l hin tng phn x nh sng. B. Phn x l hin tng nh sng b lt ngc tr li. C. Tia phn x nm trong mt phng ti v bn kia php tuyn so vi tia ti. D. Gc gia tia ti vi mt phn x bng gc gia tia phn x vi mt . 5. Cc tai sng mt tri chiu xung mt t vi gc 30 o (so vi mt t nm ngang). iu chnh mt gng phng ti mt t c cc tia phn x thng ng hng ln trn th nghing ca gng so vi mt t l A. 25o. B. 40o. C. 45o. D. 30o. 6. Pht biu no sau y v c im ca nh qua gng phng l khng ng? A. Anh S nm i xng vi vt S qua mt gng phng. B. Vt tht cho nh o i xng qua gng phng v ngc li. C. Vt v nh qua gng phng c cng kch thc v cng chiu so vi quang trc ca gng phng (vung gc vi GP). D. Vt v nh qua gng phng hon ton bng nhau. 7. Kt lun no sau y v gng (c gng phng v gng cu)l khng ng? A. Tia phn x t gng ra ta nh xut pht t nh ca gng. B. Tia phn x ko di ngc chiu qua nh S th tia ti ko di ngc chiu s qua vt S hoc t vt S m n gng. C. Tia phn x v tia ti i xng nhau qua gng. 8. Khi tia ti khng i, quay gng phng gc th tia phn x quay gc 2 . Kt qu ny ng vi trc quay no ca gng sau y? A. Trc quay bt k nm trong mt phng gng. B. Trc quay vung gc vi mt phng ti. C. Trc quay i qua im I. D. Trc quay vung gc vi tia ti. 9. iu no sau y v nh cho bi gng phng l ng? A. Vt tht cho nh tht thy c trong gng. B. Vt tht cho nh o thy c trong gng. C. vt o cho nh o thah61y c trong gng.D. ng i ngn nht ni t im M qua gng n im N l ng truyn ca nh sng t M qua gng n im N.


Trang 33

T Vt L Tin Hc trng THPT Nguyn Trung Trc Tnh Kin Giang10. Hai gng phng hp nhau mt gc v mt sng quay vo nhau. im sng S nm cch u hai gng cho qua h hai gng phng ny 4 nh. Gc c gi tr bng bao nhiu? A. = 50 o . B. = 72 o . C. = 60 o . D. = 90 o . 11. Min nhn thy (th trng) ca mt M t trc gng PQ (phng hoc cu) c xc nh bng cch no sau y? A. Ly M i xng ca M qua PQ ni MP v MQ ri ko di MPx v Mqy, ta c hnh chp ct xPQy (trong khng gian). B. Dng cc mt phng vung gc vi gng cc mp vi gng. Ta c hnh chp ct to bi cc mt phng v gng. C. Ni M vi cc mp gng ta c chp nh M v y l mt gng. D. Dng nh M ca Mqua gng ta c chp ct, cc mt bn ta vo cc mp gng ko di ra v cng. 12 Cho hai gng phng vung gc nhau. Tia sng ti G1 (khng trng vi G1) th tia phn x t G2 c tnh cht no sau y? A. Vung gc nhau. B. Song song nhng tri chiu. C. Song song cng chiu. D. Trng nhau. 13. Mt chic cc cm thng ng sn trng, cao 1,5 m. Bng ca cc trn nt sn nm ngang c di 1,2 m. Ct c sn trng ny c bng trn mt sn di 400 cm vo cng thi im . Chiu cao ct c l A. Khng xc nh c. B. Ct c cao 3,2 m. C. Ct c cao 5 m. D. C ba cu tr li u sai. 14. Cu no sau y nh ngha v gc ti l ng? A. Gc ti l gc hp bi tia ti v php tuyn ti im ti ca b mt phn cch hai mi trng. B. Gc ti l gc hp bi tia ti v ng thng vung gc vi mt gng. C. Gc ti c ln bng gc phn x. 15. Hai gng phng c cc mt phn x quay vo nhau hp thnh mt gc 50 o. Gc hp thnh tia ti u tin ti mt gng v tia phn x ln th hai ti gng kia l bao nhiu ? A. 100o. B. 80o. C. 50o. D. Gc ny c ln ph thuc gc ti ti gng th nht nu khng c tr s xc nh. Ch 2: GNG CU 16. Pht biu no sau y v gng cu lm l khng ng? A. Chm tia ti song song vi quang trc chnh cho chm tia phn x hi t ti tiu im F. B. Tiu im F gn ng l trung im on CO ni quang tm C v nh gng O. C. Gng cu lm c tiu im F o v chm tia ti song song vi quang trc cho chm tia phn x phn k ko di ct nhau ngc chiu truyn nh sng. D. Tia ti i qua quang tm C cho tia phn x i ngc tr li v cng i qua tm C. 17. Pht biu no sau y v gng cu li l khng ng? A. Tiu im F ca gng cu li l tiu im o v chm tia ti song song cho chm tia phn x phn k. B. Gng cu li c mt phn x l mt li. C. Tia ti ko di i qua F th cho tia phn x i song song vi quang trc chnh. D. Vt tht nm trong khong gia tiu im F v quang tm C s cho nh tht ln hnn vt v ngc chiu 18. lm gng nhn pha sau xe t, ngi ta thng dng loi gng no ? A. Gng phng. B. Gng cu lm. C. Gng cu li. D. Va phng va lm. 19. mt tia sng phn x trn gng cu lm c phng song song trc chnh th tia ti phi A. i qua t

Documents

Bai Tap Vat Ly 11 CA Nam