Zemansky-52-56

8/20/2019 Zemansky-52-56

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a) E=1−

│Qc ││QH│

→0,4=1− │ Qc││QH│

→ │Qc││QH│

=0,6

b) P=W

t → 1∗10E9 J

s = W

24∗3600 s →W =8,64E13 J

QH =eW →QH =0,4∗8,64E13→ QH =3,456E13 J

QH =mL→m= 2,65J

2,65E7 J /kg →m=1304150,94 kg

c) Qc=0,6 * 3,456E13 = 2,0736E13 J

H =2,0736E13 J 24∗3600 s

=2,4 E 8 J s

d) 2,0736E13=4190*0,05*mm=9,898E10kg= 98978520,29

H =98978520,29m3

24∗3600 s =1145,58

m3

s

e) S=2,4E8

291,15 = 824317,36J Ts

8/20/2019 Zemansky-52-56


a) Primero cac!amo" a e#cie$cia co$ a %&rm!a'e=1−

1

rγ −1=0.6110

E$(o$ce" 06110=

W

Q H

dondeQ H

=200

cac!amo" += 12221 J !ego e

QC =W −Q H =−77.78 J

b) cac!amo" e o!me$ (oma$do e$ c!e$(a a" -rea"'

Ec!aci&$ 1' .1/= r Ec!aci&$ 2' .2/= .1.2= 00864 m e$(o$ce"

re"(amo" ec!aci&$ 1 me$o" ec!aci&$ 2 ob(e$emo"'

l(¿¿1−l2)∗ A

r−1 =4.811 x10−5 m3

V =¿

c) (e$emo" o" aore" e$ a' a= 300 a= 51 10−4

me(ro" cbico"

Pa= 85 104

Pa

8/20/2019 Zemansky-52-56


Punto b' r b = a e$(o$ce" b= 481 105

m3

co$ a %&rm!a

T aV ar−1=T b V b

r−1

cac!amo" a (emera(!ra e$ b e"T b=771 K

co$ a

ec!aci&$ de ga" idea "ie$do $ co$"(a$(e" ob(e$dremo" a re"i&$ e$ b '

pb=2.32 x106 Pa

Punto c: roce"o de b a c e o!me$ b = o!me$ e$ c = 4.811 x 10−5m3

co$ a %&rm!a'Q H =n C ! T

cac!o a (emera(!ra e$ c ero rimero

debo cac!ar e $mero de moe" co$ a ec!aci&$ de ga" idea e$ e !$(o

c e" $= 001738 moe"

o$ e"(o cac!o a c= 1332 e ig!aa$do $ e$ e !$(o c b cac!o a

re"i&$ e$ c !e e"' pc=4.01 x106 Pa

Punto d: ara e"(e !$(o !(ii:o e mi"mo m;(odo !e e !$(o a !e"(o

!e (ambi;$ e" !$ roce"o adiab-(ico ob(e$go'

d= a= 51 10−4 m3

d= 518 a re"i&$' 147 105

Pa

d) ara comara a e#cie$cia cac!o ara cada cico

e<((o)= 0611 = 6110> e<ar$o()= 0775 = 775>

Podemo" ob"erar !e e<((o)?e<ar$o() ei"(e maor e#cie$cia "ig!ie$do

e cico de ar$o(

8/20/2019 Zemansky-52-56


a)

W

Q K

C

=

308.15K C294.15K,35C21 =°=°

W W KP P W K Q W C C 3

1024.28008.2, ×=⋅===

b)

W P P P W H C 33

1004.38001024.2 ×=+×=+=

c) Para aire exterior:

J sW t P Q H H 73 10094.136001004.3 ×=⋅×=⋅=

K J K

J

T

QS

H

H /1055.3

15.308

10094.1 47

×=×

==∆

Para habitación:

J sW t PcQc 6310064.836001024.2 ×=⋅×=⋅=

K J K

J

Tc

QcS /1074.2

15.294

10064.8 46

×−=×−

=−

=∆

d)

K J K J K J S S S habext net /101.8/1074.2/1055.3 344

×=×−×=∆+∆=∆

8/20/2019 Zemansky-52-56


a)

o$"idere a o"ibiidad de !$ i$#$i(e"ima de @!Ao de caor d Q H

a) d QC =−(Tc

T )d Q H

d Q H

(¿)/T

∫d QC =−Tc∫ ¿

d Q H

(¿)/T

∫ ¿

|Qc|=Tc ¿

=c |! "#|

b)

1g de ag!a a de"de 373 a 273

8/20/2019 Zemansky-52-56


8/20/2019 Zemansky-52-56


Go$de

d e" e di-me(ro de a" a"a", e" a raide: de ie$(o a co$"(a$(e k=05

+"3m5

a)

E o!me$ de !$ cii$dro e" <H d 2 4)LE m-imo oder e(raCdo e"(a dado or a e$ergCa ci$;(ica Ec= I m2

m = ρ<πd2 / 4 )L,Ec = ρ<πd2 / 8 )Lv 2.t = L v P= K/t= ρ<π / 8)d2v 3

b)

97m ¿2

3.2 x106 W /0.250.5W s3/m5(¿¿)1 /3

=14 ms =50 Km /#

¿

=( P /ek d2 )

1/3

=¿

c)E ie$(o e$ a" mo$(aa" "!ee "er ma" %!er(e (e$er eocidade"

a(a"

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Zemansky-52-56