2
Rješenje: v = 12 m/s f = 0,013 u =6% m u = 4200 kg B = 2370 mm h = 2640 mm η m.tr = 0,92 k w =0,53 Ns 2 m 4 g = 9,81m/s 2 1. Otpor kretanja vozila ΣR=R f +R u +R w =m u *g*f*cosα + m u *g*sinα + k w *A*v 2 ΣR= 4200 *9.81*0.013*0.998 + 4200*9.81*0.059 + 0.53*5.64*144 ΣR= 534.555 + 2430.918 + 430.445 = 3395.918 N

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  • Rjeenje:v=12m/sf=0,013u=6%mu=4200kgB=2370mmh=2640mmm.tr=0,92kw=0,53Ns2m4

    g=9,81m/s2

    1.OtporkretanjavozilaR=Rf+Ru+Rw=mu*g*f*cos+mu*g*sin+kw*A*v2

    R=4200*9.81*0.013*0.998+4200*9.81*0.059+0.53*5.64*144R=534.555+2430.918+430.445=3395.918N

  • A=0.9*B*h=0.9*2.37*2.64=5.64m2

    tg=6/100=0.06arctg=3.433=3.433sin=0.059cos=0.998

    2.Procentualnoueepojedinihotporauukupnomotporuiznosi:Otporkotrljanja:(Rf/R*100=16%)Otporuspona:(Ru/R*100=72%)Otporvazduha:(Rw/R*100=12%)3.Potrebnasnaga(Peefektivnasnaga)kojumotorrazvija:Pot=R*vPot=3395.918N*12m/s=40751.016W40.751kWPe=Pot/m.tr=40.751kW/0.92=44.294kWPe=44.294kWProcenatiskoritenjamaksimalnesnage:m=Pe/Pemaxm=44.294kW/55kW*100m=81%PotojePe