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  • 8/13/2019 HMTSheet

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    HEAT EQUATION

    Cp

    T

    t+ (u )T

    =k2T+ Sv = k

    Cpthermal diffusivity

    t

    CpT dV =

    CV

    Sv dVCS

    (q n) dA

    CpT(v n) dA

    Rate heat generation heat flow surface heat loss from flow

    THERMAL RESISTANCES

    Q= T

    RR=

    ln routrin2Lk

    CYLINDER R= L

    kACONDUCT.

    R= 1

    hACONVEC. R=

    1

    4k

    1

    r1 1

    r2

    SPHERE

    SIMPLE

    q = k dTdx

    Conduction

    q = hA(T T) Convection

    BIOT NUMBER

    Bi = hL

    k

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    DILUTE SOLUTION (k - solvent) Assumes 1 wk Tg rubbery Rrelax >> Rdiff not limited by bending rate!

    FICKIAN DIFFUSION.

    T < Tg glassy Rdiff >> Rrelax limited by bending

    CASE II Diffusion. Sharp front advances at const. rate.

    CONVECTION-DIFFUSION-REACTION EQUATION Derivedusing RTT

    c

    t+ (u )c= D2c + S

    Boundary Conditions:

    Ni n= 0 impermeable wall Ni|1 n= Ni|2 n condition at interfacePi = Hici Henrys Law Ni n= Ri production at boundary

    ci|1 = ci|2 liquid-porous with partition coefficientNi

    n=

    K(ci

    |2

    ci

    |1) permeable boundary

    TRANSIENT DIFFUSION Laplace Method

    c

    t=D

    2c

    x2 sC= D

    2C

    x2

    BCs: x = 0 c= c0 C= c0s

    || x c, C 0

    which has general soln. C= Ae

    sD + Be

    sD

    Final solution in s-domain must be inverted.Concent. boundary layer can be defined e.g.= 0.01 c c0

    DIFFUSION with CONVECTION Peclet Number P e = ULD

    dif-fusion/convection time.Situation: Membrane in middle, flow through membrane. One side is at a

    set conc. c0, flow is u in the x-direction.BC at the membrane: Ni n= K(ci|2 ci|1)

    N =J+ cU= Dc + cu(i) =Dc

    x+ cu

    Hence our actual boundary cond. is: (for x = 0 i.e. at membrane )

    Dcx

    + cu= K(c0 c)

    Governing eq.2c

    x2 u

    D

    c

    x= 0

    Gen. soln:c= Ae

    uxD

    MASS DIMENSIONLESS NUMBERS

    Sc =

    DSchmidt Number; MOM/MASS diffusivity

    Shx = Kmx

    D Re 12 Sc 13

    km = N n

    c=

    Jy

    c0flux per unit conc drop

    PROD/ABSORPTION IN BULK

    D2c

    x2 kc = 0

    No flux condition at a boundary gives cx

    At permeable boundaries member that flux needs to be continuous, therefore equate.

    REACTIONS Separate equation for each species. Assume reactirate k.

    mA + nB pC SA = km[A]m[B]n

    Now put into CDR.Reaction at an electrode has associated flux NA n= REAC

    KROGH MODEL CDR reduces to:

    D

    r

    r

    r

    c

    r

    R0

    Where R0 is the rate at which cells take up oxygen. (EQ for TISSUE)

    uc

    z= 2

    rcJwall

    Governing equation IN capillary.Flux across wall:

    Jwall = Dct

    r|rc =K0(cc ct|rc)

    i.e. the flux across wall IS proportional to the conc. difference.

    GENERAL

    Lct

    =sC(s) c(0)

    F(s) = Lf(t) =

    0estf(t) dt Laplace transform

    DT

    Dt=

    T

    t+ v T Material derivative

    Ni n dA= cuA Concentration flux i.e. CV analysis

    dU =Q W First Law Isometric (no work) W = 0

    Adiabatic means no heat transfer.

    E= T4 q = (T4s T4surround)