bai tap CHƯƠNG 7 LƯỢNG TỬ ÁNH SÁNG

7/31/2019 bai tap CHNG 7 LNG T NH SNG

1/6

Bi tp t lun Lng t nh sng

CHNG 7: LNG TNH SNGCho h = 6,625.1034J.s ; c = 3.108m/s ; e = 1,6.1019C; me = 9,1.1031kg; 1eV = 1,6.1019J.

DNG 1: HIN TNG QUANG IN NGOICu 1. Gii hn quang in ca Kali l 0,55m. Chiu vo Kali mt nh sng n sc c bc sng 0,33m.Tm cng thot ca electron khi Kali v hiu in th hm cn t vo gia ant v catt dng qutrit tiu hon ton.Cu 2. Khi chiu bc x c bc sng1 = 0,2m vo mt tm kim loi th cc quang electron bt ra v c vtc u cc i l 6,5.105 m/s. Hi khi chiu ln lt vo tm kim loi hai bc x2 = 0,1m v3 = 0,6mth c hin tng quang in khng? Nu c th tnh vn tc ban u cc i ca cc quang electron.Cu 3. Chiu cc bc x 1 = 0,35 m v 2 = 0,54 m vo mt t bo quang in, ngi ta nhn thy vn t ban u cc i ca cc electron quang in khc nhau 2 ln. Hy xc nh gii hn quang in ca cloi. ( 0 = 0,66 m)Cu 4.Mt kim loi c gii hn quang in 0 = 0,6 m, nhn mt chm sng n sc = 0,4 m.a. Hi c xy ra hin tng quang in hay khng? b. Tnh cng thot ca electron khi b mt kim loi ra jun v eV.( A = 3,31.10-19 J = 2,07 eV)c. Tnh vn tc ban u cc i ca cc electron quang in.( 6,06.105 m/s.)Cu 5. Mt t bo quang in c catt lm bng Xsi (Cs). Cng thot ca electron khi Xsi l 1,9 eVvo catt ca t bo quang in ny nh sng c bc sng 0,4m.a. Tnh gii hn quang in ca Xsi.( 0 = 0,654 m ) b. Tnh vn tc ban u cc i ca cc electron quang in trong trng hp ny. ( v0 = 6,5.105m/s )c. Mun cho dng in trong th nghim trn trit tiu hon ton th phi t gia ant v catt mt hiu

hm bng bao nhiu ? (Uh = 1,2 V)Cu 6. Mt t bo quang in c catt lm bng Natri ( c gii hn quang in l 0,5 m). Chiu vo cmt t bo quang in ny nh sng trng c bc sng 0,4 m 0,75 m. Hi trong mch c dng quangin khng? Nu c hy tnh ng nng ban u cc i ca electron quang in bt ra. S : C ;W0max= 9,93.10-20J.Cu 7. Chiu chm bc x c bc sng = 2000A0 vo mt tm kim loi, cc electron bc ra c ng nng bu cc i l 5 eV. Hi khi chiu vo tm kim loi ln lt 2 bc x c bc sng l 16000 A0 v 1000 A0 thc hin tng quang in xy ra khng ? Nu c tnh ng nng ban u cc i ca quang electron bc rCu 8. Dng nh sng n sc c bc sng 1 = 0,4 m chiu vo catt ca mt t bo quang in. Khi vo ant v catt ca t bo quang in ny mt hiu in th hm Uh1 = 2V th dng quang in trit tiu. Hdng nh sng n sc c bc sng 2 = 0,2 m th hiu in th hm Uh2 c gi tr bng bao nhiu? Tnh t svn tc ban u cc i ca electron quang in trn hai trng hp trn.

S : Uh2 = 5,1V ; v2/v1 = 1,6Cu 9. Chiu bc x c bc sng = 0,56 m vo catt ca mt t bo quang in, electron thot ra t cac ng nng ban u thay i t 0 n 5,38.10-20J.

a. Nu thay bc x khc c bc sng 1 = 0,75 m th c xy ra hin tng quang in khng? b. Nu dng bc x c bc sng 2 = 0,405 m th hiu in th hm lm trit tiu dng quang in b

bao nhiu ? (Uh = 1,18 V)

Cu 10. Khi chiu vo catt ca mt t bo quang in mt bc x in t c bc sng = 0,1584 m thhiu in th hm l UAK = 2 V.a. Xc nh gii hn ca quang in ca kim loi lm catt. ( 0 = 0,2643 m)

b. Nu chiu vo catt ca t bo quang in mt bc x c bc sng / = 2

v vn duy tr hiu in thgia ant v catt l UAK = 2V th ng nng cc i ca cc quang lectrn khi bay sang n ant l bao n(Wdmax= 1,072.10-18J)Cu 11.Cng thot ca Na l 2,5 eV.

a. Tm gii hn quang in ca Na. b. Ln lt chiu vo Na cc bc x1 = 2000 A0 v 2 = 21. Bc x no c th gy ra hin tung quang

in?Cu 12.Chiu bc x c tn s 7.108 MHz ln lt vo tm Nhm v Kali. Bit gii hn quang in ca Nv Kali l 0,36m v 0,55m.

a. Tm no s xy ra hin tng quang in ? b. Tnh vn tc ban u cc i ca quang electron?

Trang 1


2/6

Bi tp t lun Lng t nh sng Cu 13.Catt ca mt t bo quang in lm bng Xsi (Cs) c gii hn quang in l0 = 0,66m. Chiu vocatt mt bc x mu vng c bc sng = 0,55m.

a. Tnh nng lng ca phtn nh sng mu vng. b. Tnh vn tc ban u cc i ca cc electron quang in?c. Tnh vn tc ca electron khi n ant. Bit hiu in th gia ant v catt l 100V.

Cu 14.Mt t bo quang in c catt lm bng Xsi. Bit gii hn quang in ca Xsi l 0,66m.a. Tnh cng thot ca electron ra khi b mt catt. b. Nu chiu nh sng trng vo t bo quang in th trong mch c dng quang in khng? Gii th

c. S dng nh sng n sc c bc sng 0,66m, chiu vo t bo quang in. Xc nh vn tc bu cc i ca electron quang in. Trong trng hp ny nu mun trit tiu hon ton dng quang phi t vo gia ant v catt ca t bo quang in mt hiu in th bng bao nhiu?Cu 15. Khi chiu nh sng c bc sng = 0,405m vo catt ca mt t bo quang in th n to ra mdng quang in bo ho. C th lm trit tiu dng quang in ny bng mt hiu in th hm c gi tV.

a. Tm vn tc ban u cc i ca quang electron? b. Tnh cng thot ca electron ra khi b mt catt?c. Gi s c mi phtn n p vo catt lm bc ra mt electron. Tm gi tr ca cng dng b

bit cng sut ca chm bc x trn l 1,5 W.Cu 16. Chiu mt nh sng n sc c bc sng = 0,55m va mt t bo quang in c catt lm bnXsi (Cs) c cng thot l 1,8 eV.

a. Hi c hin tng quang in xy ra khng ? Ti sao ? b. Bit hiu in th gia ant v catt l 90V. Tnh vn tc ca electron khi n ant .

Cu 17.Mt ngn n pht ra nh sng n sc c bc sng = 0,6m s pht ra bao nhiu phtn trong 30snu cng sut pht x ca n l 10 W?Cu 18.Chm sng chiu n catt ca mt t bo quang in c cng sut 1 W v bc sng 0,4m.

a. Tnh nng lng ca mt phtn ra n v eV? b. Tm s phtn p vo catt trong mt giy .c. Tm cng dng quang in bo ho ,bit hiu sut lng t l 10% v hiu sut t bo l 100%

Cu 19.T bo quang in c hiu sut l 100%, c chiu bng bc x c buc sng 0,2m, cng sut chm

bc x l 20 mW v cng dng in bo ho l 1,6 mA. Tnh s electron bc ra khi catt trong 1ssut lng t.Cu 20.T bo quang in c hiu sut l 100%, khi chiu chm nh sng c cng sut 1,5 W, th cng quang in bo ho l 80 mA. Cho hiu sut lng t l 2%

a. Tnh s electron bc ra khi catt vs phtn ti catt trong mt giy . b. Tnh bc sng chm nh sng.

Cu 21.T bo quang in c hiu sut l 50%, khi chiu chm nh sng c cng sut 1,2 W. Bc sng 20.Hiu sut lng t l 5%.

a. Tm nng lng 1 phtn vcng dng quang in bo ho. b. Tnh nhy ca t bo quang in ( nhy J ca t bo l t s gia cng bo ho vi c

chm bc x chiu n catt).

Cu 22. Catt ca mt t bo quang in lm bng Kali c cng thot l 2,15 eV, c chiu bng bc bc sng 0,25m.a. Tm gii hn quang in ca Kali. b. Tnh vn tc ban u cc i ca quang electron.c. Tnh hiu in th hm t vo gia ant v catt lm trit tiu dng quang in .

Cu 23.Cho gii hn quang in ca nhm l 0,36m. Chiu ti tm nhm mt bc x c bc sng l 0,3m.Tm cng thot ra n v eV, hiu in th hm, vn tc ban u cc i ca quang electron bc ra khi cCu 24.Mt tm kim loi c chiu sng bng 1 bc x c bc sng th hiu in th hm l 4 V, khi chiu bng bc x c bc 2 th hiu in th hm l 0,855 V.

a. Tnh? b. Tnh cng thot v gii hn quang in ?c. Tnh vn tc ban u cc i ca quang electron khi chiu bng bc x.

Cu 25. T bo quang in c catt lm bng Xsi, hiu sut t bo 100%, t bo c chiu bng b bc sng 0,4m, cng dng bo ho l 32A

a. Tnh nng lng cu mt photn

Trang 2


3/6

Bi tp t lun Lng t nh sng b. Tm cng sut chm sng ,bit hiu sut lng t l 0,1%.c. Bit hin tng quang in ch xy ra khi bc sng nh sng c gi tr ti a l 0,654m. Tm cng thot

ca Xsi, vn tc ban u cc i ca quang electron v hiu in th gia ant v catt cng dnin bng khng.

d. Tm vn tc ln nht ca quang electron khi n ant, hiu in th gia ant v catt l 1,5V.Cu 26.T bo quang in c catt lm bng Kali c cng thot l 2,2 eV, c chiu bng ngun pht b1= 0,75m,2= 0,6m;3= 0,5m.

a. Tm gii hn quang in .

b. Bc x no trong ngun c hin tng quanh in xy ra.c. Tnh vn tc ban u cc i ca quang electron v hiu in th hm l trit tiu dng quang in.Cu 27.Mt tm kim loi c chiu bng bc x1 = 325 nm th ng nng ban u cc i ca electron bcl 5,3 eV, khi chiu bng bc x2= 300 nm th ng nng ban u cc i l 1,14 eV.

a. Tm hng s Planck vgii hn quang in ca kim loi ny. b. Chiu ti kim loi hai bc x c bc sng v 400 nm. Tnh hiu in th hm.

Cu 28.Gii hn quang in ca kim loi dng lm catt ca t bo quang in l0= 0,35m.a. Tnh cng thot ca electron ca kim loi ra n v eV. b. Tnh vn tc ban u cc i ca electron khi chiu nh sng c bc sng = 0,3m.c. Bit cng sut ca ngun sng l P = 1 W v gi thit c 100 phtn p vo catt th c 1 elect

c ant. Tnh cng dng in bo ho ?Cu 29.Cng thot ca Csi l 1,6.10-19J.

a. Tm gii hn quang in ca Xsi. b. Nu chiu nh sng vng c bc sng 4890 A0 th quang electron tht ra khi Xsi vi vn tc ban u c

i l bao nhiu?Cu 30.Khi chiu mt bc x in t c bc sng = 0,405m vo b mt catt ca mt t bo quang ito ra mt dng in bo ho c cng . Bit gii hn quang in ca kim loi lm catt l0= 0,686m.

a. Tm cng thot. b. Tnh vn tc ban u cc i ca quang electron ?c. Gi s rng trong trng hp l tng c mi phtn p vo mt catt lm bt ra 1 electron. Tm

ca cng dng in bo ho I, bit cng sut ca bc x trn l 1,5 W.

Cu 31.Catt ca t bo quang in lm bng Kali c gii hn quang in l0= 0,55m. Tnh:a. Cng thot ca electron khi Kali. b. ng nng ban u cc i ca electron bn ra t catt khi chiu nh sng c bc sng = 0,5m.

Cu 32. Cng thot ca electron ca kim loi dng lm catt ca t bo quang in l A = 2,588 eV. Hchiu vo catt 2 bc x c tn s ln lt l f 1= 7,5.1014Hz v f 2 = 5.1014Hz th c xy ra hin tng quang inkhng? Nu c th tnh vn tc ban u cc i ca cc quang electron bc ra khi catt .Cu 33.Cng ti thiu lm bc electron ra khi b mt ca kim loi l 1,88 eV.

a. Tm gii hn quang in ca kim loi . b.Tnh vn tc ban u cc i ca electron bc ra khi b mt kim loi khi chiu ln lt cc nh

bc sng l1= 0,489m v2= 0,750mCu 34.Cng ti thiu bt 1 electron ra khi b mt kim loi l 2 eV. Ngi ta chiu nh sng c b0,42m vo tm kim loi y c dng lm catt ca mt t bo quang in. dng quang in tri phi ta phi t vo t bo mt hiu in th hm l bao nhiu?Cu 35. Khi chiu mt bc x c tn s f 1 = 2,2.1015 Hz vo mt kim loi th c hin tng quang in v cquang electron bn ra u b gi li bi hiu in th hm Uh1= 6,6 V, cn khi chiu bc x f 2= 2,538.1015Hz vokim loi th cc quang electron bn ra u b gi li bi hiu in th hm Uh2= 8 V.

a. Xc nh hm s Planck. b. Xc nh gii hn quang in ca kim loi .c. Khi chiu ng thi hai bc x c bc sng l1 = 0,4m v2 = 0,56m vo kim loi trn th hin

tng quang in c xy ra khng ? Tm hiu in th hm ca chng.Cu 36.Cng ti thiu bc mt electron ra khi b mt ca kim loi l 1,88 eV. Dng l kim loi ltrong mt t bo quang in. Hy xc nh :

a. Gii hn quang in ca kim loi cho . b. Vn tc cc i ca electron bn ra khi mt kim loi khi chiu vo nh sng c bc sng = 0,489

m?

Trang 3


4/6

Bi tp t lun Lng t nh sng c. S electron tch ra khi mt kim loi trong 1 pht vi gi thit rng tt c cc electron tch ra u

ant v cng dng quang in o c l I = 0,26 mA.d. Hiu in th gia ant v catt ca t bo quang in sao cho dng quang in trit tiu.

Cu 37.Mt t bo quang in c ant lm bng Xsi cng thot ca electron l A = 1,93 eV.a. Tnh gii hn quang in ca Xsi. b. Chiu vo t bo quang in mt nh sng n sc c bc sng = 0,489m. Tnh vn tc ban u cc

i ca electron khi ri khi mt catt .c. Phi t vo gia ant v catt mt hiu in th nh th no lm trit tiu dng quang in .

Cu 38.Mt kim loi khi chiu bng bc x c tn s 9,23.1014Hz th cc quang electron bc ra mt vn tc cc i l 8,2.105m/s.

a. Tm gii hn quang in ca kim loi . b. Khi chiu ln lt cc bc x c bc sng1= 5000 A0v2= 700 A0 vo tm kim loi trn th hi bc x

no cho hin tng quang in xy ra. Tm vn tc ban u cc i ca quang electron.Cu 39. Tnh nng lng ca phtn ng vi bc x in t sau y:

1. nh sng nhn thy c bc sng = 0,7m.2. tia phng x c tn s f = 1020Hz.3. sng v tuyn c = 103m.

Cu 40. Khi chiu bc x c bc sng = 0,405m vo b mt cu catt ca mt t bo quang in, ta

dng quang in bo ho c cng I bh. C th trit tiu dng quang in bo ho ny bng hiu in th Uh= 1,26 V.1. Tm vn tc ban u cc i ca electron quang in.2. Tm cng thot ca electron i vi kim loi lm catt.3. Gi s mi phtn p vo catt lm bt ra mt electron. Ta o c dng quang in I bh = 49 mA. Tnh s

phtn p vo catt sau mi giy. Suy ra cng sut bc x.Cu 41:Mt tm kim loi c cng thot electron l A = 7,23.1019 J.

1. Xc nh gii hn quang in ca kim loi.2. Dng tm kim loi t c lp, c ri sng ng thi bi hai bc x, bc x th nht c tn1 =

1,5.1015Hz v bc x th hai c bc sng2= 0,18m. Tnh in th cc i trn tm kim loi.3. Khi ri bc x c tn s f 1 vo t bo quang in c catt c lm bng kim loi k trn, khng

electron no v c ant th hiu in th UAK bng bao nhiu?Cu 42.Catt ca mt t bo quang in lm bng Xsi c cng thot in t l 2 eV, c chiu bng mx in t c bc sng = 0,4m.

1. Tm ng nng ban u cc i ca electron quang in v hiu in th hm ti thiu trit tquang in.

2. Cho cng dng quang in bo ho l 2A v hiu sut quang in l 1%. Tm cng sut bc x.Cu 43.Ln lt chiu vo catt ca mt t bo quang in c gii hn quang in0 cc bc x1 = 0,4m v2 = 0,8m th vn tc ban u cc i ca electron khi thot ra khi catt l v1 v v2 hn km nhau hai ln.

1. Tm0, v1 v v2.2. Chiu vo catt ca t bo quang in trn mt bc x in t c = 1m vi cng sut bng 2,4 W.a. Hi hiu in th gia AK phi tho mn iu kin g trit tiu hon ton dng quang in? b. Tnh cng dng quan in bo ho, bit hiu sut lng t H = 0,5%.

Cu 44.Chiu bc x c bc sng = 0,2m vo mt tm kim loi, cc electron bn ra c ng nng ban cc i l 5 eV. Khi chiu ln lt cc bc x c tn s f 1 = 2.1014 Hz v f 2 = 2.1015 Hz vo tm kim loi thhin tng quang in c xy ra khng? Nu c tm ng nng ban u cc i ca electron khi thot khCu 45.Khi chiu chm bc x c bc sng = 0,33m vo catt ca t bo quang in th hiu in th hl Uh.

1. c hiu in th hm l U/h gim 1V so vi Uh th phi dng bc x/ bng bao nhiu?2. Cho gii hn quang in ca catt l0 = 0,66m v t gia AK mt hiu in th dng UAK = 1,5 V.

Tm ng nng cc i ca electron quang in khi p vo ant nu dng bc x c bc sng bng 0,3m.Cu 46. Catt ca mt t bo quang in lm bng kim loi c cng thot in t l 1,9 eV. Catt c bng bc x c bc sng = 0,4m.

Trang 4


5/6

Bi tp t lun Lng t nh sng 1. Tm gii hn quang in v vn tc ban u cc i ca cc electron quang in.2. Dng mn chn tch ra mt chm hp cc electron quang in v cho chng bay vo min t tr

theo hng vung gc vi cc ng sc t c ln B = 6,4.105 T. Hy xc nh bn knh qu o ca ccelectron vi vn tc ban u cc i ca n?Cu 47.Chiu bc x c bc sng = 500 nm vo kim loi c cng thot electron bng 1,8 eV.

1. Xc nh gii hn quang in v vn tc ban u cc i ca electron quang in.2. Nu tch mt electron quang in c vn tc ln nht cho bay t M n N c hiu in th UMN = 15 V th

vn tc ca electron ti N bng bao nhiu?Cu 48. Catt ca mt t bo quang in c ph mt lp xsi (Cs) c cng thot ca electron l A = 1,9 eV.Catt c chiu sng bi mt chm sng n sc c bc sng = 0,56m.

1. Xc nh gii hn quang in ca Cs.2. Dng mn chn tch mt tia hp cc electron quang in v hng n vo mt t trng u c B =5

T v B vung gc vi vn tc ban u ca electron. Xc nh bn knh cc i cu qu o electron ttrng.Cu 49.Mt in cc bng nhm c ri bng bc x t ngoi c bc sng = 0,083m.

1. Electron quang in c th ri xa b mt in cc mt on ti a bng bao nhiu nu in trngli chuyn ng ca electron l E = 7,5 V/m, bit gii hn quang in ca kim loi l 0 = 0,332m.

2. Nu khng c in trng hm v in cc ni t qua in tr R = 1 M th dng in cc i qua intr bng bao nhiu ?

Cu 50.Chiu nh sng c bc sng = 0,4m vo t bo quang in vi cng sut P = 3.103 W. Cho bit t sgia electron bt ra v s phtn chiu n catt trong mi giy l 6,65.10-3. Tnh cng dng quang in boho ca t bo quang in.Cu 51. Chiu nh sng c bc sng = 0,489m ln catt ca t bo quang in. Bit hiu in th hm lh= 0,39 V.

1. Tm cng thot electron v gii hn quang in ca kim loi lm ca tt.2. Bit cng dng quang in bo ho l 5 mA v cng sut chiu ti l 1,25 W. Tm hiu sut l

Cu 52.Chiu nh sng c bc sng = 0,5m ln catt ca t bo quang in. Bit cng thot l A = 1,89 eV.1. Tnh gii hn quang in ca kim loi lm catt v cho bit l kim loi g?2. Tm ng nng ban u cc i ca electron khi thot khi catt.3. Dng mn chn tch mt tia hp cc electron quang in v hng n vo mt t trng u c cm

B v B vung gc vi vn tc ban u ca electron. Bn knh cc i cu qu o electron trong t tr2cm. Tnh cm ng t B ca t trng.

DNG 2: TIA X ( TIA RNGHEN )Cu 1.Hiu in th gia ant v catt mt ng tia Rnghen l 200 kV.

a. Tnh ng nng ca electron khi n i catt. (Wmax= 3,2.10-14J)

b. Tnh bc sng ngn nht ca tia Rnghen m ng c th pht ra. ( min = 6,2.10-12

m)Cu 2.t hiu in th khng i bng U = 2.104 V vo 2 cc ca ng Rnghen.1. Tnh ng nng ca electron khi n i m cc ( b qua ng nng ban u ca electron khi tho

catt).2. Tm tn s ln nht ca tia Rnghen m ng pht ra.

Cu 3.Trong ng Rnghen ta t hiu in th U = 2.104V.1. Tnh nng lng ca electron n catt (b qua ng nng ban u ca cc electron).2. Tnh bc song ngn nht ca tia Rnghen.3. Trong mt pht ngi ta m c 6.1018 in t p vo catt. Tnh cng dng in qua ng Rng

v cng sut ca ng Rnghen.

DNG 3: CC TIN CA BO V QUANG PH VCH CA HYDRCu 1.Xc nh bc sng ca bc x do nguyn t hyro pht ra khi n chuyn t trng thi dng ng vv trng thi dng ng vi n = 2 .Cu 2. Bc sng ca 4 vch H , H, H , H trong dy Banme l: = 0,656m, = 0,486m, = 0,434m , = 0,410m. Hy tnh bc sng ca 3 vch quang ph u tin trong dy Pasen.

Trang 5


6/6

Bi tp t lun Lng t nh sng Cu 3. Ba vch quang ph u tin trong dy Lyman ca nguyn t hyro c bc sng ln lt l1 = 1216 A0;2 = 1016 A0; 3 = 973 A0. Hi nu nguyn t hyro b kch thch sao cho electron chuyn ln qu o Nnguyn t c th pht ra nhng vch no trong dy Banme? Tnh bc sng ca cc vch .Cu 4. Vch quang ph u tin (c bc sng di nht) ca cc dy Laiman, Banme v Pasen trong quaca nguyn t H c bc sng ln lt l 0,122 m; 0,656 m v 1,875 m. Xc nh bc sng ca vchquang ph th 2 ca dy Laiman v dy Banme. Cc vch thuc min no ca thang sng in t?

S : 31 = 0,103 m, vng t ngoi. 42 = 0,486 m, vng nh sng thy c

Cu 5. Ba vch quang ph u tin trong dy Laimain ca nguyn t hir c bc sng 1 = 1216 A0

, 2=1016 A0, 3 = 973 A0. Hi nu nguyn t hir b kch thch sao cho electron chuyn ln v tr N th nguyc th pht ra nhng vch no trong dy Banme? Tnh bc sng ca cc vch .

S : 32 = 6566,4 A0 ; 42 = 4869 A0Cu 6. Trong quang ph ca hyro, bc sng ca cc vch quang ph nh sau: vch th 1 ca dy Lyma21=0,121568m, vch H ca dy Banme32= 0,656279m, ba vch u tin ca dy Pasen43 = 1,8751m ;53=1,2818m ;63= 1,0938m.

a. Tnh bc sng ca hai vch quang ph th hai v th ba ca dy Lyman. b. Tnh bc sng ca ba vch H, H , H ca dy Banme.

Cu 7. Bc sng ca vch ph th nht trong dy Lyman ca quang ph hyr l0 = 0,122m. Bc sng ca

ba vch ph H, H, H trong dy Banme ln lt l1= 0,656m,2= 0,486m;3= 0,434m.a. Tnh tn s ca bn bc x k trn. b. Tnh bc sng ca hai vch tip theo trong dy Lyman v hai vch u tin trong dy Pasen.

Cu 8. Vch th hai trong dy Lyman c bc sng l31= 0,103ma. Vch th nht trong dy Lyman c bc sng21 = 0,122m. Chng t trong dy Banme c mt vch

quang ph c bc sng c quan h vi hai bc sng ni trn. Tm bc sng . b.Vch th 3 trong dy Lyman c bc sng41 = 0,097m. Chng t trong dy Pasen c mt vch quan

ph c bc sng quan h vi hai bc sng31 v41 cho . Tnh bc sng .Cu 9. Chiu chm bc x f = 2,9240.1015 Hz vo mt ng kh hir nhit v p sut thch hp khi trquang ph pht x ca kh hiro ch c 3 vch ng vi tn s f 1 ; f 2 ; f 3. Bit f 1 = f ; f 2 = 2,4669.1015Hz v f 3 < f 2.

a. Gii thch s to thnh cc vch quang ph nu trn. V s chuyn mc nng lng tng ngvch quang ph ? b. Tnh bc sng ca 3 bc x n sc ni trn. Ni r cc bc x thuc dy no trong quang ph cMt ngi bnh thng c th nhn thy my vch?

Cu 10. Bc sng ca vch ph th nht trong dy Lyman ca quang ph nguyn t hir l0 = 0,122m.Bc sng ca 3 vch H , H, H ln lt l: 1= 0,656m, 2= 0,486m,3 = 0,434m.

. Tnh tn s dao ng ca 4 bc x trn. b. Tnh bc sng 2 vch khc trong dy Lyman v hai vch u tin ca dy Pasen.

Cu 11. Trong nguyn t hiro, bn knh ca qy o dng c tnh theo cng thc r n = n2r 0 vi r 0 = 0,53 A0 vn l cc s nguyn dng. Hy tnh bn knh qu o th 5 v vn tc ca electron trn qu o .

Cu 12. Trong quang ph vch ca hir bc sng di nht trong dy Lyman bng 1215 A0

, bc sng ngnnht trong dy Banme l 3650 A0. Tm nng lng cn thit bt electron ra khi nguyn t hir trn quc nng lng thp nht.

Trang 6

Documents

bai tap CHƯƠNG 7 LƯỢNG TỬ ÁNH SÁNG