S GIO DC V O TO

S GIO DC V O TO

TRNG THPT VNH VIN

THI HC K 1

VT L 12 (60 pht)

H tn:

S bo danh: M thi 482

Cu 1: Sng truyn ti mt cht lng vi vn tc truyn sng 0,9m/s, khong cch gia hai gn sng lin tip l 2cm. Tn s ca sng l:A. 90HzB. 0,45HzC. 1,8HzD. 45HzCu 2: Trong mch in xoay chiu gm R, L, C mc ni tip th:

A. lch pha ca uR v u l /2;B. Pha ca uL nhanh hn pha ca i mt gc /2C. Pha ca uC nhanh hn pha ca i mt gc /2;D. Pha ca uR nhanh hn pha ca i mt gc /2Cu 3: Vi phng trnh dao ng iu ha x = Acos( t + ) (cm), ngi ta chn.A. Gc thi gian l lc vt i qua v tr cn bng theo chiu m.B. Gc thi gian l lc vt i qua v tr bt k theo chiu dng.C. Gc thi gian l lc vt v tr bin v pha dng.D. Gc thi gian l lc vt i qua v tr cn bng theo chiu dng.Cu 4: Pht biu no sau y v dao ng cng bc l ng?A. Tn s ca dao ng cng bc bng tn s ca ngoi lc tun hon.B. Tn s ca dao ng cng bc bng tn s ring ca h.C. Bin ca dao ng cng bc ch ph thuc vo tn s ca ngoi lc tun honD. Bin ca dao ng cng bc bng bin ca ngoi lc tun hon.Cu 5: Mt con lc l xo c c nng W=0,5J v bin dao ng A=10cm. Hi ng nng ca con lc ti li x = - 5cm l bao nhiu.A. 0,4J.B. 0,375J.C. 0,75J.D. 0,125J.Cu 6: cao ca m l mt c tnh sinh l ph thuc vo:A. nng lng mB. vn tc mC. bin mD. tn s mCu 7: Pht biu no sau y l ng khi ni v sng c hc?A. Sng m truyn c trong chn khng.B. Sng dc l sng c phng dao ng vung gc vi phng truyn sng.C. Sng dc l sng c phng dao ng trng vi phng truyn sng.D. Sng ngang l sng c phng dao ng trng vi phng truyn sng.Cu 8: Mt sng c tn s 120Hz truyn trong mt mi trng vi tc 60m/s, th bc sng ca n l bao nhiu?A. 0,5mB. 1mC. 2mD. 0,25mCu 9: S o ca vn k v ampe k xoay chiu ch:A. gi tr tc thi ca hiu in th v cng dng in xoay chiu.B. gi tr cc i ca hiu in th v cng dng in xoay chiu.C. gi tr hiu dng ca hiu in th v cng dng in xoay chiu.D. gi tr trung bnh ca hiu in th v cng dng in xoay chiuCu 10: Vt dao ng iu ha, Cu no sau y ng?A. Khi vt qua v tr cn bng, tc cc i, gia tc bng khngB. Khi vt qua v tr cn bng, tc bng khng, gia tc cc iC. Khi vt qua v tr cn bng, tc bng khng, gia tc bng khngD. Khi vt v tr bin, tc bng khng, gia tc bng khngCu 11: Mt dng in xoay chiu i = 2cos(t (A) qua 1 on mch AB gm R = 10(, L= 0,2 (H),C =

EMBED Equation.DSMT4F ni tip. Cng sut tiu th ca an mch AB bng:A. 20WB. 40WC. 60WD. 10 WCu 12: Xt hai im A, B trn cng mt phng truyn m, ln lt cch ngun l 5m v 10m. chnh lch v mc cng m gia hai im A v B bngA. 7 dB.B. 6dBC. 8,8dBD. 3dBCu 13: Trong hin tng giao thoa sng trn mt mt cht lng, vi hai ngun S1, S2 ccng phng trnh dao ng u0 = Acos(t. im M trn mt cht lng,cch hai ngun l d1 v d2, c bin dao ng cc i (k l s nguyn).A. d1 d2 = k

B. d1 d2 = 2kC. d1 + d2 = k(D. d1 d2 = k(Cu 14: Mt vt thc hin ng thi hai dao ng iu ha x1 = 4cos10(cm), x2 = 4cos(10+ ) (cm). Phng trnh dao ng tng hp l :A. x = 4cos(10+ ) (cm)B. x = 8 cos(10- ) (cm)C. x = 4 cos(10-) (cm)D. x = 8 cos(10+ ) (cm)Cu 15: Mt con lc n c chiu di . Trong khong thi gian (t n thc hin 12 dao ng. Khi gim di 32cm th cng trong thi gian ni trn, con lc thc hin c 20 dao ng. Chiu di ban u ca con lc bngA. 80cmB. 30cmC. 40 cmD. 50cmCu 16: Mt sng m truyn trong thp vi tc 5000 m/s. Nu lch pha ca sng m hai im gn nhau nht cch nhau 1 m trn cng mt phng truyn sng l /2 th tn s ca sng bngA. 1250 Hz.B. 5000 Hz.C. 2500 Hz.D. 1000 Hz.Cu 17: Hiu in th gia hai u mt on mch in xoay chiu l: v cng dng in qua mch l:. Cng sut tiu th ca on mch l:

A. 400WB. 200WC. 600WD. 800WCu 18: Mt con lc khi chu tc dng ca ngoi lc bin thin iu ho c tn s f1 hoc f2 > f1 th c bin dao ng l A1. Nu con lc chu tc dng ca lc iu ho (cng cng nh trn) c tn s th bin dao ng ca n l A. So snh A1 v A2 ta cA. A1 > A2B. A1 = A2.C. A1 < A2.D. A1 A2Cu 19: Mt con lc l xo gm vt nng c khi lng 500g, cng ca l xo 50 N/m, dao ng iu ho vi bin 2cm. Tc ca vt nng khi qua v tr cn bng l:A. 2cm/sB. 2m/sC. 0,2m/sD. 0m/sCu 20: Mt on mch in gm R = 100(, L = H, C =

EMBED Equation.DSMT4F mc ni tip. Cho dng in xoay chiu tn s f = 50Hz qua mch. Tng tr ca on mch bng:A. 200(B. 100(C. 100(D. 50(Cu 21: Trong mt th nghim v giao thoa sng trn mt nc, hai ngun kt hp A, B dao ng vi tn s f=24Hz v ngc pha. Ti mt im M cch A, B nhng khong d1=16cm, d2=20cm sng c bin cc tiu. Gia M v ng trung trc ca AB c hai dy cc tiu khc . Vn tc truyn sng trn mt nc lA. 48cm/sB. 32cm/sC. 36cm/sD. 20cm/sCu 22: Con lc l xo nm ngang, vt nng c m = 0,3 kg, dao ng iu ha theo hm cosin. Gc th nng chn v tr cn bng, c nng ca dao ng l 24 mJ, ti thi im t vn tc v gia tc ca vt ln lt l 20 cm/s v - 400 cm/s2. Bin dao ng ca vt lA. 2cmB. 1cmC. 4cmD. 3cmCu 23: Chn Cu sai:A. Tai ngi cm nhn c sng m c tn s t 16Hz n 20.000HzB. Sng m truyn c trong mi trng chn khngC. Sng m c tn s ln hn 20.000Hz gi l siu mD. Sng m c tn s nh hn 16Hz gi l h mCu 24: Mt si dy c chiu di khng i ,cng gia hai im c nh, ngi ta to sng dng trn dy. Hai tn s gn nhau nht to ra sng dng trn dy l 150Hz v 200Hz , vn tc truyn sng vn khng i . Tn s nh nht to ra sng dng trn si dy lA. 75Hz.B. 100Hz.C. 50Hz.D. 125Hz.Cu 25: Hin tng cng hng, chn Cu saiA. khi bin ca dao ng cng bc t n gi tr cc i ta c hin tng cng hngB. iu kin c hin tng cng hng l tn s ca ngoi lc trong dao ng cng bc bng tn s ring ca hC. hin tng cng hng th hin r nt khi lc cn mi trng nhD. trong k thut hin tng cng hng lun c liCu 26: Hai con lc n c chu k T1 = 1,5s ; T2 = 2s. Tnh chu k con lc n c chiu di bng tng chiu di hai con lc trn.A. 3,5sB. 2,5s.C. 3s .D. 3,25sCu 27: Mt my pht in xoay chiu mt pha c phn rto l mt nam chm in c 10 cp cc. pht ra dng xoay chiu c tn s 50 Hz th vn tc gc ca rto phi bng:

A. 1500 vng/pht.B. 500 vng/pht.C. 3000 vng/pht.D. 300 vng/pht.Cu 28: iu no sau y l sai khi ni v my bin th ( my bin p ) ?A. My bin th no cng c cun dy s cp v cun dy th cp.B. My bin th hot ng da trn hin tng cm ng in t.C. My bin th l thit b cho php thay i in ap ca dng in xoay chiu.D. My bin th c th s dng cho dng in khng i.Cu 29: Mt con lc l xo treo thng ng khi cn bng l xo gin 3 cm. B qua mi lc cn. Kch thch cho vt dao ng iu ha theo phng thng ng th thy thi gian l xo b nn trong mt chu k l T/3(T l chu k dao ng ca vt).Bin dao ng ca vt bngA. 6cm.B. 2cm.C. 3cm.D. 3cm.Cu 30: Ch ra Cu sai. m LA ca mt ci n ghita v ca mt ci kn c th cngA. cng B. th dao ng mC. mc cng D. tn sCu 31: Trong vic truyn ti in nng i xa, bin php ch yu gim hao ph trn ng dy ti in l:A. gim chiu di ca dyB. tng hiu in th ni truyn iC. gim tit din ca dyD. chn dy c in tr sut nhCu 32: Trong mch in xoay chiu gm R, L, C mc ni tip ang c cng hng. Nu tng tn s ca hiu in th xoay chiu p vo hai u mch th:

A. Tng tr mch gimB. Hiu in th hai u t tngC. Hiu in th hai u R gimD. Cng dng in qua mch tngCu 33: Con lc n dao ng iu ha vi chu k 1s ti ni c gia tc trng trng 9,8 m/s2, chiu di ca con lc l:A. l = 1,56 m.B. l = 24,8 cm.C. l = 24,8 m.D. l = 2,45 m.Cu 34: ng c in l thit b:A. bin i in nng thnh c nngB. bin i nhit nng thnh c nngC. bin i c nng thnh in nngD. bin i nhit nng thnh in nngCu 35: Vt dao ng iu ho c tc cc i bng 20( cm/s v gia tc c ln cc i ca vt l 4 m/s2 .Ly (2 = 10 th bin dao ng ca vt l:A. 10cmB. 15cmC. 5cmD. 20cmCu 36: Vt dao ng iu ha, thi gian ngn nht vt i t v tr cn bng n v tr c li bng na li cc i l 0,1s. Chu k dao ng ca vt lA. 12 sB. 0,6 sC. 1,2 sD. 0,12 sCu 37: Trn mt si dy di 2m ang c sng dng vi tn s 100 Hz, ngi ta thy ngoi 2 u dy c nh cn c 3 im khc lun ng yn. Vn tc truyn sng trn dy l :A. 60 m/sB. 40 m/sC. 100 m/sD. 80 m/sCu 38: on mch xoay chiu AB cha 3 linh kin L,R,C mc ni tip. on AM cha cun dy thun cm L, on MN cha R v on NB cha C. Bit: in tr R = 50 ; cm khng ZL = 50

EMBED Equation.DSMT4; dung khng ZC = . Ti thi im t , gi tr tc thi uAN = 80V th gi tr tc thi uMB = 60V. Gi tr cc i ca uAB l:A. 100V.B. 100V.C. 150V.D. 50V.Cu 39: oan mach in xoay chiu gm cun cam thun mc ni tip vi in tr thun R = 30(. t vao hai u oan mach in ap u = 120cos100(t (V) thi in ap hiu dung hai u cun cam la 60V . Biu thc cng dong in qua mach la :A. (A)B. (A)C. (A)D. (A)Cu 40: Khi cng hng trong mch in xoay chiu AB gm R, L, C mc ni tip xy ra th biu thc no sau y sai?A. ZL = ZCB. H s cng sut ca mch in : cos( = 1C. UL = URD. UAB = UR-----------------------------------------------

----------- HT ----------4821D

4822B

4823A

4824A

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4827C

4828A

4829C

48210A

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48221B

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48226B

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48228D

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48231B

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48233B

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