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[funlearn] 三角函數講義Ans(一)

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funlearn 三角函數

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Fun Learn

1 AOB = 0o90oABCD( 1 ) sincostancotseccsc

Sol )(1)C E D A E

(2)C E D A E

O F B

O EF OE

FO

F B

O OF OE

F OF 1 = cos

=

EF 1

= sin

=

(3)C E D A A

(4)C EO F B AB OB

D

A

A

O

1 =

B

O F B= tan

O OA OB

1

B OA 1 = sec

AB 1

=

(5)C E D A O 1 D F B CD OC = CD 1 = cotC E D A O 1 D F B OD OC = OD 1 = csc

O

CO

C

4

Fun Learn

2sin 45 o sec 45 o + cos 30 o csc 60 o + tan 60 o cot 60 o =

Sol )= 2 2 3 2 1 + + 3 2 2 2 3 3 = 1+1+1 = 3

31 1 1 1 1 1 + + + + + = 1 + sin 1 + cos 1 + tan 1 + cot 1 + sec 1 + csc

Sol )= 1 1 1 1 1 1 + + + + + 1 + sin 1 + cos 1 + tan 1 + cot 1 + sec 1 + csc

=

1 1 1 + + + 1 + sin 1 + cos 1 + tan

1 1+ 1 tan

+ 1+

1 1 cos

+ 1+

1 1 sin

= =

1 1 1 tan cos sin + + + + + 1 + sin 1 + cos 1 + tan 1 + tan 1 + cos 1 + sin 1 + tan 1 + cos 1 + sin + + = 1+1+1 = 3 1 + tan 1 + cos 1 + sin

4sin 2 17 O + sin 2 73 O + tan 2 35 O cot 2 29 O sec 2 35 O + csc 2 29 O =

Sol )= sin 2 17 O + cos 2 17 O + (tan 2 35 O sec 2 35 O ) (cot 2 29 O csc 2 29 O ) = 1 + ( 1) ( 1) = 1

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