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Part 1: SYSTEM RESPONSE (mainly revisions)
Summary of first order systems:
Specified by two parameters – Gain (A) and A
Time-constant (T).
Output reaches steady state after input, hence name ‘LAG’
1 sT+
A first order system has a gain of 10 and a time-constant of 1 msec,
What is its transfer function?
Part 1: SYSTEM RESPONSE - Example
Example: Describe the system, if the transfer function of a system is given as
204s +
Hence: A first order systemGain is 5Time-constant is 0.25 s
20 54 1 0.25s s=
+ +
2
Part 1: SYSTEM RESPONSE
From Characteristic Equation to POLES
1 tTe−Loosely, the term ‘pole’ indicates that the
‘value’ of the transfer function is infiniteeT value of the transfer function is infinite.
The roots (or eigenvalues) of the CE locate the poles of the system.
We can represent the position of the pole(s) on the s-plane by means of a cross.
α+sk
Im (jω)
Our example (of the first order lag system) has one real pole, at s = - α
Re (σ)
Part 1: SYSTEM RESPONSE
Second Order Systems
In the previous examples ( )( )10110
++ ss( )( )
Characteristic Equation ( )( ) 0101 =++ ss
010112 =++ ss
Two real polesTwo real poles – two decaying exponential terms in transient response
More generally, roots of quadratic (of CE) are COMPLEX
3
Part 1: SYSTEM RESPONSE
Second Order Systems - Example
525
2 ++ ssCharacteristic Equation
0522 =++ ss
A pair of conjugate poles
;211 js +−=
212 js −−=
212,1 js ±−=
- 1
Part 1: SYSTEM RESPONSE
Second Order Systems - Example
212,1 js ±−=
Amplitude decayingat e-t
- 1 Frequency of oscillation = 2 rad/s
4
Part 1: SYSTEM RESPONSE
Second Order Systems – Standard Form
2
22
2
2 nn
n
ss ωζωω
++
ωn -- Natural Frequencyn y
ζ -- Damping ratio, or damping factor
ONLY for complex poles
Part 2: SYSTEM RESPONSE
Second Order Systems – Standard Form
02 22 =++ nnss ωζωPoles are roots of CE
122,1 −⋅±⋅−= ζωωζ nns
Four important casesζ = 0 undampedζ = 0 – 1, under-dampedζ = 1, critical dampingζ > 1, over-damped
5
Part 2: SYSTEM RESPONSE
Pole locations
Pole far from the axisPole far from the axis Shorter time-constant Faster response.
Pole in Left Half-plane Stable System
Pole in Right Half-plane Unstable S stemUnstable System
Pole on axisMarginally Stable
Part 2: SYSTEM RESPONSE
Cascade systems and dominant pole
1 101
1+s 10+s
S stem C E
( )( )10110
++ ss
System C.E.(s+1)(s+10)=0
System poles at s = -1; and s = -10
6
Revision: complex numbers or vectors
Im
bjba +=Y
Rea
bθjMe=Y
θ∠==→
MYY
22 baM +=
⎟⎠⎞
⎜⎝⎛= −
ab1tanθ
)cos(θMa =
)sin(θMb =
Revision: basic operations of complex numbers
)sin()cos( θθθ je j +=M=1: )()( j
)sin()cos( θθθ je j −=−
2)cos(
θθ
θjj ee −+
=
jee jj
2)sin(
θθ
θ−−
=
7
Revision: basic operations of complex numbers
( ) ( ) ( ) ( )dbjcajdcjba +++=+++( ) ( ) ( ) ( )jjj
( ) ( ) ( ) ( )dbjcajdcjba −+−=+−+
( ) ( ) bdjbcjadacjdcjba −++=+×+
( ) ( )bcadjbdac ++−=
jdcjdc
jdcjba
jdcjba
−−
×++
=++ ( ) ( )
22 dcadbcjbdac
+−++
=
Revision: Basic operations of complex numbers
( ) 11
θjeMjba =+
( ) ( ) ( ) ( )2121
θθ jj eMeMjdcjba ⋅=+×+
( ) ( ) mjm
j eMeMM θθθ =⋅= + 2121
( ) 22
θjeMjdc =+
2
1
2
1θ
θ
j
j
eMeM
jdcjba
=++
( ) njn
j eMeMM θθθ =⎟⎟
⎠
⎞⎜⎜⎝
⎛= − 21
2
1
8
Revision: Basic operations of complex numbers
( ) ( )tjttj eee βαβα −−+− ⋅= ( )eee
( ))sin()cos( tjte t ββα −⋅= −
( ) ( )tjttj eee βαβα +−−− ⋅= ( )eee
( ))sin()cos( tjte t ββα +⋅= −
tjtj BeAe )21()21( +−−− +