Gio vin thc hin: Phm Nghip - Trng THPT Trn Quc TunGio n Vt l 12 Nng cao

Cu hi: Trong mt on mch xoay chiu ch c in tr thun, hiu in th bin thin th no so vi cng dng in? Vit cng thc nh lut m cho on mch .

1. on mch xoay chiu ch c t ina. Th nghim+ Dng c+ Tin hnh v kt quHy chn dng c th nghim? S ?

1. on mch xoay chiu ch c t ina. Th nghim+ Dng c+ Tin hnh v kt qu-T khng cho dng in mt chiu i qua.-T cho dng in xoay chiu i qua nhng cn tr dng in xoay chiu (gy ra in tr i vi dng in xoay chiu).

1. on mch xoay chiu ch c t ina. Th nghim+ Tin hnh v kt qu-Cng dng in qua t bin thin iu ho cng tn s v lch pha /2 i vi in p gia hai bn t in.Da vo th ca i(t) v u(t) hy cho bit s bin i ca cng dng in v hiu in th gia hai bn t theo thi gian? So snh chu k v pha dao ng ca hiu in th v cng dng in? + Dng c

b. Gi tr tc thi ca cng dng in v in p-t vo hai u on mch hiu in th xoay chiu: ~ -in tch trn bn M ca t ti thi im t:n tch q c c im g?1. on mch xoay chiu ch c t in q = Cu = CU0sint u = U0sint

b. Gi tr tc thi ca cng dng in v in pNu trong khong thi gian t b in lng chuyn qua on mch l q th cng dng in i qua on mch c xc nh bng h thc no ? -V 1. on mch xoay chiu ch c t in~

b. Gi tr tc thi ca cng dng in v in p*Nhn xt: cng dng in qua t bin thin iu ho cng tn s v sm pha /2 so vi in p gia hai bn t in.Nu in p t vo hai u on mch c dng u=U0cost th biu thc i c dng nh th no?1. on mch xoay chiu ch c t invi I0 = CU0

th hin s lch pha gia cng dng in tc thi v hiu in th tc thi gia hai u on mch ngi ta thng dng hnh v biu din, hnh v gi l g?c. Biu din bng vect quay biu din cc gi tr: i = I0cost v u = U0 cos(t -/2 ) bng cc vect th ta phi lm nhng vic g?-Chn trc chun Ox nm ngang, chiu dng l chiu lng gic -Gin vect1. on mch xoay chiu ch c t in Hy v gin vect?

c. Biu din bng vect quay1. on mch xoay chiu ch c t in

d. nh lut m i vi on mch ch c t in. Dung khng: Dung khng ca t ()1. on mch xoay chiu ch c t inH thc I = U/ZC cho ta nhn xt g?

d. nh lut m i vi on mch ch c t in. Dung khng1. on mch xoay chiu ch c t inTi sao t khng cho dng in mt chiu i qua, cho dng in xoay chiu i qua?c. Biu din bng vect quayb. Gi tr tc thi ca cng dng in v in pa. Th nghim: Dung khng ca t ()

tng dung khng ca mt t in phng c in mi l khng kh, ta cn A. tng tn s ca in p t vo hai bn t in.B. tng khong cch gia hai bn t in.C. gim in p hiu dng gia hai bn t in.D. a bn in mi vo trong lng t in.2. Trong mch in xoay chiu ch c t in, ta c th cC. u=U0cos (t - /4)( V ); i =I0cos (t + /4)( A ). B. u=U0cos (t + /2)( V ); i =I0cos (t)( A ). A. u=U0cos (t)( V ); i =I0cos (t - /2)( A ).D. u=U0cos (t - /2)( V ); i =I0cos (t - /2)( A ).

3. Nhn xt no v on mch xoay chiu ch c t in l sai?A. T in khng cho dng in mt chiu i qua nhng cho dng in xoay chiu i qua.B. Hiu in th hai u t in lun chm pha /2 so vi cng dng in qua t.C. Cng dng in qua t in lun chm pha /2 so vi hiu in th gia hai bn t in.D. Gi cho cc yu t khc khng i, nu in dung ca t in tng 2 ln th dung khng ca t gim 2 ln.4. Chn cu sai?D. cng dng in qua mch bin thin vi chu k 0,02s.A. dung khng ca t l 100 .B. dng in qua mch c cng hiu dng l 1 A .C. biu thc cng dng in qua mch l