Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC PHN PHI CHNG TRNH MN VT L LP 11CHNG TRNH NNG CAO THPT THANH BNH 1HC K I (2012 2013)Chng I: in tch, in trngTit 1.nh lut CulngTit 2. Bi tpTit 3.Thuyt lctrn. nh lut bo ton in tchTit 4.in trngTit 5. Cng ca lc in. Hiu in th ( Tit 1: Ht phn 1 SGK)Tit 6. Cng ca lc in. Hiu in th ( Tit 2: T phn 2 SGK)Tit 7. Bi tpTit 8. Bi tp v nh lut Culng, in trngTit 9. Vt dn v in mi trong in trngTit 10. T inTit 11. Nng lng in trng. Tit 12. Bi tp v t inChng II: Dng in khng iTit 13. Dng in khng i, ngun inTit 14.Pin v cquyTit 15. in nng v cng sut in. inh lut Jun-Lenx ( Tit 1: Ht phn 2 SGK)Tit 16. in nng v cng sut in. inh lut Jun-Lenx ( Tit 2: T phn 3 SGK)Tit 17. Bi tp Tit 18. nh lut m i vi ton mchTit 19. Bi tpTit 20. nh lut m i vi cc loi on mch. Mc cc ngun thnh b ( Ht phn 3 SGK)Tit 21. nh lut m i vi cc loi on mch. Mc cc ngun thnh b ( T phn 4 SGK)Tit 22. Bi tp Tit 23. Bi tp v nh lut m v cng sut inTit 24+25 Thc hnh: xc nh sut in ng v in tr trong ca mt pin in haTit 26. Kim tra 1 titChng III: Dng in trong cc mi trngTit 27. Dng in trong kim loiTit 28. Hin tng nhit in. Hin tng siu dnTit 29. Dng in trong cht in phn. nh lut Faraday ( Ht phn III SGK)Tit 30. Dng in trong cht in phn. nh lut Faraday ( T phn IV SGK)Tit 31. Bi tp v dng in trong kim loi v cht in phnTit 32. Bi tpTit 33. Dng in trong chn khng (phn 1-2)Tit 34. Dng in trong chn khng (phn 3-4)Tit 35. Dng in trong cht kh Tit 36. n tp hc k ITit 37. n tp hc k ITit 38. Kim tra hc k IGV: NguynMinh Hi Trang1Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC HC K II (2012 2013)Tit 39. Dng in trong cht kh Tit 40. Dng in trong cht bn dn ( Ht phn 2 SGK)Tit 41. Dng in trong cht bn dn ( T phn 3 SGK)Tit 42. Linh kin bn dnTit 43 Bi tp .Tit 44+45. Thc hnh: Kho st c tnh chnh lu ca it bn dn v c tnh khuch i ca tranzitoChng IV: T trngTit 46. T trngTit 47. Phng v chiu ca lc t tc dng ln dng in. Tit 48. Cm ng t. nh lut AmpeTit 49. T trng ca dng in trong cc dy dn c hnh dng n ginTit 50. Bi tp v t trng. Tit 51. Tng tc gia hai dng in thng song song. nh ngha n v ampeTit 52. lc Lo ren x Tit 53. Khung dy c dng in t trong t trng Tit 54. S t ha cc cht. St t Tit 55. T trng Tri t Tit 56. Bi tp v lc tTit 57+58. Thc hnh: Xc nh thnh phn nm ngang ca t trng Tri tChng V: Cm ng in tTit 59. Kim tra 1 titTit 60. Hin tng cm ng in t. Sut in ng cm ngTit 61. Hin tng cm ng in t. Sut in ng cm ng Tit 62. Bi tp Tit 63. Sut in ng cm ng trong mt on dy dn chuyn ngTit 64. Dng in Phuc Tit 65. Hin tng t cm Tit 66.Nng lng t trng Tit 67. Bi tp v cm ng in tChng VI: Khc x nh sngTit 68. Khc x nh sngTit 69. Bi tp Tit 70. Phn x ton phnTit 71. Bi tp Tit 72. Bi tp v khc x nh sng v phn x ton phnTit 73. Kim tra 1 titChng VII: Mt v cc dng c quang hcTit 74. Lng knhTit 75. Bi tp Tit 76. Thu knh mng ( Ht phn 3 SGK)Tit 77. Thu knh mng ( T phn 4 SGK)Tit 78. Bi tp v lng knh v thu knh mngTit 79. Mt. Tit 80. Cc tt ca mt v cch khc phcTit 81. Bi tp Tit 82. Knh lp Tit 83. Knh hin vi Tit 84. Bi tp Tit 85. Knh thin vn Tit 86. Bi tp v dng c quang hc GV: NguynMinh Hi Trang2Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tit 87+88. Thc hnh: Xc nh chit sut ca nc v tiu c ca thu knh phn kTit 89. n tpTit 90. n tpTit 91. n tpTit 92. Kim tra hc k II.GV: NguynMinh Hi Trang3Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 1Ngy san: 5-08-12 Tit PPCT: 1Ngy dy: CHNG I : IN TCH. IN TRNGBi 1. IN TCH. NHLUT CU-LNGI.Mc Tiu:- Kin Thc:- Hc sinh nm c cc khi nim: Hai loi in tch, lc tng tc gia hai in tch im cng du v tri du.- Trnh by c khi nim in tch im v cu to ca in nghim.-Pht biu nh lut Cu-lng v vit biu thc ca nh lut Cu-lng v tng tc gia cc in tch im trong chn khng, ni r phng chiu ca lc Cu-lng. - K Nng:p dng nh lut Cu-lng gii cc bi tp Bit cch biu din lc tng tc gia cc in tch bng cc vectBit cch tm lc tng hp tc dng ln mt in tch bng php cng cc vect lcII. CHUAN B1. Giao vien- Mt s th nghim n gin v s nhim in (nu c)2. Hoc sinh: On tap kien thc a hoc ve ien tch THCS.III. T Chc Hot ng Dy-Hc:Hot ng 1(10 pht): Hai loi in tch.S nhim in ca cc vt.TgNoi dungHot ng Ca GV Hot ng Ca HS11 1. Hai loi in tch. S nhim in ca cc vt. a.Hai loi in tch:- in tch dng (+)- in tch m (-)-Cc in tch cng du th y nhau, khc du th ht nhau.- in tch ca electron: e = - 1,6.10-9 (C) b. S nhim in ca ccvt. THCShcccloiin tch no?Vt b nhim in khi no? M t cc hin tng nhim in i vi cc vt?Hng dn HS nghin cu nhim in do tip xc v do hng ng.Vt b nhim in cn gi l vt mang in,vt tch in hay l mt in tch. in tch xut hin s c tc dng nh th no?in tch dng (+), in tch m (-)Cc in tch cng du th y nhau, khc du th ht nhau. Khi c xtthanh thy tinh vo la. Ta thy thanh thy tinh c th ht cc vt nh:giy vn,si bng=> Thanh thy tinh b nhim in. Gia cc vt b nhim in v cc vt nh b ht c xut hin in tch.GV: NguynMinh Hi Trang4BBTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC - Nhim in do c xt.- Nhim in do tip xc.- Nhim in do hng ng.Tr li cu hi C1 trong SGK. Cc em bit g v tnh cht ca nhng vt mang in? HS tr li cu C1cc vt c tnh cht tng tc vi nhau

Hot ng 2 (12 pht): nh Lut Cu-lng.n v in tch162. nh lut Cu-lng.

S cn xon cu-lng-nh lut Cu-lng: (SGK) 22 1.rq qK F vi K: l h s t lK=9.109Nm2/C2F: lc tnh in, (N) r: Khang cch gia 2 din tch,(m); q1,q2: ln in tch, (C) Nm 1785, Cu-lng(Php) thit lp c nh lut v s ph thuc calctngtcgiaccin tchimvokhongcchgia chng,olcygia2qu cu nh cng in tchng dng chic cn xon.Quan st v m t cn xon?-Trnh by th nghim dn n kt qu- Ch ti phng ca lc tng tc. ? Qua cc kt qu trn hy pht biu nh lut Cu-lng?biu din lc tng tc gia 2 in tch cng du,khc du?Hyvit cngthcnhlut Cu-lng? Trong h SI: K=9.109Nm2/C2 n v cc i lng trong cng thctrn?tnunv in tch?Hng dn HS tr li cu hi C2 HS lng nghe-HS quan st,kt hp c trong SGK tr li.-HS pht biu nh lut Cu-lng v Mt HS ln bng biu din lc tng tc gia 2 in tch cng du, khc du. 22 1.rq qK F vi K l h s t l.n v: -HS c v tr li cu hi C2 trong SGK.1. .Khi tng ng thi khong cch gia 2 in tch im ln gp i v ln ca mi in tch ln gp bath lc tng tc tnh in gia chng s:A. Tng ln gp i B.Gim i mt naC.Tng 2,25 ln D.Tng 2,5 lnGV: NguynMinh Hi Trang5F21Fq2 q1 21F21F12FrATrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 3 (8 pht): Lc tng tc gia cc in tch im t trong in mi 8 3.Lc tng tc gia cc in tch im t trong in mi ( cht cch in) 22 1..rq qK F-Hng s in mi: ( 1) c trng cho tnh cht in ca 1 cht cch in.i vi chn khng:=1 so snh ln cc in tch ta nghin cu Lc tng tc gia cc in tch trong in mi.? in mi l mi trng cch in hay dn in?? Vt cng thc nh lut Cu-lng trong trng hp ny ?? Hng s in mi cho ta bit u g? -GV kt lun li vn -HS lng nghe.in mi l mi trng cch in 22 1..rq qK FKhi cc in tch im t trong in mi ng tnh th lc tng tc gia chng nh hn ln so vi khi t chng trong chn khngHot ng 4(10 pht):Cng c, Vn dng, dn d:Cng c: Noi dung nh luat CuLong, Cong thc nh luat CuLong. 22 1.rq qK F Trong moi trng co hang so ien moi:22 1..rq qK F : Hang so ien moi cua moi trng.Vn dng: Tr li cu hi 1,2,3 v bi tp 1,2 sgk trang 8,9 Bi tp: Xc nh lc tng tc gia hai in tch q1 = 3.10-6C v q2= - 3.10-6 C cch nhau mt khang r = 3 cm trong 2 trng hp:a) t trong chn khngb) t trong du ha c hng s in mi bng 2.D n d : V nh lm bi tp 3,4 trang 9 sgk v 1.1; 1.2; 1.4 SBT, tit sau gii bi tp.GV: NguynMinh Hi Trang6Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 1 Ngy san: 5-08-12Tit PPCT: 2Ngy dy: BAI TAPI. MUC TIEU1. Kien thc : Bit cch biu din lc tng tc gia cc in tch bng cc vectBit cch tm lc tng hp tc dng ln mt in tch bng php cng cc vect lc2. Ky nang : Vn dng nh lut Cu-lng gii cc bi tp II. CHUAN BGiao vien- Xem, giai cac bai tap sgk va sach bai tap.- Chuan b them not so cau hoi trac nghiem va bai tap khac. Hoc sinh- Giai cac cau hoi trac nghiem va bai tap.III. TIEN TRNH DAY HOCHoat ong 1 (5 phut) : Kiem tra bai cu:Cu 1: Pht biu ni dung nh lut Cu-lng v vit biu thc ca nh lut.Cu 2: Hai in tch bng nhau t trong chn khng, cch nhau mt an 4 cm. Lc y tnh in gia chng l 10-5N. Tm ln mi in tch? Hoat ong 2(8 phut) : Giai cac cau hoi trac nghiem.TgNoi dung c ban Hoat ong cua giao vienHoat ong cua HS8 Cau 1 trang 8 : CCau 2 trang 8 : CCau 1.1 SBT: CCau 1.2 SBT: BCu 1.4 SBT: CYeucauhsgiai thchtai sao chon C.Yeucauhsgiai thchtai sao chon C.Yeucauhsgiai thchtai sao chon C.Yeucauhsgiai thchtai sao chon B.Yeu cau hs giai thch tai sao chon CGiai thch la chon.Giai thch la chon.Giai thch la chon.Giai thch la chon.Giai thch la chonHoat ong 3 (30 phut) : Giai cac bai tap t luan.TgNoi dung c ban Hoat ong cua GV Hoat ong cua HS8 Bi 3 trang 9:22,4 (l)2.6,02.10231.10-3 (l)?S nguyn t hir trong 1 cm3193 2310 . 375 , 54 , 2210 . 10 . 02 , 6 . 2 nY/c HS tm tt gi thuyt bi tanGv hng dn gii-Tnh s nguyn t trong 1 cm3.- Mt nguyn t hir c bao nhiu electron, proton? Hs tm tt gi thuytMt HS ln bng giiGV: NguynMinh Hi Trang7Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 5107Tng cc in tch dng:Q = 5,375.1019. 1,6.10-19 = 8,6 (C)Tng cc in tch m:Q =5,375.1019.(-1,6.10-19) = - 8,6 C Bi 4 trang 9:Cho bit:r = 5.10-11 (m)K = 9.109/q1/ = /q2/ = e = 1,6.10-19CGii:pdngcngthccanhlut Cu-lng:22 1.rq qK F = 9,216.10-6 (N)Bi 1:a) Hai in tch y nhau nn q1.q2 > 0 v q1 = q2 = qTa c: 22 1.rq qK F = 22rqK) ( 10 .3410 .916 .61222C qKr Fqt b) Khi lcygiahai in tch F= 2,5 NTa c: ) ( 08 , 064 , 0/ /.'2222m rFqK rrqK F Bai 2:- intchca1electronl bao nhiu?- in tch ca 1 proton l bao nhiu?- Tnh tng in tch dng v tng in tch m trong n nguyn t.Bi 4 trang 9:Y/c HS tm tt gi thuyt bi tonGv gi HS ln giiBi tp 1: Hai in tch im bng nhau t trong chn khngcchnhau4cm. Lc y gia chng l 10 Na) Tm ln mi in tch b) Tnhkhangcchgia chnglctcdng F= 2,5 NY/c HS tm tt gi thuyt bi tonGv hng dn gii- Hai intchynhauth cng hay tri du?- Vietbieuthcnh luat Cu-lng.- Bin i thnh cng thc tnh in tch q.- Thay lc bng 2,5 Ntnh khong cch rBi tp2:Hai qu cunh -Mt electron v mt protone = - 1,6.10-19 Cp = 1,6.10-19 CHs tm tt gi thuytMt HS ln bng giiHs tm tt gi thuytMt HS ln bng gii- Cng du- 22 1.rq qK F ) ( 10 .3410 .916 .61222C qKr Fqt GV: NguynMinh Hi Trang8Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Theo nh luat Cu-long ta co F = k22 1| |rq q = k22rq=> q2 = 92 1 3 210 . 9) 10 .( 1 . 10 . 9 kr Fq =t 10-7(C)Bi 3:Lc tnh in: 22 1.rq qK F = 22.reK (q1=q2=e)Lc hp dn: 2222 1rmGrm mG Fhd F = Fhd th:Gm2 = ke2=> m = 1,86.10-9 (kg)manghai intchcln bngnhau, t cchnhau10 cmtrongchnkhngth tc dng ln nhau mt lc l 9.10-3 N. Xc nh in tch ca hai qua cu . Y/c HS tm tt gi thuyt bi ton- Vietbieuthcnh luat Cu-lng.- Bin i thnh cng thc tnh in tch q thay s vo tm q.Gv gi HS ln giiBi 3: Hai vt nh ging nhau mi vt tha mt electron. Tm khi lngmi vt, bit lc tnh in bng lc hp dn.Y/c HS tm tt gi thuyt bi ton- Vietbieuthcnh luat Cu--lng.- Viet bieuthc tnh lc hp dn- Cho hai lc bng nhau, suy ra tnh khi lngGi HS ln bng gii) ( 08 , 064 , 0/ /'22m rFqK r Hs tm tt gi thuyt22 1.rq qK F Kr Fq22. =t 10-7CMt HS ln bng gii Hstmtt gi thuyt22 1.rq qK F 2222 1rmGrm mG Fhd Gm2 = ke2=> m = 1,86.10-9 (kg)Mt HS ln bng giiHoat ong 4: (2 phut) : Cng c- Dn d- Nhc li cng thc tnh lc tnh in- Chun b son bai thuyet electron: + Noi dung thuyet electron.+ nh luat bao toan ien tch.GV: NguynMinh Hi Trang9Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC

GV: NguynMinh Hi Trang10Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun2 Ngy san: 5-08-12Tit PPCT: 3Ngy dy: Bi 2: THUYET ELECTRON- NH LUAT BAO TOAN IEN TCH.I Mc tiu:- Kin Thc Trnh by c nhng ni dung chnh ca thuyt lectron. T trnh by c ngha ca cc khi nim ht mang in v vt nhim in.Pht biu c ni dung ca nh lut bo ton in tch.- K Nng: Gii thch c tnh dn in ca mt vt, ba hin tng nhim in ca cc vt.II Chun b:Gio vin:Th nghim v nhim in do c xt (thanh thu tinh hay thoc nha, mnh la hay mnh d, giy vn) cc qu cu bng kim loi, my pht tnh in (nu c)Hc sinh: n li hin tong nhim in do c xt, cht nhim in, cht cch in ( hc THCS)III. T Chc Hot ng Dy-Hc:Hot ng 1: (5 pht)Kim tra bi cHot ng 2( 10 pht): Tm hiu v ni dung chnh ca thuyt electron.TgNoi dung Hot ng Ca GV Hot ng Ca HS10 1/ Thuyt lectron: Thuytdavos c mtca electron v chuyn ng ca chng gii thch mt s hin tng in t gi l thuyt electron.Ni dung: - Bnh thng nguyn t trung ho v in + Nu nguyn tmt i mt e th nguyn t tr thnh ion dng. + Nu nguyn t nhn thm mt e th nguyn t tr thnh ion m.- Vt nhim in m l vt tha e. Vt nhim in dng l vt thiu e.Yu cu HS nhc li cu to ca nguyn t, ht nhn?

Nhc li hin tng nhim in do c xt. - Yu cu HS c phn 1.-YucuHStrnhby3ni dung ca thuyt.- Nhn xt tr li ca HS.- Nu cu hi C1.- Nu cu hi C2.- Nhn xt tr li ca HS. HS nu cu to nguyn t. c SGK-Tm hiu ni dung c bn ca thuyt electron.- Trnh by ni dung ca thuyt.- Nhn xt bn tr li.-Trnhbycutrli ca cu hi C1.-Trnhbycutrli C2 GV: NguynMinh Hi Trang11Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 3 (5 pht): Tm hiu Vt(cht) dn in v vt (cht) cch in62. Vt(cht) dn in v vt (cht) cch in.- Vt (cht) dn in l vt (cht) c cha cc in tch t do. - Vt (cht) cch in l vt (cht) cha rt t in tch t do.- Yu cu HS c phn 2.- T chc hot ng nhm.- YucuHStrnhbyhiu bit ca mnh v cht dn in.- Yu cu HS nu nhn xt.- Nhn xt tr li ca HS.-c SGK- Tho lun nhmtm hiu cht dn in v cht cch in l g.- Tm hiu cht dn in v cht cch in. - Trnh by cht dn in v cht cch in. - Nhn xt bn tr li. Hot ng 4(10 pht):Vn dng thuyt electron gii thch 3 hin tng nhim in13 3. Gii thch ba hin tng nhim in:a) Nhim in do c xtb) Nhim in do tip xcc) Nhim in do hng ng- Yu cu HS c phn 3a.- T chc hot ng nhm.- Yu cu HS gii thch hin tng nhim in do c xt.- Nhn xt tr li ca HS.- Yu cu HS c phn 3b.- T chc hot ng nhm.- Yu cu HS gii thch hin tng nhim in do tip xc.- Nhn xt tr li ca HS.Hon thnh C3- Yu cu HS c phn 3c.- T chc hot ng nhm.YucuHSgii thchhin tng nhim in do- Nhn xt tr li ca HS.c SGK.- Tho lun nhm tm hiu cch gii thch.- Trnh by s nhim in do c xt.- Nhn xt bn tr li.-c SGK.- Tho lun nhm tm hiu cch gii thch.- Trnh by s nhim in do tip xc.- Nhn xt bn tr li.Tr li C3-c SGK.- Tho lun nhm tm hiu cch gii thch.- Trnh by s nhim in do hng ng. - Nhn xt bn tr li.Hot ng 5 (7 pht):Tm hiu v nh lut bo ton in tch.GV: NguynMinh Hi Trang12Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 74. nh lutbotonin tch: Trong mt hc lp v in, tng i s ca cc in tch l khng i.- Yu cu HS c phn 4.- Yu cu HS tmhiu ni dungnhlut botonin tch. Nhc li khi nim v h c lp ? Hy pht biu ni dung nh lut bo ton in tch ?GV nhn xt -cSGKtmni dung nh lut. H vt c lp v in l h vt khng c trao i in tch vi cc vt khc ngoi h.- Trnh by nh lut bo ton in tch.Hs tip thu ghi nhn1. Mi trng no di y khng cha in tch t do?a. Nc bin.b. Nc sng.c. Nc ma.C. Nc ct.2. Gii thch ti sao cc xe ti ch xng, du ngi ta thng phi lp mt si xch stchm xung t ?Hot ng 5: (4 pht):Cng c, dan do :- Ni dung thuyt electron,vn dng thuyt electron gii thch mt s hin tng nhim in.- nh lut bo tonin tch.- Tr li bi tp trc nghim 1,2 sgk trang 12. - V nh hc bi v san bi: in trng v cng in trng. ng sc in.+ T/c ien trng.+ Cng o ien trng. GV: NguynMinh Hi Trang13Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 2Ngy san: 5-08-12Tit PPCT: 4Ngy dy: Bi 3: IN TRNG I-Mc Tiu:- Kin thc: Tr li c cu hi in trng l g v tnh cht c bn ca in trong l tnh cht g. Pht biu nh ngha cng in trong. Vn dng c biu thc xt nh cng in trng u mt in tch im. Trnh by c khi nim ng sc in v ngha ca dng sc in, cc tnh cht ca ong sc in. Tr li c cu hi in trng u l g v nu ln c mt s v d v in trng u l g. Pht biu c nguyn l chng cht in trng. - K nng:- Xc nh c vect cng in trng ca mt in tch im v nhiu in tch im gy ra ti mt im trong khng gian II Chun b:Gio vin: Thit b th nghim v in ph (nu c) Hc sinh: Xem li ng sc t, t ph ( hc THCS) III.T Chc Hot ng Dy-Hc:Hoat ong1(5 phut) : Kiem tra bai cu : Neu va giai thch hien tng nhiem ien do tiep xuc, do hng ngHot ng 2( 5 pht): Tm hiu khi nim v tnh cht in trng.TgNoi dung Hot ng Ca GV Hot ng Ca HS5 1.in trng:a) Khi nim in trng:- intrng l mt dngvt cht (mi trng) bao quanh in tch v gn lin vi in tch. b) Tnhcht cbncain trng:in trng tc dng lc in ln cc in tch khc t trong n.Yu cu HS c phn 1.a.t ccintchimgn nhauth chngtngtcnhau (ht hoc y) ngha l phi c mt mi trng truyn tng tc (in) gia chng. Mi trng ta gi l in trng. Vy, in trng l g?

- Yu cu HS c phn 1.bTmhiucctnhcht cain trng- Nhn xt v kt lun chung.HS c SGK

Trnh by khi nim in trng.Nu tnh cht ca in trngGV: NguynMinh Hi Trang14Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 3( 8 pht):Tm hiu khi nim cng in trng.8 2/ Cng in trng:Thng s qF c trng cho in trng im ang xt v mt tc dng lc gi l cng in trng v k hiu l E

qFE

HayE q F Nu q > 0 thE F Nu q < 0 thE F ln qFE Cng in trng E c n v l: N/C hoc V/m

Nh ni trn, xung quanh in tch im c tn ti in trng, v tc dng lc in ln cc in tch th t trong n. Nu khong cch cng xa th lc tng tc cng yu. c trng cho s mnh, yu ca in trng ta a ra khi nim CTVy cng in trng l g?GV : Hng dan HS thanh lap cong thc qF EV lc(F) l mt i lng vect, cn qlmt snnEcnglmt i lng vect.? El mt i lng vect cn c nhng yu t no?? Xc nh phng chiu ca E.? n v ca E.Y/C tr li C1HS lng nghe.

HS thanh lap cong thc qF E

im t:Phng:

E Chiu:

ln:n v: N/Choc V/m Tr li C1: Hot ng 4: (6 pht):Tm hiu v ng sc in.63 . ng sc in: a. nh ngha:ng sc in l ng c v trong in trng sao cho hngcatiptuynti bt k im no trn ng cng trng vi hngcavctcng in trng ti im . b. Cc tnh cht ca ng sc in:- Ti mi imtrong in trng c th v c mt v ch mt ng sc in. - ng sc in l nhng Yu cu HS c phn 3a- Yu cu HS trnh by nh ngha.- Nhn xt, tm tt.- Yu cu HS c phn 3.b.- T chc hot ng nhm.Vy ng sc in l nhng ng nh th no?- YucuHStrnhbykt qu hot ng nhm.- Nhn xt, tm tt.Hnhdngngscintrong c SGK- Trnh by nh ngha ng sc in.- Nhn xt cu tr li ca bn.- tho lun nhm.- Tm hiu cc tnh cht ca ng sc in.- Trnh by cc tnh cht ca ng sc in.- Nhn xt cu tr GV: NguynMinh Hi Trang15Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC ng khng kn. Xut pht t in tch dng, v kt thcm.-nhngchCTmnh ng sc dy. nhng ch CT yu ng sc tha.- Cc ng sc khng bao gi ct nhau. c. in ph: (sgk)nhng trng hp n gin. Hnh 3.3; 3.4- Yu cu HS c phn 3.c.- Cho hs xem nhng hnh nh in ph- YucuHSquanst vnhn xt.- Nhn xt, tm tt.- Nu cu hi C2.

li ca bn- c SGK.- Tm hiu khi nim in ph- Xemhnh nh in ph v rt ra nhn xt.- Nu nhn xt v in ph.- Tr li cu hi C2 Hot ng 5: (8 pht) in trng u, in trng ca mt v nhiu in tch gy ra trong khng gian.8 4. in trng u:Mt in trng m vect cng ti mi im bng nhau gi l in trng u.5.Cngintrngca mt in tch im :

2rQkqFE + E Q M - E Q: in tch gy ra in trng (C)r: l khang cch t im kho st n in tch Q (m)Yu cu HS c phn 4- Tm hiu in trng u.- Nhn xt, tm tt.- Yu cu HS c phn 5 ? T cng thc L coulomb v cng thc E=F/q hy lp cngthc tnhcngin trng ca mt in tch im? Nu cu hi C3- c SGK.- Trnh by in trng u.- c SGK.qFE m 2.rq Qk F ta c2rQk E Tr li C31. ai lng nao di ay khong lien quan en cng o ien trng cua mot ien tch iem Q tai mot iem ?a. ien tch Q.b. ien tch thq.c. Khoang cach r t Q en q.d. Hang so ien moi cua moi trng.Hot ng 6: Nguyn l chng cht in trng GV: NguynMinh Hi Trang16Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 5 6. Nguyn l chng cht in trng:nE E E E E + + + + ...3 2 1* Nu 2 in tch Q1, Q2 gy ra CT ti M. 1E E

2E

1Q2Q

2 1E E E + Yu cu HS c phn 6 tm hiu nguyn l chng cht in trng. Nu 2 in tch Q1, Q2 gy ra CT ti M. Tm CT tng cng?- Trnh by nguyn l chng cht in trng Vn dng theo quy tc hnh bnh hnh.Hot ng 5: (8 pht):Cng c, vn dng, dn d:Cng c:- in trng l mt dng vt cht (mi trng) bao quanh in tch v gn lin vi in tch. in trng tc dng lc in ln cc in tch khc t trong n.- Cng in trng ca mt in tch im:2rQkqFE q: in tch th; Q: in tch gy ra in trng.- ng sc in l ng m ttti mi im ca n l gi ca vct cng in trng ti im . - ac iem ng sc ien. in trng u.- Nguyn l chng cht in trngnE E E E E + + + + ...3 2 1V n dng: Bi 1: t in tch q = 5.10-2 C trong mi trng c = 4. Tm cng in trng ti M cch q 10 cm.Bi 2:Cho mt in tch im t ti Ac ln 6.10-7 (C) trong chn khng.a) Tnh cng in trng gy ra ti B cch A 20 cm.b) Nu ti B t mt in tch khc C ln 4.10-7 (C) th lc tng tc gia hai in tch c ln bng bao nhiu?D n d: - Xem lai cac kien thc v lm bi tp 12,13 trang 21 sgk. Tit sau giai bai tp.GV: NguynMinh Hi Trang17Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 3Ngy san: 5-08-12Tit PPCT: 5Ngy dy: Bi 4: CNG CA LC IN. HIU IN THI. MC TIU.Kin thc:- Hiu c cch xy dng khi nim v cng lc in trng trong dch chuyn in tch trong in trng u.- Vit c cng thc tnh cng lc in trng trong s di chuyn ca mt in tch trong in trng ca mt in tch im.- Nu c c im cng ca lc in.- Hiu c khi nim hiu in th.- Nu c nh ngha v xc nh c mi lin h gia in trng v hiu in th.K nng:- Gii c mt s bi tp n gin v in th v hiu in th trong SGK.II. CHUN B.1.Gio vin:- Hnh v cc ng sc in trng, hnh nh xc nh cngca lc in trn kh giy ln.- V ln giy kh ln hnh v v s khng ph thuc vo dng ca ng i ca cng lc in tc dng vo in tch dch chuyn trong in trng.2.Hc sinh:- n li kin thc v khi nim cng trong c hc, nh lut Culng v v tng hp lc.- n li cch tnh cng ca trng lc.III. T CHC CC HOT NG DY HC.Hot ng 1:(5 pht) Kim tra bi c Gii thiu bi mi - Trnh by khi nim v in trng v tnh cht c bn ca in trng.- Biu thc xc nh cng in trng -Hai in tch q1= 2.10-6 C v q2 = 7.10-7 C t cch nhau 3 cm trong du ha ( = 2,1). Tnh lc tng tc gia hai in tch.- .t vn :Tng tc tnh in c nhiu im tng ng vi tng tc hp dn. Ta s thy ngay c cng ca lc in v th nng ca in trong in trng cng c nhng im tng t nh cng ca trng lc v th nng ca mt vt trong trng trng.Cng ca trng lc c biu din qua hiu th nng. Cn cng ca lc in trng c th c biu din qua i lng no? Ta c th thng qua cch xy dng khi nim v cng trong trng trng lc xy dng khi nim ny trong trng tnh in c khng.Hot ng 2(30 pht) Tm hiu cng ca lc inTg Ni dung Hot ng ca GV Hot ng ca HS30 1. Cng ca lc in:Y/c HS nhc li cng thc tnh cng ca mt lc v ca trng lc.c im cng ca trng lc?- os A FSc .- A = mgh- Khngphthucvohnh dng ng i, ch ph thuc vo v tr im u, im cui GV: NguynMinh Hi Trang18Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC AMN = qE MN (1)Trong MN l hnhchiuca MN trn phng x ng i.Cng ca lc in tc dng ln mt intchkhngph dng ng i ca in tch m ch ph thuc vo v tr im u v im cui ca ngi trongin trng.intrng tnhl mt trng th- Gii thiu hnh v 4.1. T hnh v xc nh lc tc dng ln in tch qo,khi qodichchuyntrongin trngu, nucimcalc ny?Tnhcngcalcintrongin trng u ng vi cc trng hp sau:-intchdichuyntheong thng MN?- in tch di chuyn theo ng gp khc MNP? Ln lt cho hc sinh xc nh F, S, trong mi trng hp ri p dng cng thc.T biu thc tnh cng ca lc in trong in trng u trongtrng hp in tch di chuyn theo ng cong MN?Hon thnh C1, C2- Gio vin nu tnh tng qut ca cng thc v cho hc sinh i n kt lun tng qut v khi lng ca vt.- Lc in tc dng ln qoc hng ca in trng (t bn ccdngsangbnccm) vcln. F q E khng i.- Cng ca lc in trong trng hp nh hnh 4.1osMNA qEc A A qEM N Trong MN l hnh chiu ca MN trn phng x ng i.Tr li C1,C2 Nu nhn xt cho trng hp nyKt lun, ghi vo vHot ng 3 (10 pht) Cng c-vn dng-dn dCng c:- Hy gii thch bng hnh v i lng MN trong cng thc 1.- Hy vit cng thc tnh cng ca lc in khi mt in tch di chuyn t im M n im N trong in trng. C g ng ch trong cng thc va vit?Vn dng:Mt electron di chuyn c an ng 1 cm, dc theo ng sc in, di tc dng ca lc in trong mt in trng u c cng in trng 1000 V/m. Hi cng ca lc in c gi tr bng bao nhiu? Dn d:- V nh lm bi tp 1,2,3 sgk trang 22, 23- Chun b tip mc 2, 3 ca bi 4.GV: NguynMinh Hi Trang19Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 3Ngy san: 5-08-12Tit PPCT: 6Ngy dy: Bi 4: CNG CA LC IN. HIU IN TH (tip)Hot ng 1: Tm hiu khi nim hiu in th.Tg Ni dung Hot ng ca GV Hot ng ca HS25 2)Khi nimhiuin th.a)Cng ca lc in v hiuth nngcain tchM Nw -w A b) Hiu in th, in th( )MN M NA qV V (VM-VN) gi l hiu in thgiahai imMv N.K hiu: UMN.MNMNAUq=>A=qUHiu in th gia hai im trong in trng l i lngctrngcho kh nng thc hin cng ca in trng khi c mt in tch di chuyngia hai im .- GV yu cu HS nhc li cc cng thc xc nh cng ca trng lc. - GV phn tch c im chung ca cng(cngcatrnglcvcng ca lc in trng) +Khinimvthnngmt in tch trong in trng.+Th nng ca mt in tch q trong in trng u.+Th nng ca mt in tch q trong in trng ca mt in trng ca mt in tch im.+ Cng ca lc in v gim th nng tnh in.+Vai tr thnh phn trong cng thc tnh in th c trng cho in trngvphngdintora th nng.? Th nng ca mt vt t l vi khi lngcavt. Tngtthnng in tch th tnh nh th no?-GVthngbo: cimnyc th khi qut ha cho trng hp th nng tnh in ca in tch q- Hng dn HS i n kt lun v cng ca in trng thng qua in th.- GV thng bo hiu s (VM-VN) gi l hiu in th gia hai im M v N.- GV xy dng nh ngha ca hiu in th da vo cng ca lc in MNMNAUq- Rt rahqucsdngrt nhiu sau ny l: A=qU.? Nu nh ngha n v in th Y/c hon thnh C3Y/c hon thnh C4- HSnhcli cccng thc tnh th nng trong trng trng lc.- Nghe GV trnh by v chunb trli cuhi khi GV yu cu.- Ch racngthctnh cngcalcintrong mi trng hp l: M Nw -w A - Hs tho lun theo nhm: phn tch cc cngthcxcnhth nng ca in tch: WM=qVMv WN=qVN trong VM v VN l cc i lng khng ph thuc vo in trng - Rt ra kt lun: ( )MN M NA q V V Tr li cu C3.Tr li C4GV: NguynMinh Hi Trang20Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Thng bo cho HS cch chn mc th nngHot ng 2: (8 pht)Lin h gia cng in trng v hiu in th103) Linh giacng intrngvhiu in thMNUEM N Khi khng n du ta c th vit:UEdD l khong cch gia hai im MNHngdnxydngh thc giaEvUdavovictnh hiu in th gia hai im nm cngtrnmt ngsc ca in trng u.- ThngbochoHS: Hthc ny vn dng c cho in trng khng u..Y/c hon thnh C5-Hstipthuvcthxy dng khi nim ny di s hng dn ca GV: MNUEMN Lu: khi khngcn n du cc i lng th UEdTr li C5Hot ng 3(10 pht) Cng c, vn dng, dn dCng c:- Hy tm mi lin h gia UMN v UNM - Hy vit cng thc nh ngha hiu in th- Hy vit cng thc lin h gia cng in trng v hiu in th trong trng hp in trng u Vn dng: Cng ca lc in trng lm di chuyn mt in tch gia hai im c hiu in th U=2000 (V) l A = 1(J) . Xc nh ln ca in tch .Gii bi tp 4,5,6 sgk trang 23Dn d:V nh lm bi tp 7,8 sgk trang 23 v chun b bi 5: Xem k phng php gii bi tpGV: NguynMinh Hi Trang21Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 4Ngy son: 5-08-12 Tit PPCT: 7Ngy dy:BAI TAPI. MUC TIEU1. Kien thc : - Vec t cng o ien trng gay bi mot ien tch iem va nhieu ien tch iem.- Cac tnh chat cua ng sc ien.- Cong cua lc ien- ienthe, hieuienthe, lienhegiahieuientheva cng o ien trng.2. Ky nang : -Xacnhccngoientrnggaybi cacdientch iem.- Giai c cac bai toan tnh cong cua lc ien.- Giai c cac bai toan tnh hieu ien the, lien he gia E, U va A.II. CHU N B GV: chun b thm mt s bi tp HS:Gii bi tp nhIII. T CHC CC HOT NG DY HC.Hoat ong 1(10 phut) : Tom tat nhng kien thc lien quan en cac bai tap can giai+ Vec t cng o ien trng gay b mot ien tch iem + ac iem cua cong cua lc ien.+ Bieu thc tnh cong cua lc ien.+ Khai niem ien the, hieu ien the, lien he gia U va E.Hoat ong 2(3 phut) : Giai cac cau hoi trac nghiem.TgNoi dung c banHoat ong cua giao vienHoat ong cua HS3 Cau 1 trang 22: DCau2trang22 : D Yeu cau hs giaithch tai sao chon D.Yeucauhsgiai thchtai sao chon D.Giai thch la chon.Giai thch la chon.

Hoat ong 3 (30 phut) : Giai cac bai tap t luan.30Bi 4 trang 23:Cho bit d = 2 cm = 0,02 mq = 5.10-10CA= 2.10-9JE = ? GiiCng in trng E l:Ta c A = qEd Bi 4 trang 23:Y/cHStmtt githuyt bi tonGv gi HS ln giiGi mt HS nhn xtHs tm tt gi thuytMt HS ln bng giiHs nhn xt bi GV: NguynMinh Hi Trang22Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC => E = m VEdA/ 200 Bi 5 trang 23:Gii:Khi e bt u vo in trng th lc in tc dng ln e ng vai tr l lc cn.Lc u e c nng lng 22mvKhi ei conngs th cng ca lc cn bng eEs.Nn eEs = 22mv=> s =eEmv22= 25,6.10-4 (m)Bi 7 trang 23:Cho bitUMN=1 Vq= -1 CA = ?Gii:Khi qu cu l lng gia hai tm kim loi th lc in v trng lc cn bng: F = P Ta c F = qE = q dU v P = mg=> U = qmgd= 127,5 VBi 8 trang 23:Cho bitm = 4,5.10-3 kgl = 1 md = 4 cm = 0,04 mU = 750 V x = 1 cm = 1 mq=? g = 10 m/s2Gii:Khi qu cu cn bng, cc lc tc dng ln qu cu gm: Trng lc PLc cng dy TLc in FTa c :0 + + F T P Vi F = Ptan qdU= mg 0,01 Nhn xt kt lunBi 5 trang 23:Y/cHStmtt githuyt bi tonGv hng dn, gi HS ln giiGi mt HS nhn xtNhn xt kt lunBi 7 trang 23: Y/cHStmtt githuyt bi tonGv gi gi HS ln giiGi mt HS nhn xtNhn xt kt lunBi 8 trang 23:Y/cHStmtt githuyt bi tonGv gi HS ln giiGi mt HS nhn xtNhn xt kt lunBi 1: Hai in tch q1 = 3.10-8C v q2= - 4.10-8C c t cch lm ca bnHs tm tt gi thuytMt HS ln bng giiHs nhn xt bi lm ca bnHs tm tt gi thuytMt HS ln bng giiHs nhn xt bi lm ca bnHs tm tt gi thuytMt HS ln bng giiHs nhn xt bi lm ca bnGV: NguynMinh Hi Trang23Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC ( v q = Umgd 01 , 0 .= 2,4.10-8CQu cu lch v bn dng nnq < 0 tc l q = - 2,4.10-8CBai 1Cho bit:q1 = 3.10-8C q2 = - 4.10-8C r = 10 cm = 0,1 m Tm r1 = ? khi E = 0Gii: Goi C la iem ma tai o cng o ien trng bang 0. Goi1E va2Ela cng o ien trng do q1va q2 gay ra tai C, ta co E=1E + 2E = 0 =>1E = - 2E.Do 1E2EnnE1 = E2k21.| |ACq= k22) (| |AC ABq+ => 34122

,_

+qqACAC AB=> AC = 64,6cm.Bai 2Cho bit:AB = 5 cm = 0,05 mq1 = 16.10-8C, q2 = - 9.10-8C.Tnh E = ?Gii:nhau10cmtrongchnkhng. Hy tmcc imm ti cng in trng bng khng. Ti cc im c in trtng hay khng? Hng dan hoc sinh cac bc giai.Ve hnhHngdanhocsinh tm v tr cua C.Hai vec t nay phai cung phng, tc la iem C phai nam trenngthangAB. Hai vec t nay phai ngc chieu, tc la C phai nam ngoai oan AB. Hai vec t nay phai co moun bang nhau, tc la iemC phai gan A hn B vai |q1| < |q2|. Ngoai ra con phai ke tat ca cac iem namrat xaq1vaq2. Tai iemC va cac iem nay th cng oientrngbang khong, tclakhong co ien trng.Bi 2:Ti 2imA, Bcch nhau 5 cmtrong chn khng c hai in tch q1 = 16.10-8C v q2 = - 9.10-8C. Tnh cng in trng tng hp v v vecto cng in trng ti im C nm cch A mt khang 4 cm v cch B mt khong 3 cm. Yeu cau hoc sinh tm bieu thc e xac nh AC.Goi ten cac vectcng o ien trng thanh phan.Xac nh vectcng o ien trng tong hp tai C.Lap luan e tmv tr cua C.Tm bieu thc tnh AC.Suy ra va thay so e tnh AC.Tm cac iem khac co cng o ien trng bang 0. Goi ten cac vectcng o ien trng thanh phan.GV: NguynMinh Hi Trang24Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Goi Goi1Eva2Ela cngoientrng do q1 va q2 gay ra tai C.Taco: E1=k21.| |ACq= 9.105V/m (hng theo phng AC).E2=k21.| |BCq=9.105V/m (hng theo phng CB).Cngoientrng tong hp tai CE = 1E + 2E Eco phng chieu nh hnh ve. V tam giac ABC la tam giac vuong nen hai vec t1Eva2Evuonggoc vi nhau nen o ln cua E la:E = 2221E E + = 12,7.105V/m.Yeu cau hoc sinh suy ra va thay so tnh toan.Hngdanhocsinh tm cac iem khac.Hng dan hoc sinh cac bc giai.Ve hnhHngdanhocsinh lapluanetnho ln cua E. Tnholn cac vec t cng o ien trng thanh phanXac nh vectcng o ien trng tong hp tai C.Tnholn cua EHoat ong 4: (2 pht) Cung co, dan do.-Vectcngoientrnggaybmotientchiem qFE= 2Qkr- Nhc li nguyn tc cng vect theo quy tc hnh bnh hnh- Bieu thc tnh cong cua lc ien AMN= qEd. d :k/c t iem au --> iem cuoi nhng theo phng cua ng sc nen co the dng, co the am.- Lien he gia U va E. MNU UEd d -Xem trc bai 5: Phng php gii bi tp.GV: NguynMinh Hi Trang25Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang26Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 4Ngy son: 5-08-12Tit PPCT: 8Ngy dy:Bi 5: BI TP V LC CU-LNG V IN TRNGI. MC TIU: - H thng kin thc, phng php gii bi tp v tng tc tnh in.- Rn luyn k nng t duy v cc bi tp v nh lut Culng.- Rn luyn k nng gii cc bi tp nh tnh v p dng cc c im ca in trng.II. CHUN B GV: Phng php gii bi tp - La chn bi tp c trng.HS: Gii bi tpIII. GI V PHNG PHP GII BI TP Cc bi ton trong bi ny lin quan n nh lut bo ton in tch v nh lut Culng, vi yu cu nh: Xc nh cc i lng lin quan n lc tng tc gia hai in tch im ng yn, bng cch p dng biu thc ca nh lut Culong: 1 212.oq qF kr vi mt s lu sau:- Khi chohai qu cu ging nhau nhim in, tip xc vi nhau sau tch nhau ra th tng in tch chia u cho mi qu - Hin tng tng t nu ta ni hai qu cu vi mt dy dn mnh sau ct b dy.- Nu chm tay vo qu cu dn in tch in th qu cu b mt in tch v tr nn trung ha. Xc nh lc tng hp ln mt in tch bng cch p dng biu thc:1 2... F F F + +ur uur uur( c th cng ln lt hai vect theo quy tc cng vect hnh bnh hnh lc hoc c th dng phng php hnh chiu bng cch chn h ta vung gc xOy v chiu cc vect ln cc trc Ox v Oy c c xFv yF, vct tng hp s c ln bng: 2 2x yF F F + Trong trng hp bi ton kho st s cn bng ca in tch, ta s dng iu kin cn bng 1 2... F F F + +ur uur uur=0r sau s dng phng php xc nh ln nh trn xc nh cc iu kin ca bi ton. Vectcngoientrnggaybmot ientchiem qFE= 2Qkr- Nguyn tc cng vect theo quy tc hnh bnh hnhIV. T CHC CC HOT NG DY HCHot ng 1: (5 pht)Kim tra bi c:Cu hi:- Hy tm mi lin h gia UMN v UNM - Hy vit cng thc nh ngha hiu in th- Hy vit cng thc lin h gia cng in trng v hiu in th trong trng hp in trng Hot ng 2: Gii bi tpGV: NguynMinh Hi Trang27Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC TgNoi dung c ban Hoat ong cua giao vienHoat ong cua HS38Bi 1:Cho bit:q1= 2nC = 2.10-9 Cq2 = 0,018 C = 0,018.10-6Cr = 10 cm = 0,1 mF = 0a) V tr t qob) qo = ?Gii:a)Gi khong cch t qon q1 l x.Khong cch t qo n q2 l a.Gi F1 l lc do q1 tc dng ln qo F2 llc do q2 tc dng ln qo- Nu qo < 0:F1 = 21xq qko, F2 = 22) ( x aq qko- Nu qo > 0:F1 = 21xq qko, F2 = 22) ( x aq qko qo nm cn bng th F1 = F2 21xq qko=22) ( x aq qko q1(a - x)2 = q2x2Thay s ta c x = 2,5 cmb) Du v ln ca qo l ty .Bi 2:Cho bit:q1 = 0,5 nC = 0,5.10-9Cq2 = -0,5 nC = - 0,5 .10-9 Ca = 6 cm = 0,06 mE = ? l = 4 cm = 0,04 mGii: Gi CT do q1, q2 gy ra ti M l 2 1, E E .Do/q1/ =/q2/ vr1=r2=r nn E1 = E2= k.21rqVi r2 = l2 + ( a/2)2Ta c E=1E + 2E V E1=E2nnvectE// vi Bi 1:Y/c HS tm tt gi thuyt bi tonGv hng dan hoc sinh cac bc giai, gi HS ln giiVe hnh- Vit cng thc tnh lc trong hai trng hp qo < 0; qo > 0- Cho bit iu kin qocn bng.- Bin i cng thc suy ra x cn tm Gi mt HS nhn xtNhn xt kt lunBi 2:Y/c HS tm tt gi thuyt bi tonGv hng dan hoc sinh cac bc giai, gi HS ln giiVe hnh- Cng thc tnh cng intrngdohai intch gy ra.Hs tm tt gi thuytMt HS ln bng giiHs v hnhqonmcnbng th F1 = F2q1(a - x)2 = q2x2Hs nhn xt bi lm ca bnHs tm tt gi thuytMt HS ln bng giiHs v hnh/q1/ = /q2/ v r1= r2= r nn E1= E2= k.21rqGV: NguynMinh Hi Trang28Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC ng thng ni q1,q2 c chiu nh hnh v.E = 2E1cosVi cos =2222

,_

+alaThay s, ta c E = 2160 V/mBi 3:Cho bit:d = 10 cm = 0,1 mm = 2.10-9g = 2.10 -12 kgq = - 0,06 pCv = 25 cm/s = 0,25 m/sa) U = ?b) A = ?Gii:Trng lng ca ht bi P = mgLc in tc dng ln ht bi:F = dUqLc tng hp tc dng ln ht bi:F = F P = dUq- mgGia tc: a = mF=gmdUq Qu o ca ht bi l paraboly = 22

,_

vx a => a = 222xyv gmdUq222xyv=> U = qmd(222xyv+ g)Thay s ta c U = 50 Vb) ta c dUdUOM 210 . 6 , 3=> UOM = -32 VCng ca lc in:AOM = qUOM = 1,92.10-12(J) - Tm khong cch r- Vit cngthctnhCT tng hp.-Thay s tm kt qu. Gi mt HS nhn xtNhn xt kt lunBi 3:Y/c HS tm tt gi thuyt bi tonGv hng dan hoc sinh cac bc giai, gi HS ln gii.Ve hnh- Cho bit cc lc tc dng ln in tch- Tm lc tng hp.- p dng nh lut II Niu-tn tm gia tc ca qu o cong - Bin i thay s tm U- p dng cng thc tnh cng. Gi mt HS nhn xtNhn xt kt lun r2 = l2 + ( a/2)2E = 2E1cosHs nhn xt bi lm ca bnHs tm tt gi thuytMt HS ln bng giiHs v hnhTrng lngP = mgLc in F = dUqF = F P a = mF=gmdUq U = qmd(222xyv+ g)AOM = qUOMHs nhn xt bi lm ca bnHoat ong 4: (2 pht) Cung co, dan do.GV kt lun Phng php gii tm F, E tng hp. Son bi 6: tr li cu hi 1,2,3 trang 31 Sgk.Tun 5Ngy son: 5-08-12GV: NguynMinh Hi Trang29Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tit PPCT: 9Ngy dy:Bi 6: VT DN V IN MI TRONG IN TRNGI. MC TIU: - i vi vt dn cn bng in, trnh by c cc ni dung sau: in trng bn trong vt dn, cng in trng bb ngoi vt, s phn b in tch vt- Trnh by c s phn cc trong in mi khi in mi c t trong in trng ngoi.II. CHUN B- Tnh in k, in nghim, qu cu th, mt s vt dn c dng khc nhau.- T to dng c th nghim (nu c)III. T CHC CC HOT NG DY HCHot ng 1: (5 pht) Kim tra bi c- Nu c im ca vect cng in trng? n v o- Nu nguyn l chng cht in trng- Vit biu thc tnh cng ca lc in trng, lin h U v EHot ng 2:Vt dn trong in trngTgNoi dungHoat ong cua giao vienHoat ong cua HS151.Vt dn trong in trnga) Trng thi cn bng in : L vt dn c tch in nhng bn trong vt dn khng c dng inb) in tr ng bn trongvt dn tch in. + Bn trong vt dn cng in trng ti mi im bng khng.+ Ti mi im trn b mt vt dn cng in trng lun vung gc vi mt vt dnc) in th cat vt n tch in.+ in th ti mi im trn b mt vt dn u bng nhau+in th ti mi im bn trong vt dn u bng nhau v bng in th ca cc im bn ngoi vt dn nn n l -Giovinyucuhcsinh c SGK 1.a trang 28 yu cu hc sinhtrnhbychoc th no l trng thi cn bng in.- Nhn xt -Chohcsinhlmvictheo nhm +V sao bn trong vt dn in trng bng khng+ Trnh by cng in trngti mt imtrnmt ngoi vt dnvunggcvi mt vt- Hng dn hc sinh nm c in th ca vt dn tch in+Th nghim: inth trn mt ngoi vt dn- Nhn xt b sung.- HcsinhcSGK tr li -Nghe, nhnxt cu tr li ca bn - Hc sinh lmvic theo nhm+i dinnhmln trnh by quan im ca nhm+nhn xt, bsung cc kin.- b sung nhng thiu ca nhm- quan st th nghim, nhn xt+ in th ti mi imtrn mt ngoi vt dn c gi tr bng nhauGV: NguynMinh Hi Trang30Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Vt ng thHot ng 3: S phn b in tch vt dn tch in12 d) S phn b in tch+ mt vt dn rng th in tch ch phn b mt ngoi vt dn+ nhng ch li in tch tp trung nhiu hn, nhng ch nhn in tch tptrungnhiunht, nhngchlmhu nh khng c in tch- Gio vin gii thiu: + Cc dng c th nghim.+ Cch tin hnh th nghim.- Tin hnh th nghim cho hc sinh quan st.- Chohcsinhhot ng theo nhm.-Quanst, hngdncc nhm lm vic.- Nhn xt b sungNghe, quan st cch tin hnh th nghim- Hot ng theo nhm- i din nhm ln trnh by kin ca nhm v nu c hai ni dung:+ mt vtdnrngnhim in, th intchphnb mt ngoi ca vt.+ nhng ch l ca mt vt dn, in tch tp trung nhiu hn, nhngchmi nhn in tch tp trung nhiu nht, ch lm hu nh khng c in tch- Cc nhm nhn xt.Hot ng 4: in mi trong in trng8 2. in mi trong in trngKhi in mi trong in trng th trong in mi c s phn cc - Yucuhcsinhcsch gio khoa-Yucuhcsinhgii thch hintnginmi b phn cc-YucuhcsinhtrliC2 trong sch gio khoa- c sch gio khoa- Gi thch- Nhn xt, b sung kin ca bn- Tr li cu hi C2Hot ng 5:(5 pht) Cng c - dn dBi 1: Chn cu ng trong cc cu sauMt qu cu nhm rng c nhim in thif in tch ca qu cu A. Ch phn b mt trong ca qu cuB. Ch phn b mt ngoi ca qu cu C. Phn b mt rtong v mt ngoi ca qu cuD. Phn b mt trong nu qu cu nhim in m v phn b mt ngoi nu qu cu nhim in dngBi 2: Trong cc pht biu sau y, pht biu no ng , sai?A.Mt qu cu kim loi nhim in dng th in th tren mt qu cu ln hn in th tm ca qu cu( S)B.Mt qu cu bng ng nhim in m th cng in trng ti mt im bt k bn trong qu cu c chiu hng v tm qu cu (S)C. Cng in trng fti mt im bt k trn b mt vt dn c phng vung gc vi mt vt (S)GV: NguynMinh Hi Trang31Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC D. in tch mt ngoi ca qu cu kim loi nhim in c phn b nh nhau mi im ()- V nh chun b bi sau: Bai Tu ienGV: NguynMinh Hi Trang32Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 5Ngy son: 5-08-12Tit PPCT: 10Ngy dy:Bi 7: T INI. MC TIU:Kin thc: - M t c cu to ca t in, ch yu l cu to ca t in phng- Pht biu c nh ngha in dung ca t in. - Trnh by c th no l ghp song song. th no l ghp ni tip cc t in. Vn dng c cc cng thc xc nh in dung ca t in ghp song song, cng thc xc nh in dung ca b t ghp ni tip.K nng:- Vn dng c cng thc tnh in dung ca t in phng.- ng dng ca t in trong cuc sng, v trong k thutII.CHUN B - Chun b mt s t in c, t in xoay.- Chun b cc phiu hc tp nu cnIII. T CHC CC HOT NG DY HC 1. Bi c: - Trnh by vt dn trong in trng- S phn b in tch vt dn tch in2. Bi mi: Hot ng 1: T inTgNoi dungHoat ong cua giao vienHoat ong cua HS1. T in:a) nh ngha:T in phng l mt h hai vt dnt gnnhau. Mi vt dn gi lmt bncatin. Khong khng gian gia hai bn c th l chn khng hay b chim bi mt cht in mi no + Np in cho t+ t in phng in- Yu cu hc sinh c sch gio khoa v trnh by cho c:+ nh ngha t in.+ K hiu t in+Nmc khi nimt in phng in, tch in.+ngdngcatintrong cuc sng v trong k thut- Hc sinh c sch gio khoa- Hot ng theo nhm- i din cc nhm ln trnh by kin ca nhm mnh.- Cc nhmkhc b sung, nhn xt hoc trnh by kin ca nhm mnhHot ng2: T in phngb) T in phng+ Khi nim+ in tch ca t in + K hiu - Gio vin hng dn cho hc sinh cc khi nim+ Cu to ca t in phng+ in tch ca t phng- Nhn xt cu tr li ca hc sinh, cngcbsungkin ca hc sinh- Hc sinh c sch gio khoa , kt hp quan st t phng nu+ Cu to ca t phng.+ in tch ca t phngHot ng 3: in dung ca t inGV: NguynMinh Hi Trang33Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 3.in dung ca t ina) nh nghaThng s Q/U c trng cho t in v kh nng tch ingi l in dung ca t in, k hiu: CConstUQC n v ca in dungFa ra: ( F) VCF111 b) Cng thc in dung ca t in phngdSC4 . 10 . 99Trong : S: Din tch ca hai bn tD: Khong cch hai bn t: Hng s in mic) Hiu in th nh thng U= UMax- Yu cu hc sinh hot ng theo nhm, cc nhmcn trnh by:+ nh ngha, cng thc tnh in dung+ nh ngha n v ca in dung.+Cngthctnhindung ca t in phngTani indungca t in l 1F c ngha g?- Cc nhm lm vic.- i din cc nhm ln trinh by kin ca mnh v cc vn gio vin yu cu.Cc c s ca F th-ng dng:Micro fara; nano fara; pico faraF pFF nFF F129610 110 110 1 Hot ng 4: Ghp t ina) Ghp song song:nnnC C C CQ Q Q QU U U U+ + + + + + .........2 12 13 2 1b) Ghp ni tip:- Yu cu hc sinh chia lm cc nhm: Phnnhm1trnhby cch ghp ni tip,phn nhm 2 trnh by cch ghp song song. Trongmi cchyucu hc sinh phi trnh by c:+ Cch ghp.+ Quan h v in tch+ Quan h v hiu in th.+ Cng thc tnh in dung tng ngNhnxt gvgitr indungcabghp song song vi gi tr in dung ca cc t thnh phn- Lmvictheonhm, trnh by kin ca cc nhmtheoyucuca gio vin.- i din cc nhm trnh by quan im ca mnh trn bng.- nhn xt quan im ca cc nhmGV: NguynMinh Hi Trang34C1C2C1C2Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC nnnC C C CU U U UQ Q Q Q1...1 1 1......2 12 13 2 1+ + + + + + Nhnxt gvgitr indungcabghp song song vi gi tr in dung ca cc t thnh phnHot ng 5: Cng c, vn dng, dn d:Cng c- nh ngha t in- T in phng- in dung ca t inConstUQC - Cng thc in dung ca t in phngdSC4 . 10 . 99 Trong : S: Din tch ca hai bn td: Khong cch hai bn t: Hng s in mi- Hiu in th nh thng U= UMax- Ghp t in: + Ghp song song: U = U1 = U2 = ...Q = Q1 + Q2 + ...C = C1 + C2 + ... + Ghp ni tip:U = U1 + U2 + ...Q = Q1 = Q2 = ......C C C+ + 2 11 1 1Vn dng:Bi 1: Trn v mt t in c ghi 20F 200V. Ni hai bn ca t vi mt hiu in th 120V.a) Tnh in tch ca tb)Tnh in tch ti a m t c th t c.Bi 2: Cho in dung ca ba t ghp ni tip vi nhau l C1= 20pF, C2 = 10pF, C3 = 30 pF. Tnh in dung ca b t in .Dn d: Hc bi v lm tt c cc bi tp Chun b bi Nng lng in trng+ Nng lng t in+ Nng lng in trng GV: NguynMinh Hi Trang35Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang36Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 6Ngy son: 5-08-12 Tit PPCT: 11Ngy dy:Bi 8: NNG LNG IN TRNGI. MC TIU: - Vn dng c cng thc xc nh nng lng ca t in- Thnh lp c cng thc xc nh nng lng in trng trong t in, v pht biu c cng thc xc nh mt nng lng in trngII. CHUN B - Chun b cc phiu hc tp nu cn- Hc sinh c li mc 1 bi 4 SGKIII. T CHC CC HOT NG DY HCHot ng 1: n tp bii c: (5 pht)- Trnh by vt dn trong in trng- S phn b in tch vt dn tch inHat ng2: Nng lng ca t inTg Ni dung Hat ng ca gio vin Hot ng ca HS15 1. Nng lng ca t:a) Nhn xt:T in tch in th c nng lng.b) Cng thc tnhnng lng ca t:2QCW hay 22CUW =CQ22- Hng dn hc sinh c sch gio khoa, hot ng theo nhm * Ti sao ni t in mang nng lng* nng lng ca t xc nh nh th no?- Nhn xt- Hc sinh c sch gio khoa tr li cc cu hi ca gio vinHot ng 3: Nng lng in trng102. Nng lng in trng:Khi t in tch in, th trong t c in trng. V vy, nng lngcatinchnhlnng lng ca in trng trong t in.Nng lng in trng trong t in phng:VEW8 10 . 992- Hng dn hc sinh xy dng cng thc nng lng in trng.* Ti sao ni in trng mang nng lng* nng lng in trng xc nh nh th no?* Vit cng thc xc nh indung ca t in phng?- Hot ng theo nhm- Cc nhm ln phng n thit lp cng thc nng lng in trngTa c: U= E.dThay vo cng thc:2 292. .4 . 10 . 9.21. .21d EdSU C WGV: NguynMinh Hi Trang37Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Mt nng lng in trng:8 10 . 992E-Nhnxt,bsung v khc su kin thc cho hc sinh - Cc nhm khc nhn xtHot ng 4: Bi tp vn dng10Bi 4 trang 40:Cho bit:U=200Vd=4mm= 4.10-3mw = ?Gii:p dng cng thc:8 10 . 992EVi E = m VdU/ 10 . 5004 , 02004 - Hng dn hc sinh gii bi 2 SGK trang 40- Theo di, nhn xt, nh gi , b sung.- Hc sinh gii bi tp- Nhn xt, b sung, nhn xt bi gii ca bn- Ghi nhng iu cn thitHot ng 4: (5 pht) Cng c, dn d - Nu cu hi tm tt kin thc hc, lm cc bi tp 1,2,3,4,5,6,7,8 trang 36,37v bi tp 1,2,3,4 trang 40 sgk - Yu cu: HS v nh gii bi tit sau sa v chun b bi 9 ( phng php gii bi tp)GV: NguynMinh Hi Trang38Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 6 Ngy son: 5-08-12 Tit PPCT:12Ngy dyBi 9: BI TP V T INI. MC TIU: - Vn dng c cng thc xc nh in dung ca t in phng, cng thc xc nh nng lng ca t in.- Nhn bit c hai cch ghp t in, s dng ng cc cng thc xc nh in dung tng ng v in tch ca b t in trong mi cch ghp.- Vn dng cc cch ghp s l bi mch t hn hpII. CHUN B DNG DY HC.- Chun b h thng bi tp ph hp vi tng lp hc- Hc sinh c coi li cch ghp t in, nng lng in trngIII. T CHC CC HOT NG DY HC 1. Bi c: (5 pht)- Trnh by cng thc tnh in dung tng ng ca cch ghp song song v ni tip.- Nu cng thc tnh nng lng in trng ca t in phng2. Bi mi: Tg Ni dung Hot ng ca GV Hot ng ca HS10 Bi 1:Cho bit:E = 3.105 V/mq = 100 nC = 10-7CR = ? =1Gii:Hiuinthgiahai bntin Ed U .in dung ca t in EdqUqC pdngcngthctnhindung ca t in phng ta vit c:EdqdSC 4 . 10 . 99Mt khc 2R S , do ta c:EqR9210 . 36Thay s ta c:cm m R 11 11 , 0 10 . 1202 .Yeu cau HS tom tat cac cong thc a hoc+ Nu c cc cng thc tnh in dung tng ng trong tng cch mc.+ Mi lin h gia cc i lng trong tng cch ghp t.+ Nu cng thc tnh nng lng in trngHng dan HS cac bai 1 SGKBi tp 1Cho:'nC qm / V . E10010 35 Tm: R?- Tm hiu u bi, nhng i lng cho v cn tm.- Da vo kin thc no?- Trnh by cch gii.+ UQC , + T phng: d . kS .C4Gii: U = E.d . M C = q/U = q/Ed.Theo cng thc t phng: Edqd . kS 4M: S =R2=> Eq . kR4 => R 11cm.15 Bi 2:Cho bit:Bi tp 2+cvtmtt bi.GV: NguynMinh Hi Trang39Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC V UF C V U F C2002 , 300 , 322 2 1 a)Hai t in c ghp song song nn in dung ca b t in l 2 1 1C C C + . Gi q l din tch ca c b th:2 1C CqCqU+ V ni hai bncngtnvi nhau nn:2 2 1 1 2 1U C U C q q q + + Do :VC CU C U CU 2602 12 2 1 1++b)Trc khi ni hai bn ca hai t invi nhau, nnglngtng cng ca hai t in l:J U C U C W3 22 221 110 . 1752121 + Saukhi ni, nnglngcabt in l:J U C CCUWb3 22 1210 . 169 ) (212 + Nhit lng ta ra l:J W W Qb006 , 0 Hng dan HS cac bai 2 SGK-c SGK-Tm hiu u bi, nhng i lng cho v i lng cn tm.- Lit k cckin thc lin quan - Lp phng n gii bi ton - Gii bi tp.- Trnh by cch gii - Nhn xt + Cc t c ghp song song nn in dung ca b t l: C = C1 + C2.+intchcabt l: q = q1 + q2 = C1U1 + C2U2+ Hiu in th gia cc bn t l: 2 12 2 1 1C CU C U CCqU++ = 260V+ Nng lng tng cng ca hai t trc khi ni: + 22 221 12121U C U C W 175.10-3 j+Nnglngcabt sau khi ni:22 12) (2121U C C CU Wb+ = 169.10-3 J.+ Nhit ta ra:Q = W Wb =0,006 J.15 Bi 3:Cho bit:? , 8 )? )50 , 10 thW F C bW aV U na)Trc khi b nh thng, in dungcabtinlnCCb v nng lng ca b t in bng:nCUU C Wb2 21221 Sau khi t din b nh thng, in dungcabtinl1 nCCbv nng lng ca b t in bng:) 1 ( 2 21222 nCUU C Wb bin thin nng lng ca b t in l:Hng dan HS cac bai 3 SGK-c SGK-Tm hiu u bi, nhng i lng cho v i lng cn tm.- Lit k cckin thc lin quan - Lp phng n gii bi ton - Gii bi tp.- Trnh by cch gii - Nhn xt Bi tp 3+ c v tm tt bi.+ Nng lng ca b t trc khi c 1 t b nh thng:nCUU C Wb2 21221 +Nng lng ca b sau khi 1 t b nh thng:) 1 ( 2'21222 nCUU C Wbbinthinnngl-ng:) 1 ( 221 2 n nCUW W W = 0,001 J+ Nng lng ca b t tnglnldobt vn c ni vi ngun GV: NguynMinh Hi Trang40Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Jn nCUW W W 001 , 0) 1 ( 222 1 Nng lng ca b t in tng ln mt d c s tiu hao nng lng do mt t b nh thng.b)Trc khi t in b nh thng, in tch ca b t in l:nCUU C qb 1Sau khi t in b nh thng th:12 nCUU C qbSaukhi tinb nhthngin tch ca b t in tng ln:) 1 (1 2 n nCUq q qNng lng ca b t in tng ln l do ngun in thc hin cng a thm in tch n t in:) 1 (2 n nCUqU AGi nng lng tiu hao do s nh thnglWthth nhlut boton nng ta c th vit:thW W A + T rt ra:Jn nCUW A Wth001 , 0) 1 ( 22 nn ngun cung cpnnglngchob t.+intch trc khi b nh thng: nCUU C qb 1intchsaukhi b nh thng: 1'2 nCUU C qb+ in tch ca b t tng ln:

) 1 (1 2 n nCUq q q+ Nng lng do ngun cung cp thm: ) 1 (2 n nCUqU A+ Nng lng tiu hao: ) 1 ( 22 n nCUW A Wth= 0,001 J3. Dn d:V nh chun b bi 10: dng in khng i+ Dong ien khong oi.+ suat ien ong cua nguon+ nh lut mGV: NguynMinh Hi Trang41Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 7Ngy son: 5-08-12 Tit PPCT: 13Ngy dyCHNG II : DNG IN KHNG IBi 10: DNG IN KHNG I . NGUN INI. MC TIU:1. Kin thc:+Nhc li khi nim dng in v cc tc dng cu dng in+ Nm c kha nim cng dng in . nh lut m+ Khi nim ngun in v sut in ng ca ngun in 2. K nng:+ Gii thch c mt s hin tng v in v ngun in + Vn dng cc cng thc gii cc bi tp n ginII. CHUN B1. Gio vin:+ Mt s ngun in thng thng nh pin hay acquy2. Hc sinh:+c SGK v nghin cu tr li cc cu hi SGK III. CC HOT NG DY HC1.Kim tra kin thc c (5 pht)Cu hi:-Nhc li khi nim dng in v cc tc dng ca dng n hc THCS-Pht biu nh lut m2.Bi miHot ng 1:Dng in. Cc tc dng ca dng inTg Ni dung Hot ng ca GV Hot ng ca HS7 1. Dng in. Cc tc dng ca dng in:- Dng in l dng cc in tch dch chuyn c hng.- Tc dng c trng ca dng in l tc dng t.Yu cu hc sinh nhc li cc kin thc hc THCS- Dng in l g?- tc dng ca dng in? - Dng in l dng cc in tch dch chuyn c hng- c trng ca dng in l tc dng t, ngoi ra cn c nhiu tc dng khc nh: tc dng ho,tc dng nhit,tc dng c,tc dng sinh l Hot ng 2:Cng dng in. nh lut m10 2. Cng dng in. nh lutma) nh ngha :Cng dng in t trng cho tc dng mnh yu ca dng in, c xc nh bng thng s gia in lng q dch chuyn qua tit din thng ca vt dn trong khong thi gian t v khong thi gian :I = tqDng in c chiu v cng khngthay i theo thi gian gi Yeu cau hoc sinh nhac lai nh ngha cng o dong ien.Hon thnh C3Hon thnh C4Hon thnh C5+ Hc sinh c nh ngha SGK.Tr li cu hi C3- SGKTr li cu hi C4- SGKTr li cu hi C5- SGKGV: NguynMinh Hi Trang42Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC l dng in khng i.qItTrong : q l intch qua tit din thng ca vt dn trong khong thi gian t+ n v: ampe (A)b) nh lut m vi on mch ch cha in tr thun.+ Ni dung :SGK+ Biu thc: RUI Hay:U= VA VB= I.Rc) ng c tuyn Vn-ampeYu cu hc sinh cho bit ng c tuyn Vn- ampe ng biu din s phthuccacng dnginI chy quavt dnvohiu in th U t vo vt gi lngt trng vn - ampeHot ng 3: Ngun in10 3. Ngun in:a)Khi nim ngun in Ngun in gm hai cc l cc dng v cc m, lun nhim in tri du; gia hai cccmthiuin th c duy trLc l: Bn cht khng phi l lc in trng, n c th l lc t , lc ho hc b)S di chuyn cc intchtrongngun in: +Bnngoi ngunin in tch dng di chuyn t cc dng sang cc m theo chiu in trng, lectron di chuyn theo chiu ngc li+Bn trong ngun th di tc dng ca lc l cc in tch dng di chuyn ngcchiuintrngv cc lectron di chuyn theo chiu in trng.Tc dng ca ngun in?Ti sao lc l li c bn cht khng phi lc in trng?Ngun in l thit b to ra v duy tr hiu in th, nhm duy tr dng in trong mch.Hot ng 4: Sut in ng ca ngun in8 4. Sut in ng ca ngunSut in ng ca U Khi hai cc GV: NguynMinh Hi Trang43I(A)U(V)dF lFdFIdFlFdFITrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC ina) Khi nim: SGKb) Biu thc:qA c) n v: Vn( V)d) in tr trongngun in c lun bng hiu in th gi hai cc ca ngun khng? hHot ng 4( 5 pht) Cng c, vn dng, dn d - Nu cu hi tm tt kin thc hc - Vn dng: Tnh s e i qua tit din thng ca mt dy dn kim loi trong 1s nu c in lng 15C dch chuyn qua tit diin trong 30s.- Yu cu: HS v nh chun b bi Pin v AcquyGV: NguynMinh Hi Trang44Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 7Ngy son: 5-08-12 Tit PPCT: 14Ngy dyBi 11: PIN V ACQUYI. MC TIU:1. Kin thc: + n tp cc khi nim dng in, cng dng in, ngun in v sut in ng ca ngun in + Nm c khi nim hiu in th in ho, cu to v hot ng ca pin v acquy2. K nng: + Gii thch c mt s hin tng v in v ngun inII. CHUN B1. Gio vin: Mt s ngun in thng thng nh pin Vn ta hay acquy2. Hc sinh:c SGK v nghin cu tr li cc cu hi SGK III. HOT NG DY HCHot ng 1 : Kim tra bi c (5 pht)Pht biu khi nim dng in v cc tc dng ca dng in, cng dng in l g? Pht biu ni dung ca nh lut mHot ng 2: Hiu in th in hatgNi dung Hot ng ca gio vin Hot ng ca HS101. Hiu in th in ha+ KL: Gia thanh kim loi v dung dch in phn c mt hiu in th hon ton xc nh - Hiu in th in ho+ Hiu in th in ho ph thuc vo:- Bn cht ca kim loi- Dung dch in phn+ ng dng: Lm ngun in ho+ Th nghim: Cho mt thanh kim loi tip xc vi mt cht in phn + Hin tng: Trn mt ca thanh kim loi v dung dch in phn xut hin cc in tch tri du* Hiu in th in ho ph thuc vo yu t no?*Gii thch s xut hin ca hiu in th in ho trong trng hp Zn nhng vo ZnSO4 Hot ng 3: Tm hiu Pin Vn - ta132. Pin Vn - ta+ Cu to: Pin Vnta gm mt cc bng Zn v mt cc bng Cu. V dung dch l H2SO4.+ S to thnh sut in ng ca pin c gii thch nh trn hnh v.* Nu cu to v hot ng ca pin VNTA?* Nu mt vi loi pin th-ng gp?GV: NguynMinh Hi Trang45ZnZnSO4ZnH2SO4CuS to thnh sut in ng pin Vn taThi than chMnO2NH4 Cl + h btM ngHp kmPin L - clng xTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC + Sut in ng ca pin l:Zn: U1 = - 0,74 V Cu:U2 = 0,34 V E = U2 U1 = 1,1 V+ Pin L- clng- x.c tham kho SGKE= 1,5 VHot ng 4: Tm hiu nguyn tc hot ng ca cquy123. Acquy:a) c quy n gin l acquy ch.+ Cu toBn cc dng: PbO2Bn cc m: PbHai bn nhng trong dung dchH2SO4long.E= 2V+ c quy tch lu nng lng di dng ho nng , v c th np nhiu ln+ c quy kim: c sgk cho bit cu to v nguyn tc hot ng ca cquy chHot ng 5 (5 pht) Cng c, dn d- Nu cu hi tm tt kin thc hcCu 1: Chn pht biu ngTrong ngun in ha hc (pin-Acquy) c s chuyn haA. t ni nng thnh in nngB. t c nng thnh in nngC. t ha nng thnh in nngD. t quang nng thnh in nngCu 2: Chn pht biu ngPin l ngun in ha hc c cu to gm hai in cc nhng vo dung dch in phn. Hai in cc .A. mt cc l vt dn in, cc kia l vt cch inB. u l vt cch inC. l hai vt dn cng cht D. l hai vt dn khc cht- Chun b in nng,cng sut in GV: NguynMinh Hi Trang46Dung dch H2SO4Ac quy ch ang pht inPbO2PbTi tiu thDung dch H2SO4Ac quy ch ang np inPbO2PbNgun inTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang47Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 8Ngy san: 5-08-12Tit PPCT: 15Ngy dy: Bi 12: IN NNG V CNG SUT IN NH LUT JUN LEN-XI. MC TIU:1. Kin thc: + Nm c cc khi nim cng v cng sut ca dng in+ Nm c cc kha nim cng v cng sut ca ngun in+ Nm c cc kha nim cng v cng sut ca my thu in, sut phn in2. K nng:+ Vn dng c cng thc ca nh lut Jun-Len-x+ Vn dng c cng thc tnh sut in ng ca ngun v ca my thu in+ Bit cch o cng v cng sut dng in II. CHUN B1. Gio vin: Chun b cu hi hng dn n tp kin thc hc THCS 2. Hc sinh: c SGK v nghin cu tr li cc cu hi SGKIII. HOT NG DY HCHot ng 1 : (5pht) Kim tra bi c Trnh by khi nim v s to thnh hiu in th in ho.- Trnh by cu to v s to thnh sut in ng ca pin Vn- ta.- So snh hot ng ca pin v AcquyHo t ng 2:Cng v cng sut ca dng in chy qua mt mch intgNi dung Hot ng ca gio vin Hot ng ca HS151.Cng v cng sut ca dng in chy qua mt mch ina) Cng ca dng inUIt U q A .b) Cng sut ca dng in.UItAP c) nh lut Jun- Lenx. t I R Q . .2Y/c HS c SGKKhit mt hiuinthvo hai u mt in tr, mt dng c tiu th in nng th cc in tchdchchuynchngv to thnh dng in di tc dng ca lc no?Y/c Pht biu khi nim cng ca dng in chy qua mt on mch Y/c Pht biu khi nim cng sut Y/c Pht biu ni dung nh lut Jun- Lenx. Hon thnh C1-SGKc SGKPht biu khi nim cng ca dng in chy qua mt on mch Pht biu khi nim cng sut Pht biu ni dung nh lut Jun- Lenx. Trli cu hi C1-GV: NguynMinh Hi Trang48on mchIUTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC SGKHo t ng 3: Cng v cng sut ca ngun in152. Cng v cng sut ca ngun ina) Cng ca ngunint I q A . . . b) Cng sut ca ngun in. ItAP Vsaoninguninl mt ngun nng lng ?Cththc hincngnhth no bn trong ngun in?T cng thc ng ngha sut in ng, hy vit cng thc tnh cng ca ngun inCngsut tnh cngca ngun in l g v c tnh bng cng thc no? Pht biu khi nim cng ca ngunSGK.t I q A . . . Pht biu khi nim cng sut ca ngun Ho t ng 6:(10 pht) Cng c, vn dng, dn dCng ca dng in UIt U q A .Cng sut ca dng in:UItAP nh lut Jun- Lenxt I R Q . .2Cng ca dng in: t I q A . . . Cng sut ca ngun inItAP Vn dng:Hai bng n c cng sut nh mc ln lt l 25W v 100 W u lm vic bnh thng hiu in th 110 V. Hi:a) Cng dng in qua bng n no ln hn ?b) in tr ca bng n no ln hn? - Chun b tip phn 3,4+ Cng sut ca cc dng c tiu th in+ o cng sut tiu th in nngGV: NguynMinh Hi Trang49Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 8 Ngy san: 5-08-12Tit PPCT: 16 Ngy dyBi 12: IN NNG V CNG SUT IN NH LUT JUN LEN-X(tip)Ho t ng 1 : (5 pht) n tp kin thc cCng ca dng in UIt U q A .Cng sut ca dng in:UItAP nh lut Jun- Lenxt I R Q . .2Cng ca dng in: t I q A . . . Cng sut ca ngun inHo t ng 2 : Cng sut ca cc dng c tiu th in253. Cng sut ca cc dng c tiu th in:a) Cng sut ca dng c to nhittRUt I R t I U U q A . . . . . .22 RUI R I UtAP22. . . b) Sut phn in ca my thu.

tAP' Trong : A l phn in nng m my thu chuyn ho thnh nng lng khc (ngoi nhit nng Q= rP I2t) nh: C nng; ho nng; .c) n nng v cng sut tiu th in ca my thu.t I U t I t I r Q A AP P. . . . . '2 + + y cng l in nng tiu th.Cng sut ca my thu in:I U I I rtAPP P. . . .2 + Nhnxt vgi tr ca hiu in th gia hai cc ca ngunin vhiuinthgia hai cc ca my thu.?Trnh by khi nim sut phn in ca my thu.Lu :Sut phninca ng c in ph thuc tc quay.Hon thnh C2Hon thnh C3iu kin my thu hot ng bnh thng l hiu in th Ut vomyphi ln hn sut phn in ca my.Trnh by khi nimsut phn in ca my thu.Tr li cu hi C2Tr li cu hi C3I r UP P. + GV: NguynMinh Hi Trang50Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hiu in th gia hai cc my thu c xc nh :

I r UP P. + Hiu in th gia hai cc ngun in c xc nh : I r U . + Trong : rP : in tr trong ca my thu R: in tr trong ca ngun in d) Hiu sut ca my thu in IUrHp 1Hon thnh C4CMR:IUrHp 1Tr li cu hi C4Ho t ng 3 : o cng sut tiu th in nng54. o cng sut tiu th in nngDng Cng t inCh :KWh khng phi n v ca cng sut m l n v cng: l in nng tiu th :1KW.h= 3.600.000J Gv cho hc sinh bit nguyn tc o- Mc Ampe k ?- Mc Vn k ?Ho t ng 4 :(10 pht) Cng c, vn dng, dn dCng sut ca dng c to nhit Sut phn in ca my thu. n nng v cng sut tiu th in ca my thu.Cng sut ca my thu in:Hiu in th gia hai cc my thu c xc nh : I r UP P. + Hiu in th gia haicc ngun inc xc nh : I r U . + Hiu sut ca V n dng: Bi 1: Tnh in nng tiu th v cng sut in khi dng in c cng 1 A chy qua dy dn trong mt gi, bit hiu in th gia hai u y dn ny l 6V.B i 2: Hai bng n c hiu in th nh mc ln lt l U1 = 110V v U2 = 220V. Tm t s cc in tr ca chng nu cng sut nh mc ca hai bng n bng nhau.- V nh hc bi v lm bi tp tit sau gii bi tp- Chun b bi 13: nh lut m i vi tan mch: Noi dung, cong thc nh luat omGV: NguynMinh Hi Trang51AVTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang52Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 9 Ngy san: 5-08-12Tit PPCT: 17 Ngy dy: BI TPI. MC TIU:1. Kin thc: -H thng kin thc v phng php gii bi tp v dng in v ngun in mt chiu bng cch p dng nh lut m cho on mch.2. K nng:- Rn luyn k nng phn tch cch mc mch in gm cc in tr mch ngoi. - Rn luyn k nng gii bi tp v mch in, ngun in, cng, cng sut tiu th ca on mch.II. CHUN B1. Gio vin: - Xem, giai cac bai tap sgk va sach bai tap. - Chuan b them not so cau hoi trac nghiem va bai tap khac 2. Hc sinh:- n li nh lut m cho on mch cha in tr, cc cch mc in tr.- Lm cc bi tp trong SGK v SBT. III. HOT NG DY HCHot ng 1 : Kim tra bi c Pht biu v vit biu thc nh ngha cng, cng sut ca dng in.Pht biu v vit biu thc nh lut Jun Len-x?Hot ng 2 : Giai cac cau hoi trac nghiem.tg Ni dung Hot ng ca GV Hot ng ca HSCu 1trang 62 : CCu 2 trang 36: D- Yu cu g i thch ti sao chn cu C- Yu cu g i thch ti sao chn cu D- gii thch s la chn- gii thch s la chnHot ng 3 : Giai cac bai tap t luan tg Ni dung Hot ng ca GV Hot ng ca HSBi3a) 2 1R RUI+= 0,36A.MAUPIdmdmdm227 , 0111 ; AUPIdmdmdm91 , 0222 b) 4841211PUR; Bi tp 3/63YC: c v tm tt biHD: p dng cc cng thc tnh cng sut so snh I, R ca cc n. Lu Um1 = Um2.Bi tp 3+c v tmtt bi tp.+UPI I quan 2 ln hn.+PUR2 R ca n 1 ln hn.GV: NguynMinh Hi Trang53Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 1212222PURc) I1=I2 = AI IU36 , 02 1+I1> Id1n 1 d chy hnI2 RUP2Gi thuyt P1 = P2nn ta c:4122121,_UURRBi 5 RPIddd=0,5A 2402dddPUR.+nsngbnh thng th I = I Ta c U = (R + R) I,Suy ra R = 200 +CntnhI quaccn hoc Utrnmi nkhi mc ni tip chng vo hiu in th 220VBi tp 4/63YC: c v tm tt bi.HD: Vit cng thc tnh in tr ca cc n.+Lptsccintr .Bi 5/63YC: c v tm tt bi.HD: Tm I, R.+ Da vo iu kin n sngbnhthngxc nh RBi tp 4/63+c v tmtt bi+ T cng thc PUR2 , vi P1= P2ta c:4122121,_UURRBi 5/63YC: cvtmtt bi.Hot ng 4 : Dn d.Yu cu: HS v nh chun b bai hoc mi : nh lut Om i vi ton mchGV: NguynMinh Hi Trang54Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 9 Ngy san: 5-08-12Tit PPCT: 18 Ngy dy: Bi 13: NH LUT M I VI TON MCHI. MC TIU:1. Kin thc:+ Nm c nh lut m i vi ton mch, hin tng on mch+ p dng nh lut m chomch ngoi c cha my thu. + Nm c khi nim hiu sut ca ngun in2. K nng:+ Bit cch vn dng cc cng thc ca nh lut vo vic gii cc bi tp n ginII. CHUN B1. Gio vin: c SGK Vt l 9 v 10 bit HS hc nhng g v nh lut bo tan nng lng.2. Hc sinh:c SGK v nghin cu tr li cc cu hi SGKIII. HOT NG DY HCHot ng 1 (5 pht) Kim tra bi c Trnh by cng v cng sut ca dng in chy qua mt on mch v cng sut ca ngun in Trnh by khi nim sut phn in ca my thu.Hot ng 2 : nh lut m i vi tan mchtg Ni dung Hot ng ca GV Hot ng ca HS18 1. nh lut m i vi ton mch+ Theo nh lut bo ton nng lng ta c:A= QIt = RI2t + rI2t = IR + iR = I(R + r).r RI+Pht biu ni dung nh lut: (sgk)+Hiu in th mch ngoi(hiu in th gia hai cc ca ngun) I r R I U . . + Nu r= 0 th :U = +Hng dn thnh lp nh lut m:Xt mch in kn nh hnh v sau:- Xc nh cng ca ngun in trong thi gian t- Xc nh nhit lng to ra trn cc in tr- Vn dng nh lut bo ton nng lngA= Q+Nhn xt v gi tr ca U so vi Hon thnh C1t I q A . . . t I R t I r Q Q QR r2 2.. . + + Theo nh lut bo ton nng lng ta c: A= Qr RI+Pht biu ni dung nh lut SGK- tr 65. Nhn xt v gi tr ca U so vi I r R I U . . Tr li cu hi C1. I r R I U . . V 998 , 1 1 , 0 .1 , 0 10022 + GV: NguynMinh Hi Trang55r , ABRTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 3 :Hin tng on mchtg Ni dung Hot ng ca GV Hot ng ca HS5 2. Hin tng on mch+ Hin tng on mch: Khi mach ngoi c R= 0 lc ny cng dng in trong mch rt ln+ Khc phc: Dng cu ch hoc atmat t vn : Nu mach ngoi c R= 0 th hin tng g s xy ra? rIrt lnHot ng 4 : Trng hp mch ngoi c my thu intg Ni dung Hot ng ca GV Hot ng ca HS10 3. Tr ng hp mch in ngoi c m y thu PPr r RI+ + 4. Hiu sut ca ngun in UAAHcoich + t vn nghin cu khi mch ngoi c my thu inDng in i vo t cc no ca my thu in?- in nng tiu th trong ton mch trong trng hp ny?- Mi quanhgiaI, E, Ep, R, r, rp.+ Hng dn HS xy dng khi nimhiusut ca ngun in.YC: Tr li C2 v C3. Ln bng xy dng tng t nh phn I. Tm cng thc xc nh cng dng in ITr li cu hi C2Chng minh cng thc:IrH . 1 Tr li cu hi C3Hot ng 5: (7 pht)Cng c,vn dng,dn d-nh lut m i vi ton mch- Khi no xy ra hin tng on mch-nh lut m i vi ton mch trong trng hp mch in ngoi c my thu-Hiu sut ca ngun inVn dng: Ngun in c sut in ng l 3V v c in tr trong l 2. Mc song song hai bng n nh nhau c cng in tr l 6 vo hai cc ca ngun in ny.a) Tnh cng sut tiu th ca mi bng n.GV: NguynMinh Hi Trang56r , A BRP Pr ; Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC b)Nu tho b mt bng n th bng n cn li sng mnh hn hay yu hn so vi trc?-V hc bi v lm bi tp tit sau sa bi tp-Chun b bi 14.GV: NguynMinh Hi Trang57Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 10 Ngy san: 5-08-12Tit PPCT: 19 Ngy dy: BI TPI. MC TIU:1. Kin thc: -Cng c kin thc v nh lut m i vi ton mch, nh lut m i vi on mch cha in tr, cc cch mc in tr. 2. K nng: - Rn luyn k nng phn tch cch mc mch in gm cc in tr mch ngoi.- Rn luyn k nng gii bi tp v mch in, ngun in, nh lut m i vi ton mch.II. CHUN B1. Gio vin: - Xem, giai cac bai tap sgk va sach bai tap.- Chuan b them not so cau hoi trac nghiem va bai tap khac.2. Hc sinh:.- Giai cac cau hoi trac nghiem va bai tap a cho ve nha. III. HOT NG DY HCHot ng 1 : (5pht)Kim tra bi c Pht biu nh lut v vit biu thc nh lut m i vi ton mch.-Vit biu thc nh lut m i vi ton mch trong trng hp c my thu. Khi no th hiu in th mch ngoi bng sut in ng ca ngun?Hot ng 2 : Giai cac cau hoi trac nghiem tgNi dungHot ng ca GVHot ng ca HS10Cu 1trang 66 : BCu 2 trang 67: D- Yu cu gii thch cu 1 trang 66 ti sao chn cuB ?- Yu cu gii thch cu 2 trang 67 ti sao chn cuD ?- gii thch s la chn- gii thch s la chn+ Khi I = 0 th U = E = 4,5 V+ Khi I = 2 A, U = 4 V r = 0,25 Vy p n ng l B.Hot ng 3 : Giai cac bai tap t luanGV: NguynMinh Hi Trang58Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 4 :(5 pht) Cng c, dn d - Gv nu tm tc phng php gii bi tp- Yu cu: HS v nh chun b bai hoc mi nh lut Ohm vi cc loi mch, mc ngun thnh bGV: NguynMinh Hi Trang59tgNi dungHot ng ca GVHot ng ca HS25+ ARUI 5 , 2 + E = I(R + r) = 12,25 VBi tp 4: + 122 12 112R RR RRRN = R12 + R3 = 17Ar REI I IN3112 3+ U12 = IR12 = 4VARUI 2 , 01121 ARUI1522122 U = IRN = 5.67 VBi tp 3/67YC: c v tm tt biYC: +Xcnhcng dng in I.+Xcnhsut in ng E.Bi tp4: chomchnhhnh vBi tp 3/67cvtmtt bi+Xcnhcng dng in I.+ Xc nh sut in ng E.Bi tp 4:Cho E = 6V,r = 1 , R1 = 20, R2 = 30,R3 = 5. Tmcng dng in qua cc in tr Tnh hiu in th hai u mch ngoiR3R1R2E, rTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang60Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 10 Ngy san: 5-08-12Tit PPCT: 20 Ngy dy: Bi 14: NH LUT M I VI CC LOI MCH INI. MC TIU:1. Kin thc:+ Nm c nh lut m i vi on mch c cha ngun in + Nm c nh lut m i vi on mch c cha my thu in, cng thc ca nh lut m i vi cc loi on mch + Cch mc cc ngun in thnh b + Nm c khi nim hiu sut ca ngun in + Thit lp c cc cng thc biu th nh lut m i vi cc loi mch in2. K nng: + Bit cch nhn bit cc loi on mch nh vo du hiu ca chng + Bit cch vn dng cc cng thc ca nh lut m i vi cc loi mch in vo vic gii cc bi tp n ginII. CHUN B1. Gio vin:2. Hc sinh:c SGK v nghin cu tr li cc cu hi SGK III. HOT NG DY HCHot ng 1 : (5 pht)Kim tra bi c Vit cng thc nh lut m cho ton mch Gii thch cc i lng trong cng thc.Hot ng 2: nh lut m cho an mch cha ngun intg Ni dung Hot ng ca GV Hot ng ca HS15 1.nh lut mcho an mch cha ngun ina) Th nghim kho stb) Nhn xtTa thu c biu thc:UAB = a -b.ITrong a= : sut in ng ca ngun b= r: in tr trong ca ngun inc) Kt lun rUrUIAB BA+ d) Ch : + Dng in chy t cc m sang cc dng ca ngun. VA > VB.+Nu c thm R r RUr RUIAB BA+++ S mch in Kim tra mch in m hc sinh mc v hng dn hc sinh tin hnh th nghim. Trng hp trong mch cn c thm in tr thun R Mc mch theo hng dn ca thy. Dng Vn k o hiu in th gia hai u mch in AB; Dng Ampe k o cng dng in trong mch v tm mi lin h gia :I U; ; lp bng theo mu sau1,51,51,5U(V)I(A) Tr li cu hi C1-tr 68GV: NguynMinh Hi Trang61r , A BRR0Rr ; Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Hot ng 3 : nh lut m cho an mch cha my thu tg Ni dungHot ng ca GV Hot ng ca HS15 2 . nh lut mcho anmch cha my thua) Nhn xt+ Cng ca dng in sinh ra trn mch l :A= U.I. t+ in nng tiu th l:A= PIt + rP . I2tTa thu c biu thc: UAB = P+ rP .ITrong a= P: sut phn in ca my thu,b= r: in tr trong ca my thuc) Kt lun PP ABrUI +Nu c thm R PP ABr RUI+ S mch in Trng hp trong mch cn c thm in tr thun R Xc nh in nng tiu th trn my thu Tnh cng ca dng in sinh ra trtn my thu. Tr li cu hi C2 - tr 69Hot ng 4: (10pht)Cng c, vn dng, dn dnh lut m cho an mch cha ngun inrUrUIAB BA+ nh lut m cho an mch cha my thuPP ABrUI Vn dng: Cu 1: Chn phng n ng Mt ngun in vi sut in ng , in tr trong r, mc vi mt in tr ngoi R = r; cng dng in trong mch l I. Nu thay ngun in bng ba ngun in ging ht n mc song song th cng dng in trong mch A. vn bng IB. bng 1,5 I C. bng I/3 D. gimi mt phn tCu 2: Chn phng n ngMt ngun in vi sut in ng , in tr trong r, mc vi mt in tr ngoi R = r; cng dng in trong mch l I. Nu thay ngun in bng ba ngun in ging ht n mc ni tip th cng dng in trong mch A.bng 3IB. bng 1,5 I C. bng 2I D. 2,5I- V nh hc bi v chun b tip phn 3,4 ca bi nh lut Ohm vi cc loi mch, mc ngun thnh bGV: NguynMinh Hi Trang62RP Pr ; P Pr ; Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 11 Ngy san: 5-08-12Tit PPCT: 21 Ngy dy: Bi 14: NH LUT M I VI CC LOI MCH IN(tip)Hot ng 1: (5pht) Kim tra kin thc cVit biu thc ca nh lut m cho an mch cha ngun inVit biu thc ca nh lut m cho an mch cha my thuHot ng 2. (15pht)Cng thc tng qut ca nh lut m i vi cc loi mch intgNi dungHot ng ca GVHot ng ca HS10 3.Cng th c tng qut canhlut mi vi ccloi mch in+ Nu cha bit chiu ca dng in trongmch th ta gi s dng in chy theo mot chiu no v tm gi tr ca cng dng in sau so snh du ca cng dng va tm c vi cc quy c bit+Ta c cng thc tng qut sau yr RUIAB++> 0 nu dng in I chy qua pin t cc m n cc dng< 0 Nu dng in chy qua pin t cc dng sang cc m.Nu ta cha bit chiu ca dng in trong mch th lm th no c th nhn bit mch in cha thnh phn noHot ng 3. Mc cc ngun in thnh btg Ni dung Hot ng ca GV Hot ng ca HS20 4. Mc cc ngun in thnh ba) Mc ni tipn bn br r r r + + + + + + ......2 12 1 GV: NguynMinh Hi Trang63RP Pr ; Rr ; on mch cha ngunon mch cha my thuMc xung iMc ni tipTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC + Trng hp cc ngun u ging nhau. r n r nb b. ; . b) Mc xung i 2 1 2 1; r r rb b+ c) Mc song song: Cc ngun ging nhau bnrrb d) Mc hn hp i xng song song: Cc ngun ging nhauGm n ngun ging nhau mc ni tipM hng nh vy mc song songmr nrnbb.. Hot ng 4 :(10 pht) Cng c, vn dng, dn dNu cu hi tm tt kin thc hc:- Vit cng thc nh lut m cho ton mch v gii thch cc i lng trong cng thc.- Cch mc cc ngun in thnh b v cng thc ca chng- Cng v cng sut ca on mch; ca ngun in v my thu.Vn dng: Cho mch in c s nh hnh v trong : 1= 8V, r1 = 1,2 ;2= 4V, r2 = 0,4; R = 28,4 ; hiu in th gia hai u on mch o c l 6V.a) Tnh cng dng in chy qua on mchv cho bit chiu ca n b) Cho bit mch in ny cha ngun in no v cha my thu no?V sao?c) Tnh hiu in th UAC, UCB - Yu cu: HS v nh chun b bai hoc mi bi tp v nh lut m v cng sut inGV: NguynMinh Hi Trang64Mc hn hp i xng song songMc song songTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang65Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 11 Ngy san: 5-08-12Tit PPCT: 22 Ngy dy: bi tp I. MC TIU:1. Kin thc:- H thng kin thc v phng php gii bi tp v nh lut m i vi ton mch, nh lut m cho cc loi on mch. - Xc nh sut in ng v in tr trong ca cc b ngun ghp ni tip, song song, xung i, hn hp i xng. 2. K nng: - Rn luyn k nng phn tch cc mch in, k nng gii bi tp v nh lut m v ghp ngun in.II. CHUN B1. Gio vin:- Phng php gii bi tp.La chn bi tp c trng 2. Hc sinh:- Hc l thuyt v lm cc bi tp III. HOT NG DY HCHot ng 1 : (5pht) Kim tra bi c Cau hoi:-Vit cng thc tng qut ca nh lut m i vi cc loi on mch, nu r quy c v du ca E.-Nu cch mc, sut in ng, in tr trong ca cc b ngun mc ni tip, mc song song, mc xung i?Hot ng 2 : Giai cac cau hoi trac nghiemtg Ni dung Hot ng ca GV Hot ng ca HS4 Cu 1trang 72 : BCu 2 trang 73: C- Yu cu gii thch cu 1 trang 72 ti sao chn cuB ?- Yu cu gii thch cu 2 trang 73 ti sao chn cuC ?- gii thch s la chn- gii thch s la chnHot ng 3 : Giai cac bai tap t luan tg Ni dung Hot ng ca GV Hot ng ca HS31 Bi tp 1:Cho mch in nh hnh v.E1= 55V, E2= 10V, E3 = 30V, E4 = 15Vr1 = 0,3 , r2 = 0,4 , r3 = 0,1 , r4 = 0,2 , R1= 9,5 , R2 = 19,6 , R3=4,9.TnhI1?I2? I3?Gi s chiu dng in nh hnh v.Bi 3/73.+ Gi s mt chiu dng in+ Vit nh lut m i vi on mch AB tm I. Nu I>0 th chiugisng, nu I0). Khng phi ngun v khng phi my thu( I2= 0), v l my thu( I2 dong ien qua bnh ien phan tuan theo nh luat om oi vi may thu--Tin hnh th nghim,yu cu HS nhn xt v hin tng xy ra- Quan st th nghim v trnh by v hin tng cc dng tan Cl- Na+ e- A Hien tng cc dng tan K SO42- Cu2+E SO42- Cu2+Cu e- e-e- Dung dch CuSO4 Hot ng 3: Tm hiu nh lut fa ra y v in phntg Ni dung Hot ng ca GV Hot ng ca HS105.nh lut Fa-ra-y v in phn.a. nh lut 1 Fa-ra-y- Ni dung:SGK- Biu thc: m = kq (g)Vi k:ng lng ho hc(kg/C)-Yu cu HS c SGK phn 5? Trnh by ni dung nh lut,vit biu thc v ni r cc i lng trong biu thc.- Cc nhmc SGK phn 5a,b tho lun v trnh by ni dung theo yu cu ca GV.- Nhn xt cu GV: NguynMinh Hi Trang84Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC b. nh lut 2 Fa-ra-y- Ni dung: SGK- Biu thc: k = c.A/ nVi: 1/c = F = 96500C/mol:hng s Fa ra y.c.Cng thc Fa-ra-y v in phn1.Am qF n hay 1.Am ItF nVi: I:cng dng in khng i chy qua bnh(A)t: thi giandngin chy (s)m: khilng ca cht c gii phng (g)- Nhn xt trnh by ca HS v kt lun.- Yu cu HS c phn 5c tho lun v trnh by nh lut di dng 2? Trnh by biu thc nh lut di c 2 dng,ni r cc i lng trong biu thc.- Nhn xt trnh by ca HS v kt lun v ni dung chnh.tr li ca bn v b sung.- c SGK phn 5c,tho lun v trnh by theo yu cu ca GV.- Nhn xt cu tr li ca bn v b sung.Hot ng 4 : Tm hiu v ng dng ca hin tng in phntg Ni dung Hot ng ca GV Hot ng ca HS-5- 6. ng dng ca hin tng in phn-- a. iu ch ho cht:- b. Luyn kim:- c. M in:- Yu cu HS tm hiu ngdngcahint-ng in phn v trnhbyvnguyn tc hot ng v ph-ng php tin hnh.- Nhn xt cu tr li ca HS v kt lun.- Tm hiu,tho lun v trnh by ni dung theo yu cu ca GV.+ c SGK.+Nu c cc ng dng ca hin tng in phn: iu chhacht, luyn kim, m in, c in.Hot ng 5 (10pht): Cng c, vn dng, dn d- Nu cu hi tm tt kin thc hc.- Vn dng gii bi tp 3 trang 100 sgk- Ve nha lam cac bai tap 1,2trang 100 SGK Chun b bai: Bi tp v dng in trong kim loi v cht in phnGV: NguynMinh Hi Trang85Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC + n li cc cng thc hc + Phng php gii bi tpGV: NguynMinh Hi Trang86Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 16 Ngy san: 5-08-12Tit PPCT: 31 Ngy dyBi 20:bi tp vdng in trong kim loi v cht in phn.I. MC TIU:1. Kin thc: - Vn dng h thc[ ]0 01 ( )tt t + gii cc bi tp v s ph thuc ca in tr vo nhit .- Vn dng nh lut Fa ra y giicc bitp v hin tng in phn.2. K nng:- Vn dng gii thch cc hin tng v gii cc bi tp v dng in trong kim loi v trong cht in phn.II. CHUN B1. Gio vin: - Mt s bi tp v dng in trong kim loi v trong cht in phn2. Hc sinh: -n tp dng in trong kim loi v trong cht in phnIII. HOT NG DY HCHot ng 1 (5pht) Kim tra bi c Cau hoi:- Vit biu thc v nu ni dung ca nh lut Fa ra y- Cho dng in chy qua bnh ng dd mui Niken c A bng Niken.Trong thi gian 1h,dng in 10A sn ra 1 khi lng Niken l bao nhiu?Hot ng 2 (5pht) Nhc li cc cng thc lin quan1) S ph thuc ca in tr vo nhit Rt=R0(1+ (t-t0) )Trong : R0 : in tr ca vt dn t00C Rt :in tr ca vt dn t0C : H s nhit in tr.2) Cng thc Fa-ra-y v in phn:1.Am ItF nHot ng 3 : Gii cc bi tp sgktg Ni dung Hot ng ca GV Hot ng ca HS30Bi 1: SGKCho bit: ' 1 322 110110 2 4 8240 208 25K . , ; A IV U ; mV UmA I ; C tTm: t2?Bi tp 1:YC: c, tm tt v phn tch bic v tm tt biCho bit: ' 1 322 110110 2 4 8240 208 25K . , ; A IV U ; mV UmA I ; C tTGV: NguynMinh Hi Trang87Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Giiin tr ca dy tc bng n: 5 , 2111IUR 30222IURT cng thc: R2 = R1[1+ (t2-t1)] suy ra:112211tRRt +,_ =26440CBi tp 2:Cho bit:' 1 ; 108 ; 210 ; 2n A h tV U R Xc nh mBc ?Gii:Cng dng in qua bnh in phn. I =210RU= 5Am = nAF.1.It = 1108.965001.5.7200 = 40,3 gGi HS ln bng giiGv hng dnp dng nh lut m tm c in tr ca dy tc bng nnhit t1vkhi sng bnh thng. p dng cng thc s ph thuc ca in tr vo nhit tm t2.Bi tp 2:YC: c, tm tt v phn tch bi.Gv hng dn:xcnhclngbc gii phngccmth cn xcnhcngdngin qua bnh in phn.p dng nh lut Faraday xc nh m.m: t2?Hs ln bng gii 5 , 2111IUR 30222IURR2 = R1[1+ (t2-t1)] =>112211tRRt +,_ =26440C- c v tm tt bi.' 1 ; 108 ; 210 ; 2n A h tV U R Xc nh mBc ?Tnhccngdng in qua bnh in phn. I =210RU= 5Am = nAF.1.It = 1108.965001.5.7200 = 40,3 gHot ng 4 (5 pht) Cng c, dn d.- Nu phng php gii bi tp,- Chun b bi dng in trong chn khngGV: NguynMinh Hi Trang88Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 16: Ngy son: 5-08-12Tit PPCT: 32 Ngy dy: BAI TAPI. MUC TIEU1. Kien thc : + S ph thuc ca in tr vo nhit +Ban chat dong ientrong chatien phan,hien tng dng cc tan, cac nh luat Fa-ra-ay va cac ng dung cua hien tng ien phan.2. Ky nang : + Thc hien c cac cau hoi lien quan en dong ien trong kim loai va dong ien trong chat ien phan.+ Giai c cac bai toan lien quan en dong ien trong kim loai.+ Giai c cac bai toan lien quan en nh luat Fa-ra-ay.II. CHUAN BGiao vien:+ Xem, giai cac bai tap sgk va sach bai tap.+ Chuanb them not so cau hoi tracnghiemva bai tap khac. III. TIEN TRNH DAY HOCHoat ong 1(5 phut): Tom tat nhng kien thc lien quan en cac bai tap can giaiH thc[ ]0 01 ( )tt t + gii cc bi tp v s ph thuc ca in tr vo nhit S ph thuc ca in tr vo nhit Rt=R0(1+ (t-t0) )Trong : R0 : in tr ca vt dn t00C Rt :in tr ca vt dn t0C : H s nhit in trnh luat Fa-ra-ay th nhat Khoi lng vat chat c giai phong ien cc cua bnh ien phan t le thuan vi ien lng chay qua bnh o.m = kq k goi la ng lng hoa hoc cua chat c giai phong ien cc.* nh luat Fa-ra-ay th hai ng lng ien hoa k cua mot nguyen to t le vi ng lng gam nA cua nguyen to o. He so t le F1, trong o F goi la so Fa-ra-ay.k =nAF.1m = nAF.1It Hoat ong 2 (38 phut) : Giai cac bai tap t luan.tgNoi dung c ban Hoat ong cua giao vienHoat ong cua HsGV: NguynMinh Hi Trang89Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 1215Bai1:ientrcua den khi thap sangR = 1002202 2PU = 484()ientrcuaen khi khong thap sangTa co : R = R0(1 + (t t0))= R0 = ) ( 10t tR + = ) 20 2000 ( 10 . 5 , 4 14843 += 49()Bai 2a) Thetchcua1mol ongV = 3310 . 9 , 810 . 64DA = 7,2.10-6(m3/mol)Mat o electron t do trong ongn = 62310 . 2 , 710 . 023 , 6VNA= 8,4.1028(m-3)b) So electron t do qua tiet dienthangcua day dan trong 1 giay: N = vSnCng o dong ien qua day dan: I = eN = evSn =>v= 28 5 1910 . 4 , 8 . 10 . 10 . 6 , 110 eSnI= 7,46.10-5(m/s) Bi 1: Mt bng n 220V-100W khi sng bnh thng th nhit cadytcnl2000oC. Xc nh in tr ca n khi thp sng v khi khng thp sng, bit rng nhit mi trng l 20oC v dy tc bng n lmbng vofam Yeu cau hoc sinh tnh ien tr cua bong en khi thap sang. Yeu cau hoc sinh tnh ien tr cua bong en khi khong thap sang.Bai 2:Khi lng mol nguyn t c ng l 64.10-3kg/mol. Khi lng ring ca ng l8,9.103kg/ m3. Bit rng mi nguyn t ng ng gp mt electron dn.a) Tnh mt electron t do trong ng.b) Mt dy ti in bng ng tit din 10mm2, mang dng in 10A. Tnh tc tri ca electron dn trong dy dn . Yeu cau hoc sinh tnh the tch cua 1mol ong. Yeu cau hoc sinh tnh mat o electron trong ong. Yeu cau hoc sinh tnh so electron qua tiet dien thang cua day dan trong 1 giay va viet cong thc tnh cng o dong ien theo no. Cho hoc sinh suy ra va tnh v. Bi 3: Ngi ta mun bc mt lp Tnhientr cuabongen khi thap sang.Tnhientr cuabongen khikhong thap sang.Tnh the tch cua 1 mol ong.Tnhmat o electron trong ong.Tnh so electron qua tiet dien thang cua day dan trong 1 giay va viet cong thc tnh cng o dong ien theo no.Tnhvantoc troi cua electron.GV: NguynMinh Hi Trang90Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 11 Bai 3:Khoi lng ong muon boc im = V = dS = 8,9.103.10-5.10-4 = 8,9.10-6(kg) = 8,9.10-3(g)mam = nAF.1.It =t = 2310 . 642 . 96500 . 10 . 9 , 8.. .I An F m = 2680(s)ng dy 10m trn mt bn ng din tch 1 cm2 bng phng php in phn. Cng dng in l 0,010 A. Tnh thi gian cn thit bc c lp ng . Yeu cau hoc sinh tnh khoi lngongmuon boc i. Yeu cau hoc sinh viet cong thc Fa-ra-ay. Cho hoc sinh suy ra va tnh t.Tnh khoi lng ong muon boc i.Viet cong thc Fa-ra-ay.Tnhthi gian ien phan.Hoat ong 4: (2pht) Cung c, van dung.H thc[ ]0 01 ( )tt t + ;Rt=R0(1+ (t-t0) -Cong thc tnh khoi lng (van dung nh luat Faraday) m = nAF.1It .Trong o F: so Faraday, n hoa tr, A khoi lng gam.- Hoacm = kq k goi la ng lng hoa hoc cua chat c giai phong ien cc.- Chun b bi dng in trong chn khngGV: NguynMinh Hi Trang91Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang92Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 17 Ngy san: 5-08-12Tit PPCT: 33 Ngy dyBi 21: dng in trong chn khngI. MC TIU:1. Kin thc:-Hiubnchtvtnhchtdngintrongchnkhng.Hiung c tuyn vn-ampe ca dng in trong chn khng - Hiu v ng dng ca dng in trong chn khng .2. K nng: -Gii thch bn cht dng in trong chn khng.- Gii thch ng dng ca dng in trong chn khng - Tia KattII. CHUN B1. Gio vin: - Th nghim v dng in trong chn khng,th nghim tia Katt,ng phng in t.- Tranh v phng to cc hnh trong SGK 2. Hc sinh: -n tp v khi nim chn khng hcIII. HOT NG DY HCHot ng 1: (5 pht) Kim tra bi c Cau hoi:- V sao kim loi li dn in tt hn cht in phn.Hot ng 2: Tm hiu v dng in trong chn khngtg Ni dung Hot ng ca GV Hot ng ca HS231.Dng in trong chn khnga.Th nghim: b.Bncht dngin trong chn khng:- Bn cht:(SGK)- c im:i theo 1 - Tin hnh th nghim,yu cu HS quan st.- Yu cu HS nhn xt v hin tng xy ra khi K2 ng,K1 m.Khi K1 ng,K2 m.Khi K1,K2 u ng.Khi m K1,ni A vi cc m,K vi cc dng ca ngun sau ng K1.? Gii thch v sao li xy ra cc tng trn.- Quan st th nghim v nhn xthintngxy ra theo yu cu ca GV.-Tholunnhm vgii thchcc hin tng xy ra.GV: NguynMinh Hi Trang93 iot ien tK A G 1 S oth nghiemdong ien trongchan khong2 k1k2K A Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC chiu t A n K.- ng dng:dng chnh lu dng in xoay chiu. ? Nu bn cht ca dng in trong chn khng.? Dng in chy trong chn khng c chiu nh th no.- Yu cu HS tr li C1,C2.- Nhn xt v cht li kin thc.- Nhn xt cu tr li ca bn.- Nu bn cht dng trong chn khng v tnh cht ca n.- Tr li C1,C2. Hot ng3:Tmhiusphthuccacngdngintrong chn khng vo hiu in th tg Ni dung Hot ng ca GV Hot ng ca HS-12- 2.S ph thuc ca cng dng in trong chn khng vo hiu in th.-- - Dng in trong chn khng khng tun theo nh lut m- - Khi: U Ub - Khi tng nhit K ln th I nh th no?- Yu cu HS tr li cu hi C3,C4- Nhnxt cutrli ca HS v kt lun.- Quanst ng c tuyn v nhnxtvmi quan h gia I v U theo yu cu ca GV.- Trli cuhi C3.C4. U O Ub I IbhT > TT Hot ng 4: (5pht) Cng c, dn d- Nu cu hi tm tt kin thc:Hy nu cch to ra dng in trong chn khng, bn cht dng in trong chn khng, v c im v chiu ca dng in ny. - Chun b phn cn li:Tia catt l g? Hy nu nguyn tc cu to v hot ng ca ng phng in t.GV: NguynMinh Hi Trang94Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang95Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 17 Ngy san: 5-08-12Tit PPCT: 34 Ngy dyBi 21: dng in trong chn khng (tip)I. MC TIU:1. Kin thc:-Hiubnchtvtnhchtdngintrongchnkhng.Hiung c tuyn vn-ampe ca dng in trong chn khng - Hiu v ng dng ca dng in trong chn khng .2. K nng: -Gii thch bn cht dng in trong chn khng.- Gii thch ng dng ca dng in trong chn khng - Tia KattII. CHUN B1. Gio vin: - Th nghim v dng in trong chn khng,th nghim tia Katt,ng phng in t.- Tranh v phng to cc hnh trong SGK 2. Hc sinh: -n tp v khi nim chn khng hcIII. HOT NG DY HCHot ng 1 : (5 pht) Kim tra bi c Cau hoi: Hy nu cch to ra dng in trong chn khng, bn cht dng in trong chn khng, v c im v chiu ca dng in nyHot ng 2 : Tm hiu v tia Katt v ng phng in t tg Kin thc c bn Hot ng ca GV Hot ng ca HS223. Tia Katt.- Khi nim: Dng electron do Katt pht ra v bay trong chn khng- iu kin xut hin: khi P trong khong 0,01- 0,001mmHgGii thieu th nghiem hnh - Gii thiu v tia Katt v s xut hin ca tia Katt.Neu cac ket qua th nghiem.? V sao tia Katt li b lch trong t trng v in trng.Xem hnh minh hoa th nghiem Ghi nhan cac ket qua th nghiem..HSneucac tnh chat cua tia catot.GV: NguynMinh Hi Trang96Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC 8- Tnh cht: + Tia K truyn thng + Pht ra vung gc vi mt K + Mang nng lng + C th m xuyn qua hu ht kim loi mng (c b dy t 0,003 - 0,03mm) tr Pb. + C tc dng ln knh nh + C kh nng ion ho khng kh + Lm pht quang 1 s cht kh. + B lch trong in trng v t trng. + Khi b hm bi kim loi c nng lng ln: Pht ra tia X4. ng phng in t: sgk- Yu cu HS tm hiu v ng phng in t v ng dng ca n.Gii thieu ng dung cua tia catot.Neu ban chat cua tia catot.Ghi nhan ng dung cua tia catot.- c SGK tm hiu v ng phng in t v nhng ng dng ca n.Hot ng 4 (10pht) Cng c, dn d- Nu cu hi tm tt kin thc:Hy nu cch to ra dng in trong chn khng, bn cht dng in trong chn khng, v c im v chiu ca dng in ny. Tia catt l g? Hy nu nguyn tc cu to v hot ng ca ng phng in t.- Vn dng gii bi tp 2 sgk trang - Ve nha lam cac bai tap 1trang 105 SGK - Chun b baidng in trong cht kh.+ Ban chat dong ien trong chat kh.+ Qua trnh dan ien t lc, khong t lc. Tia la ien, ho quang ienGV: NguynMinh Hi Trang97Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC GV: NguynMinh Hi Trang98Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 18 Ngy san: 5-08-12Tit PPCT: 35 Ngy dyBi 22:dng in trong cht kh (tit 1)I. MC TIU:1. Kin thc: -Hiu bn cht dng in trong cht kh v m t s ph thuc ca dng in vo hiu in th. -Hiungctuyn vn-ampe,s binthincacngdng in theo hiu in th,s va chm trong cht kh.2. K nng:- Gii thch bn cht dng in trong cht kh- Gii thch bn cht ca s phng in trong cht kh iu kin thngII. CHUN B1. Gio vin: - Th nghim v dng in trong cht kh - Tranh v phng to cc hnh trong SGK 2. Hc sinh: -n tp v chuyn ng ca cc phn t kh hc. III. HOT NG DY HCHot ng 1 (5pht) Kim tra bi c cau hoi:- Nu bn cht ca dng in trong chn khng v c im ca n.Hot ng 2:Tm hiu v s phng in trong cht kh v bn cht dng in trong cht khtg Ni dung Hot ng ca GV Hot ng ca HS201.S phng in trong cht kha.Th nghim:b. Kt lun-Khi cha t nng khng kh:V ch s 0 =>Khng kh l in mi- Khi t nngkhng kh:V ch khc 0 =>c dng in chy qua khng kh.2. Bn cht dng in trong cht kh- Hin tng ion ho cht kh:- Bn cht dng in: (SGK)- L u : S dn in ny l s dn in khng t lc.- Tin hnh th nghim v yu cu HS quan st- Nhn xt trnh by ca HS v kt lun.- Yu cu HS c SGK,tm hiu v dng in trong cht kh.? Trnh by hin tng ion ho chtkh v kt qu ca hin tng i vi cht kh.? Nu tc dng ca tc nhn ion ho khng thay i th mt ht ti in trong cht kh ntn.? Nu iu kin c dng in trong 1 mi tr-ng.? Trnh by bn cht ca dng in trong cht kh.- Nhn xt trnh by ca - Quan st th nghim v nu nhn xt v hin t-ng xy ra. B Thnghiem ves phong ien trong khongkhA V GV: NguynMinh Hi Trang99Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC HS v nu kt lun.Hot ng 3 : Tm hiu s ph thuc ca cng dng in trong cht kh vo hiu in th tg Ni dung Hot ng ca GV Hot ng ca HS-15-3.S ph thuc ca cng dng introngchtkh vo hiu in th.-- Dng in trong cht kh khng tun theo nh lut ohm- - Khi 0 U UC: Sphnginkhng t lc.- - Khi UUb: Dngdint gi tr bo ho- - Khi U>UC:S phng in t lc- - Trong qu trnh phngintrongcht kh cn kmtheo s pht sng.- Gii thiu ng c tuyn vn-ampe cho HS.? Quan st ng c tuyn v nu nhn xt tng qut v n.?Nhnxt vng c tuyn cc thi im: - U=0 n U= UC- Ub U < UC- U > UC- Yu cu HS tr li cu hi C1,C2- Nhn xt cu tr li ca HS v kt lun.- Quanst ngc tuynvnhnxt v mi quanhgiaI v U theo yu cu ca GV. O UC Ibh UbU (V) I(A) ac tuyen Von Ampecua chat kh- Tr li cu hi C1,C2.Hot ng 4 (5 pht ) cng c, dn d- Nu cu hi tm tt kin thc:Bn cht dng in trong cht khS ph thuc ca cng dng in trong cht kh vo hiu in th.- Yu cu: HS v nh chun bl thuyt phn cn li GV: NguynMinh Hi Trang10021F21F12Fq1.q2 >0r21F12Frq1.q2 < 0Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 18 Ngy san: 5-08-12Tit PPCT: 36 Ngy dyN TP(TM TT CNG THC V L THUYT) I. MC TIU:1. Kin thc: Chng 12. K nng:II. CHUN B1. Gio vin: -Cc cu hi 2. Hc sinh: -n tp III. HOT NG DY HCHot ng 1 (5pht) Kim tra bi c cau hoi: theo tng bi c thCHNG I.IN TCH IN TRNGI. Cach nhiem ien. C 3 cch nhim in mt vt: C xt, tip xc ,hng ngII. nh lut Cu lng: Lc tng tc gia 2 in tch im q1; q2 t cch nhau mt khong r trong mi trng c hng s in mi l 12 21; F Fr r c:- im t: trn 2 in tch.- Phng: ng ni 2 in tch.- Chiu:+ Hng ra xa nhau nuq1.q2 > 0(q1; q2 cng du)+ Hng vo nhau nuq1.q2 < 0(q1; q2 tri du)- ln:22 1.rq qk F ; k = 9.10922. N mC _ ,(ghi ch: F l lc tnh in) - Biu din:3. Vt dn in, in mi: + Vt (cht) c nhiu in tch t do dn in+ Vt (cht) c cha t in tch t do cch in. (in mi)4. nh lut bo ton in tch: Trong 1 h c lp v in (h khng trao i in tch vi cc h khc) th tng i s cc in tch trong h l 1 hng sIII. in trng+ Khi nim: L mi trng tn ti xung quanh in tch v tc dng lc ln in tch khc t trong n. + Cng in trng: L i lng c trng cho in trng v kh nng tc dng lc.E q FqFE . n v: E(V/m)q > 0 : F cng phng, cng chiu vi E.q < 0 : F cng phng, ngc chiu viE.+ ng sc in trng: L ng c v trong in trng sao cho hng ca tip tyn ti bt k im no trn ng cng trng vi hng ca vc t CT ti im .GV: NguynMinh Hi Trang101rrTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tnh cht ca ng sc: -Quami imtrong.trngtach cthvc1vch 1 ng sc in trng.- Cc ng sc in l cc ng cong khng kn,n xut pht t cc in tch dng,tn cng cc in tch m. - Cc ng sc in khng bao gi ct nhau. - Ni no c CT ln hn th cc ng sc v mau v ngc li+ in trng u: - C vc t CT ti mi im u bng nhau. - Cc ng sc ca in trng u l cc ng thng song song cch u nhau+ Vct cng in trng Er do 1 in tch im Q gy ra ti mt im M cch Q mt on r c: - im t: Ti M.- Phng:ng ni M v Q- Chiu:Hng ra xa Q nu Q > 0Hng vo Q nu Q 0 q < 0 MErTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC MMM MdrQqk qEd W,_MMrQk q W ; ,_NNrQk q Wien the :qWVMM suy ra:MMrQk V dM=rM, dN=rN la khoang cach t Q en M,N + Hiu in th gia 2 im trong in trng l i lng c trng cho kh nng thc hin cng ca in trng khi c 1 in tch di chuyn gia 2 im . Lin h gia E v U' 'N MUEMN hay : dUE * Ghi ch: cng thc chung cho 3 phn 6, 7, 8:.MNMN M N MNAU V V Edq V. Vt dn trong in trng- Khi vt dn t trong in trng m khng c dng in chy trong vt th ta gi l vt dn cn bng in (vdcb)+ Bn trong vdcb cng in trng bng khng.+ Mt ngoi vdcb: cng in trng c phng vung gc vi mt ngoi+ in th ti mi im trn vdcb bng nhau+ in tch ch phn b mt ngoi ca vt, s phn b l khng u (tp trung ch li nhn)VI. in mi trong in trng- Khi t mt khi in mi trong in trng th nguyn t ca cht in mi c ko dn ra mt cht v chia lm 2 u mang in tch tri du (in mi b phn cc). Kt qu l trong khi in mi hnh thnh nn mt in trng ph ngc chiu vi in trng ngoiVII. T in- nh ngha: H 2 vt dn t gn nhau, mi vt l 1 bn t. Khong khng gian gia 2 bn l chn khng hay in mi T in phng c 2 bn t l 2 tm kim loi phng c kch thc ln ,t i din nhau, song song vi nhau- in dung ca t : L i lng c trng cho kh nng tch in ca tQCU (n v l F.)Cng thc tnh in dung ca t in phng: dSC. 4 . 10 . 9.9. Vi S l phn din tch i din gia 2 bn.Ghi ch : Vi mi mt t in c 1 hiu in th gii hn nht nh, nu khi s dng m t vo 2 bn t ht ln hn ht gii hn th in mi gia 2 bn b nh thng.- Ghp t in song song, ni tip GHP NI TIP GHP SONG SONGCch mc : Bn th hai ca t 1 ni vi bn th nht ca t 2, c th tip tc Bn th nht ca t 1 ni vi bn th nht ca t 2, 3, 4 in tch QB = Q1 = Q2 = = QnQB = Q1 + Q2 + + QnHiu in thUB = U1 + U2 + + UnUB = U1 = U2 = = Unin dungn 2 1 BC1...C1C1C1+ + + CB = C1 + C2 + + CnGV: NguynMinh Hi Trang103Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Ghi ch CB < C1, C2 CnCB > C1, C2, C3- Nng lng ca t in: 2 2. .2 2 2QU CU QWC - Nng lng in trng: Nng lng ca t in chnh l nng lng ca in trng trong t in. T in phng29. .9.10 .8.E VW vi V=S.d l th tch khong khng gian gia 2 bn t in phngMt nng lng in trng:28W EwV k GV: NguynMinh Hi Trang104Trng THPT Thanh Bnh 1 Gio n Vt l 11 - NC Tun 19 Ngy san: 5-08-12Tit PPCT: 37 Ngy dyN TP (TIP)(TM TT CNG THC V L THUYT)I. MC TIU:1. Kin thc: Chng 2,32. K nng:II. CHUN B1. Gio vin: -Cc cu hi 2. Hc sinh: -n tp III. HOT NG DY HCHot ng 1 (5pht) Kim tra bi c cau hoi: theo tng bi c thCHNG II. DNG IN KHNG II. DNG IN Dng in l dng cc in tch (cc ht ti in) di chuyn c hng Chiu quy c ca dng in l chiu dch chuyn c hng ca cc in tch dng. Dng in c:* tc dng t (c trng)(Chiu quy c I)* tc dng nhit, tc dng ho hc tu theo mi trng. Cng dng in l i lng cho bit mnh ca dng in c tnh bi:q: in lng di chuyn qua cc tit din thng ca vt dnt: thi gian di chuyn(t0: I l cng tc thi)Dng in c chiu v cng khng thay i theo thi gian c gi l dng in khng i (cng gi l dng ip mt chiu).Cng ca dng in ny c th tnh bi:qI =ttrong q l in lng dch chuyn qua tit din thng ca vt dn trong thi gian t.Ghi ch:a) Cng dng in khng i c o bng ampe k (hay miliampe k, . . . ) mc xen vo mch in (mc ni tip). b) Vi bn cht dng in v nh ngha ca cng dng in nh trn ta suy ra:* cng dng in c gi tr nh nhau ti mi im trn mch khng phn nhnh.* cng mch chnh bng tng cng cc mch r.II. NH LUT M I VI ON MCH CH C IN TR1) nh lut: Cng dng in chy qua on mch c c in tr R:- t l thun vi hiu in th hai u on mch.- t l nghch vi in tr. RUI (A) Nu c R v I, c th tnh hiu in th nh sau :GV: NguynMinh Hi Trang105qI =tAIRIUA BTrng THPT Thanh Bnh 1 Gio n Vt l 11 - NC UAB = VA - VB = I.R ; I.R: gi l gim th ( st th hay st p) trn in tr. Cng thc ca nh lut m cng cho php tnh in tr:IUR ()2) c tuyn V - A (vn - ampe) l th biu din I theo U cn gi l ng c trng vn - ampe. i vi vt dn kim loi (hay hp kim) nhit nht nh c tuyn V A l on ng thng qua gc cc trc: R c gi tr khng ph thuc U. (vt dn tun theo nh lut m).Ghi ch : Nhc li kt qu tm hiu lp 9.a) in tr mc ni tip:in tr tng ng c tnh bi:Rm = Rl + R2+ R3+ + Rn Im = Il = I2 = I3 = = InUm = Ul + U2+ U3+ + Unb) in tr mc song song