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8/9/2019 Tom+Tat+Cong+Thuc+Luong+Giac
1/2
Cng thc l-ng gic I. Gi tr cc hm s l-ng gi c ca cc cung (gc ) c bit
00 300 450 00 900 1200 1350 1500 1800 3600Gc
Hslg0
6
4
3
2
3
2
4
3
6
5
2
sin 0
2
1
2
2
2
3
1
2
3
2
2
2
1
0 0
cos 123
22
21 0
21
22
23 -1 1
tg 0
3
3
1 3 kx 3 -1
3
3
0 0
cotg kx 3 1
3
3
0
3
3
-1 3 kx kx
Ta nn s dng -ng trn l-ng gic ghi nh cc gi tr c bitII. Quan h l-ng gic ca cc c ung (gc) c lin quan c bit
1. Cung i nhau:( Cos i) 2. Cung b nhau(Sin b)cos( ) cossin( ) sin
( )
cot ( ) cot
tg tg
g g
cos( ) cos
sin( ) sin
( )
cot ( ) cot
tg tg
g g
3. Cung ph nhau: (ph cho) 4. Cung hn km cos( ) sin
2
sin( ) cos2
( )2
cot ( ) t2
tg cotg
g g
cos( ) cos
sin( ) sin( )
cot ( ) cot
tg tg
g g
5.Cung hn km2
6. Cung hn km 2k
cos( ) sin2
sin( ) cos2
( )2
cot ( ) t2
tg cotg
g g
sin( 2 ) sin
cos( 2 ) cos
( 2 )
cot ( 2 ) cot
k
k
tg k tg
k g
8/9/2019 Tom+Tat+Cong+Thuc+Luong+Giac
2/2
III. Cng thc l-ng gic 1. Cng thc l-ng gic c bn 2 2
2
2
cos sin 1
11 tg =
cos
2
2
11 cotg =
sin
tg . cotg = 1
2. Cng thc cngcos( ) cos .cos sin .sin
cos( ) cos .cos sin .sin
sin( ) sin .cos sin .cos
sin( ) sin .cos sin .cos
tg +tgtg( + ) =
1 .
tg tgtg( ) =
1 .
tg tg
tg tg
3. Cng thc nhn i
2
sin 2 2sin .cos
22
1
tgtg
tg
2 2
2
2
cos 2 cos sin
2cos 1
1 2sin
4 Cng thc nhn ba(tham kho)3
3
cos3 4cos 3cos
sin 3 3sin 4sin
5. Cng thc h bc:1
sin .cos sin 22
x x 21 cos 2
cos2
2 1 cos 2sin2
2 1 cos 2
1 cos 2tg
6.Cng thc tnh sin ,cos ,tg theo2
t tg
22
2
2 1
2;
1
1cos;
1
2sin
t
ttg
t
t
t
t
7. Cng thc bin i tch thnh tng
1cos .cos cos( ) cos( )
2
1sin .sin cos( ) cos( )
2
1sin .cos sin( ) sin( )
2
8. Cng thc bin i tng thnh tchcos cos 2cos .cos
2 2
cos cos 2sin .sin2 2
sin sin 2sin .cos2 2
sin sin 2cos .sin2 2
2
2
sin( )
cos cos
sin( )
cos cos
1 cos 2cos2
1 cos 2sin2
tg tg
tg tg
aa
aa
4
cos33coscos3
4
3sinsin3sin 3