# 組長 : 胡林瑋 4A12C072 組員 : 黃冠智 4A12C075 陳坤篁 4A12C066 蘇昱偉 4A12C082 陳建志 4A12C105

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### Text of 組長 : 胡林瑋 4A12C072 組員 : 黃冠智 4A12C075 陳坤篁 4A12C066 蘇昱偉 4A12C082...

:4A12C072:4A12C0754A12C0664A12C0824A12C105

(pole)(polar axis) 2 P (x,y) r =x 2 y 2 OP OP

(r,)p P (r,)p = (r,2n+)pnZ (-r,+)p = (-r,(2n+1)+)pnZ P = (x,y) = (r,2n+)p = (-r,(2n+1)+)p P

x = rcosy = rsin r=2x 2 y 231. r = a | a | x2 + y2 = a2-1-0.8-0.6-0.4-0.200.20.40.60.81-1-0.2

-0.4

-0.6

-0.800.6

0.4

0.20.81r=14(1,)2. = y= tanx-10-8-6-4-20246810-104

20

-2

-4(-r ,)-6

-8610

8=5(r ,)3. rcos= d x= d.rsin= d y= d.rcos()=d64. r = acos nn n n 2n .r = asin n0.20.40.60.8130210602409027012030015033018000.20.40.60.813021060240902701203001503301800(a)r=cos(2)7(b)r=cos(5)5. r =.2463021060240902701203001503301800 (r=/3,r>0)8r a b cos6. r a b sin | a | =| b | .1233021060240902701203001503301800 (r=1+2cos())910

x r cos

y r sinr 0 I I 2

R R21. ==r =1()

r =2() 0 {PR2d(P, l)16PF= e}(1) d(P, l ) P l F (focus)l (directrix) e (eccentricity) e < 1 e = 1 e > 1 l d =r cos F = O l F d P = (r,)p

(1) d(P, l ) = d + r cos e =d rcosr r =1 ecosed(2) l d = rcosr =1 ecosed(3) l d = rsin r =1 esin17ed(4)(2)(3)(4)18 2. r =2 -3cos4r =1 - 3cos22 e = 3 ed = 2 d = 4 e = 3 r cos 4 2323

1

x2 + y2 = 9 (x + 4 )24319 20 1.

212.

223.

237. Find the area of the region bounded by the graph of the equation.Solution :The area is.24.

25:1.2. http://www.amath.nchu.edu.tw/~tdoc/13_2.htmEND

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