Upload
hang-hip
View
253
Download
1
Embed Size (px)
Citation preview
7/25/2019 200 Bai Tap Tich Phan Megabook
1/48
Trang 1
TP1: TCH PHN HM S HU T
Dng 1: Tch phn thc
Cu 1.x
I dx
x x
2 2
21 7 12
I dxx x
2
1
16 91
4 3
= x x x
2
116ln 4 9ln 3 = 1 25ln2 16ln3 .
Cu 2.dx
I
x x
2
5 31
Ta c:x
xx x x x3 2 3 2
1 1 1
( 1) 1
I x xx
2
2
21 1 3 1 3ln ln( 1) ln2 ln5
2 2 2 812
Cu 3.x
I dx
x x x
5 2
3 24
3 1
2 5 6
I
2 4 13 7 14ln ln ln2
3 3 15 6 5
Cu 4.xdx
I
x
1
0 3( 1)
Ta c:x x
x xx x
2 3
3 3
1 1( 1) ( 1)( 1) ( 1)
I x x dx 1 2 3
0
1( 1) ( 1) 8
Dng 2: i bin s
Cu 5.x
I dx
x
2
4
( 1)
(2 1)
Ta c:
x xf x
x x
21 1 1
( ) . .3 2 1 2 1
x
I Cx
31 1
9 2 1
Cu 6.
xI dx
x
991
1010
7 1
2 1
x dx x xI d
x x xx
99 991 1
20 0
7 1 1 7 1 7 1
2 1 9 2 1 2 12 1
x
x
1001001 1 7 1 11 2 1
09 100 2 1 900
Cu 7.
xI dx
x
1
2 20
5( 4)
t t x2 4 I
1
8
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
2/48
Trang 2
Cu 8.x
I dx
x
1 7
2 50 (1 )
t t x dt xdx 21 2
tI dt
t
2 3
5 51
1 ( 1) 1 1.
2 42
Cu 9. I x x dx 1
5 3 6
0
(1 )
tdt t t
t x dt x dx dx I t t dt
x
1 7 83 2 6
20
1 1 11 3 (1 )
3 3 7 8 1683
Cu 10. I dxx x
4 3
41
1
( 1)
t t x
2 t
I dtt t
3
21
1 1 1 3ln
2 4 21
Cu 11.dx
I
x x
2
10 21 .( 1)
x dx
I
x x
2 4
5 10 21
.
.( 1)
. t t x
5 dt
I
t t
32
2 21
1
5 ( 1)
Cu 12.x
I dx
x x
2 7
71
1
(1 )
x xI dx
x x
2 7 6
7 71
(1 ).
.(1 )
. t t x
7 t
I dtt t
128
1
1 1
7 (1 )
Cu 13.dx
I
x x
3
6 21 (1 )
t : xt
1
tI dt t t dt
t t
3
1634 2
2 21 3
3
11
1 1
=
117 41 3
135 12
Cu 14.x
I dx
x
2 2001
2 10021
.(1 )
x
I dx dx
x x
xx
2 22004
3 2 1002 10021 1
32
1. .
(1 ) 1 1
. t t dt dx x x
2 3
1 21 .
Cch 2: Ta c:x xdx
I
x x
1 2000
2 2000 2 20
1 .2
2 (1 ) (1 )
. t t x dt xdx
21 2
t
I dt d t tt t
10002 21000
1000 2 10011 1
1 ( 1) 1 1 1 11 1
2 2 2002.2
Cu 15.x
I dx
x
2 2
41
1
1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
3/48
Trang 3
Ta c:x x
xx
x
2 2
42
2
11
1
11
. t t x dt dx x x
2
1 11
dt
I dt
t tt
3 3
2 2
21 1
1 1 1
2 2 2 22
t
t
31 2 1 2 1
.ln ln22 2 2 2 2 2 11
Cu 16.x
I dx
x
2 2
41
1
1
Ta c:x x
x xx
2 2
4
22
11
1
11
.t t x dt dx x
x
2
1 11
dt
I
t
5
2
2
2 2
.
tdu
t u dt
u2
2 tan 2cos
; u u u u1 25 5
tan 2 arctan2; tan arctan2 2
u
u
I du u u
2
1
2 1
2 2 2 5( ) arctan arctan2
2 2 2 2
Cu 17.x
I dx
x x
2 2
3
1
1
Ta c: xI dx
xx
2 2
1
11
1
. t t xx
1 I
4ln
5
Cu 18.x
I dx
x
1 4
60
1
1
Ta c:x x x x x x x x
x x x x x x x x
4 4 2 2 4 2 2 2
6 6 2 4 2 6 2 6
1 ( 1) 1 1
1 1 ( 1)( 1) 1 1 1
d x
I dx dx
x x
1 1 3
2 3 20 0
1 1 ( ) 1.
3 4 3 4 31 ( ) 1
Cu 19.x
I dx
x
3
23
40 1
x
I dx dx
x x x x
3 3
23 3
2 2 2 20 0
1 1 1 1ln(2 3)
2 4 12( 1)( 1) 1 1
Cu 20.xdx
I
x x
1
4 20 1
. t t x2
dt dt I
t t
t
1 1
2 220 0
1 1
2 2 6 31
1 32 2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
4/48
Trang 4
Cu 21.x
I dx
x x
1 5
22
4 21
1
1
Ta c:x x
x xx
x
2 2
4 22
2
111
11 1
. t t x dt dx x x
2
1 11
dt
I
t
1
20 1
. tdu
t u dt
u2
tancos
I du4
0 4
TP2: TCH PHN HM S V T
Dng 1: i bin s dng 1
Cu 22.x
I dx
x x23 9 1
xI dx x x x dx x dx x x dx
x x
2 2 2
2(3 9 1) 3 9 1
3 9 1
+ I x dx x C 2 31 13 + I x x dx 2
2 9 1 x d x x C 3
2 2 2 22
1 19 1 (9 1) (9 1)
18 27
I x x C
32 32
1(9 1)
27
Cu 23.x x
I dx
x x
2
1
x x
dx
x x
2
1
x xdx dx
x x x x
2
1 1
.
+ x
I dx
x x
2
1
1
. t t= x x t x x 21 1 x t3 2 2( 1) x dx t t dt 2 2
4( 1)
3
t dt t t C 2 34 4 4
( 1)3 9 3
= x x x x C3
1
4 41 1
9 3
+x
I dx
x x2
1
=
d x x
x x
2 (1 )
3 1
= x x C2
41
3
Vy: I x x C 3
41
9
Cu 24.
xI dx
x
4
0
2 1
1 2 1
tt x
2 1
. I =
tdt
t
3 2
12 ln21 .
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
5/48
Trang 5
Cu 25.dx
I
x x
6
2 2 1 4 1
t t x4 1 . I
3 1ln
2 12
Cu 26. I x x dx 1
3 2
0
1 t: t x21 I t t dt
12 4
0
2
15 .
Cu 27.x
I dx
x
1
0
1
1
t t x dx t dt2 . . I =t t
dtt
1 3
0
21
= t t dt
t
12
0
22 2
1
=
114ln2
3 .
Cu 28.x
I dx
x x
3
0
3
3 1 3
t t x tdu dx 1 2 t t
I dt t dt dt tt t
2 2 23
21 1 1
2 8 1(2 6) 6
13 2
33 6 ln
2
Cu 29. I x x dx 0
3
1
. 1
t
t tt x t x dx t dt I t dt
11 7 4
3 2 33
00
9
1 1 3 3( 1) 3 7 4 28
Cu 30.x
I dx
x x
5 2
1
1
3 1
ttdt
t x dx 2
3 13
t
tdtI
tt
22
4
22
11
3 2.
31.
3
dtt dt
t
4 42
22 2
2( 1) 2
9 1
tt t
t
3 4 42 1 1 100 9ln ln .9 3 1 27 52 2
Cu 31.x x
I dx
x
3 2
0
2 1
1
t x t x t21 1 dx tdt 2
t t t
I tdt t t dt t t
22 22 2 2 5
4 2 3
11 1
2( 1) ( 1) 1 4 542 2 (2 3 ) 2
5 5
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
6/48
Trang 6
Cu 32.x dx
I
x x
1 2
0
2( 1) 1
t t x t x tdt dx 21 1 2
t tI tdt t dt t
t tt
222 22 2 3
311 1
( 1) 1 1 16 11 2.2 2 2 2
3 3
Cu 33.
xI dx
x
4
20
1
1 1 2
tdx
t x dt dx t dt
x
1 1 2 ( 1)1 2
vt t
x
2 2
2
Ta c: I =t t t t t t
dt dt t dt tt t t
4 4 42 3 2
2 2 22 2 2
1 ( 2 2)( 1) 1 3 4 2 1 4 232 2 2
=t
t tt
21 23 4ln
2 2
=1
2ln24
Cu 34.x
I dx
x
8
23
1
1
x
I dx
x x
8
2 23
1
1 1
= x x x8
2 23
1 ln 1
= 1 ln 3 2 ln 8 3
Cu 35. I x x x dx 1
3 2
0
( 1) 2
I x x x dx x x x x x dx 1 1
3 2 2 2
0 0
( 1) 2 ( 2 1) 2 ( 1) . t t x x22 I
2
15 .
Cu 36.x x x
I dx
x x
2 3 2
20
2 3
1
x x xI dx
x x
2 2
20
( )(2 1)
1
. t t x x
2 1 I t dt 3
2
1
42 ( 1)3
.
Cu 37.x dx
I
x
2 3
3 20 4
t t x x t xdx t dt 3 2 2 3 24 4 2 3 I t t dt 3
24 3
4
3 3 8( 4 ) 4 2
2 2 5
Cu 38.dx
I
x x
1
211 1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
7/48
Trang 7
Ta c:x x x x
I dx dx xx x
1 12 2
2 21 1
1 1 1 1
2(1 ) (1 )
xdx dx
x x
1 1 2
1 1
1 1 11
2 2
+ I dx x x x
11
1 11
1 1 11 ln | 12 2
+x
I dxx
1 2
21
1
2
. t t x t x tdt xdx
2 2 21 1 2 2 I2=t dt
t
2 2
22
02( 1)
Vy: I 1 .
Cch 2: t t x x2 1 .
Cu 39. x x
I dx
x
1
3 31
41
3
Ta c: I dx
x x
11
3
2 31
3
1 11 .
. t tx
2
11 I 6 .
Cu 40.x
I dxx
2 2
1
4
Ta c:x
I xdx
x
2 2
21
4 .t t = x t x tdt xdx
2 2 24 4
I =t tdt t t
dt dt t tt t t
00 0 02
2 2 2
33 3 3
( ) 4 2(1 ) ln
24 4 4
=
2 33 ln
2 3
Cu 41.x
I dx
x x
2 5
2 22 ( 1) 5
t t x2 5
dtI
t
5
23
1 15ln
4 74
.
Cu 42.x
I dx
x x
27
3 21
2
t t x6 t t
I dt dt tt t t t
3 33
2 2 21 1
2 2 2 15 5 1
( 1) 1 1
2 55 3 1 ln
3 12
Cu 43. I dxx x
1
20
1
1
t t x x x 2 1 dt
I tt
1 31 3
11
2 3 2 3ln(2 1) ln
2 1 3
Cu 44.x
I dx
x x
3 2
2 20 (1 1 ) (2 1 )
t x t2 1 I t dt t t
4
23
42 36 4
2 16 12 42ln 3
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
8/48
Trang 8
Cu 45.x
I dx
x x x x
3 2
0 2( 1) 2 1 1
t t x 1 t t dt
I t dt t t
2 22 22
21 1
2 ( 1)
2 ( 1)( 1)
t2
3
1
2 2
( 1)3 3
Cu 46.x x x
I dx
x
32 2 3
41
2011
Ta c: xI dx dx M N x x
32 2 2 22
3 31 1
11
2011
xM dx
x
32 2
23
1
11
.t tx
32
1 1 M t dt
37
323
0
3 21 72 128
N dx x dx
x x
2 22 2 2 23
3 21 1 1
2011 2011 140772011
162
I314077 21 7
16 128 .
Cu 47.dx
I
x x
1
33 30 (1 ). 1
t t x3 31 t dt
I dt
t t t t
3 32 22
2 21 14 3 2 33 3.( 1) .( 1)
dt dt tdt
t
tt ttt
3 3 3
2
3
2 2 2 3
2 2 41 1 1
3 342 333
11
111. 1
tdt
u du
t t3 4
1 31
u uI du u du u
111 12 1 2
2 122 23 33 3
30 0
00
1 1 1
13 3 3 23
Cu 48.x
I dx
x xx
2 2 4
23 1
1
t t x2
1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
9/48
Trang 9
t
I dt
t
3 2 2
22
( 1)
2
=
t tdt t dt dt
t t
3 3 34 22
2 22 2 2
2 1 1 19 2 4 2ln
3 4 4 22 2
Dng 2: i bin s dng 2
Cu 49. x
I x x dx
x
1
0
12 ln 1
1
Tnhx
H dx
x
1
0
1
1
. t x t tcos ; 0;
2
H 2
2
Tnh K x x dx 1
0
2 ln(1 ) . tu x
dv xdx
ln(1 )
2
K
1
2
Cu 50. I x x x dx 2
5 2 2
2
( ) 4
I =x x x dx
25 2 2
2( ) 4
=x x dx
25 2
2 4
+x x dx
22 2
2 4
= A + B.
+ Tnh A = x x dx2
5 2
2
4
. t t x . Tnh c: A = 0.
+ Tnh B = x x dx2
2 2
2
4
. t x t2sin . Tnh c: B = 2 .
Vy: I 2 .
Cu 51. x dx
I
x
2 2
41
3 4
2
Ta c:x
I dx dx
x x
2 2 2
4 41 1
3 4
2 2
.
+ Tnh I1= dx
x
2
41
3
2 = x dx
24
1
3 7
2 16
.
+ Tnhx
I dx
x
2 2
2 41
4
2
. t x t dx tdt2sin 2cos .
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
10/48
Trang 10
tdt
I t dt t d t
t t
22 2 22 2
2 4 2
6 6 6
1 cos 1 1 1 3cot cot . (cot )
8 8 8 8sin sin
Vy: I 1 7 2 316
.
Cu 52.x dx
I
x
1 2
60 4
t t x dt x dx 3 23 dt
I
t
1
20
1
3 4
.
t t u u dt udu2sin , 0; 2cos2
I dt
6
0
1
3 18
.
Cu 53.x
I dxx
2
0
2
2
t x t dx tdt2cos 2sin
tI dt
22
0
4 sin 22
.
Cu 54.x dx
I
x x
1 2
20 3 2
Ta c:x dx
Ix
1 2
2 20 2 ( 1) . t x t1 2cos .
t t
I dt
t
22
22
3
(1 2cos ) 2sin
4 (2cos )
= t t dt
2
3
2
3 4cos 2cos2
=3 3
42 2
Cu 55. x x dx
1
22
0
1 2 1 t x tsin I t t tdt 6
0
3 1(cos sin )cos
12 8 8
Dng 3: Tch phn tng phn
Cu 56. I x dx 3
2
2
1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
11/48
Trang 11
tx
du dx u x
xdv dx
v x
221 1
xI x x x dx x dx
x x
3 32 2
2 22 2
3 11 . 5 2 1
2 1 1
dxx dx
x
3 32
22 2
5 2 11
I x x2 3
25 2 ln 1
I 5 2 1ln 2 1 ln22 4
Ch : Khng c dng php i bin xt
1
cos v 2;3 1;1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
12/48
Trang 12
TP3: TCH PHN HM S LNG GIC
Dng 1: Bin i lng gic
Cu 57. x xI dxx x
28cos sin2 3
sin cos
x x x
I dx x x x x dx x x
2(sin cos ) 4cos2sin cos 4(sin cos
sin cos
x x C3cos 5sin .
Cu 58.x x x
I dxx
cot tan 2 tan2
sin4
Ta c:x x x x
I dx dx dx C x x xx
2
2cot 2 2tan2 2cot 4 cos4 12
sin4 sin4 2sin4sin 4
Cu 59.
x
I dx
x x
2cos8
sin2 cos2 2
Ta c:x
I dx
x
1 cos 21 4
2 21 sin 2
4
x
dxdx
xx x
2
cos 2
1 42 2 1 sin 2 sin cos4 8 8
xdx
dx
x x2
cos 21 14
2 32 2 1 sin 2 sin4 8
x x C1 3
ln 1 sin 2 cot
4 84 2
Cu 60.dx
I
x x
3
2 3sin cos
dx
I
x3
1
21 cos
3
=dx
Ix2
3
1
42sin
2 6
=1
4 3
.
Cu 61.
I dxx
6
0
1
2sin 3
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
13/48
Trang 13
Ta c: I dx dx x x
6 6
0 0
11 1 22
sin sin sin sin3 3
x x
dx dx x x
x
6 6
0 0
coscos 2 6 2 63
sin sin 2cos .sin3 2 6 2 6
x x
dx dx x x
6 6
0 0
cos sin2 6 2 61 1
2 2sin cos
2 6 2 6
x x
6 60 0
ln sin ln cos .....2 6 2 6
Cu 62. I x x x x dx 2
4 4 6 6
0
(sin cos )(sin cos )
.
Ta c: x x x x4 4 6 6(sin cos )(sin cos ) x x33 7 3
cos4 cos864 16 64
I 33
128 .
Cu 63. I x x x dx 2
4 4
0
cos2 (sin cos )
I x x dx x d x 2 22 2
0 0
1 1 1cos2 1 sin 2 1 sin 2 (sin2 ) 0
2 2 2
Cu 64. I x x dx 2
3 2
0
(cos 1)cos .
A = xdx x d x2 2 2
5 2
0 0
cos 1 sin (sin )
=8
15
B = xdx x dx2 2
2
0 0
1cos . (1 cos2 ).
2
=4
Vy I =8
15
4
.
Cu 65.2
2
0
I cos cos 2x xdx
I x xdx x xdx x x dx 2 2 22
0 0 0
1 1cos cos2 (1 cos2 ) cos2 (1 2cos2 cos4 )2 4
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
14/48
Trang 14
x x x 2
0
1 1( sin2 sin4 )
4 4 8
Cu 66.
xI dxx
3
20
4sin1 cos
x x x
x x x x xx x
3 3
2
4sin 4sin (1 cos )4sin 4sin cos 4sin 2sin2
1 cos sin
I x x dx 20(4sin 2sin2 ) 2
Cu 67. I xdx 2
0
1 sin
x x x xI dx dx
22 2
0 0
sin cos sin cos2 2 2 2
x dx2
0
2 sin2 4
x xdx dx
3
22
30
2
2 sin sin2 4 2 4
4 2
Cu 68.dx
I
x
4
60cos
Ta c: I x x d x 4
2 4
0
28(1 2tan tan ) (tan )
15
.
Dng 2: i bin s dng 1
Cu 69.xdx
Ix x
sin2
3 4sin cos2
Ta c: x xI dxx x
22sin cos
2sin 4sin 2
. t t xsin I x C
x
1ln sin 1sin 1
Cu 70.dx
I
x x3 5sin .cos
xx
dx
xxx
dxI
23233 cos.2sin8
cos.cos.sin
t t xtan . I t t t dt x x x C t x
3 3 4 2
2
3 1 3 13 tan tan 3ln tan
4 2 2tan
Ch :t
x
t2
2sin2
1
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
15/48
Trang 15
Cu 71.dx
I
x x3sin .cos
dx dx
I
x x x x x
2 22
sin .cos .cos sin2 .cos
. t t xtan dx t
dt x
x t
2 2
2; sin2
cos 1
dt t
I dtt t
t
2
2
12
2
1
t x
t dt t C x C t
2 21 tan( ) ln ln tan
2 2
Cu 72.x x
I xdx
x
2011 2011 2009
5
sin sincot
sin
Ta c:xx
I xdx xdx
x x
2011 2011 22
4 4
11
cotsin cot cot
sin sin
t t xcot I t tdt t t C 2 4024 8046
22011 2011 20112011 2011t (1 )4024 8046
= x x C
4024 8046
2011 20112011 2011cot cot4024 8046
Cu 73.x x
I dxx
2
0
sin2 .cos
1 cos
Ta c:x x
I dxx
22
0
sin .cos2
1 cos
. t t x1 cos t
I dtt
2 2
1
( 1)2 2ln2 1
Cu 74. I x xdx 3
2
0
sin tan
Ta c:x x x
I x dx dx x x
23 32
0 0
sin (1 cos )sinsin .
cos cos
. t t xcos
u
I duu
122
1
1 3ln2
8
Cu 75. I x x dx 2
2
sin (2 1 cos2 )
Ta c: I xdx x xdx H K 2 2
2 2
2sin sin 1 cos2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
16/48
Trang 16
+ H xdx x dx 2
2 2
2sin (1 cos2 )2 2
+ K x x x xdx 2 2 2
2 2
sin 2cos 2 sin cos
xd x2
2
22 sin (sin )3
I 2
2 3
Cu 76.dx
I
x x
3
2 4
4
sin .cos
dx
I
x x
3
2 2
4
4.sin 2 .cos
. t t xtan dx
dt
x2cos
.
t dt t I t dt t
tt t
33 32 2 3
2
2 211 1
(1 ) 1 1 8 3 42 2
3 3
Cu 77.
2
2
0
sin2
2 sin
xI dx
x
Ta c:x x x
I dx dx
x x
2 2
2 20 0
sin2 sin cos2
(2 sin ) (2 sin )
.t t x2 sin .
t
I dt dt t t tt t
33 3
2 22 2 2
2 1 2 22 2 2 ln
3 22ln
2 3
Cu 78.x
I dx
x
6
0
sin
cos2
x x
I dx dx x x
6 6
20 0
sin sin
cos2 2cos 1
. t t x dt xdx cos sin
i cn: x t x t 3
0 1;6 2
Ta ct
I dt
tt
31
2
2
31 2
1 1 2 2ln
2 2 2 22 1
=
1 3 2 2ln
2 2 5 2 6
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
17/48
Trang 17
Cu 79. xI e x x dx 22 sin 3
0
.sin .cos .
t t x2sin I = te t dt
1
0
1(1 )
2 = e
11
2 .
Cu 80. I x x dx 2 12sin sin
2
6
t t xcos . I 3
( 2)16
Cu 81.x
I dx
x x
4
6 60
sin4
sin cos
x
I dx
x
4
20
sin4
31 sin 2
4
. t t x23
1 sin 24 I = dtt
1
4
1
2 1
3
= t
1
1
4
4 2
3 3 .
Cu 82.
xI dx
x x
2
30
sin
sin 3cos
Ta c: x x xsin 3 cos 2cos6
;
x xsin sin 6 6
=x x
3 1
sin cos2 6 2 6
I =
x dxdx
x x
2 2
3 20 0
sin63 1
16 16cos cos
6 6
=3
6
Cu 83.x x
I dx
x
24
2
3
sin 1 cos
cos
x xI x dx x dx
x x
4 42
2 2
3 3
sin sin1 cos . sin
cos cos
x x
x dx x dx
x x
0 4
2 20
3
sin sinsin sin
cos cos
=x x
dx dx
x x
0 2 24
2 20
3
sin sin
cos cos
7
3 112
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
18/48
Trang 18
Cu 84. I dxx x
6
0
1
sin 3 cos
I dxx x
6
0
1
sin 3 cos
= dxx
6
0
1 1
2sin
3
=x
dx
x
6
20
sin1 3
21 cos
3
.
t t x dt x dx cos sin3 3
I dt
t
1
2
20
1 1 1ln3
2 41
Cu 85. I x xdx 2
2
0
1 3sin2 2cos
I x x dx 2
0
sin 3 cos
= I x x dx x x dx 3 2
0
3
sin 3cos sin 3cos
3 3
Cu 86.xdx
I
x x
2
30
sin
(sin cos )
t x t dx dt2
tdt xdx It t x x
2 2
3 30 0
cos cos
(sin cos ) (sin cos )
dx dx
2I x
x xx
2 2 4
22 00 0
1 1cot( ) 1
2 2 4(sin cos ) sin ( )4
I 1
2
Cu 87.x x
I dx
x x
2
30
7sin 5cos
(sin cos )
Xt:
xdx xdxI I
x x x x
2 2
1 23 30 0
sin cos;
sin cos sin cos
.
t x t2
. Ta chng minh c I1 = I2
Tnh I1 + I2 =
dx dx x
x x x
2 2
220 0
1tan( ) 12
2 4sin cos 02cos ( )4
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
19/48
Trang 19
I I1 21
2 I I I1 27 5 1 .
Cu 88.
x x
I dxx x
2
30
3sin 2cos
(sin cos )
t x t dx dt2
t t x x I dt dx
t t x x
2 2
3 30 0
3cos 2sin 3cos 2sin
(cos sin ) (cos sin )
x x x x
I I I dx dx dx
x x x x x x
2 2 2
3 3 20 0 0
3sin 2cos 3cos 2sin 12 1
(sin cos ) (cos sin ) (sin cos )
I
1
2 .
Cu 89.
x xI dx
x2
0
sin
1 cos
tt t t
x t dx dt I dt dt I
t t2 2
0 0
( )sin sin
1 cos 1 cos
t d tI dt I
t t
2
2 20 0
sin (cos )2
4 4 81 cos 1 cos
Cu 90.x x
I dx
x x
42
3 3
0
cos sin
cos sin
t x t dx dt2
t t x x I dt dx
t t x x
0 4 42
3 3 3 30
2
sin cos sin cos
cos sin cos sin
x x x x x x x x
I dx dx xdx
x x x x
4 4 3 32 2 2
3 3 3 30 0 0
cos sin sin cos sin cos (sin cos ) 1 12 sin2
2 2sin cos sin cos
I 1
4
.
Cu 91. I x dx x
22
20
1tan (cos )
cos (sin )
t x t dx dt2
I t dt t
22
20
1tan (sin )
cos (cos )
x dx
x
22
20
1tan (sin )
cos (cos )
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
20/48
Trang 20
Do : I x x dx x x
22 2
2 20
1 12 tan (cos ) tan (sin )
cos (sin ) cos (cos )
= dt
2
0
2
I2
.
Cu 92.x x
I dx
x
4
0
cos sin
3 sin2
t u x xsin cos duI
u
2
21 4
. t u t2sin tdt
I dt
t
4 4
2
6 6
2cos
124 4sin
.
Cu 93.x
I dx
x x
3
20
sin
cos 3 sin
t t x23 sin = x24 cos . Ta c: x t2 2cos 4 vx x
dt dx
x2
sin cos
3 sin
.
I =x
dx
x x
3
20
sin.
cos 3 sin
=
x xdx
x x
3
2 20
sin .cos
cos 3 sin
=
dt
t
15
2
2
3 4
= dtt t
15
2
3
1 1 1
4 2 2
=t
t
152
3
1 2ln
4 2
=
1 15 4 3 2ln ln
4 15 4 3 2
= 1 ln 15 4 ln 3 22
.
Cu 94.x x x x
I dx
x x
2
33 2
3
( sin )sin
sin sin
x dx
I dxxx
2 2
3 32
3 31 sinsin
.
+ Tnh xI dxx
2
31 2
3 sin
. t
u x
du dxdxdv v x
x2
cotsin
I13
+ Tnhdx dx dx
I =x x
x
2 2 2
3 3 32
23 3 3
4 2 31 sin
1 cos 2cos2 4 2
Vy: I 4 2 33
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
21/48
Trang 21
Cu 95.x
dx
x x
I2
2 20
sin2
cos 4sin
x x
dx
x
I2
20
2sin cos
3sin 1
. t u x23sin 1
udu
duu
I
2 2
1 1
22 233 3
Cu 96.x
I dxx
6
0
tan4
cos2
xx
I dx dx x x
26 6
20 0
tantan 14
cos2 (tan 1)
. t t x dt dx x dx
x
2
2
1tan (tan 1)
cos
dt
Itt
11
33
200
1 1 3
1 2( 1)
.
Cu 97.x
I dx
x x
3
6
cot
sin .sin4
x
I dxx x
3
2
6
cot2sin (1 cot )
. t x t1 cot dx dt x21sin
t
I dt t t t
3 1 3 1
3 1
3 1 3
3
1 22 2 ln 2 ln 3
3
Cu 98.dx
I
x x
3
2 4
4
sin .cos
Ta c:dx
I
x x
3
2 2
4
4.sin 2 .cos
.tdt
t x dx
t2
tan1
t dt t
I t dt t t
t t
32 2 33 3(1 ) 1 1 8 3 42( 2 ) ( 2 )2 2 3 31 1 1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
22/48
Trang 22
Cu 99.x
I dx
x x x
4
20
sin
5sin .cos 2cos
Ta c:x
I dx
x x x
4
2 20
tan 1.
5tan 2(1 tan ) cos
.t t xtan ,
t
I dt dt t tt t
1 1
20 0
1 2 1 1 2ln3 ln2
3 2 2 1 2 32 5 2
Cu 100.xdx
x x x
I
24
4 2
4
sin
cos (tan 2 tan 5)
tdt
t x dx
t2
tan1
t dt dt
I
t t t t
21 1
2 21 1
22 ln 3
32 5 2 5
Tnhdt
I
t t
1
1 21 2 5
. tt
u I du
0
1
4
1 1tan
2 2 8
. Vy I
2 32 ln
3 8
.
Cu 101.x
I dxx
22
6
sin
sin3
.
x x
I dx dx
x x x
22 2
3 2
6 6
sin sin
3sin 4sin 4cos 1
t t x dt xdx cos sin dt dt
I
tt
3
0 2
2203
2
1 1ln(2 3)
14 44 14
Cu 102.
x xI dxx
2
4
sin cos1 sin2
Ta c: x x x x x1 sin2 sin cos sin cos (v x ;4 2
)
x x
I dxx x
2
4
sin cos
sin cos
. t t x x dt x x dx sin cos (cos sin )
I dt t t
22
11
1 1ln ln2
2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
23/48
Trang 23
Cu 103.I x x xdx 2
6 3 5
1
2 1 cos .sin .cos
t
t dt
t x t x t dt x xdx dx x x
56 3 6 3 5 2
2
2
1 cos 1 cos 6 3cos sin cos sin
t tI t t dt
11 7 13
6 6
00
122 (1 ) 2
7 13 91
Cu 104.xdx
I
x x
4
20
tan
cos 1 cos
Ta c:
xdx
Ix x
4
2 20
tan
cos tan 2
.t2 2 2
2
tan
2 tan 2 tan cos
x
t x t x tdt dxx
3 3
2 2
3 2 tdt
I dtt
Cu 105.x
I dx
x x
2
30
cos2
(cos sin 3)
t t x xcos sin 3 t
I dt
t
4
32
3 1
32
.
Cu 106. xI dxx x
4
2 40
sin4
cos . tan 1
Ta c:x
I dx
x x
4
4 40
sin4
sin cos
. t t x x4 4sin cos I dt
2
2
1
2 2 2 .
Cu 107.x
I dx
x
4
20
sin4
1 cos
Ta c:x x
I dx
x
24
20
2sin2 (2cos 1)
1 cos
. t t x
2cos t
I dtt
12
1
2(2 1) 12 6ln
1 3
.
Cu 108.x
I dxx
6
0
tan( )4
cos2
Ta c:26
2
0
tan 1
(tan 1)
x
I dxx
. t t xtan
1
3
2
0
1 3
( 1) 2
dt
It
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
24/48
Trang 24
Cu 109.36
0
tan
cos2
x
I dxx
Ta c:3 36 6tan tan
2 2 2 2cos sin cos (1 tan )0 0
x xI dx dx
x x x x
.
t t xtan
3
33 1 1 2ln
2 6 2 310
tI dt
t
.
Cu 110.x
I dx
x
2
0
cos
7 cos2
xdx
I
x
2
2 20
1 cos
2 6 22 sin
Cu 111.dx
x x
3
4 3 5
4
sin .cos
Ta c: dxx
x
x
3
384
4 3
1
sin.cos
cos
dxxx
3
24 3
4
1 1.
costan
.
t t xtan I t dt 33
84
1
4 3 1
Cu 112.3
2
0
cos cos sin( )
1 cos
x x xI x dx
x
Ta c:x x x x x
I x dx x x dx dx J K
x x
2
2 20 0 0
cos (1 cos ) sin .sin.cos .
1 cos 1 cos
+ TnhJ x x dx
0.cos .
. tu x du dx
dv xdx v x cos sin
J
2
+ Tnhx x
K dx
x2
0
.sin
1 cos
. t x t dx dt
t t t t x x K dt dt dx
t t x2 2 2
0 0 0
( ).sin( ) ( ).sin ( ).sin
1 cos ( ) 1 cos 1 cos
x x x x dx x dxK dx K
x x x2 2 2
0 0 0
( ).sin sin . sin .2
21 cos 1 cos 1 cos
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
25/48
Trang 25
t t xcos dtK
t
1
21
2 1
, t t u dt u du2tan (1 tan )
u duK du u
u
2 24 4 42
44 4
(1 tan ) .2 2 2 41 tan
Vy I2
24
Cu 113.2
2
6
cosI
sin 3 cos
x
dx
x x
Ta c:2
2 2
6
sin cos
sin 3 cos
x xI dxx x
. t t x23 cos
dtIt
15
2
23
1ln( 15 4) ln( 3 2)
24
Dng 3: i bin s dng 2
Cu 114.I x x dx 2 12sin sin .
2
6
t x t t3
cos sin , 02 2
I = tdt
42
0
3cos
2
=3 1
2 4 2
.
Cu 115.2
2 2
0
3sin 4cos
3sin 4 cos
x x
I dxx x
2 2 2
2 2 2
0 0 0
3sin 4cos 3sin 4cos
3 cos 3 cos 3 cos
x x x x
I dx dx dxx x x
2 2
2 2
0 0
3sin 4cos
3 cos 4 sin
x xdx dx
x x
+ Tnh2
1 2
0
3sin
3 cos
xI dx
x. t cos sin t x dt xdx
1
1 2
0
3
3
dt
It
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
26/48
Trang 26
t 23 tan 3(1 tan ) t u dt u du 26
1 2
0
3 3(1 tan ) 3
3(1 tan ) 6
u du
Iu
+ Tnh 22 2
0
4cos4 sin
xI dxx
. t 1 1sin cos t x dt xdx1
12 12
10
4 ln34
dtI dtt
Vy:3
ln36
I
Cu 116.x
I dx
x x
4
2
6
tan
cos 1 cos
Ta c: x xI dx dx x x
x
x
4 4
2 22
26 6
tan tan1 cos tan 2cos 1
cos
t u x du dx x
2
1tan
cos
uI dx
u
1
21
3
2
. tu
t u dt du
u
2
22
2
.
I dt t
33
77 33
7 3 73 .
3 3
Cu 117.
x
I dxx x
2
4
sin4
2sin cos 3
Ta c:
x xI dx
x x
2
2
4
1 sin cos
2 sin cos 2
. t t x xsin cos I dt
t
1
20
1 1
2 2
t t u2 tan u
I du
u
1arctan22
20
1 2(1 tan ) 1 1arctan
22 22tan 2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
27/48
Trang 27
Dng 4: Tch phn tng phn
Cu 118.
x x
I dxx
3
2
3
sin
cos
.
S dng cng thc tch phn tng phn ta c:
x dxI xd J
x x x
3 33
33 3
1 4,
cos cos cos 3
vi
dxJ
x
3
3
cos
tnh J ta t t xsin . Khi
dx dt t
J x tt
3 33 2 2
2 33
23 2
1 1 2 3
ln lncos 2 1 2 31
Vy I 4 2 3
ln .3 2 3
Cu 119. xx
I e dx x
2
0
1 sin.
1 cos
Ta c:
x x
x x
x xx 2 2
1 2sin cos1 sin 12 2 tan1 cos 2
2cos 2cos2 2
x
xe dx x I e dx
x
2 2
20 0
tan2
2cos2
= e2
Cu 120.
x xI dx
x
4
20
cos2
1 sin2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
28/48
Trang 28
tu x du dx
xdv dx v
xx2
cos2 1
1 sin2(1 sin2 )
I x dx dx x x
x
4 4
20 0
1 1 1 1 1 1 1. . .4
2 1 sin2 2 1 sin2 16 2 20 cos4
x1 1 1 2 2
. tan . 0 1416 2 4 16 2 2 4 162 0
TP4: TCH PHN HM S M - LOGARIT
Dng 1: i bin s
Cu 121.x
x
eI dx
e
2
1
t x x xt e e t e dx tdt 2 2 .
tI dt
t
3
2 1
t t t t C
3 22
2 2ln 13 x x x x x e e e e e C
2
2 2ln 13
Cu 122.x
x
x x eI dx
x e
2( )
x
x
x x eI dx
x e
2( )
=
x x
x
xe x edx
xe
.( 1)
1
. t
xt x e. 1 x xI xe xe C 1 ln 1 .
Cu 123.x
dxI
e2 9
tx
t e
2
9
dt t
I Ctt2
1 3
ln6 39
x
x
e
Ce
2
2
1 9 3
ln6 9 3
Cu 124.x
x
x xI dx
ex e2
2
2 1
ln(1 ) 2011
ln ( )
Ta c:x x
I dx
x x
2
2 2
ln( 1) 2011
( 1) ln( 1) 1
. t t x2ln( 1) 1
t
I dtt
1 2010
2
t t C
11005ln
2 = x x C2 2
1 1ln( 1) 1005ln(ln( 1) 1)
2 2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
29/48
Trang 29
Cu 125.e x
x
xeJ dx
x e x1
1
( ln )
e x eex
x
d e x eJ e x
ee x 11
( ln ) 1ln ln ln
ln
Cu 126.x x
x x x
e eI dx
e e e
ln2 3 2
3 20
2 1
1
x x x x x x
x x x
e e e e e eI dx
e e e
ln2 3 2 3 2
3 20
3 2 ( 1)
1
=
x x x
x x x
e e edx
e e e
ln2 3 2
3 20
3 21
1
=x x x
e e e x 3 2 ln2 ln2ln( 1)
0 0 = ln11ln4 =
14ln
4
Cu 127.
x
dxI
e
3ln2
230
2
x
x
x
e dxI
e e
3ln2 3
20 33 2
.tx x
t e dt e dx 3 31
3 I
3 3 1ln
4 2 6
Cu 128. xI e dx ln2
3
0
1
t xe t3 1 t dt
dx
t
2
3
3
1
I = dt
t
1
3
0
13 1
1
=
dt
t
1
30
3 31
.
Tnhdt
I
t
1
1 30
31
=t
dtt t t
1
20
1 2
1 1
= ln23
Vy: I 3 ln23
Cu 129. x x
x x x x
e e dx I
e e e e
ln15 2
3ln2
24
1 5 3 1 15
t x xt e t e21 1 xe dx tdt2 .
t t dt I dt t t t t tt
4 42 4
2 33 3
(2 10 ) 3 72 2 3ln 2 7ln 2
2 24
2 3ln2 7ln6 7ln5
Cu 130.ln3 2
ln2 1 2
x
x x
e dxI
e e
t t = xe 2 xe dx tdt 2 2
I = 2 t tdt
t t
1 2
20
( 2)
1
= 2
tt dt
t t
1
20
2 11
1
= t dt
1
0
2 ( 1) +d t t
t t
1 2
20
( 1)2
1
= t t1
20( 2 ) + t t
12
02ln( 1) = 2ln3 1 .
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
30/48
Trang 30
Cu 131.x x
x x
e eI dx
e e
ln3 3 2
0
2
4 3 1
t
x x x x x xt e e t e e tdt e e dx
3 2 2 3 2 3 2
4 3 4 3 2 (12 6 ) x x
tdte e dx
3 2
(2 ) 3
tdtI dt
t t
9 9
1 1
1 1 1(1 )
3 1 3 1
t t
91
1 8 ln5( ln 1) .
3 3
Cu 132. 3
16ln
3
8ln
43 dxeI x
t: x x t
t e e
2 43 4
3
tdtdx
t2
2
4
t dtI dt dt
t t
2 3 2 3 2 32
2 22 2 2
22 8
4 4
I14 3 1 8 , vi
dtI
t
2 3
1 22 4
Tnhdt
I
t
2 3
1 22 4
. t: t u u2tan , ;2 2
dt u du
22(1 tan )
I du
3
1
4
1 1
2 2 3 4 24
. Vy: I 4( 3 1)
3
Cu 133.x
x
eI dx
e
ln3
30 ( 1)
t x x xx
tdtt e t e tdt e dx dx
e
2 21 1 2 tdt
I
t
2
32
2 2 1
Cu 134.x
x
eI dx
e
ln5 2
ln2 1
t x xx
tdt t t e t e dx I t d t
e
22 32 2
11
2 201 1 2 ( 1) 2
3 3
Cu 135. xI e dx ln2
0
1
t x x xx
td td t e t e tdt e dx dx
e t
2
2
2 21 1 2
1
t
I dt dt t t
1 12
2 20 0
2 1 42 1 21 1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
31/48
Trang 31
Cu 136.x x
x xI dx
2
1
2 2
4 4 2
tx x
t 2 2
x x x x 2
4 4 2 (2 2 ) 4
1 81
ln4 ln 2 25I
Cu 137.1
0
6
9 3.6 2.4
x
x x x
dxI
Ta c:
x
x x
dx
I
1
20
3
2
3 33 2
2 2
.tx
t 3
2
.
dtI
t t
3
2
21
1
ln3 ln2 3 2
ln15 ln14
ln3 ln2
Cu 138.e
xI x x dx
x x
2
1
ln3 ln
1 ln
e e
xI dx x xdx
x x
2
1 1
ln3 ln
1 ln
=
2(2 2)
3
+
e32 1
3
=
e35 2 2 2
3
Cu 139.e
x xI dx
x
3 2
1
ln 2 ln
t t x2
2 ln x
dt dx x
2ln
I tdt
33
2
1
2 33 4 43
3 28
Cu 140.e
e
dxI
x x ex
2
ln .ln
e e
e e
dx d x I
x x x x x
2 2
(ln )
ln (1 l n ) ln (1 l n )
=
e
e
d xx x
2
1 1(ln )
ln 1 ln
= 2ln2ln3
Cu 141.x
x x
eI dx
e e
ln6 2
ln4 6 5
tx
t e . I 2 9ln3 4ln2
Cu 142.e x
I dx
x x
32
21
log
1 3ln
e e e
x
x x xdx I dx dx
xx x x x x
3
3 22
32 2 21 1 1
ln
log ln2 1 ln . ln.
ln 21 3ln 1 3ln 1 3ln
tdx
x t x t x tdtx
2 2 21 11 3ln ln ( 1) ln .3 3
.
Suy ra I t t
2
33 3
1
1 1 439ln 2 27ln 2
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
32/48
Trang 32
Cu 143.ex x x
I dxx x
1
( 2) ln
(1 ln )
e ex
dx dx x x1 1
ln
2 (1 ln ) =e
x
e dxx x1
ln
1 2 (1 ln )
Tnh J =e
xdx
x x1
ln
(1 ln ). t t x1 ln
tJ dt
t
2
1
11 ln2
.
Vy: I e 3 2ln2 .
Cu 144.e
e
x x x xI dx
x x
3
2
2 22 ln ln 3
(1 ln )
e e
e e
I dx xdx
x x
3 3
2 2
13 2 ln
(1 ln )
e e
3 23ln2 4 2 .
Cu 145.e
x xI dx
x
22 2
21
ln ln 1
t :dx
t x dt x
ln t t t t
t t t t t I dt dt dt dt I I
e e e e
22 2 1 2
1 20 0 0 1
2 1 1 1 1
+ tt t t t
tdt dt dt dt I te
ee e e e
11 1 1 1
1 0 0 0 00
1
+t t
t t t t
tdt dt dt dt
I te te ee e e e e
2 22 2 2 2
2 1 1 1 1 21 1
1 2
Vy :e
I
e2
2( 1)
Cu 146.5
2
ln( 1 1)
1 1
x
I dxx x
t t xln 1 1 dxdtx x
21 1
I dtln3
2 2
ln2
2 ln 3 ln 2 .
Cu 147.
33
1
ln
1 ln
ex
I dxx x
tdx
t x x t tdt x
21 ln 1 ln 2 v x t3 2 3ln ( 1)
t t t t
I dt = dt t t t dt t t t
2 2 22 3 6 4 25 3
1 1 1
( 1) 3 3 1 1( 3 3 )
15ln2
4
Cu 148.e
xI dx
x x1
3 2ln
1 2ln
t t x1 2ln
e
I t dt 2
1
(2 ) =3
524
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
33/48
Trang 33
Cu 149.e
x xI dx
x
3 2
1
ln 2 ln t t x
22 ln I 33 4 43 3 2
8
Cu 150.1
1
( ln )
e x
x
xeI dx
x e xt xt e xln
1ln
eeI
e.
Dng 2: Tch phn tng phn
Cu 151.
inxI e xdx
2s
0
.sin2
inxI e x xdx 2
s
0
2 .sin cos
.t x xu x du xdx
dv e xdx v esin sin
sin cos
cos
x x xI xe e xdx e e2
sin sin sin2 20 0
0
2sin .cos 2 2 2
Cu 152.
I x x x dx
1
2
0ln( 1)
htt ://me abook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
34/48
Trang 34
t
xdu dx
u x x x x
dv xdx xv
2 2
2
2 1
ln( 1) 1
2
x x xI x x dx
x x
112 3 2
2
20 0
1 2ln( 1)
2 2 1
x dxx dx dx
x x x x
1 1 1
2 20 0 0
1 1 1 2 1 3ln3 (2 1)
2 2 4 41 1
3 3ln3
4 12
Cu 153.x
I dx
x
8
3
ln
1
tu x dx
dudx xdv
v xx
ln
2 11
xI x x dx J x
883
3
12 1.ln 2 6ln8 4ln3 2
+ Tnhx
J dxx
8
3
1 . t
t tt x J tdt dt dt
t tt t
3 3 32
2 22 2 2
1 11 .2 2 2
1 11 1
tt
t
83
12 ln 2 ln3 ln2
1
T I 20ln2 6ln3 4 .
Cu 154.
exx x x
I e dx x
2
1
ln 1
e e e x
x x eI xe dx xe dx dx
x1 1 1
ln . + Tnhe ee
x x x eI xe dx xe e dx e e11
1 1
( 1)
+Tnhe e ex xe
x x ee eI e xdx e x dx e dx
x x2
11 1 1
ln ln .
Vy:e x
eI I I dx
x1 2
1
=e
e 1 .
Cu 155.e
xI x dx
x x
2
1
lnln
1 ln
Tnhe
xI dx
x x1
1
ln
1 ln
.t t x1 ln I1
4 2 2
3 3 .
+ Tnhe
I xdx 2
21
ln . Ly tch phn tng phn 2 ln c I e2 2 .
Vy I e 2 2 2
3 3
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
35/48
Trang 35
Cu 156.2
3
2
1
ln( 1)xI dx
x
t
xdu
u x xdx
dvv
xx
2
2
32
2
ln( 1) 11
2
. Do I = x dxx x x
22
2 21
2ln( 1)
12 ( 1)
xdx
x x
2
21
ln2 ln5 1
2 8 1
dx d x
x x
2 2 2
21 1
ln2 ln5 1 ( 1)
2 8 2 1
x x2 2ln2 ln5 1ln | | ln | 1|
2 8 2 1
=
52ln2 ln5
8
Cu 157.
xI = dx
x
2
21
ln( 1)
t
dxu x du
dxxdx I xdv x x x
vxx
2
2 1
ln( 1)1 321 ln( 1) 3ln2 ln3
1 1 ( 1) 2
Cu 158.x
I x dx x
1
2
0
1ln
1
tdu dx xu x
xxdv xdx v
2
2
21ln (1 )1
2
x
I x x dx x x
1
22 2
20
11 1 2ln 2
2 1 10
xdx dx
x xx
1 1
22 2
20 0
ln3 ln3 1 ln3 1 1 21 ln
8 8 ( 1)( 1) 8 2 2 31
Cu 159.I x x dx x
22
1
1.l n
t
u xx
dv x dx
2
1ln
I 10 1
3ln3 ln23 6
Cu 160.I x x dx 1
2 2.ln(1 )
0
tu x
dv x dx
2
2
ln(1 )
I
1 4.ln2
3 9 6
Cu 161.x
I dx
x
3
21
ln
( 1)
t
u x
dxdv
x 2
ln
( 1)
I 1 3
ln3 ln4 2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
36/48
Trang 36
Cu 162.2 2
1
ln ( ln ).
1
e x x
x
x e e xI dx
e
Ta c:e e x
x
eI x dx dx H K
e
22
1 1
ln .1
+e
H x dx 2
1
ln . . t:u x
dv dx
2ln
e
H e x dx e
1
2ln . 2
+e x
x
eK dx
e
2
1 1
. t
xt e 1
ee
e
ee
t eI dt e e
t e
1
21
1 1ln
1
Vy: ee
eI e
e
1 2 ln
1
Cu 163.
2 1
1
2
1( 1 )
x
x
I x e dxx
Ta c:2 31 1
1 1
2 2
1
x x
x xI e dx x e dx H Kx
+ TnhH theo phng php tng phn I1=2 21 1 5
2
1 12 2
1 3
2
x x
x xH xe x e dx e Kx
5
23
.
2
I e
Cu 164.4
2
0
ln( 9 ) I x x dx
t u x xdv dx
2ln 9
xI x x x dx
x
4 42
20 0
ln 9 29
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
37/48
Trang 37
TP5: TCH PHN T HP NHIU HM S
Cu 165.
x x
I x e dx x
31 4
2
0 1
x xI x e dx dx
x
31 1 4
2
0 01
.
+ Tnh xI x e dx 3
12
10
. t t x3 t tI e dt e e
1 1
10
0
1 1 1 1
3 3 3 3 .
+ Tnhx
I dx
x
1 4
201
. t t x4
tI dt
t
1 4
2 20
24 4
3 41
Vy:I e1 33
Cu 166. x x
I x e dx
x
2 2
31
4
xI xe dx 2
1
+x
dx
x
2 2
21
4 .
+ Tnh xI xe dx e2
21
1
+ Tnhx
I dx
x
2 2
2 21
4 . t x t2sin , t 0;
2
.
t
I dt t t
t
222
2 2
66
cos( cot )
sin
= 33
Vy: I e2 33
.
Cu 167. xxI e x x dx x
12 2 2
20
. 4 .4
x xI xe dx dx I I
x
1 1 32
1 22
0 0 4
+ Tnh x e
I xe dx
1 22
10
1
4
+ Tnhx
I dx
x
1 3
22
0 4
. t t x24 I2
163 3
3
eI
2 61
3 34 12
htt ://me abook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
38/48
Trang 38
Cu 168. xx
I e dx
x
1 2
20
1
( 1)
t t x dx dt 1 t tt t
I e dt e dt tt t
2 221 1
2 21 1
2 2 2 2
1
=e
e ee
22
1 12
Cu 169.x
x e dxI
x
23 3 1
20
.
1
t t x dx tdt 21 tI t e dt 2
2
1
( 1) t t
t e dt e J e e
22 2
1
2( )
1
+ t t t t t t t J t e dt t e te dt e e te e dt e e te e2 2 2
2 2 2 2
1 1 1
2 2 22 4 2 4 2( )
1 1 1
Vy: I e2
Cu 170.x x x
I dx
x
2 3
2
ln( 1)
1
Ta c:x x x x x x x x
f x x
x x x x
2 2 2
2 2 2 2
ln( 1) ( 1) ln( 1)( )
1 1 1 1
F x f x dx x d x xdx d x 2 2 21 1
( ) ( ) ln( 1) ( 1) ln( 1)2 2
= x x x C2 2 2 21 1 1
ln ( 1) ln( 1)4 2 2 .
Cu 171. x x x
I dx
x
4 2 3
20
ln 9 3
9
x x x x x x
I dx dx dx I I
x x x
4 4 42 3 2 3
1 22 2 2
0 0 0
ln 9 3 ln 93 3
9 9 9
+ Tnh x x
I dx
x
4 2
12
0
ln 9
9
. t x x u2ln 9 du dx
x2
1
9
u
I udu
ln9 2 2 2
1ln3
ln 9 ln 3ln9
ln32 2
+ Tnhx
I dx
x
4 3
22
0 9
. t x v2 9
xdv dx x v
x
2 2
2, 9
9
u
I u du u
5 32
23
445( 9) ( 9 )
33 3
Vy
x x xI dx I I
x
4 2 3 2 2
1 220
ln 9 3 ln 9 ln 3
3 4429
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
39/48
Trang 39
Cu 172.e
x x xI dx
x x
3 2
1
( 1) ln 2 1
2 ln
e ex
I x dx dx x x
2
1 1
1 ln2 ln . +
ee
x ex dx
3 3
2
11
13 3
+e e
ex d x xdx x x
x x x x 1
1 1
1 ln (2 ln )ln 2 ln
2 ln 2 ln
e 2
ln2
. Vy:
e eI
3 1 2ln
3 2
.
Cu 173.e
xI dx
x x
33
1
ln
1 ln
tdx
t x x t tdt x
21 ln 1 ln 2 v x t3 2 3ln ( 1)
t t t t I dt = dt t t t dt t t t
2 2 22 3 6 4 2 5 3
1 1 1
( 1) 3 3 1 1( 3 3 ) 15 ln2
4
Cu 174.4
2
0
sin
cos
x x
I dxx
tu x du dx
xdv dx v
xx2
sin 1
coscos
x dx dx
Ix x x
4 44
0 0 0
2
cos cos 4 cos
+dx xdx
Ix x
4 4
1 20 0
cos
cos 1 sin
.t t xsin dt
I
t
22
1 20
1 2 2ln
2 2 21
Vy:2 1 2 2
ln4 2 2 2
Cu 175.4 3
2
1
ln(5 ) . 5
x x xI dx
x
Ta c:4 4
2
1 1
ln(5 )5 .
xI dx x x dx K H
x.
+x
K dx
x
4
21
ln(5 ) . t
u x
dxdv
x2
ln(5 )
K 3
ln45
+ H= x x dx 4
1
5 . . t t x5 H 164
15
Vy: I 3 164
ln45 15
Cu 176.
I x x x dx 0
22
(2 ) ln(4 )
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
40/48
Trang 40
Ta c: I x x dx 2
0
(2 ) + x dx2
2
0
ln(4 ) = I I1 2
+ I x x dx x dx
2 22
10 0
(2 ) 1 ( 1) 2
(s dng i bin: x t1 sin )
+x
I x dx x x dx
x
2 2 222 2
2 0 20 0
ln(4 ) ln(4 ) 24
(s dng tch phn tng phn)
6ln2 4 (i bin x t2tan )
Vy: I I I1 23
4 6 ln22
Cu 177.8 ln
13
xI dx
x
tu x dx
dudx x
dvv xx
ln
2 11
xI x x dx
x
88
33
12 1ln 2
+ Tnhx
J dxx
8
3
1 . t t x 1
t dtJ dt
t t
3 32
2 22 2
2 12 1 2 ln3 ln2
1 1
I 6ln8 4ln3 2(2 ln3 ln2) 20ln2 6ln3 4
Cu 178. dxxx
xI
2
1
3
2
ln1
Ta c: I xdx xx
2
31
1 1ln
.t
u x
dv dx xx
3
ln1 1
( )
I x x x dx xx x
22
4 511
1 1 1ln ln ln
4 4
=
21 63 1ln2 ln 264 4 2
Cu 179.e
xx x xI e dx
x
2
1
ln 1
Ta c:
e e e xx x e
I xe dx e xdx dx H K J x1 1 1ln
+e e
x x e x eH xe dx xe e dx e e1
1 1
( 1)
+e e ex xe
x x e ee eK e xdx e x dx e dx e J
x x11 1 1
ln ln
Vy: e e e eI H K J e e e J J e1 1 .
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
41/48
Trang 41
Cu 180.x x
I dx
x
2
3
4
cos
sin
Ta cx
x x2 3
1 2cos
sin sin
. t
u x
xdv dx
x3
cos
sin
du dx
v
x2
1
2sin
I = xx
2
2
4
1 1.
2 sin
+dx
x
x
2 2
2
44
1 1 1( ) cot
2 2 2 2 2sin
=
1
2.
Cu 181.
x x
I dxx
4
30
sin
cos
t:u x du dx
xdv dx v
x x3 2
sin 1
cos 2.cos
x dxI x
x x
44 4
2 200 0
1 1 1tan
2 4 2 4 22cos cos
Cu 182. dxx
xxI
2
0
2
2sin1
)sin(
Ta c:x x
I dx dx H K x x
22 2
0 0
sin1 sin2 1 sin2
+x x
H dx dx x
x
2 2
20 01 sin2
2cos4
. t:
u xdu dx
dxdv
v xx
21
tan2cos 2 4
4
x
H x x
22
0 0
1tan ln cos
2 4 2 4 4
+x
K dxx
22
0
sin
1 sin2
. t t x2
xK dx
x
22
0
cos
1 sin2
dx
K x
x
2 2
20 0
12 tan 1
2 42cos
4
K 1
2
Vy, I H K 1
4 2
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
42/48
Trang 42
Cu 183.x x x x
I dx
x
3
20
(cos cos sin )
1 cos
Ta c:
x x x x x
I x dx x x dx dx J K x x
2
2 20 0 0
cos (1 cos ) sin .sin
.cos .1 cos 1 cos
+ Tnh J x x dx 0
.cos .
. tu x
dv xdx cos
J x x x dx x 0 0
0
( .sin ) sin . 0 cos 2
+ Tnhx x
K dx
x2
0
.sin
1 cos
. t x t dx dt
t t t t x x K dt dt dx
t t x2 2 2
0 0 0
( ).sin( ) ( ).sin ( ).sin
1 cos ( ) 1 cos 1 cos
x x x x dx x dxK dx K
x x x2 2 2
0 0 0
( ).sin sin . sin .2
21 cos 1 cos 1 cos
t t x dt x dx cos sin . dtK
t
1
21
2 1
, t t u dt u du2tan (1 tan )
u duK du u
u
2 24 44
2
44 4
(1 tan ).
2 2 2 41 tan
Vy I2
24
Cu 184.x x x x
I dx
x x
2
32
3
( sin )sin
(1 sin )sin
Ta c:x x x x dx
I dx dx H K xx x x
2 2 223 3 3
2 2
3 3 3
(1 sin ) sin
1 sin(1 sin )sin sin
+x
H dx
x
2
3
23
sin
.t
u xdu dx
dx
dv v xx
2 cotsin
H3
+dx dx dx
Kx x
x
2 2 2
3 3 3
23 3 3
3 21 sin
1 cos 2cos2 4 2
Vy I 3 23
Cu 185.x x
I dxx
23
0
sin
1 cos2
htt ://me abook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
43/48
Trang 43
Ta c:x x x x
I dx dx dx H K x x x
2 23 3 3
0 0 2 0 2
sin sin
1 cos2 2cos 2cos
+x x
H dx dx x x
3 30 2 0 2
1
22cos cos
.tu x
du dxdxdv v x
x2
tancos
H x x xdx x 3 3300 0
1 1 1tan tan ln cos ln2
2 2 22 3 2 3
+x
K dx xdx
x
223 3
0 2 0
sin 1tan
22cos
x x 301 1
tan 32 2 3
Vy:
I H K 1 1 3 1 1
ln2 3 ( 3 ln2)2 2 3 6 22 3
Cu 186.I x x dx 3
0
1sin 1.
t t x 1 I t t tdt t tdt x xdx 2 2 2
2 2
1 1 1
.sin .2 2 sin 2 sin
t du xdxu xv xdv xdx
2 42cossin
I x x x xdx
222
11
2 cos 4 cos
t u x du dx
dv xdx v x
4 4
cos sin
. T suy ra kt qu.
Cu 187. xx
I e dx x
2
0
1 sin.
1 cos
x
xe dx x I e dx
x x
2 2
20 0
1 sin
2 1 coscos
2
+ Tnh x x
x x
xI e dx e dx xx
2 2
120 0
2sin .cossin 2 2
1 cos2cos
2
xxe dx
2
0
tan2
+ Tnhx
e dxI
x
2
220
1
2cos
2
. t
xxu e
du e dxdx
dv xvx2 tan2cos 2
2
xx
I e e dx
22
20
tan2
Do : I I I e21 2
.
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
44/48
Trang 44
Cu 188.x
xI dx
e x
20
cos
(1 sin2 )
x
xI dx
e x x
20 2
cos
(sin cos )
. tx x
x x x dx
u due edx x
dv vx xx x
2
cos (sin cos )
sin
sin cos(sin cos )
x x x
x x xdx xdxI
x xe e e
2 22
0 0 0
cos sin sin sin.sin cos
t
x x
u x du xdx
dxdv v
e e
1 1
1 1
sin cos
1
x x x
xdx xdxI x
e e ee
2 22
0 0 02
1 cos 1 cossin .
tx x
u x du xdx
dxdv v
e e
2 2
1 1
cos sin
1
x x
xdxI x I I e
e ee e
222
0 02 2
1 1 sin 1cos . 1 2 1
e
I2 1
2 2
Cu 189. x
x xI dx
6 64
4
sin cos6 1
t t x dt dx t xt x
t t x x I dt dx
6 6 6 64 4
4 4
sin cos sin cos6 6
6 1 6 1
xx
x xI dx x x dx
6 64 46 6
4 4
sin cos2 (6 1) (sin cos )
6 1
x dx4
4
5 3cos4
8 8
5
16
I 5
32
.
Cu 190.x
xdxI
46
6
sin
2 1
Ta c:
x x x
x x x
xdx xdx xdxI I I
04 4 46 6
1 20
6 6
2 sin 2 sin 2 sin
2 1 2 1 2 1
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
45/48
Trang 45
+ Tnhx
x
xdxI
0 4
1
6
2 sin
2 1
. t x t t
t t x
t t xI dt dt dx
0 0 04 4 4
1
6 6 6
2 sin ( ) sin sin
2 1 2 1 2 1
x
x x
xdx xdxI xdx x dx
4 46 6 6 64 2
0 0 0 0
sin 2 sin 1sin (1 cos2 )
42 1 2 1
x x dx
6
0
1(3 4cos2 cos4 )
8
4 7 3
64
Cu 191.e
I x dx
1
cos(ln )
tt t
t x x e dx e dt ln
tI e tdt
0
cos
= e1
( 1)2
(dng pp tch phn tng phn).
Cu 192. xI e x xdx 2
2sin 3
0
.sin .cos
t t x2sin t
I e t dt e
1
0
1 1(1 )
2 2 (dng tch phn tng phn)
Cu 193.I x dx 4
0
ln(1 tan )
t t x4
I t dt
4
0
ln 1 tan4
=
tdt
t
4
0
1 tanln 1
1 tan
= dt
t
4
0
2ln
1 tan
= dt t dt 4 4
0 0
ln2 ln(1 tan )
= t I40.ln2
I2 ln24
I ln2
8
.
Cu 194.I x x dx 2
0
sin ln(1 sin )
tx
u x du dx x
dv xdx v x
1 cosln(1 sin )
1 sinsincos
htt ://me abook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
46/48
Trang 46
x x
I x x x dx dx x dx x x
22 2 2
0 0 0
cos 1 sincos .ln(1 sin ) cos . 0 (1 sin ) 12
1 sin 1 sin 20
Cu 195.x x
I dxx
4
0
tan .ln(cos )
cos
t t xcos dt xdx sin t t
I dt dt
t t
1
12
2 211
2
ln ln .
t
u t
dv dt t2
ln
1
du dt t
vt
1
1
I
2
2 1 ln22
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
47/48
Trang 47
TP6: TCH PHN HM S C BIT
Cu 196.Cho hm sf(x) lin tc trn R v f x f x x 4( ) ( ) cos vi mixR.
Tnh: I f x dx 2
2
( )
.
t x = t f x dx f t dt f t dt f x dx 2 2 2 2
2 2 2 2
( ) ( )( ) ( ) ( )
f x dx f x f x dx xdx 2 2 2 4
2 2 2
2 ( ) ( ) ( ) cos
I 3
16
Ch : x x x4 3 1 1
cos cos2 cos48 2 8
.
Cu 197.Cho hm sf(x) lin tc trn R v f x f x x ( ) ( ) 2 2cos2 , vi mixR.
Tnh: I f x dx
3
2
3
2
( )
.
Ta c : I f x dx f x dx f x dx
3 302 2
03 3
2 2
( ) ( ) ( )
(1)
+ Tnh : I f x dx 0
1
32
( )
. t x t dx dt I f t dt f x dx 3 3
2 2
10 0
( ) ( )
Thay vo (1) ta c: I f x f x dx x x dx 3 3 3
2 2 2
0 0 0
( ) ( ) 2 1 cos2 2 cos
xdx xdx
32 2
0
2
2 cos cos
x x20
3
22 sin sin 6
2
http://megabook.vn
7/25/2019 200 Bai Tap Tich Phan Megabook
48/48
Cu 198.x
I dx
x x
4
2
4
sin
1
I x xdx x xdx I I 4 4
21 2
4 4
1 sin sin
+ Tnh I x xdx 4
21
4
1 sin
. S dng cch tnh tch phn ca hm s l, ta tnh c I1 0 .
+ Tnh I x xdx 4
2
4
sin
. Dngpp tch phn tng phn, ta tnh c: I22
24
Suy ra: I 2
24
.
Cu 199.
5
2
3 2 1
1 1
x
x
e x xI dx
e x x
5 5 5 5
2 2 2 2
3 2 1 1 1 2 1 2 1
1 1 1 1 1 1
x x x x
x x x
e x x e x x e x e xI dx dx dx dx
e x x e x x e x x
5 5
2 2
5 2 1 2 13
2 1( 1 1) 1( 1 1)
x x
x x
e x e xx dx dx
x e x x e x
t 2 1
1 12 1
x
x e x
t e x dt dxx
5
2
52 1 5
22
1
2 12 2 13 3 2ln 3 2ln
11
e
e
e eI dt I t
t ee
Cu 200.
xI dxx x x
24
20( sin cos )
.
x x x
I dxx x x x
4
20
cos.
cos ( sin cos )
. t
xu
x
x xdv dx
x x x2
coscos
( sin cos )
x x xdu dx
x
vx x x
2
cos sin
cos1
sin cos
x dx
I dx
44
=4